An FBI agent orders a block of ballistics gel. The gel weighs 54 pounds per cubic foot. What is the weight of the block of gel?

Answer:

The value of x is 5 that represents the searched number

Step-by-step explanation:

Let us assume x be the number [^ 2] i.e. squared.

Now  

x^2  -10 = 3x

This is a quadratic equation

x^ 2 - 3x - 10 = 0

x^2 - 5x + 2x - 10

x (x - 5) + 2(x - 5)

(x-5) (x + 2) = 0  

x - 5 = 0 where x = 5 positive.

x + 2 = 0 where x = -2 negative.

Here we considered the positive  

The value of x is 5 that represents the searched number

Answer:

three thirds is one whole

Step-by-step explanation:

The answer is 18 because three thirds is one whole which in this case is 18! Have a nice day!

Answer:

Alfredo está en lo correcto porque los números negativos se encuentran a la izquierda del cero y mientras más a la izquierda se encuentra un número negativo, más pequeño será y a medida que te desplazas hacia la derecha mayor será el número. Puedes representar los dos números en una recta numérica de la siguiente forma:

___________________________________________________________

-14   -13    -12    -11    -10    -9    -8    -7    -6    -5    -4    -3    -2    -1    0    1    2    3

Como se ve aquí, -14 se encuentra a la izquierda de -10 y esto significa que es menor. Por esto, Alfredo está en lo correcto al decir que -14 es menor.

Answer:

-14

Step-by-step explanation:

Hello,

Let's have a look at this figure and think about how are these two angles related to each other. These two angles are vertically opposite angles, and any two vertically opposite angles should be equal to each other.

Because the two angles should be equal to each other, we can equate the two equations together and solve for x.

9x + 184 = 7x + 156

9x - 7x = 156 - 184

2x = -28

x = -14

Answer:

-2x^2 + 2x + 1

Step-by-step explanation: If you try to factorize, there are no solutions, and if you use the quadratic formula, you don't get 2 solution for x

The ratio of students who wish they had x-ray vision to all students: 2:9

The ratio of students who wish for flight to all students: 3:1

The ratio of students who wish for flight to those who wish for invisibility: 6:1

1. The ratio of students who wish they had x-ray vision to all students: 2:9

This means that out of a group of students, there are 2 students who wish they had x-ray vision for every 9 students in total.

2. The ratio of students who wish for flight to all students: 2:3

This ratio indicates that out of a group of students, there are 2 students who wish for the ability to fly for every 3 students in total.

3. The ratio of students who wish for flight to those who wish for invisibility: 1:6

This ratio compares the number of students who wish for flight to the number of students who wish for invisibility. It states that for every student who wishes for flight, there are 6 students who wish for invisibility.

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The instrument uncertainty in e/m for each data point is calculated using error propagation.

e/m = 3.125x10^6 V/r^2I^2

From the given equation above, the formula for error propagation required in experiment step 8 can be derived. The error propagation formula is given as;Δe/m = (e/m)(ΔV/V + 2Δr/r + 2ΔI/I)

The voltage is changed to 400 V for the third dataset. The instrument uncertainties in V, I, and r are to be estimated.

The last digit place read from the power supplies is used as the uncertainties V and I. The uncertainty in r should be estimated from the thickness of the beam path.

Estimation of instrument uncertainties in V, I, and r:For V, the reading is up to 0.1 V.

Hence, the uncertainty in V isΔV = 0.1 VFor I, the reading is up to 0.01 A.

Hence, the uncertainty in I isΔI = 0.01 AFor r, the thickness of the beam path is given as 0.25 cm. Hence, the uncertainty in r isΔr = 0.25 cm

The instrument uncertainty in e/m for each data point is to be calculated using error propagation.

Data for three datasets are given below;

Data Set 1: V = 200 V, r = 0.56 cm, I = 0.2 AData Set 2: V = 300 V, r = 0.56 cm, I = 0.2 AData Set 3: V = 400 V, r = 0.56 cm, I = 0.2 A

For Data Set 1;e/m = 3.125 x 106 × 200/ (0.56)2 (0.2)2= 1.75867 × 1011 C/kgΔe/m = (1.75867 × 1011)(0.1/200 + 2(0.25/0.56) + 2(0.01/0.2))= 1.78853 × 1010 C/kg

For Data Set 2;e/m = 3.125 x 106 × 300/ (0.56)2 (0.2)2= 2.63800 × 1011 C/kgΔe/m = (2.63800 × 1011)(0.1/300 + 2(0.25/0.56) + 2(0.01/0.2))= 1.70314 × 1010 C/kg

For Data Set 3;e/m = 3.125 x 106 × 400/ (0.56)2 (0.2)2= 3.51733 × 1011 C/kgΔe/m = (3.51733 × 1011)(0.1/400 + 2(0.25/0.56) + 2(0.01/0.2))= 1.61057 × 1010 C/kg

Hence, the instrument uncertainty in e/m for each data point is calculated as;

For Data Set 1, Δe/m = 1.78853 × 1010 C/kg

For Data Set 2, Δe/m = 1.70314 × 1010 C/kg

For Data Set 3, Δe/m = 1.61057 × 1010 C/kg

Therefore, the instrument uncertainty in e/m for each data point is calculated using error propagation.

