A city council with six members must elect a five-person executive committee consisting of a mayor, deputy mayor, secretary, administrator, and treasurer. How many executive committees are possible?
Determine the appropriate counting technique. Choose the correct answer below
A. Arrangements with repetition should be used because no llem may be selected more than once and the order maters
B. Permutations should be used because no item may be selected more than once and the order matters
C. Combinations should be used because no tem may be selected more than once and the order does not matter
D. Arangements with repetition should be used because we make selections from a group of choices
E. Permutations should be used because we make selections from a group of choices

Calculate how many different committees are possible

the test statistic (t = -12.857) is smaller than the critical value (-1.860), we have enough evidence to reject the null hypothesis.

To test the hypothesis regarding the population mean, we can perform a one-sample t-test.

Given:

- Null hypothesis (H₀): μ = 13

- Alternative hypothesis (Hₐ): μ < 13

- Sample mean ([tex]\bar{X}[/tex]) = 10

- Sample standard deviation (s) = 0.7

- Sample size (n) = 9

- Significance level (α) = 0.05

To conduct the t-test, we can calculate the test statistic and compare it with the critical value from the t-distribution.

The test statistic (t-score) is calculated as:

t = ([tex]\bar{X}[/tex] - μ) / (s / √n)

Plugging in the values:

t = (10 - 13) / (0.7 / √9)

t = -3 / (0.7 / 3)

t = -3 / 0.233

t ≈ -12.857

To determine the critical value, we need to find the appropriate degrees of freedom (df) for a one-sample t-test. In this case, df = n - 1 = 9 - 1 = 8.

Using a significance level of α = 0.05 and looking up the critical value for df = 8 in the t-distribution table, we find the critical value to be approximately -1.860.

Since the test statistic (t = -12.857) is smaller than the critical value (-1.860), we have enough evidence to reject the null hypothesis.

Decision: Based on the test results, at α = 0.05, we reject the null hypothesis (H₀: μ = 13). There is sufficient evidence to support the alternative hypothesis (Hₐ: μ < 13), suggesting that the population mean is less than 13.

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Given question is incomplete, the complete question is below

Assuming the sample was taken from a normal population, test at α = 0.05 and state the decision. Họ: μ = 13 HA: μ < 13 [tex]\bar{X}[/tex]= 10 s= 0.7 n = 9

Answer:

x²=20² -14²

x²=400-196

x²=204

x=√204

The correct answer should be 32.

To simplify the expression (4 + 3i)(2 - 8i), we can use the distributive property of multiplication.

First, we multiply the real parts of the two complex numbers:

(4)(2) = 8.

Next, we multiply the imaginary parts of the two complex numbers:

(3i)(-8i) = -24i^2.

Remember that i^2 is defined as -1, so we can substitute -1 for i^2:

-24i^2 = -24(-1) = 24.

Now, we combine the real and imaginary parts:

8 + 24 = 32.

Therefore, the simplified expression is 32.

Since none of the given answer choices match the simplified expression, it appears that there may be an error in the options provided. The correct answer should be 32.

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Answer:

The answer is B, have a wonderful day!

Step-by-step explanation:

a. The probability of all girls in a family with four children is 1/16 or 0.0625.

b. The probability of all girls given there is at least one girl is 1/15 or 0.0667.

c. The probability of having at least one boy and one girl in a family with four children is 15/16 or 0.9375.

a. To calculate the probability of all girls, we need to consider the possible outcomes of each child being a girl. Since each child has an independent probability of being a girl or a boy, the probability of all girls is (1/2) * (1/2) * (1/2) * (1/2) = 1/16 or 0.0625.

b. Given that there is at least one girl, we have three remaining children. The probability of all girls among the three remaining children is (1/2) * (1/2) * (1/2) = 1/8. Therefore, the probability of all girls given there is at least one girl is 1/8 divided by the probability of having at least one girl, which is 1 - (1/2)⁴ = 15/16, resulting in a probability of 1/15 or approximately 0.0667.

c. The probability of having at least one boy and one girl can be calculated by subtracting the probability of having all boys from the total probability space. The probability of having all boys is (1/2)⁴ = 1/16. Therefore, the probability of having at least one boy and one girl is 1 - 1/16 = 15/16 or approximately 0.9375. This probability accounts for all possible combinations of boys and girls in a family with four children, excluding the scenario of having all boys.

