a scientist claims that 60% of u.s. adults believe humans contribute to an increase in global temperature. a 95% confidence interval for the proportion of u.s. adults who say that the activities of humans are contributing to an increase in global temperatures is found to be (0.626, 0.674). does this confidence interval support the scientist's claim?\

Answers

Answer 1

The scientist claims that 60% of U.S. adults believe humans contribute to an increase in global temperature. A 95% confidence interval for the proportion of U.S. adults who hold this belief is found to be (0.626, 0.674). This confidence interval supports the scientist's claim.

To determine if this confidence interval supports the scientist's claim, we need to examine whether the claimed proportion of 60% falls within the confidence interval.

The confidence interval (0.626, 0.674) indicates that we are 95% confident that the true proportion of U.S. adults who believe humans contribute to an increase in global temperature lies between 0.626 and 0.674. Since the claimed proportion of 60% falls within this range, it is within the confidence interval.

Therefore, we can conclude that the confidence interval supports the scientist's claim. This means there is strong evidence to suggest that a significant majority of U.S. adults believe humans contribute to an increase in global temperature, as the lower bound of the confidence interval is 62.6% and the upper bound is 67.4%.

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Related Questions

convert the angle 0=17 pie/18 radians to degrees

Answers

Answer:

it would be 170°

Step-by-step explanation:

( 17 πover 18 )  ⋅  180 °  over π

17over18 ⋅  180

then you cancel the common factors

17 ⋅  10 mulitply those two and end up with

170°

2.75603957 rounded to 2 decimal places

Answers

The answer is 2.76 because u round it 2 places to the right

Eileen jogs every day. Last month, she jogged 6.5 hours for a total of 37.05 miles. At this speed, if Eileen runs 31.5 hours, how far can she run? (what equation would I use?)

Answers

I hope this helped

Step-by-step explanation:

First: 37.05 miles / 6.5 hours = 5.7

Next: 5.7 miles per hour

Third: 31.5 hours  times 5.7 miles= 179.55 miles

Lastly: 179.55 miles for 31.5 hours

Organisms are present in ballast water discharged from a ship according to a Poisson process with a concentration of 10 organisms/m3 (the article "Counting at Low Concentrations: The Statistical Challenges of Verifying Ballast Water Discharge Standards"† considers using the Poisson process for this purpose).
For what amount of discharge would the probability of containing at least 1 organism be 0.993? (Round your answer to two decimal places.)

Answers

The amount of discharge for which the probability of containing at least 1 organism is 0.993 is approximately 0.14 m³.

To find the amount of discharge for which the probability of containing at least 1 organism is 0.993, we can use the Poisson distribution formula. The Poisson distribution describes the probability of a certain number of events occurring in a fixed interval of time or space, given the average rate of occurrence.

In this case, the concentration of organisms in the ballast water is given as 10 organisms/m³. Let's denote λ as the average rate of occurrence, which is equal to the concentration in this case, λ = 10 organisms/m³.

The Poisson distribution formula is:

P(X ≥ k) = 1 - P(X < k) = 1 - e^(-λ) * (λ^0/0! + λ^1/1! + λ^2/2! + ... + λ^(k-1)/(k-1)!)

We want to find the amount of discharge (let's call it x) for which P(X ≥ 1) = 0.993. Plugging in the values into the formula, we have:

0.993 = 1 - e^(-10) * (10^0/0! + 10^1/1!)

Simplifying the equation, we have:

0.993 = 1 - e^(-10) * (1 + 10)

Now we can solve for e^(-10) using logarithms:

e^(-10) = 1 - 0.993 / (1 + 10)

e^(-10) ≈ 0.0045

Substituting this back into the equation, we have:

0.993 = 1 - 0.0045 * (1 + 10)

Simplifying further, we get:

0.993 = 1 - 0.0045 * 11

Now, let's solve for the discharge amount x:

0.993 = 1 - 0.0495x

0.0495x = 1 - 0.993

0.0495x ≈ 0.007

x ≈ 0.007 / 0.0495

x ≈ 0.14 m³

Therefore, the amount of discharge for which the probability of containing at least 1 organism is 0.993 is approximately 0.14 m³.

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Type the correct answer in the box. Use numerals instead of words.
Consider this equation.
10*+25
How many valid solutions does the equation have?
The equation has
valid solution(s).