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Answer: Bella is correct.

Step-by-step explanation:

Let the number of weeks will it take her to save enough to buy her coveted bike be represented by w.

The information given in the question can then be formed into an equation as:

45 + 11(w) = 265

45 + 11w = 265

Collect like terms

11w = 265 - 45

11w = 220

w = 220/11

w = 20

He'll save for 20 weeks

Bella is correct.

Answer: Figure B is 2x bigger on all sides

Explanation: You can see that each of the numbers times 2 would equal all of the numbers on B.

Answer:

Measure of angle A = 100°

Measure of angle B = 80°

Measure of angle C = 65°

Step-by-step explanation:

From the given picture,

Angle A and angle B are the linear pair of angles, and linear pair of angles are supplementary angles,

m(∠A) + m(∠B) = 180°

(3x - 20)° + (2x)° = 180°

5x - 20 = 180

5x = 200

x = 40

By substituting the value of x in the measures of each angle,

m(∠A) = (3x - 20)°

          = 3(40) - 20

          = 120 - 20

          = 100°

m(∠B) = 2x°

          = 2(40)

          = 80°

m(∠C) = (2x - 15)°

          = 2(40) - 15

          = 80 - 15

          = 65°

Answer:

c is your answer

Step-by-step explanation:

(a) The unit vector normal to the surface at point P is n = (-2/3, -2/3, 1/3).

(b) The gradient vector ∇f = (-2x, -2y, 0.5z).

(c) The curl of the gradient vector, ∇ × ∇f, is not applicable in this case since ∇f is not a vector field, but a surface normal.

To find a unit vector normal to the surface at point P(1, 1, 2) given the equation 0.25z² - x² - y² = 0, we can follow these steps:

Step 1: Define the Surface Function

Let's define the surface function f(x, y, z) based on the given equation:

f(x, y, z) = 0.25z² - x² - y²

Step 2: Calculate the Gradient Vector (∇f)

The gradient vector (∇f) represents the vector of partial derivatives of the surface function. Calculate ∇f(x, y, z) by taking the partial derivatives of f(x, y, z) with respect to each variable:

∂f/∂x = -2x

∂f/∂y = -2y

∂f/∂z = 0.5z

Thus, the gradient vector (∇f) is (∇f) = (-2x, -2y, 0.5z).

Step 3: Evaluate ∇f at Point P

Evaluate the gradient vector (∇f) at point P(1, 1, 2) by substituting the coordinates into (∇f):

∇f(P) = (-2(1), -2(1), 0.5(2))

= (-2, -2, 1)

Step 4: Normalize the Normal Vector

To obtain a unit vector normal to the surface at point P, we need to normalize (∇f(P)) by dividing it by its magnitude.

Magnitude of ∇f(P) = √((-2)² + (-2)² + 1²)

= √(4 + 4 + 1)

= √9

= 3

The unit vector normal to the surface at point P is then:

n = (∇f(P)) / |∇f(P)|

= (-2, -2, 1) / 3

= (-2/3, -2/3, 1/3)

So, the unit vector normal to the surface at point P(1, 1, 2) is n = (-2/3, -2/3, 1/3).

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The question is -

Find a unit vector normal to the surface at Point P: (1,1,2):

0.25z² - x² - y² = 0

(a) n = ?

(b) ∇f = ?

(c) ∇ × ∇f = ?

The set has a size of 1, which is the largest possible size for a subset that is common to A and B.

To find a set of largest possible size that is a subset of both A and B, we need to find the common elements of A and B.

The common element of A and B is 10. Therefore, any subset of A and B that is of largest possible size must include 10.

One possible set of largest possible size that is a subset of both A and B is:

{10}

This set has a size of 1, which is the largest possible size for a subset that is common to A and B.

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Answer:

B)All the real numbers

Step-by-step explanation:

the given Graph is Parabola

so the function has to be quadratic

we know that the domain of a quadratic function is always [tex]x\in\mathbb{R}[/tex]

hence, our answer is B

Answer:

I would say C or B

Step-by-step explanation:

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Answer:  

The second box  

Step-by-step explanation:

The volume of a pyramid can be given by the formula:  V=31​Ah. Where.  A:  Area of the V=(1/3)(B)(h)

multiply both sides by 3

3V=Bh

divide both sides by B

3V/B=h

Therefore, If it is wider it has more space to carry more items such as macaroni.

Answer:

It can be calculated by finding the difference between the two angles. Half of this difference will be the angle that is required.

Therefore

236 - 124 = 112

Tanget-tanget angle = 112 / 2 = 56 degrees

Answer:

tangent x = 12/9

Step-by-step explanation:

Hello There!

