A chemical reaction occurs according to the reaction mechanism shown below. Sort the chemical species involved into the appropriate categories.
H2O2(aq) + I-(aq) -> IO-(aq)+H2O(l)
H2O2(aq) + IO-(aq) -> I-(aq) +H2O(l) + O2(g)
what are the....
reactant :
product:
intermediate:
catalyst:

Hydrogen peroxide and water both contain the same two elements. The chemical formulas of hydrogen peroxide and water are respectively H2O2 and H2O. The two compounds have distinct physical and chemical properties. Here is a long answer to the question posed.

Water is a colorless, odorless, and tasteless liquid that is vital for life. Its melting point is 0 degrees Celsius, while its boiling point is 100 degrees Celsius. Water is the most prevalent chemical substance on Earth, with about 71% of the planet's surface covered by it.

Hydrogen peroxide is a pale blue liquid that is slightly more viscous than water. It has a bitter taste, and its odor is similar to that of bleach. The boiling point of hydrogen peroxide is 150.2°C, while the melting point is -0.43°C. Hydrogen peroxide is a powerful oxidizer that is commonly used as a bleaching agent, disinfectant, and antiseptic.


Chemical formulas are utilized in a variety of scientific applications, including chemical reactions and product descriptions. An incorrect chemical formula can have significant ramifications, potentially resulting in the formation of a hazardous substance.

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Answer:

5

Explanation:

Na, N, O, O, O

Answer:

it is b

Explanation:

mid ocean ridge diverges meaning it moving in two different direction horizontally - left to right

Answer:

A

Explanation:

[H+] = 10^-pH

[H+] = 1 x 10^-4 M

Answer:

True

Explanation:

The wavelength that corresponds to photons with greater energy is 320 nm. Hence, option a is correct.

The energy of a photon is inversely proportional to its wavelength according to the equation:

E = hc/λ

where E is the energy of the photon, h is Planck's constant (approximately 6.626 x 10^-34 J·s), c is the speed of light (approximately 3.00 x 10^8 m/s), and λ is the wavelength of the photon.

Since energy (E) is inversely proportional to wavelength (λ), shorter wavelengths correspond to photons with greater energy. Therefore, the photon with a wavelength of 320 nm has greater energy compared to the photon with a wavelength of 530 nm.

The wavelength that corresponds to photons with greater energy is 320 nm (option a).

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The transition wavelength, λ is given as:λ = (hc)/Eλ = (6.626 x 10^-34 Js * 3 x 10^8 m/s)/(4.585 x 10^-20 J)λ = 4.325 x 10^-7 mλ = 432.5 nmTherefore, if the length of the box is doubled, the transition wavelength remains the same as 200 nm.

The length of the box, L = 1 nm.The transition wavelength, λ = 200 nm.Formula:For particle in a one-dimensional box,For the energy of a particle in a one-dimensional box,E = (n²h²)/(8mL²)where, n = quantum numberh = Planck's constanm = mass of the particleL = length of the box.1. For the lowest energy level,n = 1E₁ = (n²h²)/(8mL²)E₁ = (1²h²)/(8mL²)E₁ = (1*6.626 x 10^-34 Js)²/(8(9.11 x 10^-31 kg)(1 x 10^-9 m)²)E₁ = 9.170 x 10^-20 JFrom the above formula, the probability of finding the particle within 0.01 nm of the center of the box is given as:ψ(x) = sqrt(2/L)sin(nπx/L)Probability, P = ∫ψ²dxFrom the above formula, the probability of finding the particle within 0.01 nm of the center of the box for the lowest-energy level is given as:P = ∫[sqrt(2/L)sin(πx/L)]²dxP = ∫2/L sin²(πx/L)dxP = 2/L * L/2P = 1Hence, the probability of finding the particle within 0.01 nm of the center of the box for the lowest-energy level is 1.2. For the first excited state,n = 2E₂ = (n²h²)/(8mL²)E₂ = (2²h²)/(8mL²)E₂ = (4*6.626 x 10^-34 Js)²/(8(9.11 x 10^-31 kg)(1 x 10^-9 m)²)E₂ = 3.668 x 10^-19 JFrom the above formula, the probability of finding the particle within 0.01 nm of the center of the box for the first excited state is given as:P = ∫[sqrt(2/L)sin(2πx/L)]²dxP = ∫2/L sin²(2πx/L)dxP = 2/L * L/2P = 0.5Hence, the probability of finding the particle within 0.01 nm of the center of the box for the first excited state is 0.5.3. (i) If the mass of the particle is doubled:For the energy of a particle in a one-dimensional box,E = (n²h²)/(8mL²)The energy of a particle is inversely proportional to the mass of the particle.Hence, if the mass of the particle is doubled, the energy of the particle is halved.E = 0.5E₁ = 0.5(9.170 x 10^-20 J)E = 4.585 x 10^-20 JFrom the above formula, the transition wavelength, λ is given as:λ = (hc)/Eλ = (6.626 x 10^-34 Js * 3 x 10^8 m/s)/(4.585 x 10^-20 J)λ = 4.325 x 10^-7 mλ = 432.5 nm(ii) If the charge of the particle is doubled:The charge of the particle does not have any effect on the energy of the particle.Therefore, the transition wavelength, λ remains the same as 200 nm.(iii) If the length of the box is doubled:For the energy of a particle in a one-dimensional box,E = (n²h²)/(8mL²)The energy of a particle is inversely proportional to the length of the box.Hence, if the length of the box is doubled, the energy of the particle is halved.E = 0.5E₁ = 0.5(9.170 x 10^-20 J)E = 4.585 x 10^-20 JFrom the above formula, the transition wavelength, λ is given as:λ = (hc)/Eλ = (6.626 x 10^-34 Js * 3 x 10^8 m/s)/(4.585 x 10^-20 J)λ = 4.325 x 10^-7 mλ = 432.5 nmTherefore, if the length of the box is doubled, the transition wavelength remains the same as 200 nm.

