The power developed by the electric motor is 980 W. The power developed by an electric motor can be calculated using the formula:
[tex]\[ \text{Power} = \frac{\text{Work}}{\text{Time}} \][/tex]
where Work is the force applied multiplied by the distance travelled. In this case, the force applied is equal to the weight of the mass being lifted, which is given by:
[tex]\[ \text{Force} = \text{mass} \times \text{acceleration due to gravity} \][/tex]
The acceleration due to gravity is approximate [tex]9.8 m/s\(^2\)[/tex]. Therefore, the force is
[tex]\(10 \, \text{kg} \times 9.8 \, \text{m/s}^2 = 98 \, \text{N}\)[/tex]
The work done is given by:
[tex]\[ \text{Work} = \text{Force} \times \text{distance} \][/tex]
In this case, the distance is 100 meters, so the work done is
[tex]\(98 \, \text{N} \times 100 \, \text{m} = 9800 \, \text{J}\).[/tex]
Finally, substituting the values into the power formula, we have:
[tex]\[ \text{Power} = \frac{9800 \, \text{J}}{10 \, \text{s}} = 980 \, \text{W} \][/tex]
Therefore, the power developed by the motor is 980 W, which corresponds to option (C).
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Find the direction of the sum of
these two vectors:
What is the magnitude of the electrostatic force between two electrons each having a charge of 1.6 x 10-19 C separated by a distance of 1.00 × l0– 8 meter?
Answer:
[tex]fe = \frac{9 \times 10 {}^{9} \times 1.6 \times 10 {}^{ - 19} \times 1.6 \times 10 { - 19}^{?} }{(1 \times 10 { }^{ - 8}) {}^{2} } \\ fe = 23.04 \times 10 {}^{ - 13} n[/tex]
A football thrown by a professional quarterback goes farther than one thrown by a 10-year old. What Newton Law is this?
Answer:
2nd law of motion
Explanation:
Answer:
Newton's 2nd Law of Motion
Explanation:
The amount of force needed to make an object change its acceleration depends on the mass of the object. In other words, the amount of force thrown by a professional quarter-back has more acceleration from his mass.
calculate the concentrations of all species in a 1.37 m na2so3 (sodium sulfite) solution. the ionization constants for sulfurous acid are a1=1.4×10−2 and a2=6.3×10−8.
IN a 1.37 M Na₂SO₃ solution, the concentrations of the different species are approximately [Na⁺] = 2.74 M, [H₂SO₃] = 2.17 × 10⁷ M, [HSO₃⁻] = 2.17 × 10⁷ M, [SO₃²⁻] = 1.37 M
To calculate the concentrations of all species in a 1.37 M Na₂SO₃ solution, we need to consider the dissociation of Na₂SO₃ in water. Na₂SO₃ dissociates into sodium ions (Na⁺) and sulfite ions (SO₃²⁻).
The dissociation of sulfurous acid (H₂SO₃) in water can be described by the following equilibrium reactions
H₂SO₃ ⇌ H⁺ + HSO₃⁻ (Equation 1)
HSO3- ⇌ H⁺ + SO₃^²⁻ (Equation 2)
Given the ionization constants (Ka) for sulfurous acid, we can use these equations to determine the concentrations of the different species in the Na₂SO₃ solution.
Let's define the following variables
[H₂SO₃] = concentration of sulfurous acid
[HSO₃⁻] = concentration of bisulfite ion
[SO₃²⁻] = concentration of sulfite ion
Since Na₂SO₃ is a strong electrolyte, we can assume that it dissociates completely into its ions, so
[Na⁺] = 2 × 1.37 M = 2.74 M
[SO₃²⁻] = 1.37 M
From Equation 2, we can write the equilibrium expression
Ka₂ = [H⁺][SO₃²⁻] / [HSO₃⁻]
We know that [HSO₃⁻] = [H⁺] from Equation 1, so we can substitute [HSO₃⁻] with [H⁺] in the equilibrium expression
Ka₂ = [H⁺][SO₃²⁻] / [H⁺]
Rearranging the equation, we get
[SO₃²⁻] = Ka₂ × [H⁺]
Plugging in the values, we have
[SO₃²⁻] = (6.3 × 10⁻⁸) × [H⁺]
Since [H⁺] = [HSO₃⁻] = [H₂SO₃] (from Equation 1), we can write
[H₂SO₃] = [HSO₃⁻] = [H⁺] = [SO₃²⁻] / Ka₂
Plugging in the values, we have
[H₂SO₃] = [HSO₃⁻] = [H+] = (1.37 M) / (6.3 × 10⁻⁸)
Calculating the numerical value, we find
[H₂SO₃] ≈ 2.17 × 10⁷ M
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In a slow-pitch softball game, a 0.200-kg softball crosses the plate at 15.0 m/s at an angle of 45.0° below the horizontal. The batter hits the ball toward center field, giving it a velocity of 40.0 m/s at 30.0° above the horizontal. (a) Determine the impulse delivered to the ball. (b) If the force on the ball increases linearly for 4.00 ms, holds constant for 20.0 ms, and then decreases to zero linearly in another 4.00 ms, what is the maximum force on the ball?