Once again these are the Trigonometric Ratios

SOH CAH TOA

Sine = Opposite over Hypotenuse (SOH)

Cosine = Adjacent over Hypotenuse (CAH)

Tan = Opposite over Adjacent (TOA)

And for this one we are asked to find the tangent of angle x

Remember tangent = opposite over adjacent

opposite - the side length that is opposite of the angle (so the angle will be facing that side length)

adjacent - the side length that is not the opposite nor the hypotenuse

The opposite of angle x is 12 and the adjacent of angle x is 9

so tangent x = 12/9

The test that can be used to assess whether variances are equal between multiple groups is the Levene test.

The Levene test is a hypothesis test for the equality of variances in a statistical population. It is named after the American statistician Howard Levene. It is commonly used to check the null hypothesis of homoscedasticity or equal variances across k groups. The test is used to determine if two or more groups have different variances or if the variance is unequal. The null hypothesis of the Levene test is that the variance of the populations from which the groups are drawn is equal. The Levene test is an alternative to the F-test for equal variances. Therefore, it can be concluded that the Levene test can be used to assess whether variances are equal between multiple groups.

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Answer:

q = -10

Step-by-step explanation:

If the slope is undefined, then there is no change in x. Therefore, since -10-(-10) = 0, then q=-10.

Answer:

18

Step-by-step explanation:

she needs 18 boxes divide 144 by 8 then u get ur answer

The contraction of the diaphragm causes an increase in the volume of the chest cavity, leading to the correct answer, option 'D'.

The diaphragm is a dome-shaped muscle located at the bottom of the chest cavity. When it contracts, it flattens and moves downward. This contraction of the diaphragm plays a crucial role in the process of inhalation or inspiration.

During inhalation, the diaphragm contracts, which causes it to move downward. This downward movement creates more space in the chest cavity, leading to an increase in its volume. As a result, the lungs expand, and air rushes in from the external environment to fill this increased space. This process allows oxygen to be drawn into the lungs for respiration.

Therefore, option 'D' is the correct answer because the contraction of the diaphragm causes an increase in the volume of the chest cavity, facilitating inhalation or inspiration.

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The circumference is:

14.6 x 3.14 = 45.844 (m)

Answer:

c = 45.8 m

Step-by-step explanation:

The diameter of this circle is 14.6 m.  The formula for the circumference of a circle of diameter d is πd.  Here, using 3.14 for π, C = (3.14)(14.6 m), or

C = 45.8 m

1- True: Linear programming can be used to identify the critical path for a PERT network.

2- False: The probabilistic approach characterized by PERT does not use median activity times.

3- False: The critical path is the sequential path of activities from the first to the last, defined by activities with zero slack.

4- False: Linear programming can be used for both profit and nonprofit organizations.

Linear programming can indeed be used to identify the critical path for a PERT network. The critical path represents the sequential path of activities from the first activity to the last, and it is defined by activities with zero slack. By analyzing the dependencies and constraints between activities, linear programming techniques can be applied to determine the optimal schedule and identify the critical path.

The probabilistic approach characterised by PERT does not use median activity times. Instead, it utilises three time estimates for each activity: optimistic, most likely, and pessimistic activity times. These estimates are used to calculate the expected duration and variability of the project.

Regarding the statement about linear programming and profit optimization, it is incorrect to say that linear programming cannot be used for nonprofit organizations. Linear programming can be applied to various optimisation problems, including those related to resource allocation, cost minimisation, and efficiency improvement, which are relevant to both for-profit and nonprofit organisations.

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Answer:

Volume of Cylinder 1 = π×r×r×h

= 22÷7×1×1×8

= 25.13cm

Volume of Cylinder 1 = π×r×r×h

= 22÷7×2×2×8

= 100.53cm

Volume of Cylinder 1 = π×r×r×h

= 22÷7×3×3×8

= 226.19cm

The critical value for the [tex]X^{2}[/tex] goodness-of-fit test with 4 categories and α = 0.05 is approximately 7.815.

In a chi-square goodness-of-fit test, we compare the observed frequencies of a nominal variable across different categories with the expected frequencies under the null hypothesis. The test statistic, [tex]X^{2}[/tex], measures the discrepancy between the observed and expected frequencies.

To determine if the observed frequencies significantly differ from the expected frequencies, we compare the test statistic with the critical value at the specified significance level (α). The critical value is determined based on the degrees of freedom, which is the number of categories minus 1.

In this scenario, the nominal variable has 4 categories. Degrees of freedom is (4 - 1) = 3. Using the degrees of freedom and the significance level of α = 0.05, we can consult the chi-square distribution table or use statistical software to find the critical value.

The critical value for the [tex]X^{2}[/tex] goodness-of-fit test with 4 categories and α = 0.05 is approximately 7.815.

Since the test statistic [tex]X^{2}[/tex] = 6.432 is less than the critical value of 7.815, we fail to reject the null hypothesis. This means that there is not enough evidence to suggest a significant difference between the observed and expected frequencies.

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