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The mass of the ice melted by a complete transfer of thermal energy is 83.84 g.

The mass of the ice melted by a complete transfer of thermal energy is calculated by applying the following equation as follows;

Q = mcΔθ

where;

heat gained by the ice = heat loss by the steam

The mass of the ice melted by a complete transfer of thermal energy is calculated;

m x heat of fusion = 12.39g x heat of vaporization

m x 334 J/g = 12.39 g  x 2260 J/g

334m = 28,001.4

m = 28,001.4 / 334

m = 83.84 g

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We can see here that the acid-catalyzed addition of alcohols to alkenes proceeds in a mechanism analogous to the acid-catalyzed addition of water to yield ethers. True.

Alcohol is a broad term that refers to a class of organic compounds characterized by the presence of a hydroxyl (-OH) functional group attached to a carbon atom.

The acid-catalyzed addition of alcohols to alkenes is a useful reaction for the synthesis of ethers. It is also a relatively mild reaction, which makes it a good choice for the synthesis of ethers from sensitive compounds.

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In accordance with the diagram, activation energy is the distance from the reactants to the top of the "hill"

The activation energy represented on the energy diagram is as given as

"Activation energy is the distance from the reactant to the top of the hill"

So, the correct option is A.

The minimum amount of energy required by the reactant to do the reaction is called activation energy.

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Answer:

Refraction is the bending of a wave when it enters a medium where its speed is different, like going from the air (gas) to a glass of water (liquid). Absorption is when light energy penetrates an object. Typically this energy is then converted to heat.

Answer:

Explanation:

H m sarav

The pressure equilibrium constant expression for the given reaction 2Li3N(s) ⇌ 6Li(s) + N2(g) is given below: P = (PN2 ) (PLi)6/ (PLi3N )2Where, PN2 is the partial pressure of nitrogen PLi is the partial pressure of lithiumPLi3N is the partial pressure of lithium nitride.

The above formula of pressure equilibrium constant expression gives the ratio of the product of partial pressures of reactants and products to the power of their stoichiometric coefficients. Here, the stoichiometric coefficients of Li3N, Li and N2 are 2, 6 and 1 respectively. The reaction 2Li3N(s) ⇌ 6Li(s) + N2(g) represents the dissociation of lithium nitride to lithium and nitrogen gases. The dissociation reaction is endothermic.

As the temperature increases, the dissociation of lithium nitride increases which results in the formation of more lithium and nitrogen gas molecules. Therefore, the value of the equilibrium constant for this reaction increases with increasing temperature. The above-pressure equilibrium constant expression helps to determine the equilibrium concentration of reactants and products when the reaction is in equilibrium.

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To calculate the standard reaction free energy (ΔG°) for the given redox reaction, we need to use the standard reduction potentials from the ALEKS data tab.

To calculate the standard reaction free energy (ΔG°) for the given redox reaction, we need to utilize the standard reduction potentials (E°) of the involved species. The ΔG° is related to the standard reduction potentials through the equation: ΔG° = -nFΔE°, where n represents the number of electrons transferred and F is the Faraday constant.

Let's analyze the reaction and identify the half-reactions to determine the number of electrons transferred.

Half-reaction 1: I2(s) + 2e- → 2I- (aq)

Half-reaction 2: Br2(l) + 2e- → 2Br- (aq)

Half-reaction 3: 6H2O (l) → 12H+ (aq) + 6e-

Half-reaction 4: 2IO3- (aq) + 12H+ (aq) + 10e- → I2 (s) + 6H2O (l)

By comparing the half-reactions, we can see that 5 electrons are transferred in the reaction.

