a number is multiplied by 8 and that product is added to 2. The sum is equal to the product of 2 and 25 . Find the number

Answer:

20 socks fit $14.99 is the best deal out of the 3

Step-by-step explanation:

Here, we want to know the bag that contain the best deals for socks .

The best way to go about this is to know the unit prices of socks in each of the bags.

Let’s proceed;

12 socks for $9.99

The unit price here is 9.99/12 = 0.8325 per socks

20 socks for 14.99

Unit price here is 14.99/20 = 0.7495

10 socks for 19.99

The unit price here is 19.99/10 = 1.999

Out of all these options , we can see that the second option is actually the cheapest and offers what we should be pick as we are looking for suppliers since it charges the lowest;

So the best deal for socks is in the bag of 20 socks for $19.99

Answer:

x = ±4

Step-by-step explanation:

Step 1: Write out quadratic

2x² - 5 = 27

Step 2: Add 5 to both sides

2x² = 32

Step 3: Divide both sides by 2

x² = 16

Step 4: Take the square root of both sides

x = ±4

∴ x can equal -4 or 4

Answer:

[tex] \boxed{ \bf \huge \: x =4}[/tex]

[tex] \rm \: Or,[/tex]

[tex] \boxed{\bf \huge \: x = - 4}[/tex]

Step by step explanation:

Given Equation is :-

[tex]\sf \implies \: 2 {x}^{2} - 5 = 27[/tex]

We need to find the value of [tex]x[/tex] using Quadric formula.

Firstly, Subtract 27 from both of the side(s):-

[tex]\sf \implies2 {x}^{2} - 5 - 27 = 27 - 27[/tex]

On Simplification:-

Add -5-27 as (-) and (-) equals to (+). -5-27 would be represented as 5+27, which results to 32.

[tex]\sf\sf \implies2 {x}^{2} - 32 = 0[/tex]

Then, for this equation , a=2, b=0, c=-32.

Put the values :-

That is,

[tex]\sf \implies2 {x}^{2} + 0x + ( - 32) = 0[/tex]

As we know, that the quadratic formula is:-

[tex]\sf \implies \: x = \dfrac{ -b \pm \sqrt{b {}^{2} - 4ac } }{2a} [/tex]

Put the values :-

[tex]\sf \implies \: x = \dfrac{ - 0 \pm \sqrt{0 {}^{2} \: - 4(2) ( - 32)} }{2(2)} [/tex]

On Simplification:-

[tex]\sf \implies \: x = \dfrac{ - 0 {}^{} \pm \sqrt{ {0 } - \: 8 \times - 32}}{2 \times 2} [/tex]

[tex]\sf \implies \: x = \dfrac{ - 0 \pm \: \sqrt{ - 8 \times - 32} }{4}[/tex]

[tex]\sf \implies x = \dfrac{ - {0}^{}\pm \: \sqrt{ + 256} }{4} [/tex]

As 0 has no value here,

[tex]\sf \implies \: x = \dfrac{ \pm \sqrt{256} }{4} [/tex]

On cancelling,

Remove the square of 256 ( √256)

[tex]\sf \implies \: x = \dfrac{ \pm \cancel{ \: 256}}{ \cancel4} [/tex]

[tex]\sf \implies \: x = ± + 4[/tex]

It may be represented as,

[tex]\sf \implies \: x = - 4[/tex]

Or,

[tex]\sf \implies \: x = 4[/tex]

_______________________________

I hope this helps!

Please let me know if you have any questions.

~MisterBrian

Answer:

A 99.9% confidence interval for the population mean is [22.31, 59.91] .

Step-by-step explanation:

We are given the following sample values;

X = 45.3, 42.3, 53, 49, 15.2, 52.3, 45.6, 39.6, 39.4, 16.1, 54.4.

Firstly, the pivotal quantity for finding the confidence interval for the population mean is given by;

                       P.Q.  =  [tex]\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }[/tex]  ~  [tex]t_n_-_1[/tex]

where, [tex]\bar X[/tex] = sample mean = [tex]\frac{\sum X}{n}[/tex]  = 41.11

             s = sample standard deviation = [tex]\sqrt{\frac{\sum (X - \bar X)^{2} }{n-1} }[/tex]  =  13.59

             n = sample size = 11

Here for constructing a 99.9% confidence interval we have used a One-sample t-test statistics because we don't know about population standard deviation.

