Answer: 13.2678 kg
Explanation: Well, 13.2678 kg is 29.25 in mass and kg.
The moon is half dark, half lit on two days each month . What causes this?
Answer:
This is caused by the rotation and position of the Earth with respect to the sun.
Explanation:
The constant change of the Moon's surface relative to Earth is called "The moon phases".
These modifications in our satellite are due to the change of position of the satellite with respect to the Earth and the Sun.
During the lunar phases of the third quarter and the first quarter, the moon lights up just a half, being that both only light half, the first quarter lights the right side of the moon, and the last quarter lights the left side.
Can you please help me?
Answer:
a= 18.4m
b= 26.2m
Explanation:
Please see the attached picture for full solution.
One multicellular organism is a cube. Each of its sides is 3 cm long. Each of its cells is 1 cm. How many cells does it have? If each side doubles in length how many cells will it then have? Show your work below.
Answer:
W23e45rdfytg
Explanation:
Eawsredtrftgvbyhgtfrd54e
One multicellular organism is a cube. Each of its sides is 3 cm long. If each of its cells is 1 cm, then it would have 27 cells, if each side doubles its length then it would have 216 cells.
What is the matter?Anything which has mass and occupies space is known as matter , mainly there are four states of matter solid liquid gas, and plasma.
These different states of matter have different characteristics according to which they vary their volume and shape.
As given in the problem, one multicellular organism is a cube. Each of its sides is 3 cm long. Each of its cells is 1 cm.
The volume of the multicellular organism = 3 × 3× 3
= 27 cm³
The number of cells = 27 cm³ / 1 cm³
= 27
Thus, If each of its cells is 1 cm, then it would have 27 cells, if each side doubles its length then it would have 216 cells.
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I REALLY NEED HELP What is a closed physical system A.A system where matter and energy can enter, but not leave the system B.non of the answers are true C.A system where matter and energy can leave, but not enter the system D.A system where matter and energy cannot enter or leave the system
You probably already took this but if anyone wanted to know the answer it's D. "A system where matter and energy cannot enter or leave the system".
(I also took the quiz for it and got it correct)
A closed physical system is a system where matter and energy cannot enter or leave the system. The correct option is D.
What is a physical system?A physical system is any item or part of an object that can be analyzed using physics laws.
An atom and lake water are both examples of physical systems. Everything outside the system is referred to as the environment, and it is ignored in the analysis except for its effects on the system.
A physical system is a collection of parts or elements that, when combined, exhibit behavior that the constituents do not. Matter and energy make up physical systems.
A closed system is a natural physical system that does not allow the transfer of matter into or out of the system, though it does allow the transfer of energy in contexts such as physics, chemistry, or engineering.
Thus, the correct option is D.
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A communications satellite orbiting the earth has solar panels that completely absorb all sunlight incident upon them. The total area A of the panels is 10m2.
1) The intensity of the sun's radiation incident upon the earth is about I = 1.4kW/m2. Suppose this is the value for the intensity of sunlight incident upon the satellite's solar panels. What is the total solar power P absorbed by the panels?
2) What is the total force F on the panels exerted by radiation pressure from the sunlight?
Answer:
0.00004666N
Explanation:
We know that
intensity (I) = P/ A
Where
P= power
A= Area
So lets say that the power absorbed
Will be = Intensity x Area
Which Is = 1.4 x 10^3 x(10)
So
14000 Watt = 14 kWatt
However we know that radiation pressure is equal to
time-averaged intensity all over the speed of light in free space
So
P = (1.4 x 1000)/c
But
F= P x A
So
((1.4 x 1000)/(3 x1 0^8)) x 10
Which is
=0.000046666N
Explanation:
Water forming a droplet is an example of:________.
Answer:
A perfect example of Surface tensionExplanation:
what is surface tension?
simply put, surface tension is the ability of water to act or behave as if it were or were covered by an elastic skin.
other notable examples of surface tension are
Examples of surface tension of water
1. Ants walking on water
2.Razor blades floating on water
3. Capillary action (water rising or falling in a narrow capillary tube)
Should you need further clarification do not hesitate to let me know
The inhabitants of a small island begin exporting beautiful clothmade from a rare plant that grows only on their island. Seeing howpopular the small quantity that they export has been, they steadilyraise their prices. A clothing maker from New York, thinking thathe can save money by "cutting out the middleman," decides to travelto the small island and buy the cloth himself. Ignorant of thelocal custom of offering strangers outrageous prices and thennegotiating down, the clothing maker accepts (much to everyone'ssurprise) the initial price of 400 tepizes/m^2. The price of thiscloth in New York is 120 dollars/yard^2.If the clothing maker bought 500m^2 of this fabric, how muchmoney did he lose? Use = 0.625Express your answer in dollars tothree significant figures.
