My answer to the question is Velocity.
"A student bikes to school by traveling first dN = 0.900" and "Similarly, let d⃗ W be the displacement vector corresponding to the second leg of the student's trip. Express d⃗ W in component form. Express your answer as two numbers separated by a comma. Be careful with your signs"
Complete Question
A student bikes to school by traveling first dN = 0.900 miles north, then dW = 0.300 miles west, and finally dS = 0.100 miles south.
Similarly, let d⃗ W be the displacement vector corresponding to the second leg of the student's trip. Express d⃗ W in component form.
Express your answer as two numbers separated by a comma. Be careful with your signs.
Answer:
The value is [tex]dT = ( -0.3, 0.8)[/tex]
Explanation:
From the question we are told that
The first displacement is [tex]dN = 0.900 \ due \ North[/tex] i.e positive y-axis
The second displacement is [tex]dW = 0.300 \ miles \ due \ west[/tex] i.e negative x-axis
The final displacement is [tex]dS = 0.100 \ miles \ due \ south[/tex] i.e negative y-axis
Generally dW in component for is
[tex]dW = (-0.3 , 0)[/tex]
Generally the total displacement of the student is mathematically represented as
[tex]dT = ( -0.3, (0.90 - 0.10))[/tex]
[tex]dT = ( -0.3, 0.8)[/tex]
HELP PLEASE . SCIENCE
WIL GIVE BRAINLISEST PLEASE HELP SPEED ACCELERATION GRAPHS LABEL THE GRAPHS PLEASEEeeee
Answer:
Take the numbers and fill them in graph.
Plot time as X and speed as Y and afterward join then like a line graph.
art integration in superconductors
copper wire is the example of superconductor
In which block of the periodic table is uradium (U) found?
s block
d block
р
block
f block
Answer:
f block on edge 2020
Explanation:
hope this helps:)
Is anyone interested in a pile of bricks, it's free on craigslist?
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Therefore, Interest in a free pile of bricks on Craigslist depends on local individuals' needs and preferences, and posting clear details can attract potentially interested parties.
To learn more about Craigslist click:
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If I drop a paper clip from rest and it falls freely until it hits the ground with a speed of 30 m/s. How long is the ball in free fall?
Answer:
3.06sExplanation:
If I drop a paper clip from rest and it falls freely until it hits the ground with a speed of 30 m/s,we ae to find the time taken for the ball to drop. To do that we will use the equation of motion v = u + gt
v is the final velocity = 30m/s
u is the initial velocity = 0m/s (the object drops from rest)
g is the acceleration due to gravity = 9.81m/s²
time is the time taken
Substituting the given parameters into the formula;
30 = 0 + (9.81)t
30 = 9.81t
t = 30/9.81
t = 3.06secs
Hence it will take the object 3.06secs in free fall
A dolphin maintains a constant speed of 2.0 m/s for 24 s while swimming in a straight line. It then reverses direction and returns to its starting point in 8 s. Its average speed and average velocity for the entire trip are
Answer:
Average speed 3m/sAverage velocity is 4m/s
Explanation:
In this problem, we are going to solve for the average speed and average velocity for the entrire trip made by the dolphin.
Given data
speed v= 2 m/s
time t= 24s
the distance travelled by the dolphin is
speed= distance/time
distance= speed*time
distance= 2*24
distance= 48m
now the dolpine made a reverse and covered this 48m in 8s to return to it initial position
the speed it took is
speed= distance/time
speed= 48/8
speed= 6m/s
It average speed is the total distance divided by the total time taken
average speed= (48+48)/(24+8)= 96/32= 3m/s
average speed= 3 m/s
it average velocity is the sum of the initial and final velocity is divided by 2 to find the average
(2+6)/2= 8/2= 4m/s
average velocity is 4m/s
your alpaca is walking down the road at 4 m/s. how far does it go in 45 seconds?
Answer:
180
Explanation:
4m/s x 45s=180m
A spaceship is flying through space at a very high velocity .The astronaut shuts the engines off the spaceship will
Answer:
The astronauts will simply have to fire the rocket engines again to keep moving. The spacecraft will keep coasting at the same speed and in the same direction. The spacecraft will slow down until it comes to a complete stop. ... Its speed will be constant except for very slow changes that are part of its orbital motion.
Explanation:
What year will y'all graduate
Answer:
I'm in college and i'm a senior so i will graduate this year.
Explanation:
In Einstein's special theory of relativity, mass and energy are equivalent. An expression of this equivalence can be made in terms of electron volts ( units of energy) and kilograms, with one electron volt (eV) being equal to 1.78*10^ -36 kg. Using this ratio, express the mass of the heaviest mammal on earth, the blue whale, which has an average mass of 1.90*10^ 5 kg , in mega electron volts and tera electron volts
Answer:
In MeV: 10.674 × 10^(34) MeV
In TeV: 10.674 × 10^(28) TeV
Explanation:
We are given that;
1.78 × 10^(-36) kg = 1 eV
We are now told that the blue whale has an average mass of 1.90 × 10^(5) kg
Thus, converting this mass of the blue whale to eV, we have;
(1.90 × 10^(5) × 1)/(1.78 × 10^(-36)) = 10.674 × 10^(40) eV
Now, converting to mega electron volts;
From conversions;
1 eV = 10^(-6) MeV
Thus,
10.674 × 10^(40) eV will be;
(10.674 × 10^(40) × 10^(-6))/1 = 10.674 × 10^(34) MeV
Also, converting to Tera electron Volts;
From conversion, we know that;
1 eV = 10^(-12) TeV
Thus;
10.674 × 10^(40) eV will give;
(10.674 × 10^(40) × 10^(-12))/1 = 10.674 × 10^(28) TeV
Beasy is driving in his car to take care of some errands. The first errand has him
driving to a coffee shop 2 km East and 6 km North of his starting location. Once he
completes that errand, he drives to a thrift store which is 4 km East of the first errand.
What is the displacement of the car from the starting point, rounded to the nearest
km?
At this point in the story, Beasy has driven his car (2+6+4) = 12 km.
He is parked at the thrift store, (2+4) = 6 km East and 6 km North of his starting point.
As the crow flies, the thrift store is √(6km² + 6km²) in a straight line from the starting point.
That's √(72 km²) , which works out to 8.485 km . When rounded to the nearest whole km, he can phone up his wife and tell her he's "eight kilometers from home can you hear me now ?".
Displacement is a vector, so to answer the question completely, we also need to state its direction.
The angle from home to the thrift store, relative to East, is arctan(6km/6km).
That's 45 degrees.
The full displacement vector is 8.485 km Northeast.
From the question, Beasy drives 2km East and 6 km North. He then drives 4 km East of the first errand. An illustrative diagram is shown in the attachment below.
From the diagram S is the starting starting point, C is coffee shop and T is the thrift store.
The displacement of the car from the starting point is giving by /TS/ in the diagram. To calculate /TS/, consider the right-angled triangle TSQ, /TS/ is the hypotenuse.
From The Pythagorean theorem, in a right-angled triangle, the square of the longest side (hypotenuse) equals sum of the squares of the other two sides.
That is,
/TS/² = /SQ/² + /TQ/²
But /TQ/ = /CP/ = 6km
and /SQ/ = /SP/ + /PQ/
/SP/ = 2 km, /PQ/ = 4 km
∴ /SQ/ = 2 km + 4 km
/SQ/ = 6 km
Hence,
/TS/² = 6² + 6²
/TS/² = 36 + 36
/TS/² = 72
/TS/ = [tex]\sqrt{72}[/tex]
/TS/ = 8.485 km
/TS/ ≅ 8 km ( to the nearest km)
Hence, the displacement of the car from the starting point rounded to the nearest km is 8 km.
Learn more about displacement here: https://brainly.com/question/19232260
what are the factor that affect the efficiency of a pulley
Answer:
Tension in the chains - In a chain drive, technically, you have a closed-chain (which has no end) going around 2 pulley or gears; looking closely you have 2 parallel chains going in opposite direction. If kept in horizontal direction, the one below the other is the slack side and the other the tight side. The tension on the upper or tight side is more than the slack side. So you need to keep in mind to keep your chain drive tight so that there is no loss or rotation or lags.
Sizes of the pulley/gear - The chain will be warped around a pair of pulley or gear. The sizes of these pulley/gear will also determine the efficiency of the chain drive (consider one big and one small)
Number of pulley/gear - If the number of pulley/gear is more and chain wrapped on it with little complexity will result in decrease in efficiency because of extra tension.
Length of the chain drive - You cannot have much too long chain drive. It will make your slack side more heavy because the end are further away. You have to apply more power and possibilities of lag increases decreasing efficiency. In an ideal situation, this won't happen, but this world isn't ideal.
Friction between chains & pulley/gear - If you have studied gears (involving its teeth), you will come to know that there is friction offered on the two meeting surfaces.
Angle of contact - This would have been explained better with a diagram. Although, if you are familiar with the terms you won't have difficulty understanding. Angle of contact is the angle the chain forms with the pulley/gear at the point of contact with the center of the pulley. The angle of contact should not be too small, or else the things will be slippery.
Explanation:
Convert the following measurements. Only type numbers and decimals into the answer boxes:
1. 34mm =
cm
2.234cm =
m
3.3km =
m
4.35 m =
mm
Answer:
2m 4m2Explanation:rteji3ujnrej
1. .134
2. 22.34
3. 330
4. 4350
How is a scientific theory different from a scientific law?
Which are functions of the endoplasmic reticulum (ER)?
Choose 2 answers:
A. DNA storage
B. Protein modification
C. Lipid synthesis
D. ATP production
Answer:
a. DNA storage
Explanation:
Which is an example of heat transfer by convection?
Answer:
Boiling water - The heat passes from the burner into the pot, heating the water at the bottom. Then, this hot water rises and cooler water moves down to replace it, causing a circular motion. Radiator - Puts warm air out at the top and draws in cooler air at the bottom.
The diagram below shows a 1.5 kilogram kitten jumping from the top of a 1.80 meter high refrigerator to a 0.90 meter high
counter.
Refrigerator
Counter
CO
The kitten's gravitational potential energy on top of the refrigerator is greater, but what is the kitten's gravitational
potential energy on top of the counter? Assume gravity as 10, if needed.
Answer:
E = 27 J
Explanation:
It is given that,
Mass of a kitten is 1.5 kg
Initially, it was at a height of 1.8 m refrigerator and finally jumps to a 0.9 m height counter.
We need to find the kitten's gravitational potential energy on top of the counter. Potential energy is possessed due to the position of an object. It can be given by :
[tex]E=mgh[/tex]
g is acceleration due to gravity
[tex]E=1.5\ kg\times 10\ m/s^2\times 1.8\ m\\E=27\ J[/tex]
So, the kitten's gravitational potential energy on top of the counter is 27 J.