The impulse delivered to the softball in the slow-pitch game is determined by the change in momentum of the ball.
Given that the initial velocity of the ball is 15.0 m/s at an angle of 45.0° below the horizontal, and the final velocity is 40.0 m/s at 30.0° above the horizontal, we can calculate the change in momentum using vector addition.
(a) The impulse delivered to the ball can be found by subtracting the initial momentum from the final momentum:
[tex]\[\text{{Impulse}} = \Delta \text{{momentum}} = \text{{final momentum}} - \text{{initial momentum}}\][/tex]
To calculate the momentum, we need to find the x- and y-components of the initial and final velocities. Given that the mass of the softball is 0.200 kg, the x-component and y-component velocities are:
[tex]\[v_{i_x} = 15.0 \, \text{{m/s}} \cdot \cos(-45.0°) \quad \text{{and}} \quad v_{i_y} = 15.0 \, \text{{m/s}} \cdot \sin(-45.0°)\][/tex]
[tex]\[v_{f_x} = 40.0 \, \text{{m/s}} \cdot \cos(30.0°) \quad \text{{and}} \quad v_{f_y} = 40.0 \, \text{{m/s}} \cdot \sin(30.0°)\][/tex]
The initial momentum is given by [tex]\(p_{i_x} = m \cdot v_{i_x}\)[/tex] and [tex]\(p_{i_y} = m \cdot v_{i_y}\)[/tex], and the final momentum is given by [tex]\(p_{f_x} = m \cdot v_{f_x}\)[/tex] and [tex]\(p_{f_y} = m \cdot v_{f_y}\)[/tex].
The total impulse is the vector sum of the x- and y-component impulses:
[tex]\[\text{{Impulse}} = \sqrt{(\Delta p_x)^2 + (\Delta p_y)^2}\][/tex]
(b) To determine the maximum force on the ball, we need to consider the change in momentum over time. The force is given by Newton's second law: [tex]\(F = \frac{\Delta p}{\Delta t}\)[/tex].
In this case, the force on the ball increases linearly for 4.00 ms, holds constant for 20.0 ms, and then decreases to zero linearly in another 4.00 ms. By knowing the time intervals and the change in momentum, we can calculate the force during each phase:
- Phase 1 (increasing force): The change in momentum [tex](\(\Delta p_1\))[/tex] can be calculated by multiplying the impulse by the fraction of time during this phase [tex](\(\frac{4.00}{28.00}\))[/tex].
- Phase 2 (constant force): The change in momentum [tex](\(\Delta p_2\))[/tex] can be calculated by multiplying the impulse by the fraction of time during this phase [tex](\(\frac{20.00}{28.00}\))[/tex].
- Phase 3 (decreasing force): The change in momentum [tex](\(\Delta p_3\))[/tex] can be calculated by multiplying the impulse by the fraction of time during this phase [tex](\(\frac{4.00}{28.00}\))[/tex].
The maximum force on the ball is the maximum of the forces during these three phases.
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Fleas have remarkable jumping ability. A 0.60mg flea, jumping straight up, would reach a height of 35cm if there were no air resistance. In reality, air resistance limits the height to 20cm .
Part A
What is the flea's kinetic energy as it leaves the ground?
Part B
At its highest point, what fraction of the initial kinetic energy has been converted to potential energy?
The kinetic energy of the flea as it leaves the ground is 0.0072 J. At its highest point, approximately 30.56% of the initial kinetic energy has been converted to potential energy.
Part A:
The kinetic energy of an object can be calculated using the formula:
[tex]\[ KE = \frac{1}{2}mv^2 \][/tex]
where m is the mass of the flea and v is its velocity. Given that the flea has a mass of 0.60 mg (or [tex]0.60 \times 10^{-3} g[/tex]), we first convert it to kilograms:
[tex]\[ m = 0.60 \times 10^{-6} \, \text{kg} \][/tex]
The velocity of the flea can be determined by considering the height it reaches with and without air resistance. Without air resistance, it would reach a height of 35 cm, which can be converted to meters as 0.35 m. However, due to air resistance, the height is limited to 20 cm, or 0.20 m. Using the concept of conservation of mechanical energy, we can equate the initial kinetic energy to the potential energy at the maximum height:
KE = PE
[tex]\[ \frac{1}{2}mv^2 = mgh \][/tex]
Solving for v :
[tex]\[ v = \sqrt{2gh} \][/tex]
Substituting the values of [tex]\( g = 9.8[/tex] [tex]\text{m/s}^2 \)[/tex] and [tex]\( h = 0.20 \, \text{m} \)[/tex], we can calculate the velocity:
[tex]\[ v = \sqrt{2 \times 9.8 \times 0.20} \approx 1.98 \, \text{m/s} \][/tex]
Now we can calculate the kinetic energy:
[tex]\[ KE = \frac{1}{2} \times 0.60 \times 10^{-6} \times (1.98)^2 \approx 0.0072 \, \text{J} \][/tex]
Part B:
At its highest point, the flea's velocity is zero, so all of its initial kinetic energy has been converted to potential energy. The fraction of the initial kinetic energy converted to potential energy can be calculated by dividing the potential energy at the highest point by the initial kinetic energy:
[tex]\[ \text{Fraction} = \frac{PE}{KE} \][/tex]
Since the flea's mass remains constant and the gravitational force is the same throughout the motion, the ratio of potential energy to kinetic energy is equal to the ratio of the height at the highest point to the total height the flea could have reached without air resistance:
[tex]\[ \text{Fraction} = \frac{h_{\text{max}}}{h_{\text{total}}} \][/tex]
Substituting the values of [tex]\( h_{\text{max}} = 0.20 \, \text{m} \)[/tex] and [tex]\( h_{\text{total}} = 0.35 \, \text{m} \)[/tex], we can calculate the fraction:
[tex]\[ \text{Fraction} = \frac{0.20}{0.35} \approx 0.5714 \][/tex]
Multiplying by 100 to convert to a percentage, the fraction is approximately 57.14%. Therefore, approximately 30.56% (100% - 57.14%) of the initial kinetic energy has been converted to potential energy at the flea's highest point.
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A car traveling at 60km/h undergoes uniform acceleration at a rate of 2/ms^2 until is velocity reached 120km/h determine the distance traveled and the time taken to make the distance
Explanation:
Given that,
Initial speed of a car, u = 60 km/h = 16.67 m/s
Acceleration, a = 2m/s²
Final speed, v = 120 km/h = 33.33 m/s
We need to find the distance traveled and the time taken to make the distance.
acceleration = rate of change of velocity
[tex]a=\dfrac{v-u}{t}\\\\t=\dfrac{v-u}{a}\\\\t=\dfrac{33.33 -16.67 }{2}\\\\t=8.33\ s[/tex]
let the distance be d.
[tex]d=\dfrac{v^2-u^2}{2a}\\\\d=\frac{33.33^{2}-16.67^{2}}{2(2)}\\\\d=208.25\ m[/tex]
Hence, the distance traveled and the time taken to make the distance is 208.25 m and 8.33 seconds respectively.
1. how many lines of symmetry does a square have?
2. how many lines of symmetry does a triangle have?
3. how many lines of symmetry does a pentagon have?
4. how many lines of symmetry does a hexagon?
Answer:
1) four lines
2) three lines
3) fives lines
4) six lines
Answer:
4
Explanation:
Describe the parts of a hurricane and the hazards of a Category 3 Hurricane.
A category three hurricane are major ones that can cause incredible damage like blowing off roofs, cause power outages, uproot trees, lead old buildings to fall, etc. The parts of a hurricane are the eye, storm surge, eyewall, rain bands, and outflow.
A meteorite is DIFFERENT from a comet mainly because it
A) has a tail of ice and dust.
B) enters the Earth’s atmosphere.
C) has a nucleus made of snow and rock.
Eliminate
D) is found in orbit between Mars and Jupiter.
1. meaning of heat and temperature
2. differences between heat and temperature
Answer:
1.heat is a form of 1.temperature is a form
energy that gives of energy that is used to
sensation of measure hotness or
warmth. or coldness of body.
2.its si unit is 2.its si unit is kelvin.
joule.
¿Cuáles de las siguientes cualidades permiten identificar un cuerpo como planeta? I) Debe ser aproximadamente esférico. II) Debe girar en torno a una estrella. III) Su velocidad debe ser constante.
Answer:
The correct answer is ii) It must revolve around a star
Explanation:
For a celestial body to be called a planet, it must meet at least three characteristics
* rotate around a star
* its mass must be sufficient to maintain hydrostatic equilibrium
* have control over its orbital that is to say to prevent that other body is in its same orbital
if we check the different proportions
i) False. Most of the planets are spheres deformed by their rotation on themselves and around the star
ii) True. It is in accordance with the minimum characteristics of the plants
iii) False .. the orbit of the planet can be elliptical and the speed changes at each point for this at a different distance from the star that is in a focus of the ellipse.
The correct answer is ii) It must revolve around a star
Which describes an image that a concave mirror can make? Which describes an image that a concave mirror can make?
Answer: The image can be either virtual or real.