Answer:
Lost Money = $ 53200
Explanation:
First, we calculate the selling price of the cloth:
Selling Price = (Area of Bought Fabric)(Unit Price in America)
Selling Price = (500 m²)($ 120/yard²)(1 yard/0.9144 m)²
Selling Price = $ 71759.4
Now, we calculate the amount that the cloth maker paid (cost) for buying the fabric from America:
Cost = (Area of Fabric Bought)(Unit Selling Price)
Cost = (500 m²)(400 tepizes/ m²)($ 0.625/1 tepize)
Cost = $ 125000
Hence, the money lost is given as:
Lost Money = Cost - Selling Price
Lost Money = $ 125000 - $ 71759.4
Lost Money = $ 53240
Rounding off to 3 significant figures, we get:
Lost Money = $ 53200
Which of the following describes how the mechanical advantage of a simple machine affects the amount of force needed for work? A. By decreasing the distance over which the input force is applied, less force is needed to do the same amount of work. B. By increasing the distance over which the input force is applied, more force is needed to do the same amount of work. C. By decreasing the distance over which the input force is applied, more force is needed to do the same amount of work. D. By increasing the distance over which the input force is applied, less force is needed to do the same amount of work.
Answer:
The answer is a
Explanation:
Enter the following expression in the answer box below: 2gλ3m−−−−√, where λ is the lowercase Greek letter lambda.
Answer:
[tex]\sqrt{\dfrac{2g\lambda^3}{m}}[/tex]
Explanation:
We can write the expression here, but the point of the problem seems to be to see if you can manipulate the controls on the answer box to reproduce that expression.
[tex]\boxed{\sqrt{\dfrac{2g\lambda^3}{m}}}[/tex]
A toy car that is 0.12 m long is used to model the actions of an actual car that
is 6 m long. Which ratio shows the relationship between the sizes of the
model and the actual car?
A: 5:1
B: 1:50
C: 50:1
D: 1:5
Answer:
it is B 1:50
Explanation:
just did it on apex
If A= +4j - 2i - 3k and C= -4i -2j - 3k , which of the following numbers is closest to the magnitude of A-C ?
The magnitude of Dot product of two vectors is 3.
Given vectors are,[tex]A= 4j - 2i - 3k[/tex] and [tex]C= -4i -2j - 3k[/tex]
The dot product two vectors shown below,[tex]A\cdot C=(-4*4)+(-2*-2)+(-3*-3)\\\\A\cdot C=-16+4+9\\\\A\cdot C=-16+13=-3[/tex]
Thus, The magnitude of Dot product of two vectors is 3.
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A particle is moving along the x-axis. Its position as a function of time is given as x=bt-ct^2a) What must be the units of the constants b and c, if x is in meters and t in seconds?b) At time zero, the particle is at the origin. At what later time t does it pass the origin again?c) Derive an expression for the x-component of velocity.d) At what time t is the particle momentarily at rest?e) Derive an expression for the x-component of the particles acceleration, ax
Answer:
We are given x= bt +ct²
So
A. bxt= m
Because m/s*s= m
So b= m/s and c= m/s²
B.
x= bt-ct²
So at x=0 t=0
x=0 t= 2
We have
bt = ct² so t = b/c at x= 0
So b-2ct= 0
B. To find velocity we use
dx / dt = b - 2 Ct
C. At rest wen V= 0
We have t= b/2c
D. To find acceleration we use
dv / dt = - 2C
When We are given x= bt +ct²
Then A. bx.t = mJust Because of the m/s*s= mSo that, b= m/s and c= m/s²Now B. x= bt-ct²the So at x=0 t=0After that x=0 t= 2Now We have bt = ct² so t = b/c at x= 0After that So b-2ct= 0Then B. To find velocity we use that isThen dx / dt = b - 2 CtThen C. At rest wen V= 0We have t= b/2cNow D. To find acceleration we useNow the answer is dv / dt = - 2CLearn more about:
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Which of the following are properties of a conductor in electrostatic equilibrium? The force on a charge near the conductor is zero. Electric field lines just outside the conductor are perpendicular to the surface. All net charge in the conductor is on the surface. The electric field inside the conductor is zero.