For the oxidation reactions:

   2IO3- (aq) + 12H+ (aq) + 10Br- (aq) → I2 (s) + 6H2O (l) + 5Br2 (l): coefficient = 1

Now we can calculate ΔGᴰ:

ΔGᴰ = (1 * E°(I2/I-)) + (5 * E°(Br2/Br-)) + (3 * E°(H2O/O2)) - (1 * E°(IO3-/H2O/Br2))

Substituting the values:

ΔGᴰ = (1 * 0.536 V) + (5 * 1.087 V) + (3 * 1.229 V

ΔE° = E°(half-reaction 4) - [E°(half-reaction 1) + E°(half-reaction 2) + E°(half-reaction 3)]

After obtaining ΔE°, we can calculate the standard reaction free energy (ΔG°) using the equation ΔG° = -nFΔE°. Since we know n = 5 and F is a constant, we can substitute these values into the equation to calculate ΔG°.

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Answer:

VOLTIC CELL

Battery

Electrical to chemical

Endothermic

Electrolysis

Chemical to electrical

Anode

Anode to cathode

Battery

Endothermic

Negative

Enthomeric

Reduction

Oxidation

ELECTRYOTIC CELL

No

Non spontaneous

positive

negative

yes

Anode

Electrical to chemical

Anode to cathode

Exothermic

positive

oxidation

Electroplating

Chemical to electrical

Answer:

uhm i believe its D hope i helped

Explanation:

Answer:

D. decomposers

The fact that there are more possible combinations for amino acids than the number of amino acids themselves implies that each amino acid can be encoded by multiple codons.

A codon is a sequence of three nucleotides in DNA or RNA that corresponds to a specific amino acid.

There are 20 standard amino acids used to build proteins in living organisms. However, there are 64 possible three-letter combinations of nucleotides (4³) that can be used to form codons. This means that on average, there are more than three codons that can encode each amino acid.

To calculate the number of codons per amino acid on average, we divide the total number of codons (64) by the number of amino acids (20). Therefore, the average number of codons per amino acid is 64/20 = 3.2.

This indicates that there is a degeneracy or redundancy in the genetic code, where multiple codons can specify the same amino acid.

For example, the amino acid leucine is encoded by six different codons (UUA, UUG, CUU, CUC, CUA, CUG), while methionine and tryptophan are each encoded by a single codon.

In conclusion, the existence of more possible combinations for amino acids than amino acids themselves means that the genetic code is degenerate, allowing for redundancy and flexibility in protein synthesis.

This redundancy helps to protect against errors in DNA replication and transcription and allows for evolution to occur through the accumulation of genetic variations.

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Answer:

(40 g O) / (15.99943 g O/mol) x (1 mol CaCO3 / 3 mol O) x (100.0875 g CaCO3/mol) =  

83 g CaCO3

So answer D), although three significant digits are not justified.

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The molar mass of the acid is 82.0 g/mol. The Ka of the unknown acid is  1.69 × 10⁻⁶.

Molar mass of the acid:

The molar mass of the acid can be calculated using the following equation:

Molar mass = mass / moles

The mass of the acid is 0.2140 g and the moles of the acid can be calculated using the following equation:

moles = volume × concentration

The volume of NaOH used to reach the equivalence point is 27.4 mL and the concentration of NaOH is 0.0950 M.

moles of NaOH = 27.4 mL × 0.0950 M = 2.613 mmol

Since the acid and NaOH react in a 1:1 ratio, the moles of the acid is also 2.613 mmol.

Substituting these values into the first equation:

Molar mass = 0.2140 g / 2.613 mmol = 82.0 g/mol

Ka for the unknown acid:

The Ka for the unknown acid can be calculated using the following equation:

Ka = [H⁺][A⁻] / [HA]

where:

Ka is the acid dissociation constant

[H⁺] is the concentration of hydrogen ions

[A⁻] is the concentration of the conjugate base

[HA] is the concentration of the acid

The concentration of hydrogen ions can be calculated using the pH. The pH of the solution after 15.0 mL of base had been added is 6.50.

pH = -log[H⁺]

6.50 = -log[H⁺]

[H⁺] = 10^-6.50

[H⁺] = 3.162 × 10⁻⁷ M

The concentration of the conjugate base can be calculated using the following equation:

[A-] = moles of A- / volume of solution

The moles of A⁻ = the moles of NaOH added after 15.0 mL, which is 1.438 mmol. The volume of the solution is 25.0 mL + 15.0 mL = 40.0 mL.