Answers

The original equation (10x + 25) / (3x + 12) = 5x / (x + 4) has no valid solutions.

We have,

To determine the number of valid solutions for the equation

(10x + 25) / (3x + 12) = 5x / (x + 4), we need to solve the equation and check if there are any values of x that satisfy the equation while not causing any division by zero.

Let's solve the equation step by step:

(10x + 25) / (3x + 12) = 5x / (x + 4)

Cross-multiply to eliminate the fractions:

(10x + 25)(x + 4) = (3x + 12)(5x)

Expand both sides:

10x² + 40x + 25x + 100 = 15x² + 60x

Combine like terms:

10x² + 65x + 100 = 15x² + 60x

Subtract 10x² + 60x from both sides:

5x² + 5x + 100 = 0

Now we have a quadratic equation.

To solve it, we can use the quadratic formula:

x = (-b ± √(b² - 4ac)) / 2a

For the equation 5x² + 5x + 100 = 0, a = 5, b = 5, and c = 100.

Calculating the discriminant (b² - 4ac):

Discriminant = (5²) - (4 x 5 x 100)

Discriminant = 25 - 2000

Discriminant = -1975

Since the discriminant is negative (-1975), the quadratic equation has no real solutions.

Therefore,

The original equation (10x + 25) / (3x + 12) = 5x / (x + 4) has no valid solutions.

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5. Arrange these numbers in ascending order (from least to greatest) -2.6 -2.193 -2.2 -2.01 I

Answers

Answer:

see below

Step-by-step explanation:

-2.6

-2.2

-2.193

-2.01

Since they are negatives, the higher number it is, the smaller it actually is.  The smaller the number is, that number will be closer to 0 and will actually be higher than the rest.

Hope this helps! :)

Which of the following
represents 9!
A. 9
B. 9*8*7*6*5*4*3*2*1
C. 9+8+7+6+5+4+3+2+1

Answers

The answer is B. Btw don’t click on the link provided by the other answer provider it’s a virus.

Consider a sample with data values of 6, 17, 14, 7, and 16. Compute the variance. (to 1 decimal) Compute the standard deviation.

Answers

The standard deviation of the sample data is 4.6 and the variance is 21.2.

To compute the variance, follow these steps:

1. Calculate the mean (average) of the data values. In this case, (6 + 17 + 14 + 7 + 16) / 5 = 12.

2. Subtract the mean from each data value and square the result. For each value: (6 - 12)² = 36, (17 - 12)² = 25, (14 - 12)² = 4, (7 - 12)² = 25, and (16 - 12)² = 16.

3. Calculate the sum of all the squared differences: 36 + 25 + 4 + 25 + 16 = 106.

4. Divide the sum by the number of data values (5) to get the variance: 106 / 5 = 21.2 (rounded to 1 decimal place).

To compute the standard deviation, take the square root of the variance.

Standard deviation = √(21.2) = 4.6

Variance measures how much the data values differ from the mean, while the standard deviation represents the average amount of deviation from the mean. In this sample, the variance is 21.2 and the standard deviation is 4.6. These metrics help quantify the spread and variability of the data set.

Therefore the standard deviation of the sample data is 4.6.

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Events A and B are such that P() = 0.55 and P( ∪ ) = 0.75. Given that A and B are independent and non-mutually exclusive, determine P().

Answers

Given that A and B are independent and non-mutually exclusive. The answer is: P(A or B) = 0.52.

we haveP(A and B) = P(A) * P(B)P(A ∪ B) = P(A) + P(B) - P(A and B)

Also, given that P(A) = 0.55 and P(A ∪ B) = 0.75, we can find P(B)

as follows:0.75 = P(A) + P(B) - P(A and B)0.75 = 0.55 + P(B) - P(A and B)0.75 - 0.55 = P(B) - P(A and B)0.2 = P(B) - P(A) * P(B)             [Using P(A and B) = P(A) * P(B)]0.2 = P(B)(1 - P(A))            [Taking out P(B) as a common factor]0.2 = P(B)(1 - 0.55)            [Substituting the value of P(A)]0.2 = 0.45P(B)              [Simplifying]P(B) = 0.2/0.45 = 4/9Now, we can find P(A or B) as follows:P(A or B) = P(A) + P(B) - P(A and B)P(A or B) = 0.55 + 4/9 - (0.55 * 4/9)            [Substituting the values of P(A), P(B), and P(A and B)]P(A or B) = 1.16/2.25            [Simplifying]P(A or B) = 0.52

Therefore, the answer is: P(A or B) = 0.52.