Answer:
The electric field inside the conductor is zero.
Explanation:
In electrostatic equilibrium charges are assumed to be in rest. Therefore no current.
I = 0
From the ohm's law
ΔV= IR = 0
⇒ΔV =0
Therefore, potential V is same through the conductor.
Also, E = -ΔV d = 0
Hence, The electric field inside the conductor is zero.
A 2250 kg truck has a velocity of 25 m/s to the east. What is the momentum of the truck? p = mv
The momentum of the truck is "56250 kgm/s".
According to the question,
Mass,
m = 2250 kgVelocity,
v = 25 m/sAs we know,
→ [tex]p = mv[/tex]
By putting the values, we get
→ [tex]= 2250\times 25[/tex]
→ [tex]= 56250 \ kgm/s[/tex]
Thus the answer is right.
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A wire carries a steady current of 2A.the Charge that passes a cross Section in 2s is
◈ Electric current :
Electric current is defined as the rate of charge flow. (per unit time)
I = Q/tI denotes current
Q denotes charge
t denotes time
Given : I = 2A and t = 2s
To Find : Charge flow in wire (Q)
[tex]:\implies\sf\:I=\dfrac{Q}{t}[/tex]
[tex]:\implies\sf\:2=\dfrac{Q}{2}[/tex]
[tex]:\implies\:\boxed{\bf{\red{Q=4\:C}}}[/tex]
A flow of electrical charge carriers, generally electrons or electron-deficient atoms, is referred to as current. The charge that will be in the wire is 4 C.
What is current?A flow of electrical charge carriers, generally electrons or electron-deficient atoms, is referred to as current. The capital letter I is a typical sign for current. The ampere, abbreviated as A, is the standard unit.
As it is given to us that the current in the wire is 2A, while the time for which the current flows through the wire is 2 seconds.
[tex]\rm I=\dfrac Qt[/tex]
Substitute the value we will get,
[tex]\rm 2\ A = \dfrac{Q}{2\ sec}\\\\Q = 4\ C[/tex]
Thus, the charge that will be in the wire is 4 C.
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If a car is driving at 10 m/s and is driving for 2 minutes, what is the total distance it will
cover?
Distance = (speed) x (time)
Distance = (10 meter/second) x (2 minutes)
Distance = (10 meter/second) x (2 minutes) x (60 second/minute)
Distance = (10 x 2 x 60) (meter-minute-second / second-minute)
Distance = 1,200 meters
Challenge Problem
5.
A man is standing on the top of a hill and sees a flagpole he knows is 45 feet high. The angle of
depression to the bottom of the pole is 12 degrees, and the angle of elevation to the top of the
pole is 16 degrees. Find his distance from the pole.
Answer: his distance from the pole is 90.16 ft
Explanation:
based on the diagram of the question i will upload along this answer;
45 - d is equal to part of the pole below the horizontal line
d/x = tan(16) ; x = d/tan(16)............equ1
(45-d) / x = tan(12); x = (45-d) / tan(12)-----------equ2
∴ d/tan(16) = (45-d) / tan(12)
d.tan(12) = (45-d).tan(16)
d.tan12 = (45×tan16) - d.tan16
0.2125d = 12.9034 - 0.2867d
0.2125d + 0.2867d = 12.9034
0.4992d = 12.9034
d = 12.9034/0.4992
d = 25.85 ft
now substitute value of d into any of our previous equation, lets take equation 1
x = 25.85 / tan(16)
x = 25.85 / 0.2867
x = 90.16 ft
Therefore his distance from the pole is 90.16 ft
A projectile is launched at some angle to the horizontal with some initial speed vi, and air resistance is negligible.(a) Is the projectile a freely falling body? (b) What is its acceleration in the vertical direction? (c) What is its acceleration in the horizontal direction?
Answer:
Explanation:
When a projectile is launched at some angle to the horizontal with some speed vi , and air resistance is negligible , it is definitely a freely falling body .
It is so because it is free to accelerate towards the earth with acceleration of g . Air has no resistance , hence no force is acting on it except the gravitational force . Hence it is a freely falling body .
b )
The acceleration in the vertical direction is due to force exerted by the earth that is gravitational force on it . Hence its acceleration is equal to g in vertically downward direction .
c )
It has zero acceleration in horizontal direction . It is so because no force is acting on it in horizontal direction . So no acceleration will be present in horizontal direction . It will move in horizontal direction with constant speed of vi cos θ where θ is the angle vi make with the horizontal .
The second law of thermodynamics leads us to conclude what?
a. the total energy of the universe is constant
b. disorder in the universe is increasing with the passage of time
c. it is theoretically impossible to convert work into heat with 100% efficiency
d. the total energy in the universe is increasing with time
e. the total energy in the universe is decreasing with time
Answer:
b. disorder in the universe is increasing with the passage of time
Explanation:
The second law of thermodynamics states that the total entropy of an isolated system increases over time . The entropy of a system measures the randomness or disorder in the system . So the we can state, in terms of disorder , the second law of thermodynamics as follows .
The disorder in the universe is increasing with the passage of time .
The second law of thermodynamics leads us to conclude that disorder in the universe is increasing with the passage of time. So, here, option b is the correct option.
Entropy is a measure of the disorder or randomness in a system. The second law of thermodynamics states that in any spontaneous process, the total entropy of an isolated system (including both the system and its surroundings) tends to increase or, at best, remain constant. This means that over time, natural processes tend to lead to an increase in the overall disorder or randomness of the system. It's important to note that while the increase in entropy is a statistical tendency on a macroscopic scale, there can still be localized decreases in entropy within a system.
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A boy throws a ball on a spring scales which oscillates about the equilibrium position with a period of T = 0.5 sec. The amplitude of the vibration is A = 2 cm. Assume the ball does not bounce from the scales’s surface afterwards. Assume the vibration of the scale is expressed mathematically as x(t) = Acos(t + ). Find:
Complete Question
A boy throws a ball on a spring scales which oscillates about the equilibrium position with a period of T = 0.5 sec. The amplitude of the vibration is A = 2 cm. Assume the ball does not bounce from the scales’s surface afterwards. Assume the vibration of the scale is expressed mathematically as x(t) = Acos(t + ). Find:
a) frequency
b) the maximum acceleration
c) the maximum velocity
Answer:
a
[tex]f = 2 \ Hz[/tex]
b
[tex]a_{max} = 3.2 \ m/s^2[/tex]
c
[tex]v_{max} = 0.25 \ m/s[/tex]
Explanation:
From the question we are told that
The period is [tex]T = 0.5 \ sec[/tex]
The amplitude is [tex]A = 2 \ cm = 0.02 \ m[/tex]
The vibration of the scale is [tex]Acos(wt + \phi )[/tex]
Generally the frequency is mathematically represented as
[tex]f = \frac{1}{T}[/tex]
=> [tex]f = \frac{1}{0.5}[/tex]
=> [tex]f = 2 \ Hz[/tex]
The maximum acceleration is mathematically represented as
[tex]a_{max} = A *(2 \pi f)^2[/tex]
=> [tex]0.02 * (2 * 3.142 * 2)^2[/tex]
=> [tex]a_{max} = 3.2 \ m/s^2[/tex]
The maximum velocity is mathematically represented as
[tex]v_{max} = A * (2 \pi f)[/tex]
=> [tex]v_{max} = 0.02 * (2 * 3.142 * 2)[/tex]
=> [tex]v_{max} = 0.25 \ m/s[/tex]
Public television station KQED in San Francisco broadcasts a sinusoidal radio signal at a power of 777 kW. Assume that the wave spreads out uniformly into a hemisphere above the ground.
A) At a home 5.50km away from the antenna, what average pressure does this wave exert on a totally reflecting surface? answer in PA units
B) At a home 5.50km away from the antenna, what are the amplitudes of the electric and magnetic fields of the wave? answer in N/C, T
C) At a home 5.50km away from the antenna, what is the average density of the energy this wave carries? answer in J/m^3
D) For the energy density in part (c), what percentage is due to the electric field?
E) For the energy density in part (c), what percentage is due to the magnetic field?
Answer:
A. Using
I= P/ A
So = P/ 2π R²
So=777E3 watt/ 2*πx (²5.5E3m)
4.3*10^ -3W/m²
So pressure= 2I/c
=2* 4.3*10^ -3W/m²/ 3*10^ 8
2.7*10^-11p.a
B.
Using Emax= √2I/Eoc
So
√ 2*4.3*10^-3/8.8E-12*3*10^8
= 5.48V/m
So
Bmax= Emax/c
5.58/3E8
= 1.83*10-9T
D.average density is given by
= Eo(Emax/√2)²
= 8.85E-12(5.48/√2)²
1.3*10^10W/m²
Which law of motion is this an example of?
Newton's 1st Law of Motion
Newton's 2nd Law of Motion
Newton's 3rd Law of Motion
Answer:Newton’s law also states that larger bodies with heavier masses exert more gravitational pull, which is why those who walked on the much smaller moon experienced a sense of weightlessness, as it had a smaller gravitational pull. To help explain his theories of gravity and motion, Newton helped create a new, specialized form of mathematics.
Explanation:
Answer: newtons 2nd law of motion because in order to push the object you must put force to the mass and move it causing motion
Explanation:
how much heat is required to convert 1 gm of ice into steam
Answer:
Heat required in converting 1g of ice at −10∘C into steam at 100∘C is: latent heat of fusion= 80 cal/g80 cal/g. latent heat of vaporization=540 cal/g.
You travel down the highway at a steady rate of 75 mph (33.53 m/s)  for a total of 25 minutes, calculate how far you traveled in meters
Answer:
50280 meters
Explanation:
33.52 meters/seconds is 2011.2 meters/minutes (multiply by 60)
2011.2 meters/m * 25 minutes = answer
Choose the correct definition of angular momentum.
the product of the object’s moment of inertia and the object’s angular velocity
the product of the object’s momentum and the object’s angular velocity
the product of the object’s momentum and the object’s moment of inertia
the product of the object’s momentum and the object’s angle through space
The answer is "the product of the object's moment of inertia and the object's angular velocity.
The correct definition of angular momentum would be that it is the product of the object’s moment of inertia and the object’s angular velocity, therefore the correct answer is option A.
What is momentum?It can be defined as the product of the mass and the speed of the particle, it represents the combined effect of mass and the speed of any particle, and the momentum of any particle is expressed in Kg m/s unit.
As given in the problem we have to find the correct definition of angular momentum,
The angular momentum of the object = the moment of the inertia of the object × the angular velocity of the particle
The right response is option A since the definition of angular momentum is that it is the product of an object's moment of inertia and its angular velocity.
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Which is NOT one of the 11 organ systems of the body?
Integumentary system
Immune system
Skeletal system
Digestive system
Answer:
Immune
Explanation:
because I remember taking that test and I I specifically remember that question and that's the answer
Caroline, a piano tuner, suspects that a piano's B4 key is out of tune. Normally, she would play the key along with her B4 tuning fork and tune the piano to match, but her B4 tuning fork is missing! Instead, she plays the errant key along with her A4 tuning fork (which has a frequency of 440.0 Hz), displays the resulting waveform on a handheld oscilloscope, and measures a beat frequency of 15.9 Hz. Then, she plays the errant key along with her C5 tuning fork (which has a frequency of 523.3 Hz) and measures a beat frequency of 67.4 Hz. What frequency is being played by the out-of-tune key? If the B4 key is supposed to produce a frequency of 493.9, is the frequency of the key lower than it should be ("flat") or higher than it should be ("sharp")?
Answer:
455.9 Hz, Flat
Explanation:
The beat frequency is basically the difference between the frequency of the B4 note and the frequency of the A4 tuning fork. This means the B4 note is 15.9 Hz off of 440Hz, and 67.4 Hz off of 525.3 Hz. As B4 is between the two notes, it would make sense to find its frequency by adding 15.9 to 440 and subtracting 67.4 from 523.3, both if which give us a frequency 455.9 Hz for the B4 key. This is because the note doesn't change for the different turning forks so both differences should result in the same frequency. Because the note should be 493.9 frequency but instead has a frequency of 455.9 Hz, it is flat because the frequency is lower than it is supposed to be.
Hope this helped!
This question deals with the phenomenon of "Beat Frequency".
The frequency being played by the B4 key is "455.9 Hz", which is "lower (flat) than it should be".
When two waves with a slightly different frequency interfere with each other, they produce a pattern known as beat frequency. The beat frequency is the difference between the frequencies of the interfering wave. Since the frequency of B4 key produces beat frequency with both the C5 tuning fork (which has a frequency of 523.3 Hz) and the A4 (which has a frequency of 440 Hz). Hence, the frequency of the B4 key must be between the range of these frequencies, that is, 440 Hz to 523.3 Hz.
ANALYZING THE BEAT FREQUENCY WITH A4 TUNING FORK:
Beat Frequency with A4 tuning fork = Frequency of B4 - Frequency of A4
Frequency of B4 = Frequency of A4 + Beat Frequency with A4 tuning fork
Frequency of B4 = 440 Hz + 15.9 Hz
Frequency of B4 = 455.9 Hz
ANALYZING THE BEAT FREQUENCY WITH C5 TUNING FORK:
Beat Frequency with C5 tuning fork = Frequency of C5 - Frequency of C5
Frequency of B4 = Frequency of C5 - Beat Frequency with C5 tuning fork
Frequency of B4 = 440 Hz - 67.4 Hz
Frequency of B4 = 455.9 Hz
Both the answers validate each other.
Since the expected frequency of the B4 key is 493.9 Hz, which is greater than the actual frequency produced by the B4 key. Hence, we can say that "the frequency of the key lower than it should be ("flat")"
The attached picture shows the general formula of the beat frequency.
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Which is the least dense liquid?
Answer:
lamp oil.
Explanation: the ping pong ball doesnt sink through the lamp oil.
The pilot of a helicopter drops a lead brick from a height of 500 m. (assume no air resistance and g~10 m/s2) roles Evalu How long does it take to reach the ground?
Answer:
The value is [tex]t = 10 \ s[/tex]
Explanation:
From the question we are told that
The height is [tex]h = 500 \ m[/tex]
The acceleration is [tex]g = 10 \ m/s[/tex]
Generally from the second equation of motion we have that
[tex]h = ut + \frac{1}{2} a t^2[/tex]
Here the initial velocity u = 0 m/s given that the stone started from rest
So
[tex]500 = 0 (t) +0.5 * (10) t^2[/tex]
=> [tex]t = 10 \ s[/tex]
what is the average number of electrons per second that flow past a fixed reference cross section that is perpendicular to the direction of flow
The complete question is;
In electronic circuits it is not unusual to encounter currents in the microampere range. Assume a 35 μA current, due to the flow of electrons. What is the average number of electrons per second that flow past a fixed reference cross section that is perpendicular to the direction of flow?
Answer:
2.185 × 10^(14) electrons/seconds
Explanation:
We are given current as 35 μA = 35 × 10^(-6) Amperes
The value of the charge on one electron is; e = 1.602 × 10^(-19) coulombs
Now, from conversions;
One ampere = one coulomb/second =
Then, 35 × 10^(-6) Ampere's would give;
35 × 10^(-6) Coulombs/sec
Now,
1.602 × 10^(-19) coulombs = 1 electron
Thus;
35 × 10^(-6) Coulombs/sec gives;
(35 × 10^(-6))/(1.602 × 10^(-19)) = 2.185 × 10^(14) electrons /sec
The average number of electrons per second that flow past a fixed reference cross-section perpendicular to the direction of flow is 2.185 × 10⁻¹⁴ electrons /sec
The flow of charge:The question is as given below:
In electronic circuits, it is not unusual to encounter currents in the microampere range. Assume a 35 μA current, due to the flow of electrons. What is the average number of electrons per second that flow past a fixed reference cross-section that is perpendicular to the direction of flow?
Given information:
Current I = 35 μA = 35 × 10⁻⁶ A
charge on electron e = 1.602 × 10⁻¹⁹C
We know that:
I = de/dt, rate of flow of charge.
1A = 1C/s
Thus,
35 × 10⁻⁶ A = 35 × 10⁻⁶ C/s
Now, one electron has a charge of 1.602 × 10⁻¹⁹C
So, the number of electrons for a current of 35 × 10⁻⁶ C/s will be:
n = (35 × 10⁻⁶ C/s) ÷ (1.602 × 10⁻¹⁹C)
n = 2.185 × 10⁻¹⁴ electrons /sec
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