[A⁻] = 1.438 mmol / 40.0 mL

[A⁻] = 3.595 × 10⁻³ M

The concentration of the acid can be calculated using the following equation:

[HA] = moles of HA / volume of solution

The moles of HA = the moles of acid, which is 2.613 mmol. The volume of the solution is 40.0 mL.

[HA] = 2.613 mmol / 40.0 mL

[HA] = 6.532 × 10⁻³ M

Substituting these values into the Ka equation:

Ka = (3.162 × 10⁻⁷ M)(3.595 × 10⁻³ M) / (6.532 × 10⁻³ M)

Ka = 1.69 × 10⁻⁶

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Answer:

[tex]d=1.78\times 10^{-7}\ Dg/\mu m^3[/tex]

Explanation:

Given,

The density of Helium is [tex]1.78\times 10^4\ g/cm^3[/tex]

We need to find the density in Dg/μm

We know that,

1 g = 10 dg

1 cm³ = 10¹² μm³

So,

[tex]d=1.78 \times 10^4\ g/cm^3\\\\=1.78 \times 10^4\times \dfrac{10\ dg}{10^{12}\ \mu m^3}\\\\=1.78\times 10^{-7}\ Dg/\mu m^3[/tex]

So, the density of Helium is equal to [tex]1.78\times 10^{-7}\ Dg/\mu m^3[/tex].

Explanation:

Na2CO3+Ca(No3)2---> CaCO3+2NaNo3

Answer: 2

Explanation: Greenhouse gases are very important in keeping our planet just right. If we have too many Greenhouse gases it would be too hot, but we can't eliminate all of them or it will be too cold

Answer:

Light waves are electromagnetic waves while sound waves are mechanical waves. light waves are transverse while sound waves are longitudinal. sound waves require a material medium to travel, and hence, cannot travel in a vacuum. the speed of light in a medium is constant.

Explanation:

Hope this helped Mark BRAINLIEST!!

For the B₁-B₂ cell pair, B₂ is the cathode, and B₁ is the anode. For the A₁-B₂ cell pair, B₂ is the cathode, and A₁ is the anode. For the A₂-B₂ cell pair, B₂ is the cathode, and A₂ is the anode.

B₁-B₂:

The half-reaction at B₁ is given as A⁺(aq) + 2e⁻ → A(s) with a reduction potential of -0.78 V.

The half-reaction at B₂ is given as B⁺(aq) + e⁻ → B(s) with a reduction potential of -0.45 V.

Since the reduction potential of B₂ (-0.45 V) is more positive than B₁ (-0.78 V), B2 will be the cathode, and B1 will be the anode.

A₁-B₂:

The half-reaction at A₁ is given as C⁺(aq) + 2e⁻ → C(s) with a reduction potential of -0.95 V.

The half-reaction at B₂ is the same as mentioned before B⁺(aq) + e⁻ → B(s) with a reduction potential of -0.45 V.

Since the reduction potential of B₂ (-0.45 V) is more positive than A₁ (-0.95 V), B₂ will be the cathode, and A₁ will be the anode.

A₂-B₂:

The half-reaction at A₂ is given as D⁺(aq) + 2e⁻ → D(s) with a reduction potential of -0.70 V.

The half-reaction at B₂ is the same as mentioned before B⁺(aq) + e⁻ → B(s) with a reduction potential of -0.45 V.

Since the reduction potential of B₂ (-0.45 V) is more positive than A₂ (-0.70 V), B₂ will be the cathode, and A₂ will be the anode.

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At a pressure of 537.7 torr, pure water would boil at approximately 95.8°C.

To calculate the boiling point of water at a given pressure, we can use the Clausius-Clapeyron equation:

ln(P2/P1) = (-ΔHvap/R) × (1/T2 - 1/T1)

where:

P1 and P2 are the initial and final pressures,

ΔHvap is the molar enthalpy of vaporization,

R is the ideal gas constant (8.314 J/(mol·K)),

T1 is the initial temperature,

T2 is the final temperature.

In this case, we want to find the boiling point (T2) of water at a pressure of 537.7 torr. The normal boiling point of water is 100°C (373.15 K) at atmospheric pressure (760 torr).

We can rearrange the equation to solve for T2:

T2 = (1/(((-ΔHvap/R) × (1/T1)) + (ln(P2/P1))))

Substituting the given values:

P1 = 760 torr

P2 = 537.7 torr

ΔHvap = 40.7 kJ/mol (convert to J/mol by multiplying by 1000)

R = 8.314 J/(mol·K)

T1 = 373.15 K

T2 = (1/(((-40.7 kJ/mol × 1000 J/kJ) / (8.314 J/(mol·K)) × (1/373.15 K)) + (ln(537.7 torr/760 torr))))

Calculating this expression gives us:

T2 ≈ 95.8°C

Therefore, at a pressure of 537.7 torr, pure water would boil at approximately 95.8°C.

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