Answer:
the image can be rather real or virtual
In a real pully system the work supplied must be _____ the work accomplished and no links plz
Bilateria are characterized by Multiple Choice a plane of symmetry around a transverse plane across the center of the body so that the front and back halves are mirror images. a plane of symmetry that forms mirror images around any plane through the longitudinal midline of the body. a plane of symmetry that forms mirror images around a horizontal plane in the midline. a plane of symmetry that forms mirror images around a vertical plane in the midline. a plane of symmetry that forms mirror images around an oblique plane in the midline.
Answer:
A plane of symmetry that forms mirror images around a vertical plane in the midline.
Explanation:
Bilateria are animals that have a bilateral symmetry,
Bilateral symmetry refers to organisms that are mirror images along their midline called a sagittal plane.
Examples of bilateria include butterflies and humans because, a line through their midline divides the organism into two identical halves which are mirror images of each other.
So, Bilateria are characterized by a plane of symmetry that forms mirror images around a vertical plane in the midline.
Calculate the rotational kinetic energy of a 12-kg motorcycle wheel if its angular velocity is 120 rad/s and its inner radius is 0.280 m and outer radius 0.330 m. 809.14 J O 1056.32 J 646.38 O 1218.56 J
The rotational kinetic energy of the motorcycle wheel is 809.14 J.
The formula for rotational kinetic energy (KE) is given by KE = (1/2)Iω², where I is the moment of inertia and ω is the angular velocity.
To calculate the moment of inertia of the motorcycle wheel, we need to consider its shape. The wheel can be approximated as a solid cylindrical disk. The moment of inertia for a solid disk rotating about its axis is given by I = (1/2)mr², where m is the mass of the wheel and r is the radius.
Given:
Mass of the wheel (m) = 12 kg
Inner radius (r₁) = 0.280 m
Outer radius (r₂) = 0.330 m
Angular velocity (ω) = 120 rad/s
First, we calculate the moment of inertia for the entire wheel by considering it as a solid disk. The average radius (r_avg) of the wheel can be calculated as (r₁ + r₂) / 2.
r_avg = (0.280 m + 0.330 m) / 2 = 0.305 m
Next, we substitute the values into the formula for moment of inertia:
I = (1/2)mr² = (1/2)(12 kg)(0.305 m)² = 1.1034 kg·m²
Finally, we substitute the moment of inertia and the angular velocity into the formula for rotational kinetic energy:
KE = (1/2)Iω² = (1/2)(1.1034 kg·m²)(120 rad/s)² ≈ 809.14 J
The rotational kinetic energy of the motorcycle wheel, with a mass of 12 kg, an angular velocity of 120 rad/s, an inner radius of 0.280 m, and an outer radius of 0.330 m, is approximately 809.14 J.
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two 2.10 cm × 2.10 cm plates that form a parallel-plate capacitor are charged to ± 0.706 nc. What is the electric field strength inside the capacitor if the spacing between the plates is 1.30 mm ?
The electric field strength inside the capacitor is approximately 541.5 V/m if the spacing between the plates is 1.30 mm.
The electric field strength (E) inside a parallel-plate capacitor is given by the formula:
E = σ / ε₀
where σ is the surface charge density on the plates and ε₀ is the permittivity of free space.
To calculate E, we need to find the surface charge density on the plates. The surface charge density (σ) is defined as the charge (Q) divided by the area (A) of the plate:
σ = Q / A
Given that the plates are charged to ±0.706 nC and have dimensions of 2.10 cm × 2.10 cm, we can calculate the surface charge density:
σ = (±0.706 nC) / (2.10 cm × 2.10 cm)
Next, we need to convert the spacing between the plates to meters:
d = 1.30 mm = 1.30 × 10^(-3) m
Finally, we can substitute the values of σ and ε₀ into the formula for E:
E = σ / ε₀
Using the value of ε₀ = 8.854 × 10^(-12) F/m, we can calculate the electric field strength (E).
The electric field strength inside the capacitor, with plates charged to ±0.706 nC and a spacing of 1.30 mm, is approximately 541.5 V/m.
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1. boiling point of water
water vapor
2. formed by condensation
sun
3. freezing point of water
clouds
4. gas form of water
precipitation
5. main cause of evaporation
32° F
6. rain, sleet, snow, or hail
100° C
Answer:
what is the question. . .
Answer:
see the answer above
Explanation:
What must be true about a surface in order for diffuse reflection to occur?
Answer:
carpet
Explanation:
Diffuse reflection is the reflection of light from a surface such that an incident ray is reflected at many angles rather than at just one angle as in the case of specular reflection.
The structure of carpet's surface is as shown. Thus it shows large amount of diffuse reflection.
A mass of 327 g connected to a light spring of force constant 27.6 N/m oscillates on a horizontal, frictionless track. The amplitude of the motion is 6.7 cm. Calculate the total energy of the system. Answer in units of J. 009 (part 2 of 3) 10.0 points What is the maximum speed of the mass? Answer in units of m/s. 010 (part 3 of 3) 10.0 points What is the magnitude of the velocity of the mass when the displacement is equal to 3.9 cm? Answer in units of m/s.
The total energy of the system is 7.06 J. The maximum speed of the mass is 0.692 m/s. The magnitude of the velocity of the mass when the displacement is equal to 3.9 cm is 0.455 m/s.
When a mass of 327 g is connected to a light spring of force constant 27.6 N/m oscillates on a horizontal, frictionless track with an amplitude of motion of 6.7 cm. The total energy of the system is obtained by adding the kinetic energy of the mass and the potential energy of the spring. By using the formula for total energy of a system given as E = ½ kA², where k is the force constant and A is the amplitude of oscillation, we get; E = ½ (27.6 N/m) (0.067 m)²E = 7.06 J Therefore, the total energy of the system is 7.06 J. Maximum speed of the mass: The maximum speed of the mass is given by the formula v_max = Aω, where A is the amplitude of oscillation and ω is the angular frequency given by ω = √(k/m).
Therefore, the maximum speed of the mass is; v_max = Aωv_max = (0.067 m) √(27.6 N/m / 0.327 kg)v_max = 0.692 m/s Magnitude of velocity of the mass: To obtain the magnitude of the velocity of the mass when the displacement is equal to 3.9 cm, we use the formula v = Aω cos(ωt) and find the value of t such that the displacement is 3.9 cm. The magnitude of the velocity of the mass is obtained by taking the absolute value of v.Using the relationship between the angular frequency and period given by T = 2π/ω, we have T = 2π/√(k/m) = 2π/√(27.6/0.327) = 1.48 s. Since the displacement is equal to 3.9 cm, we have;0.039 m = 0.067 m cos(ωt)ωt = cos⁻¹(0.039/0.067)ωt = 1.012 rad Therefore, the magnitude of the velocity of the mass is given by;v = Aω cos(ωt) = (0.067 m) √(27.6 N/m / 0.327 kg) cos(1.012) = 0.455 m/s.
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A photon of wavelength 0.0940 nm strikes a free electron that is initially at rest and the photon is scattered backwards at an angle of 180 degree from its original direction. (Give your answer in keV. 1 keV = 10^3 eV.) a) What is the energy of the scattered photon? b) What is the speed of the electron after it has had the collision with the photon?
Photon with wavelength 0.0940 nm scatters backward, transferring energy and momentum to an initially at rest free electron. (a) The energy of the scattered photon is approximately 2.102 keV, and (b) the speed of the electron after the collision is approximately 7.679 × 10¹⁴ m/s.
Here is the explanation :
a) To find the energy of the scattered photon, we can use the energy-wavelength relationship for photons:
[tex]E = \frac{hc}{\lambda}[/tex]
Where:
E is the energy of the photon,
h is Planck's constant (6.626 × 10⁻³⁴ J·s),
c is the speed of light (3.00 × 10⁸ m/s),
λ is the wavelength of the photon.
First, let's convert the wavelength from nanometers to meters:
λ = 0.0940 nm = 0.0940 × 10⁻⁹ m
Substituting the values into the equation, we have:
[tex]E = \frac{6.626 \times 10^{-34} \cdot 3.00 \times 10^{8}}{0.0940 \times 10^{-9}} \text{ J}[/tex]
Calculating this expression, we find:
E ≈ 2.102 keV
Therefore, the energy of the scattered photon is approximately 2.102 keV.
b) To determine the speed of the electron after the collision with the photon, we can use the
. Since the electron is initially at rest, the momentum of the system before the collision is zero. After the collision, the momentum of the electron and the scattered photon must still add up to zero.
Since the photon is scattered backward at an angle of 180 degrees, its momentum after the collision is equal in magnitude but opposite in direction to its initial momentum. Let's denote the magnitude of the photon's momentum as p.
The momentum of the electron after the collision is given by its mass (m) multiplied by its final velocity (v). Let's denote the final velocity of the electron as [tex]v_\text{e}[/tex].
Considering the conservation of momentum, we have:
-p + m * [tex]v_\text{e}[/tex] = 0
Solving for [tex]v_\text{e}[/tex], we find:
[tex]v_\text{e} = \frac{p}{m}[/tex]
The momentum of a photon can be calculated using the equation:
[tex]p = \frac{E}{c}[/tex]
Where:
E is the energy of the photon,
c is the speed of light.
Using the energy value we calculated in part a, we have:
[tex]p = \frac{2.102 \times 10^{-1}}{3.00 \times 10^{8}} \text{ MeV/m}[/tex]
Calculating this expression, we find:
p ≈ 7.007 × 10⁻¹⁶ kg·m/s
Now, the mass of an electron is approximately 9.109 × 10⁻³¹ kg. Substituting these values into the equation for the final velocity, we have:
[tex]\begin{equation}v_e = \frac{7.007 \times 10^{-16} \text{ kg·m/s}}{9.109 \times 10^{-31} \text{ kg}}[/tex]
Calculating this expression, we find:
v_e ≈ 7.679 × 10¹⁴ m/s
Therefore, the speed of the electron after the collision with the photon is approximately 7.679 × 10¹⁴ m/s.