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For independent and non-mutually exclusive A and B, the value of P(A ∪ B) is 0.64.

Events A and B are such that P(A) = 0.55 and P(A ∪ B) = 0.75.

A and B are independent and non-mutually exclusive.

To find out the probability of B, we can use the formula:

P(B) = P(A ∪ B) - P(A)

As we have already been given the value of P(A) and P(A ∪ B), so we can easily find the value of P(B)

P(B) = P(A ∪ B) - P(A)

P(B) = 0.75 - 0.55

P(B) = 0.2

Now, to find P(A ∩ B), we can use the formula:

P(A ∩ B) = P(A) × P(B)

As we have been given that A and B are independent events.

Hence, we can say that:

P(A ∩ B) = P(A) × P(B) = 0.55 × 0.2

P(A ∩ B) = 0.11

Now, we can use the formula of addition of probabilities to find P(A ∪ B):

P(A ∪ B) = P(A) + P(B) - P(A ∩ B)

P(A ∪ B) = 0.55 + 0.2 - 0.11

P(A ∪ B) = 0.64

Therefore, the value of P(A ∪ B) is 0.64.

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Find the midpoint of the segment with the following endpoints.
(5,5) and (10,8)

Answers

Answer: G

Step-by-step explanation:

Answer:

(7.5, 6.5)

Step-by-step explanation:

Edg 2021

What is the value of x? i will give brainliest please help

Answers

Answer:

I completely forgot how to do this I'm sorry

Step-by-step explanation:

OK a quarter steam covers a 100' square feet how many courts should you buy to stay in the wheelchair ramp

Answers

Answer:

He should buy about 2 quart of stain

Step-by-step explanation:

Find the diagram attached

First we need to find the area of the given ramp

The ramp consists of two identical triangles, a larger and small rectangles

Since area of triangle  = 1/2 * base * height

Area of the identical triangles = 1/2 * 25ft * 25/12 ft (Note that 1ft = 12in)

Area of the 2 identical triangles = 2* 625/24ft² = 625/12 ft²

Area of the large rectangle = Length * Width

Area of the large rectangle = 25 1/12 * 5

Area of the large rectangle = 301/12 * 5

Area of the large rectangle = 1505/12 ft²

Area of the small rectangle = 25/12 * 5

Area of the small rectangle = 125/12 ft²

Area of the figure = 625/12 + 1505/12 + 125/12

Area of the figure = (625+1505+125)/12

Area of the figure = 2255/12

Area of the figure = 187.917

Area of the figure = 187.917ft²

Since  a quarter steam covers a 100' square fee, then;

1 quarter = 100ft²

x = 187.917ft²

Cross multiply

100 * x = 187.917

100x =187.917

x = 187.917/100

x = 1.87917

x ≈ 2

Hence he should buy about 2 quart of stain

What is the value of C?

Answers

Answer:

2

Step-by-step explanation:

The answer is 2.

Explanation:

y varies directly with the cube of x
y = 108 when x = 3

Express y In terms of x

Answers

Answer:

y = 36x

Step-by-step explanation:

y varies directly with x ,

that is y [tex]\propto[/tex] x

Let k be constant

=> y = kx

=> 108 = k(3)

=> k = 108/3

=> k = 36

y can be expressed in terms of x as kx or simply 36x . As we found value of constant as 36.

Which function has the graph shown?

Answers

Answer:

D) -cos(x)

Step-by-step explanation:

What is the line of symmetry for the parabola whose equation is y = x2 + 10x + 25?

A-x = -5
B-x = 5
C-x = -10

Answers

Answer:

x = -5

Step-by-step explanation:

Please write this as y = x^2 + 10x + 25.  Here the coefficients are {1, 10, 25}.

The equation of the axis of symmetry is x = -b/[2a], which here is

x = -10 / [2*1] = -5

Please Help — Neil is going to a bookstore 45 miles away. The bridge was closed on the way back, so
he had to take an alternate route and had to drive 15 mph slower, which make the trip
back take 7 minutes longer. How fast was he going on the way to the bookstore??