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Answer:

12

Step-by-step explanation:

1/5 mint = 6

30 - 6 = 24

Half of 24 is 12

12 is chocolate

so 12 must be vanilla

Answer: 9 x 6 x 6

Step-by-step explanation: 9 x 6=54  54 x 6 = 324 ft

Answer:

42+123+x=180

x=180-165

x=15 degrees

Step-by-step explanation:

Answer:

1733.33

Step-by-step explanation:

The volume of a pyramid is (length*width*height) divided by 3

Answer:

1733.33

Step-by-step explanation:

v = (lwh)/3

v = (20 x 20 x 13)/3 = 5200/3 = 1733.33

Answer:

okay then

Step-by-step explanation:

Answer: gtyrehretr

Step-by-step explanation:

Answer:

4324eqW

Step-by-step explanation:

3 + 5 =7

a.  the value of P(2.4 < x < 3) is 8.1.

b. the value of E(X) is 10.

Given function is f(x) = 5(6)x for x≥1 and elsewhere for a continuous random variable z.  

a. Compute P(2.4 < x < 3)

For continuous random variable, P(a < x < b) = ∫f(x)dx, where f(x) is the probability density function (PDF).

Here, f(x) = 5(6)x for x≥1 and elsewhere

So, P(2.4 < x < 3) = ∫f(x)dx = ∫2.4^35(6)xdx= 5 ∫2.4^36xdx= 5 [(3^2 - 2.4^2)/2] = 5 [(9 - 5.76)/2] = 5 [1.62] = 8.1

Hence, the value of P(2.4 < x < 3) is 8.1.

b. Compute E(X)Expected value of X is given by E(X) = ∫xf(x)dxFor continuous random variable, E(X) = ∫xf(x)dx, where f(x) is the probability density function (PDF).Here, f(x) = 5(6)x for x≥1 and elsewhereSo, E(X) = ∫xf(x)dx = ∫1∞5(6)x.xdx+ ∫-∞0 0dx= 5 ∫1∞6x^2dx+ 0 = 5 [(6) (x^3)/3]1∞= 5 [(6) (1^3)/3] = 10

Hence, the value of E(X) is 10.

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Given f(x)= 5 (6) x for rexeh 1 o elsewhere for a continuous veidon variable z. We are required to compute p(2.4 < x <3) and E(x).

Compute p(2.4 < x <3)For the given function, f(x) = 5 (6) x for 1 ≤ x ≤ 3 and 0 elsewhere.

So, the total area under the curve will be equal to 5 (6) 2 = 60.

And the required probability is given by the area under the curve from 2.4 to 3.  [Illustration is provided below]

Hence, p(2.4 < x <3) = 3.6

(b)Compute E(x)Expected value of x, E(x) is given by E(x) = ∫xf(x) dx,

which is equal to the area under the curve multiplied by the distance over which the function is spread.

Let's calculate the area under the curve, which is equal to 60, as we have calculated earlier.

Now, we calculate the distance over which the function is spread.

Distance = 3 - 1 = 2 unitsHence, E(x) = 60/2 = 30.

Answer:Therefore, p(2.4 < x <3) = 3.6 and E(x) = 30.

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Answer:

not a right triangle

Step-by-step explanation:

you can use the pythagorean theorem to prove whether not this is a right triangle

if this triangle is a right triangle then the following equality should be true

a²+b²=c²

(9.75)²+(3.45)²=(10.24)²

(95.06)+(11.90)=(104.86)

106.96≠104.86

since the following equality is not true, this is not a right triangle.

Answer:

I would need to see the different tables to answer this question.

Add 4.5

---

hope it helps

Answer: add 4.5 to both sides

Step-by-step explanation: this will allow the 4.5 to be removed from the y side and since you added it to one side you have to add it to the other side. This will give your y the value of 16.7.