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an automobile engine slows down from 3200 rpm to 1300 rpm in 3.0 s . Calculate its angular acceleration, assumed constant. For this my answer was correct with -87.2 rad/s. I need help with this one....Calculate the total number of revolutions the engine makes in this time. Please show steps.
The total number of revolutions the engine makes in 3.0 s is 157.9 revolutions.
The initial speed, ω1 = 3200 rpm
The final speed, ω2 = 1300 rpm
The time taken, t = 3.0 s
The acceleration is ,
a = (ω2 - ω1) / t
a = (1300 - 3200) / 3.0 rad/s²
a = -660 / 3.0 rad/s²
a = -220 rad/s²
Negative sign indicates that the angular acceleration is in the opposite direction of ω1.
The angular displacement is
θ = ω1t + 1/2 a t²
initial angular displacement is 0
then
θ = 1/2 a t²
θ = 1/2 (-220 rad/s²) (3.0 s)²
θ = -990 rad
The negative sign indicates that the angular displacement is in the opposite direction of ω1.
To calculate the total number of revolutions, we need to convert angular displacement from radians to revolutions.
So,
θ = -990 rad x (1 rev/2π rad)
θ = -157.9 rev
(Negative sign indicates that the displacement is in the opposite direction of ω1)
Therefore, the total number of revolutions the engine makes in 3.0 s is 157.9 revolutions.
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1) Si un mango cae a una velocidad de 75m/s y tarda 26 seg. en caer. ¿ Cuál habrá sido la velocidad con qué el mango llegó al suelo?
Answer:
El mango llega al suelo a una velocidad de 329.982 metros por segundo.
Explanation:
El mango experimenta un movimiento de caída libre, es decir, un movimiento uniformemente acelerado debido a la gravedad terrestre, despreciando los efectos de la viscosidad del aire y la rotación planetaria. Entonces, la velocidad final del mango, es decir, la velocidad con la que llega al suelo, se puede determinar mediante la siguiente fórmula cinemática:
[tex]v = v_{o}+g\cdot t[/tex] (1)
Donde:
[tex]v_{o}[/tex] - Velocidad inicial, en metros por segundo.
[tex]v[/tex] - Velocidad final, en metros por segundo.
[tex]g[/tex] - Aceleración gravitacional, en metros por segundo al cuadrado.
[tex]t[/tex] - Tiempo, en segundos.
Si sabemos que [tex]v_{o} = -75\,\frac{m}{s}[/tex], [tex]g = -9.807\,\frac{m}{s^{2}}[/tex] y [tex]t = 26\,s[/tex], entonces la velocidad final del mango es:
[tex]v = v_{o}+g\cdot t[/tex]
[tex]v = -75\,\frac{m}{s}+\left(-9.807\,\frac{m}{s} \right)\cdot (26\,s)[/tex]
[tex]v = -329.982\,\frac{m}{s}[/tex]
El mango llega al suelo a una velocidad de 329.982 metros por segundo.
Write down 2 differences between electrical conductors and electrical insulators.
Answer:
electrical conductors help electric current to pass through it
electrical conductors are usually made of any metal
electrical insulator don't help electric current to pass through it
electrical insulators are made of non metals
hope it helped you
Explanation:
conductors allows free flow of electrons from one atom to another.
insulators restrict free flow of electrons
conductors allow electrical energy to pass through them
insulators do not allow electrical energy to pass through them
why x ray is called an electromagnetic wave
If an electron vibrates back and forth in an clean wire with a frequency of 60.0 Hz, how many cycles make in 1.0 h?
a. 8.1 x 10^5
b. 6.0 x 10^2
c. 3.7 x 10^3
d.2.2 x 10^5
e. 4.6 x 10^4
Plz Help
If an electron vibrates back and forth in an clean wire with a frequency of 60.0 Hz, then it will make 2.2×10⁵ cycles. in 1.0 h. Hence option D is correct.
What is electric charge ?Electric charge is the physical property of matter that experiences force when it is placed in electric field. F = qE where q is amount of charge, E = electric field and F = is force experienced by the charge. there are two types of charges, positive charge and negative charge which are generally carried by proton and electron resp. like charges repel each other and unlike charges attract each other. the flow charges is called as current. Elementary charge is amount of charge a electron is having, whose value is 1.602 x 10⁻¹⁹ C
Amplitude is a measure of loudness of a sound wave. More amplitude means more loud is the sound wave.
Wavelength is the distance between two points on the wave which are in same phase. Phase is the position of a wave at a point at time t on a waveform. There are two types of the wave longitudinal wave and transverse wave.
Frequency is nothing but the number of oscillation in a unit time.
Given,
frequency f = 60.0 Hz.
time t = 1.0 h = 60*60 = 3600s
F = number of cycles/time
number of cycles = F×time
The number of cycles in 1 Hr is
60*3600 = 2.2×10⁵ cycles.
Hence option D is correct.
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Water flows smoothly through a pipe with various circular cross-sections of diameters 2D, 6D,and D`, respectively.
What is the ratio of the speed in section 3 to the speed in section 1?
In which section is the pressure largest? Choose the best answer.
Therefore, the largest pressure is in section 1. Therefore, the answer is Section 1.
Water flows smoothly through a pipe with various circular cross-sections of diameters 2D, 6D, and D', respectively. The velocity, pressure, and volume flow rate of water in the pipe are all unknown. In this case, Bernoulli's equation can be used to determine the velocity and pressure changes that occur throughout the pipe. However, Bernoulli's equation can be used to determine the velocity and pressure changes that occur throughout the pipe. The following is the formula for Bernoulli's equation:
p1 + (1/2)ρv1² + ρgh1 = p2 + (1/2)ρv2² + ρgh2
Where:
p1 is the pressure at section 1,
ρ is the density of water,
v1 is the velocity at section 1,
g is the acceleration due to gravity,
h1 is the height at section 1,
p2 is the pressure at section 2,
v2 is the velocity at section 2, and
h2 is the height at section 2.
Let's take the velocity ratio first. Bernoulli's equation can be used to calculate the velocity in each section.
p1 + (1/2)ρv1² + ρgh1 = p2 + (1/2)ρv2² + ρgh2
p2 = p1, h1 = h2, and ρ are all constants, and thus can be canceled. Using Bernoulli's equation, we get:
(1/2)ρv1² = (1/2)ρv2² + (1/2)ρv3²
v3/v1 = (v1² - v2²)½ / (v1² - v3²)½ = (D'² - D²)½ / (D'² - 4D²)½
So, the ratio of the speed in section 3 to the speed in section 1 is (D'² - D²)½ / (D'² - 4D²)½.
Next, the pressure in each section can be determined using Bernoulli's equation. In a fluid flow system, when the speed of the fluid increases, the pressure of the fluid decreases. As a result, the pressure is the highest in section 1, and the pressure decreases as the fluid flows through sections 2 and 3.
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Consider two spinning tops with different radii. Both have the same linear instantaneous velocities at their edges. Which top has a smaller angular velocity? the top with the smaller radius because the radius of curvature is inversely proportional to the angular velocity the top with the smaller radius because the radius of curvature is directly proportional to the angular velocity the top with the larger radius because the radius of curvature is inversely proportional to the angular velocity The top with the larger radius because the radius of curvature is directly proportional to the angular velocity
Answer:
the top with the largest radius because the radius of curvature is inversely proportional to the angular velocity
Explanation:
Angular and linear velocity are related
v = w r
w = v / r
Therefore, if the linear velocity of the two is the same, the one with the smaller radius has the higher angular velocity.
When reviewing the answers, the correct one is:
the top with the largest radius because the radius of curvature is inversely proportional to the angular velocity
The top that has a smaller angular velocity is D. the top with the larger radius because the radius of curvature is directly proportional to the angular velocity.
It should be noted that the top that has a higher angular velocity will be the top with the smaller radius because the radius of curvature is inversely proportional to the angular velocity
On the other hand, since the two spinning tops have different radii while both have the same linear instantaneous velocities at their edges, then the top that has a smaller angular velocity is the top with the larger radius because the radius of curvature is directly proportional to the angular velocity.
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At 237.0 kPa and 327.0°C, an ideal gas occupies 3.45 m3. Find the number of moles of the gas. Submit Answer Tries 0/12 If the pressure is now raised to 571 kPa and temperature reduced to 76.0°C, what is the new volume? Tries 0/12 Submit Answer
At 237.0 kPa and 327.0°C, an ideal gas law occupies 3.45 m3. Find the number of moles of the gas is 150.9 mol.
To find the number of moles of the gas at a given pressure and temperature, we can use the ideal gas law. The new volume can be determined by applying the ideal gas law again with the updated pressure and temperature values.
The ideal gas law equation is given by[tex]PV = nRT[/tex], where P is the pressure, V is the volume, n is the number of moles, R is the gas constant, and T is the temperature in Kelvin.
For the first part, we are given the pressure (237.0 kPa), temperature (327.0°C), and volume (3.45 m³). To find the number of moles, we need to convert the temperature to Kelvin by adding 273.15 to it. Then, we rearrange the ideal gas law equation to solve for n: [tex]n = PV / RT[/tex]. Plug in the values and calculate to find the number of moles.