Answers

I agree to the first person


Suppose the price of a bond is given by the following
function:

23.751-1+i-20i+5001+i-20=547.50
Use linear interpolation to approximate the value of
i:

Answers

The approximate value of i using linear interpolation is i ≈ 0.010526.

To approximate the value of i using linear interpolation, we need two data points on either side of the desired value of i. In the given equation, we have the following data points:

When i = 0, the price of the bond is 547.50.

When i = 0.01, the price of the bond is 23.751 - 1(0.01) - 20(0.01) + 500 / (1 + 0.01 - 20) = 442.24.

Since the desired value of i lies between 0 and 0.01, we can use linear interpolation to approximate it.

Linear interpolation assumes a linear relationship between two data points and estimates the value based on the proportionate distance between those points.

Let's denote the desired value of i as  [tex]i_d[/tex]. We can set up the following equation to find [tex]i_d[/tex]:

[tex](i_d - 0) / (0.01 - 0) = (547.50 - 442.24) / (0.01 - 0)[/tex]

Simplifying the equation:

[tex](i_d - 0) / 0.01 = (547.50 - 442.24) / 0.01i_d / 0.01 = 105.26 / 0.01i_d = 105.26[/tex]

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Choose two things that a rigid motion preserves.

Answers

I know one of them and it’s size. The lengths do not change when performing a rigid motion. And I believe rigid motions also preserves angles. The angles do not change either.

Two things that a rigid motion preserves are: length and angle.

The two things that a rigid motion preserves are:

1. Length: A rigid motion preserves the length of objects. This means that the distances between points or the lengths of line segments remain the same after the rigid motion is applied.

For example, if you have a line segment AB of length 5 units, a rigid motion such as translation, rotation, or reflection will not change the length of AB.

2. Angle: A rigid motion preserves angles between lines or line segments. This means that the measure of an angle remains the same after a rigid motion is applied.

For example, if you have an angle ABC with a measure of 60 degrees, a rigid motion will not change the measure of angle ABC.

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How do the number of faces, vertices, and edges of a cube compare to the number of faces, vertices, and edges of a tetrahedron? A cube has more faces than a tetrahedron. A cube has more vertices than a tetrahedron. A cube has more edges than a tetrahedron.

Answers

Answer:

it is 2, 4 and 6

Step-by-step explanation:

What is the mean? 2, 4, 7, 5, 8, 10
Remember- add all the
numbers, and then divide by the total
amount of numbers
6
9
5
36

Answers

Answer:

6

Step-by-step explanation:

2+4+7+5+8+10

=36÷6

=6

QUESTION 1
1.1 Find the sum:
1.1.1 2+6+(-7) + 10 =
1.1.2 (-49) + (15) + (-10) =​

Answers

Answer:

1.is 11

2. is-44

Step-by-step explanation:

1) 2+6-7+10

= 11

2) -49+15-10

= -44

Student Council is selling T-shirts to raise money for new volleyball equipment. There is a fixed cost of
$200 for producing the T-shirts, plus a variable cost of $5 per T-shirt made. Council has decided to sell
the T-shirts for $8 each.

A. Write an equation to represent the total cost, C, as a function of the number, n, of T-shirts
produced.

B. Write an equation to represent the revenue, R, as a function of the number, n, of T-shirts
produced

C. Profit, P, is the difference between revenue (R(n)) and expenses (C(n)). Develop an algebraic
function to model the profit.

D. How many T-shirts does the Student Council have to sell to "break even," make a $0 profit?

Answers

Answer:

It is A

Write an equation to represent the total cost, C, as a function of the number, n, of T-shirts

produced.

Step-by-step explanation:

:)

what is the equation of a parabola with the given vertex and focus ?
vertex(-2,5)focus(-2,6)
14.what is the center and radius of a circle with the given equation?
x^2+y^2-4x+10y=7

Answers

The equation of a parabola with vertex (h, k) and focus (h, k + p) is given by the equation (x - h)^2 = 4p(y - k). In this case, the vertex is (-2, 5) and the focus is (-2, 6). Since the x-coordinate of both the vertex and focus is the same, we can conclude that the parabola opens either upward or downward. The equation of the parabola is then (x + 2)^2 = 4p(y - 5).

The given equation x^2 + y^2 - 4x + 10y = 7 can be rewritten as (x^2 - 4x) + (y^2 + 10y) = 7. To complete the square, we need to add and subtract terms to both sides of the equation to create perfect square trinomials. By adding (4/2)^2 = 4 to the x terms and (10/2)^2 = 25 to the y terms, we have (x^2 - 4x + 4) + (y^2 + 10y + 25) = 7 + 4 + 25, which simplifies to (x - 2)^2 + (y + 5)^2 = 36. Comparing this equation to the standard form of a circle (x - h)^2 + (y - k)^2 = r^2, we can identify the center of the circle as (2, -5) and the radius as the square root of 36, which is 6. Therefore, the center and radius of the circle are (2, -5) and 6, respectively.

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The results of a linear regression are shown below.
y=ax+b
a=-1.15785
b=139.3171772
r=-0.896557832
r^2=0.8038159461
Which phrase best describes the relationship between x and y?
A. Strong negative correlation
B. Strong positive correlation
C. Weak positive correlation
D. Weak negative correlation

Answers

Hello!

As we can see, our a value, which would be the coefficient of [tex]x[/tex], which determines our slope, is negative, meaning that this whole line is negative.

Furthermore, the correlation can be determined using the r value of the linear regression, which is around -0.9.

If the r value of the linear regression is close to 1 or -1, let's say around |r| > 0.8, then we can consider the regression a strong correlation, meaning that this is a strong negative correlation, which is answer choice A.

What’s 1/5 divided by 1/12?

Answers

Flip the second fraction and multiply.

1/5*12/1

You get 12/5, or 2 & 2/5

Find the mean of the following probability distribution? Round your answer to one decimal. P(2) 0 0.0017 1 0.3421 2 0.065 3 0.4106 4 0.1806 mean = ___

Answers

The mean of the given probability distribution is 3.4.

To find the mean of a probability distribution, we multiply each value of x by its corresponding probability and then sum them up. Using the provided data:

P(2)    0

P(1)    0.0017

P(2)    0.3421

P(3)    0.065

P(4)    0.4106

P(5)    0.1806

mean = 2(0) + 1(0.0017) + 2(0.3421) + 3(0.065) + 4(0.4106) + 5(0.1806)

     = 0 + 0.0017 + 0.6842 + 0.195 + 1.6424 + 0.903

     = 3.4263

Therefore, the mean of the given probability distribution is approximately 3.4 (rounded to one decimal place).

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PLEASE HELP!
Write down the Equation of the following lines:

1)parallel to y=2x-1 and passing through (1, 8)

Answers

Answer:

y=2x+6

Step-by-step explanation:

We use this following formula to find the equation:

[tex]y-y_{1} =m(x-x_{1} )[/tex]

Now, we substitute the values in [tex]y_{1}[/tex] and [tex]x_{1}[/tex] :

[tex]y-8=2(x-1)[/tex]

Distribute the 2 inside the parentheses:

[tex]y-8=2x-2[/tex]

Now add 8 to both sides:

[tex]y=2x+6[/tex] is your answer.

Step-by-step explanation:

y=mx+b

m=slope

b=y-intercept

y=2x-1

2=slope

-1=y intercept

NOTE: parallel lines have the same slope

and we put the point (1,8) into y=mx+b with (x,y)

8=1m+b

now we put in 2 for the slope

8=1(2)+b

6=b

2=m

now insert that back into y=mx+b

y=2x+6

and that is the line that is parallel to y=2x-1 and passes through (1,8)

Hope that helps :)

In a certain raffle, you buy 2 tickets. 50 tickets are sold altogether. 7 prizes will be awarded. Find the probability that you win 0 prizes.
0.16
0.04
0.26
0.74

Answers

The probability of winning 0 prizes in the raffle is 0.74. The last option.

Probability

To find the probability of winning 0 prizes in the raffle, we need to calculate the probability of not winning any prize.

First, let's calculate the probability of winning a prize with a single ticket. Since there are 7 prizes and a total of 50 tickets sold, the probability of winning a prize with one ticket is 7/50.

To calculate the probability of not winning a prize with one ticket, we subtract the probability of winning a prize from 1:

1 - (7/50) = 43/50.

Since you bought two tickets, the probability of not winning any prize with both tickets is the probability of not winning a prize with one ticket multiplied by itself:

(43/50) * (43/50) = 1849/2500.

Therefore, the probability of winning 0 prizes in the raffle is 1849/2500, which is approximately equal to 0.7396 or 0.74 when rounded to two decimal places.

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19.
20
Z
45°
y у
60°
63
2 =
I NEED HELP WITH NUMBER 19 PLEASE HELP!

Answers

z=90degrees

Y=135degrees

Other Questions
Which of the following is/are true regarding risk and return? 1. Small company stocks carry more risk than large company stocks, but over time have had a lower return II. Diversification is the best method for reducing systematic risk III. The Market Risk Premium is the difference between the return investors expect to receive for holding a particular asset and the rate of inflation IV. Total Risk can be found by adding an asset's Beta to its Standard Deviation FILL THE BLANK. B2: COSTS and PROFITS with COBB-DOUGLAS.......... ts) (a) Suppose we have the following production function: Q=K/2L/2 Suppose K is fixed in the short-run at 16. Let r = $20 and w = $20. State the USE CRAMERS RULE TO X - X2 +4x3 = -4 - 8x, +3x2 + x3 = 8,2X1- X2 + X3 = 0. Journalize the following transactions: Blaise Inc. sold merchandise on account to Boomer Inc., $12,000, terms Mar 6 FOB destination, 2/10 n/30. The cost of the merchandise sold was $3,000. Mar 6 Blaise Inc. paid $335 in freight charges. Mar 14 Mar 16 Blaise Inc. issued Boomer Inc. a credit memo for merchandise returned, $1,000. The cost of the merchandise returned was $250. Blaise Inc. received payment from Boomer Inc. for purchase of March 6th. Journalize the entries for Blaise Company (seller) first below (Format: use Chart of Accounts for names, be careful of spelling!! DO NOT bother to include company names; debits and credits should be whole numbers, WITH COMMAS, but NO DECIMALS OR DOLLAR SIGNS) Mar 6 Date Account Names Debit Credit 20 Journalize the following transactions: Blaise Inc. sold merchandise on account to Boomer Inc., $12,000, terms Mar 6 FOB destination, 2/10 n/30. The cost of the merchandise sold was $3,000. Mar 6 Blaise Inc. paid $335 in freight charges. Mar 14 Mar 16 Blaise Inc. issued Boomer Inc. a credit memo for merchandise returned, $1,000. The cost of the merchandise returned was $250. Mar 6 Blaise Inc. received payment from Boomer Inc. for purchase of March 6th. Journalize the entries for Blaise Company (seller) first below (Format: use Chart of Accounts for names, be careful of spelling!! DO NOT bother to include company names; debits and credits should be whole numbers, WITH COMMAS, but NO DECIMALS OR DOLLAR SIGNS) Date Account Names Debit Credit Mar 6 Mar 6 Date Account Names Debit Credit 49 Mar 14 Mar 16 Journalize the entries for Boomer Inc. next, below (Format: use Chart of Accounts for names, be careful of spelling!! DO NOT bother to include company names; debits and credits should be whole numbers, WITH COMMAS, but NO DECIMALS OR DOLLAR SIGNS) D Mar 14 Mar 16 Journalize the entries for Boomer Inc. next, below (Format: use Chart of Accounts for names, be careful of spelling!! DO NOT bother to include company names; debits and credits should be whole numbers, WITH COMMAS, but NO DECIMALS OR DOLLAR SIGNS) 110 120 Accounts Receivable 125 Notes Receivable 130 Prepaid Insurance 135 Prepaid Rent 140 Inventory 150 Supplies 160 Equipment 165 Machinery 168 Truck 170 Allowance for Doubtful Accounts 175 Accumulated Depreciation 176 Estimated Returns Inventory 55 Machinery 58 Truck 70 Allowance for Doubtful Accounts 75 Accumulated Depreciation 76 Estimated Returns Inventory 410 Accounts Payable 220 Notes Payable 225 Interest Payable 230 Uncarned Fees 240 Wages Payable 245 Salaries Payable 250 Customer Refunds Payable Steckholder's Equity: 310 Common Stock 315 Preferred Stock 320 Retained Earnings 330 Cash Dividends 335 Stock Dividends 340 Paid In Capital in Excess of Par 410 Fees Earned 415 Sales 420 Rent Revenue 425 Interest Revenue 430 Gain on Sale 431 Loss on Sale 435 Cash Short/Over 505 Cost of Goods Sold 510 Rent Expense 520 Wages Expense 525 Interest Expense 430 Inciranes Fynence 310 Common Stock 315 Preferred Stock 320 Retained Earnings 330 Cash Dividends 335 Stock Dividends 340 Paid In Capital in Excess of Par 410 Fees Earned 415 Sales 420 Rent Revenue 425 Interest Revenue 430 Gain on Sale 431 Loss on Sale 435 Cash Short/Over 505 Cost of Goods Sold 510 Rent Expense 520 Wages Expense 525 Interest Expense 530 Insurance Expense 540 Depreciation Expense 550 Supplies Expense 560 Utilities Expense 570 Bad Debt Expense 580 Delivery Expense 590 Miscellaneous Expense Select the correct point on the graph. Which point on the graph indicates the lowest quantity supplied of goods? 