Brainliest plz

Answer:

10 liters of water

Step-by-step explanation:

Given

[tex]A = 10L\ milk[/tex]

Required

How much the second holds

Since they are both identical, then both containers hold the same volume (even if the quantity they hold are different)

Hence:

[tex]B = 10L\ water[/tex]

Answer:

By using iteration, we can guess the explicit formula for the given sequence. It is found that the sequence follows a quadratic pattern, and the explicit formula is dx = 3([tex]2^{k-1}[/tex]) + 3[tex]k^2[/tex] - 6k + 3.

Let's start by analyzing the given sequence: dx = 2dx-1 + 3[tex]k^2[/tex]. We are given that d1 = 3. We can use this initial value to find d2, d3, and so on.

Substituting k = 2 into the given equation, we get d2 = 2d1 + 3([tex]2^2[/tex]) = 2(3) + 3(4) = 6 + 12 = 18.

Similarly, substituting k = 3, we get d3 = 2d2 + 3[tex](3^2)[/tex] = 2(18) + 3(9) = 36 + 27 = 63.

Based on these calculations, we observe that each term in the sequence is related to the previous term by multiplying it by 2 and adding 3[tex]k^2[/tex]. Moreover, we notice a quadratic pattern in the sequence.

To find the explicit formula, we can express dx in terms of k:

dx = 2dx-1 + 3[tex]k^2[/tex]

  = 2(2dx-2 + 3[tex](k-1)^2[/tex]) + 3[tex]k^2[/tex]

  = 4dx-2 + 6[tex](k-1)^2[/tex][tex](k-1)^2[/tex] + 3[tex]k^2[/tex].

We can continue this iteration process, expanding dx-2 in terms of dx-3, and so on. By continuing this process and simplifying the equation, we find that the explicit formula for the sequence is dx = 3([tex]2^{k-1}[/tex]) + 3[tex]k^2[/tex] - 6k + 3.

In conclusion, by using iteration, we have determined that the explicit formula for the given sequence dx = 2dx-1 + 3[tex]k^2[/tex], with d1 = 3, is dx = 3([tex]2^{k-1}[/tex]) + 3[tex]k^2[/tex] - 6k + 3.

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Answer:

1/3 or 33%

Step-by-step explanation:

15 + 15 + 20 +25 is equal to 75

25/75 is 1/3

Answer:

1 by 3

Step-by-step explanation:

15 + 15 + 20 + 25 = 75

so,

again,

Answer: Y less than -3x – 3

Step-by-step explanation:

Answer: 6 liters

Step-by-step explanation:

24 liters

He sells 75%

24 x 0.75 = 18 liters

24 - 18 = 6

He still has 6 liters left

Answer: 11x + 20y ≥ 220

x + y ≤ 15

Hope this helps

9514 1404 393

Answer:

Step-by-step explanation:

The two inequalities represent the two relations described in the problem statement.

  x + y ≤ 15 . . . . . . . Mia works a maximum of 15 hours

  11x + 20y ≥ 220 . . . . Mia makes at least $220

These are graphed in the attachment. The solution area is the doubly-shaded area with vertices at (9, 6), (0, 11) and (0, 15). One possible solution is shown at (3, 11), which represents ...

  3 hours babysitting

  11 hours lifeguarding . . . . . . . . total 14 hours for $253

1. When a fair die is tossed the expected value E[X1] = 3.5 and the variance var(X1) = 35/12.

When a fair die is tossed, each of the six possible outcomes has an equal probability of 1/6. Let X1 denote the score obtained in the first toss.

To calculate the expected value E[X1], we find the sum of all possible values of X1 multiplied by their respective probabilities:

E[X1] = (1 * 1/6) + (2 * 1/6) + (3 * 1/6) + (4 * 1/6) + (5 * 1/6) + (6 * 1/6) = 3.5

To calculate the variance var(X1), we use the formula:

var(X1) = E[X1^2] - (E[X1])^2

First, we find E[X1^2] by taking the sum of the squares of all possible values of X1 multiplied by their respective probabilities:

E[X1^2] = (1^2 * 1/6) + (2^2 * 1/6) + (3^2 * 1/6) + (4^2 * 1/6) + (5^2 * 1/6) + (6^2 * 1/6) = 91/6

Substituting the values into the formula, we calculate var(X1):

var(X1) = (91/6) - (3.5)^2 = 35/12

Therefore, E[X1] = 3.5 and var(X1) = 35/12.