So, 99.9% confidence interval for the population mean, [tex]\mu[/tex] is;

P(-4.587 < [tex]t_1_0[/tex] < 4.587) = 0.999  {As the critical value of t at 10 degrees of

                                                freedom are -4.587 & 4.587 with P = 0.05%}    

P(-4.587 < [tex]\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }[/tex] < 4.587) = 0.999

P( [tex]-4.587 \times {\frac{s}{\sqrt{n} } }[/tex] < [tex]{\bar X-\mu}{[/tex] < [tex]4.587 \times {\frac{s}{\sqrt{n} } }[/tex] ) = 0.999  

P( [tex]\bar X-4.587 \times {\frac{s}{\sqrt{n} } }[/tex] < [tex]\mu[/tex] < [tex]\bar X+4.587 \times {\frac{s}{\sqrt{n} } }[/tex] ) = 0.999

99.9% confidence interval for [tex]\mu[/tex] = [ [tex]\bar X-4.587 \times {\frac{s}{\sqrt{n} } }[/tex] , [tex]\bar X+4.587 \times {\frac{s}{\sqrt{n} } }[/tex] ]

                                       = [ [tex]41.11-4.587 \times {\frac{13.59}{\sqrt{11} } }[/tex] , [tex]41.11+4.587 \times {\frac{13.59}{\sqrt{11} } }[/tex] ]

                                       = [22.31, 59.91]

Therefore, a 99.9% confidence interval for the population mean is [22.31, 59.91] .

Answer:

domain is x

range is y

Step-by-step explanation:

The values for the domain of the function appear on the x-axis and the values for the range appear on the y-axis.

A function's range is the set of all values that the function accepts, and its domain is the set of all values for which the function is defined.

The domain is for the independent variable while the range is for the dependent variable.

For example f(x) = x²

Now if we put x = 1 then it is called as domain variable while the value of function at x = 1 its that f(1) = 1 called range variable.

The range is the interval where the function f(x) is defined whereas the domain is the input interval of the independent variable (x).

For example f(x) = x²

Now if we put x = 1 then it is called as domain variable while the value of function at x = 1 its that f(1) = 1 called range variable.

Hence "The values for the domain of the function appear on the x-axis and the values for the range appear on the y-axis".

For more details about the range and domain of the function,

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Answer:

  27a³ -8

Step-by-step explanation:

A binomial has two terms. If one of the terms is the constant -8, the other must be a cubic term, something with a variable to the third power.

  27a³ -8 . . . . . a cubic binomial with a constant of -8

Answer:

-7 + 4 = -3

Step-by-step explanation:

So you start at -7 and if you add a positive number to a negative number you basically subtract from the negative number, so you would do -7 + 4 which equals -3

Answer:

  13

Step-by-step explanation:

The value halfway between them is their average: 27/2 = 13.5.

The smaller number is 13.

__

The larger number is 14.

Answer:

GK = 9x-5

Step-by-step explanation:

GK = GH +HJ + JK

= (GJ - HJ) + (HJ) + (HK - HJ)

= (4x-3-x) + (x) + (6x-2-x)

= 3x-3 + x + 5x-2

= (3x+5x+x)+(-3-2)

GK = 9x-5

Answer:

Distance traveled= 41968.4 km

The domain of the function is t

t(h)= 478

h = hours

Step-by-step explanation:

the distance that they traveled in kilometers, d, can be modeled by

d(t) = 97.8t

where t is the time in hours

They traveled a total of 478 hours.

Distance traveled d(t)

d(t) = 87.8(478)

d(t) = 41968.4

Distance traveled= 41968.4 km

The domain of the function is t

t(h)= 478

Answer:

A)P(A ∩ B) cannot be equal to 0.5.

B)P(A ⋃ B) = 0.7

C)P[(A ∪ B)'] = 0.3

D)P(A ∩ B') = 0.3

E)probability that the selected student has exactly one of these two types of cards = 0.4

Step-by-step explanation:

A) We want to find out if P(A ∩ B) = 0.5

Now, this value is not possible because the probability of intersection of two events can not be greater than the probability of each individual event.

We are told that P(A) = 0.6 and P(B) = 0.4.

Due to the fact that the probability of B is less than 0.4 which is less than 0.5, It means that the intersection of A and B can't be greater than 0.4.

Thus, P(A ∩ B) cannot be equal to 0.5.

B) Now, P(A ∩ B) = 0.3

The probability that the selected student has at least one of these two types of cards would be P(A ⋃ B)

Now, this is expressed as;

P(A ⋃ B) = P(A) + P(B) − P(A ∩ B)

Thus,

P(A ⋃ B) = 0.6 + 0.4 - 0.3

P(A ⋃ B) = 0.7

C) Probability that the selected student has neither type of card would be expressed as; P[(A ∪ B) ' ]

Thus is further expressed as;

P[(A ∪ B) ' ] = 1 − P(A ∪ B)

P[(A ∪ B)'] = 1 - 0.7

P[(A ∪ B)'] = 0.3

D) We want to describe in terms of A and B, the event that the selected student has a Visa card but not a MasterCard.

This is simply an intersection of event A and compliment of event B. Thus, it implies that we we will remove the events when student has both types of cards from the events of A. This probability is expressed as P(A ∩ B')

Thus gives;

P(A ∩ B') = P(A) - P(A ∩ B)

P(A ∩ B') = 0.6 - 0.3

P(A ∩ B') = 0.3

E) Now, we want to find the probability that the selected student has exactly one of these two types of cards.

This is simply the addition of intersection of event A with compliment of event B and intersection of event B with compliment of event A . The probability is given by:

P(A ∩ B') + P(A' ∩ B)

Expanding this gives;

P(A ∩ B') + P(B) - P(A ∩ B)

Plugging in the relevant values gives;

0.3 + 0.4 - 0.3 = 0.4

Step-by-step explanation:

13? i forgot all this math XD

Answer: D

Step-by-step explanation:

This problem seems to ask for the slope of the line. If not by counting, we can use the slope formula to solve. The formula is [tex]m=\frac{y_{2}-y_{1} }{x_{2}-x_{1} }[/tex]. Let's use (1,2) and (2,-1).

[tex]m=\frac{-1-2}{2-1} =\frac{-3}{1}=-3[/tex]

Now, we know that the slope is -3.

We also know that A and C are eliminated because the line is going down, which signifies negative. We would be left with B and D. We know that B is incorrect because the slope would be less steep if B were to be the answer. Therefore, D is the correct answer.

Answer:

Triangle

Step-by-step explanation:

Basically, you have to multiply the base and the height of the triangle, and then divide it by two.

Answer:

O triangle

Step-by-step explanation:

Triangle area = (base*heigth)/2

Even though 0.84800 has two more zeroes at the end, this is still the same number as 0.848.

0.84800 -> 0.848

Therefore, 0.848 = 0.48400

Best of Luck!

Answer:

mark owes Kira $2

I think

Answer:

a = [tex]\frac{9}{2}[/tex]

Step-by-step explanation:

To find the value of a, find the Slope of both the equations.

For lines to be perpendicular to each other    [tex]m_{1}m_{2} = - 1[/tex]

For line 1:

2x + 3y − 6 = 0 represent the line in y=mx +c form

3y = -2x + 6

y = [tex]\frac{-2}{3} x[/tex] + [tex]\frac{6}{3}[/tex]

y = [tex]\frac{-2}{3} x[/tex] + 2

[tex]m_{1}[/tex] = [tex]\frac{-2}{3}[/tex]

For line 2:

ax - 3y = 5

ax = 5 + 3y

ax - 5 = 3y

y = [tex]\frac{ax}{3} - \frac{5}{3}[/tex]

[tex]m_{2}[/tex] = [tex]\frac{a}{3}[/tex]

Apply the condition of perpendicularity:

[tex]\frac{-2}{3}[/tex] * [tex]\frac{a}{3}[/tex] = - 1

[tex]\frac{2a}{9} = 1[/tex]

a = [tex]\frac{9}{2}[/tex]

Answer:

1. -9/20

2.  1  7/12

3.  -4  1/3

Step-by-step explanation:

When adding and subtracting fractions with unlike denominators, you must first make them like denominators. To do this we must:

1. Find the Least Common Multiple of the denominators (which is called the Least Common Denominator).

2. Change each fraction (using equivalent fractions) to make their denominators the same as the least common denominator.