9.00 8.00 Price per Pound 7.00 6.00 5.00 4.00 3.00 2.00 supply Curve 1,000 2,000 3,000 4,000 5,000 6,000 7.000 Quantity in Pounds 9. A student was provided with only a thermometer, a stopwatch and a beaker. What could the student measure? A 10.5g solid and 24.8 cm liquid B 10.5g solid and 25C C D 24.8 cm liquid and 45 seconds 25 and 45 seconds Which of the following risk factors does corporate bond rating capture?POSSIBLE ANSWERS:-Interest rate risk-Liquidity-Maturity-Default risk Write the equation of this line. A line that contains point (2, 2) and perpendicular to another line whose slope is 1. . If A Firm Can Only Set Its Price So High For Its Product, Then This Is Considered ________. A) Breakeven Regulation B) Cost-Plus Regulation C) Price-Cap Regulation how many bytes large is the following definition? struct my_coord new_array[] = { { 0,0,3.5 }, { 1,2,4.5}, { 2,0,9.5} }; The relationships between demand and supply of the Olympios Dollar and the exchange rate with the Terranian Credit are given by the following functions: E=8.75-0.03DsE=0.025$-3.50where: E = Exchange rate: - price of Olympios dollar(Terranian credits/Olympios dollarsDs = index of demand for Olympios dollar Ss index of supply of Olympios dollar.Determine the exchange rate that would prevail under a clean floatii) Explain what this exchange rate would mean for the balance of payments of Olympiosb) The government of Olympios elects instead to fix the exchange rate with the Terranian credit at E=1 5 credits per dollar.i) Describe what actions the central bank will need to take in the short run to maintain this exchange rate, and the state of the balance of payments. ii) Explain what measures would be required if the government wishes to maintain this exchange rate in the long run Suppose that in a ring toss game at a carnival, players are given 5 attempts to throw the rings over the necks of a group of bottles. The table shows the number of successful attempts for each of the players over a weekend of games. Complete the probability distribution for the number of successful attempts, X. Please give your answers as decimals, precise to two decimal places. Successes # of players 0 31 1 68 2 26 3 16 4 6 5 2 If you wish, you may download the data in your preferred format. CrunchIt! CSV Excel JMP Mac Text Minitab14-18 Minitab18+ PC Text R SPSS TI Calc P(X = 0) = P(X= 1) = P(X= 2) = P(X = 3) = P(X= 4) = P(X= 5) = incident objectives are based on life saving incident stabalization and porperty management true or false In 250 words, discuss how Microsoft could develop a marketingplan in order to meet the company's marketing objectives andbusiness needs. ethical guidelines that are required while performing telehealth practices include Solve the system with the addition method: - 8x + 5y +8.x 4y -33 28 Answer: (x, y) Preview 2 Preview y Enter your answers as integers or as reduced fraction(s) in the form A/B. Create a hypothesis for the question below. Explain your reasoning.Which utensil will be the most reproductively fit? percentage of defective production of a light bulb factory is (10 %) if a sample of (5) lamps is taken randomly from the production of this factory Get at least one damaged? A)0.1393 B)0.4095 C)0.91845 D)0.1991 Five students took a quiz. The lowest score was 3, the highest score was 10, and the mode was 5. A possible set of scores for the students is: Assume that there are 8 different issues of Newsweek magazine, 7 different issues of Popular Science, and 4 different issues of Time, including the December 1st issue, on a rack. You choose 4 of them at random.(1) What is the probability that exactly 1 is an issue issue of Newsweek?(2) What is the probability that you choose the December 1st issue of Time?