For the second part, we are given the new pressure (571 kPa) and temperature (76.0°C). Again, convert the temperature to Kelvin and use the rearranged ideal gas law equation to solve for the new volume, [tex]V = nRT / P[/tex]. Substitute the values of n, R, T, and P to calculate the new volume.
By applying the ideal gas law in both cases, we can determine the number of moles of the gas and the new volume based on the given pressure and temperature conditions.
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An electron moves along the z-axis with vz=3.8×107m/svz=3.8×107m/s. As it passes the origin, what are the strength and direction of the magnetic field at the following (xx, yy, zz) positions?
A. (2 cmcm , 0 cmcm, 0 cmcm)
B. (0 cmcm, 0 cmcm, 1 cmcm )
C. (0 cmcm, 2 cmcm , 1 cmcm )
At position A, the magnetic field is directed in the positive z-direction with a magnitude of [tex]9.5 * 10^{-2}[/tex] Tesla.
At position B, the magnetic field is directed in the positive z-direction with a magnitude of [tex]1.52 * 10^{-6}[/tex] Tesla.
At position C, the magnetic field is directed in the positive y and z directions with a magnitude of [tex]2.85 * 10^{-1}[/tex] Tesla in the y-direction and [tex]1.43 * 10^{-1}[/tex] Tesla in the z-direction.
To calculate the strength and direction of the magnetic field at different positions, we can use the Biot-Savart Law, which gives the magnetic field produced by a current-carrying wire.
In this case, we can consider the electron's velocity as a current and calculate the magnetic field using the equation:
B = (μ₀/4π) * (v × r) / r²
where B is the magnetic field, μ₀ is the permeability of free space [tex](4\pi * 10^{-7} T.m/A)[/tex], v is the velocity of the electron, r is the position vector from the current element to the point where we want to calculate the field, and × represents the cross product.
Let's calculate the magnetic field at each given position:
A. (2 cm, 0 cm, 0 cm):
First, convert the position to meters: (0.02 m, 0 m, 0 m)
The position vector, r = (0.02 m, 0 m, 0 m), points in the positive x-direction.
Using the Biot-Savart Law, we can calculate the magnetic field:
B = (μ₀/4π) * (v × r) / r²
B = (4π * 10^{-7} T·m/A) * (3.8 × 10^7 m/s) * (0 m, 0 m, 1 m) / (0.02 m)²
B = (4π × 10^{-7} T·m/A) * (3.8 × 10^7 m/s) * (0 m, 0 m, 1 m) / (0.0004 m)
B = 9.5 × 10^{-2} T * (0 m, 0 m, 1 m) = (0 T, 0 T, 9.5 × 10^{-2} T)
Therefore, at position A, the magnetic field is directed in the positive z-direction with a magnitude of 9.5 × 10^{-2} Tesla.
B. (0 cm, 0 cm, 1 cm):
First, convert the position to meters: (0 m, 0 m, 0.01 m)
The position vector, r = (0 m, 0 m, 0.01 m), points in the positive z-direction.
Using the Biot-Savart Law, we can calculate the magnetic field:
B = (μ₀/4π) * (v × r) / r²
B = (4π × 10^{-7}T·m/A) * (3.8 × 10^7 m/s) * (0 m, 0 m, 0.01 m) / (0.01 m)²
B = (4π × 10^{-7} T·m/A) * (3.8 × 10^7 m/s) * (0 m, 0 m, 1 m)
B = 1.52 × 10^{-6} T * (0 m, 0 m, 1 m) = (0 T, 0 T, 1.52 × 10^{-6} T)
Therefore, at position B, the magnetic field is directed in the positive z-direction with a magnitude of 1.52 × 10^{-6} Tesla.
C. (0 cm, 2 cm, 1 cm):
First, convert the position to meters: (0 m, 0.02 m, 0.01 m)
The position vector, r = (0 m, 0.02 m, 0.01 m), points in the positive y and z directions.
Using the Biot-Savart Law, we can calculate the magnetic field:
B = (μ₀/4π) * (v × r) / r²
B = (4π × 10^{-7} T·m/A) * (3.8 × 10^7 m/s) * (0 m, 0.02 m, 0.01 m) / (0.02 m)²
B = (4π × 10^{-7} T·m/A) * (3.8 × 10^7 m/s) * (0 m, 1 m, 0.5 m) / (0.0004 m)
B = 2.85 × 10^{-1} T * (0 m, 1 m, 0.5 m) = (0 T, 2.85 × 10^{-1} T, 1.43 × 10^{-1} T)
Therefore, at position C, the magnetic field is directed in the positive y and z directions with a magnitude of [tex]2.85 * 10^{-1}[/tex] Tesla in the y-direction and [tex]1.43 * 10^{-1}[/tex] Tesla in the z-direction.
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