3. Then add (or subtract) the fractions, as we wish!

The easiest way to this is by multiplying the denominators. Remember that whatever you do to the bottom, you also do to the top

1. -5/4 +4/5

if we multiply 4 and 5, we get 20. Our denominator will be 20 before we simplify.

our new equation is going to be -25/20 + 16/20. Now we can add these together to get an answer of -9/20. Which is in the simplist form.

One more thing: to make a mixed number an improper fraction, you multiply the whole number by the denominator, and add the numerator.

1X4=4

4+1=5

The improper fraction is 5/4.

To make a Whole number a fraction, multiply the number by the denominator

-5x3=15

The improper is -15/3.

To go from an improper to a mixed, divide the numerator by the denominator. The remainders are going to be the fraction attached.

Answer:

To square a number, multiply the number by itself.

Step-by-step explanation:

Answer:

It does not represent a function. The domain value of 2 corresponds to two values within the range.

Step-by-step explanation:

Given the function:

Domain : Range

1 => 5

2 => 10

3 => 15

2 => 20

For a relation to be considered a function, every domain value should have exactly 1 range value assigned to it or mapped to it.

In order words, a domain value should not have different range values.

In the relation given, domain value of 2, has more than 1 range value, 10 and 20, assigned to it. It does not have exactly 1 range value.

Therefore, the relation does not represent a function because the domain value of 2 corresponds to two values (10 and 20), within the range.

Answer:

It does not represent a function. The domain value of 2 corresponds to two values within the range.

Step-by-step explanation:

Answer:

8 and 7

Step-by-step explanation:

the square root of 75 is approximately 8.66025 or 5√3 in radical form

Answer:

s > 62

Step-by-step explanation:

I hope this helps!

The inequality which represents the given statement is given by s > 62.

What are inequalities ?

When two values are compared , an inequality represents whether one is greater than, less than, or not equal to the other.

The given statement is "negative thirty-one less than s is greater than 93". This statement must be transformed into form of an inequality.

We know that an inequality comes when a number is greater than or less than another number . Here the variable is the unknown number 's'. This meant the expression can be written as :

s - (-31) > 93

Simplifying this inequality we get :

s + 31 > 93

s > 93  - 31

s > 62

Therefore , the inequality which represents the given statement is given by s > 62.

Learn more about inequalities here :

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Answer: 1 73/90 if the decimal is 1.81 and the one is repeating

If the .81 is repeating then 1 9/11

Step-by-step explanation:

Answer:

20/11

Step-by-step explanation:

let 0.(81) = x

--> 100x = 81.(81)

--> 100x - x = 81.(81) - 0.(81)

--> 99x = 81

--> x = 81/99 = 9/11

1.(81) = 1 + 0.(81) = 1 + x = 1 + 9/11 = 20/11

Answer:

4

Step-by-step explanation:

3³=27

6-³=1/216

2^5=32

27X1/216x32

=4

Answer:

  53.3

Step-by-step explanation:

One way to do this is to add half a tenth, 0.05, then drop all the digits of the result to the right of the tenths digit.

  53.2785 +0.05 = 53.3285

Dropping digits to the right of the tenths place, we have ...

  53.3

_____

The effect of this is to increase the tenths digit by 1 if the hundredths digit is 5 or more. That is the usual instruction given for rounding to tenths. (Then drop hundredths and digits to the right.)

Answer:

Step-by-step explanation:

Got it correct on Khan Academy

[tex]3d=n[/tex]

[tex]10d+5n=325[/tex]

[tex]10d+15d=325[/tex]

[tex]25d=325[/tex]

[tex]d=13[/tex]

[tex]n=39[/tex]

Hope this helps.

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