2. The probability distribution of Y = |X1 - X2| is tabulated as follows:

Y |X1 - X2| P(Y)

0 0 1/6

1 1 2/6

2 2 2/6

3 3 1/6

To calculate E[Y], we find the sum of all possible values of Y multiplied by their respective probabilities:

E[Y] = (0 * 1/6) + (1 * 2/6) + (2 * 2/6) + (3 * 1/6) = 1

Therefore, E[Y] = 1.

3. The statements E(Z^2) = E(Y^2) and Var(Z) = Var(Y) are false.

E(Z^2) and E(Y^2) represent the expected values of the squares of the random variables Z and Y, respectively. Since Z = X1 - X2 and Y = |X1 - X2|, the squares of Z and Y have different probability distributions, leading to different expected values.

Similarly, Var(Z) and Var(Y) represent the variances of Z and Y, respectively. Since Z and Y have different probability distributions, their variances will generally not be equal.

Therefore, E(Z^2) ≠ E(Y^2) and Var(Z) ≠ Var(Y).

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The given values are: Ksp of CaSO4 = 4.93 × 10⁻⁵, Molarity of Na2SO4 = 0.250(m). Molar mass of CaSO4 = 136.14 g/mol. We can write the equation for the dissolution of CaSO4 in water as:CaSO4(s) ⇌ Ca²⁺(aq) + SO₄²⁻(aq). Let's consider that "x" grams of CaSO4 dissolves in "1 L" of 0.250 M Na2SO4. Since the CaSO4 dissolves according to the following equation:CaSO4(s) ⇌ Ca²⁺(aq) + SO₄²⁻(aq). The concentration of Ca²⁺ ions in the solution will be "x" moles / 1 L. The concentration of SO₄²⁻ ions in the solution will be "x" moles / 1 L. Since the concentration of Na2SO4 in the solution is 0.250 M or 0.250 moles / L, the concentration of SO₄²⁻ ions contributed by Na2SO4 will be (2 × 0.250) M or 0.500 M. In order to determine the value of "x" or the amount of CaSO4 that dissolves, we need to consider the equilibrium of the solution. The Ksp expression for the dissolution of CaSO4 can be written as: Ksp = [Ca²⁺][SO₄²⁻], Ksp = (x)(x) = x². As the dissociation is very small compared to the concentration of Na2SO4, we can consider "0.250" moles of Na2SO4 in "1 L" of the solution completely dissociated. Thus, the final concentrations of Ca²⁺ and SO₄²⁻ ions in the solution will be:[Ca²⁺] = x moles / L[SO₄²⁻] = (x + 0.500) moles /L. Therefore, we can write the expression for the ion product: IP = [Ca²⁺][SO₄²⁻]IP = (x)(x + 0.500)As the value of Ksp is equal to the IP, we can write the expression for Ksp as: Ksp = x² + 0.500xWe can substitute the value of Ksp as 4.93 × 10⁻⁵M:4.93 × 10⁻⁵ = x² + 0.500x. Solving for "x", we get the following quadratic equation: x² + 0.500x - 4.93 × 10⁻⁵ = 0. Solving for "x" using the quadratic formula: x = 0.00796 g/L. Therefore, the solubility of CaSO4(s) in 0.250 M Na2SO4 solution at 25°C is 0.00796 g/L.

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Answer:

C

Step-by-step explanation:

4x +8 = 2x -8

4x = 2x - 16

2x = -16

x = -8

Answer:

3

Step-by-step explanation:

Answer:

b = 6.1 ft

Step-by-step explanation:

The area (A) of a triangle is calculated as

A = [tex]\frac{1}{2}[/tex] bh ( b is the base and h the perpendicular height )

Here A = 10.98 and h = 3.6 , then

[tex]\frac{1}{2}[/tex] × b × 3.6 = 10.98

1.8b = 10.98 ( divide both sides by 1.8 )

b = 6.1

Answer:

65 girls and 45 boys

Step-by-step explanation: