Consider only transitions involving the n=1 through n=4 energy levels for the hydrogen atom (using the diagram in Study Question 17).
a) How many emission lines are possible, considering only the four quantum levels?
b) Photons of the lowest energy are emitted in a trastion from the level with n=___ to a level with n=___.
c) The emission line having the shortest wavelength corresponds to a transition from the level with n=___ to the level with n=____

Answer:

a beam of electrons emitted from the cathode of a high-vacuum tube.

Explanation:

Cathode rays (also known as electron beam or e-beam) are electron waves that can be used in vacuum tubes.

Answer:

commensalism

Explanation:

It's not parasitism as the shark is not harmed in the relationship

Answer:

it is closer to the south pole

Explanation:

Answer:

Valence electrons are outer shell electrons with an atom and can participate in the formation of chemical bonds. In single covalent bonds, typically both atoms in the bond contribute one valence electron in order to form a shared pair. The ground state of an atom is the lowest energy state of the atom.

Answer:

to much sause

Explanation:

A direct current power supply of low voltage (less than 10 volts) has lost the markings that indicate which output terminal is positive and which is negative. A chemist suggests that the power supply terminals be connected to a pair of platinum electrodes that dip into 0.1-molar KI solution.  Only (B) A gas will be evolved only at the negative electrode correctly identifies the polarities of the power supply terminals.

When the power supply terminals are connected to a pair of platinum electrodes dipping into a 0.1-molar KI solution, the electrolysis of the solution will occur. In the process of electrolysis, the positive electrode (anode) attracts negatively charged ions (anions) and the negative electrode (cathode) attracts positively charged ions (cations).

In this case, when a gas is evolved, it indicates that reduction is occurring at the electrode. The gas evolved will be hydrogen gas (H₂) from the reduction of H⁺ ions in the KI solution.

Since hydrogen gas is evolved only at the negative electrode (cathode), the correct identification of the polarities of the power supply terminals is that a gas will be evolved only at the negative electrode.

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Water ([tex]H_{2}O[/tex]) appears on the product side with a coefficient of 8. To balance the given redox reaction, we can use the half-reaction method. Let's begin by balancing the reduction half-reaction and the oxidation half-reaction separately.

Reduction half-reaction: [tex]MnO_{4}^{-aq}[/tex] + [tex]8H^{+aq}[/tex] + [tex]5e^{-}[/tex] → [tex]Mn^{2+}[/tex](aq) + [tex]4H_{2}O[/tex](l)

Oxidation half-reaction: [tex]NH_{3}[/tex](aq) → [tex]NO_{2}[/tex](g) + [tex]3H^{+}[/tex](aq) + [tex]2e^{-}[/tex]

Next, we need to balance the number of electrons transferred in both half-reactions. To do this, we multiply the oxidation half-reaction by 5 and the reduction half-reaction by 2:

[tex]2NH_{3}[/tex](aq) → [tex]2NO_{2}[/tex](g) + [tex]6H^{+}[/tex](aq) + [tex]4e^{-}[/tex]

[tex]2MnO_{4}^-[/tex](aq) + [tex]16H^{+}[/tex]+(aq) + [tex]10e^{-}[/tex] → [tex]2Mn^{2+}[/tex](aq) + [tex]8H_{2}O[/tex](l)

Now, we can combine the two half-reactions and cancel out the common species:

[tex]2MnO_{4}^-[/tex](aq) + [tex]16H^{+}[/tex](aq) + [tex]10NH_{3}[/tex](aq) → [tex]2Mn^{2+}[/tex](aq) + [tex]2NO_{2}[/tex](g) + [tex]8H_{2}O[/tex](l)

From the balanced equation, we can see that water ([tex]H_{2}O[/tex]) appears on the product side with a coefficient of 8.

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Answer:

relating to or characteristic of a microorganism, especially a bacterium causing disease or fermentation.

Explanation:

ex: "skin is a major source of microbial contamination during a surgical procedure"

◕‿↼ Hey There!

Answer → Microbial means, relating to or characteristic of a microorganism, especially a bacterium causing disease or fermentation.

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Answer:

13.89% p/p

Explanation:

El porcentaje peso a peso de una solución (%p/p) es definido como cien veces la relación entre la masa del soluto (En este caso, cloruro de calcio) y la masa de la solución. La ecuación es:

%p/p = Masa cloruro de calcio (250g)/ Masa solución * 100

Para hallar la masa de la solución debemos usar el volumen y la densidad de este:

1500mL * (1,2g / mL) = 1800g

Así, el %p/p será:

250g / 1800g * 100

The molecular mass of acetylsalicylic acid (HOOC-C6H4-OOCCH3) is 180.157 g/mol.What is molecular mass Molecular mass is the sum of the masses of all the atoms in a molecule. The unit of molecular mass is grams per mole the are (g/mol).Acetylsalicylic acid molecular

mass calculation In acetylsalicylic acid, HOOC-C6H4-OOCCH3, add the mass of each atom:Oxygen (O) = 2 x 16.00 g/mol = 32.00 g/ (C) = 9 x 12.01 g/mol = 108.09 g/mol Hydrogen (H) = 8 x 1.01 g/mol = 8.08 g/molAdd the masses of all the atoms to calculate the molecular mass:32.00 g/mol + 108.09 g/mol + 8.08 g/mol = 148.17 g/molThe molecular mass of acetylsalicylic acid is 180.157 g/mol (approximately)

Molecular mass is the mass of a molecule measured in atomic mass units (amu). The molecular mass is the sum of the atomic masses of all the atoms present in the molecule.The molecular mass formula can be written as: Molecular mass = (mass of first element × number of atoms) + (mass of second element × number of atoms) + ...The molecular mass of acetylsalicylic acid (HOOC-C6H4-OOCCH3) can be calculated by adding the mass of each atom. Here's how to calculate the molecular mass of acetylsalicylic acid:Oxygen (O) = 2 x 16.00 g/mol = 32.00 g/molCarbon (C) = 9 x 12.01 g/mol = 108.09 g/molHydrogen (H) = 8 x 1.01 g/mol = 8.08 g/molAdd the masses of all the atoms to calculate the molecular mass:32.00 g/mol + 108.09 g/mol + 8.08 g/mol = 148.17 g/molThe molecular mass of acetylsalicylic acid is 180.157 g/mol (approximately) the formula to calculate molecular mass.

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There are 5.50 equivalents of Mg^2+ present in a solution containing 2.75 mol of Mg^2+.

The concept of equivalents is used to quantify the number of reactive entities or charges present in a solution. In the case of Mg^2+, each Mg^2+ ion carries two positive charges, so it is necessary to determine the number of moles of Mg^2+ and then convert it to equivalents.

Given:

Number of moles of Mg^2+ = 2.75 mol

To calculate the equivalents, we use the relationship that one mole of Mg^2+ is equal to 2 equivalents of Mg^2+ (since each Mg^2+ ion carries two positive charges):

Equivalents of Mg^2+ = Number of moles of Mg^2+ * 2

Equivalents of Mg^2+ = 2.75 mol * 2

Equivalents of Mg^2+ = 5.50 equivalents

Therefore, in a solution containing 2.75 mol of Mg^2+, there are 5.50 equivalents of Mg^2+ present.

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Answer:

CH3CH2CH3

(CH3)3CLi

CH3SNa

Explanation:

Answer:

[tex]C=0.91\frac{J}{g\°C}[/tex]

Explanation:

Hello there!

In this case, according to the given information, it is possible to recall the equation to calculate the heat, Q, in these calorimetry problems as shown below:

[tex]Q=mC(T_f-T_i)[/tex]

Thus, given the absorbed heat, mass and temperatures, we can easily calculate the specific heat of the metal as shown below:

[tex]C=\frac{Q}{m(T_f-T_i)}[/tex]

Then, by plugging in we obtain:

[tex]C=\frac{1350J}{55.0g(47.0\°C-20.0\°C)} \\\\C=0.91\frac{J}{g\°C}[/tex]

Best regards!

Answer:

mushrooms bacteria mold

Explanation:

The mass (in grams) of solute in 500 mL of 0.179 M potassium hydroxide, KOH solution is 5.02 grams (option A)

First, we shall obtain the mole of KOH in the solution. Details below:

Mole of solute = molarity × volume

Mole of KOH = 0.179 × 0.5

Mole of KOH = 0.0895 mole

Finally, we shall determine the mass of solute, KOH in the solution. Details below:

Mass = Mole × molar mass

Mass of KOH = 0.0895 × 56

Mass of KOH = 5.02 grams

Therefore, the mass of KOH present in the solution is 5.02 grams (option A)

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Answer:

Argon

Explanation:

Because, it is positioned down on the periodic table

Answer:

Argon

Explanation:

Recall the heat capacity equation:

q = mc∆T

We're given mass, specific heat capacity, as well as the change in temperature. All we need to do is plug the numbers into the variables and we'll have our answer!

Although this question doesn't try to trick you, more often than not questions regarding energy change will attempt to throw you off with specific heat capacity. It's extremely important to note the units of the specific heat capacity and ensure that the numbers you use are in those units. As an example, the specific heat capacity might be given to you in J/mol*K - in this case, you'd have to do some unit conversions with your given data in order to fit all the numbers. In this question, we're given the specific heat capacity in J/gºC, so we don't need to change anything since all of our data is already in these units.

Anyways, back to the actual question:

q = mc∆T

q = (8.50 * [tex]10^{2}[/tex]) * (0.900) * (94.6 - 22.8)

q = 54927 (J)

Remeber to include significant figures:

54927 = 5.49 * 10^4 (J)

The required energy is 5.49 * [tex]10^{4}[/tex] Joules, or 5.49 * [tex]10^{1}[/tex] kJ

Let me know if you need any of my work to be explained!

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There are approximately 0.689 moles of krypton in the gas tank.

To determine the number of moles of krypton in the gas tank, we can use the ideal gas law equation:

PV = nRT

Where:

P = pressure (in bar)

V = volume (in liters)

n = number of moles

R = ideal gas constant (0.0831 L·bar/(mol·K))

T = temperature (in Kelvin)

Given:

Pressure (P) = 5.80 bar

Volume (V) = 3.25 liters

Temperature (T) = 25.5 °C = 25.5 + 273.15 = 298.65 K

Using the ideal gas law equation, we can solve for the number of moles (n):

n = PV / RT

n = (5.80 bar * 3.25 L) / (0.0831 L·bar/(mol·K) * 298.65 K)

n ≈ 0.689 moles

Therefore, there are approximately 0.689 moles of krypton in the gas tank.

If the gas in the tank were oxygen instead of krypton, the answer would change because the molar mass of oxygen is different from that of krypton. The ideal gas law equation remains the same, but the value of n (number of moles) would be different since it depends on the molar mass of the gas. Oxygen has a molar mass of approximately 32 g/mol, while krypton has a molar mass of approximately 84 g/mol. So, the number of moles of oxygen in the gas tank would be different and can be calculated using the same ideal gas law equation, but substituting the molar mass of oxygen instead of krypton.

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tip

this is just a tip not the true answer but try to add the given number

Answer:

This regulatory mechanism is in conjunction with the endocrine system, particularly in the posterior pituitary gland. This is related in the secretion of vasopressin or antidiuretic hormone (ADH). In the event of dehydration or extreme thirst, the body will conserve as much fluid as possible and the posterior pituitary will secrete more ADH that will signal the kidney to reabsorb more water in the collecting tubules.

The reason behind the most absorbance when the solution and beam colors are different is due to the absorption spectrum.

The absorption spectrum is the range of electromagnetic radiation that a substance can absorb, and it's unique to every substance. When a beam of light passes through a substance, the substance's molecules absorb some of the light's energy.

This means that some of the light is lost, and the rest is transmitted. The amount of energy absorbed by the substance is dependent on the wavelength of the light and the substance's properties.The color of a substance is due to its ability to absorb some wavelengths of light and reflect others.

For example, a blue object reflects blue light and absorbs all other colors of light. When a blue solution is exposed to a beam of orange light, the blue solution will absorb the orange light, causing the solution to appear darker and resulting in high absorbance.

This phenomenon is known as complementary colors and is seen when a solution and a beam of light are different colors, leading to high absorbance of light.

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it should be carbon dioxide and water

A chemical equation must balance according to the rule of conservation of mass. According to the rule, mass cannot be generated or removed during a chemical process. The number of moles of hydroxide ions in the given balanced equation is 2.

A chemical equation is said to be balanced if the quantity of each type of atom in the reaction is the same on both the reactant and product sides. In a balanced chemical equation, the mass and charge are both equal.

The numbers which are used to balance the given chemical equation are known as the coefficients.

Here the balanced equation is:

2NO₃⁻(aq) + 3ClO⁻(aq) + H₂O(l) → 2NO(g) + 3ClO₂⁻(aq) + 2OH⁻(aq)

The moles of OH⁻ required is 2.

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Answer:

The final balanced equation is : 2C2H2+5O2→4CO2+2H2O.

Answer:

May be the instrument is incorrect or may be error in it.

Explanation:

The copper have not been detected by this test because the test may be not for the detection of copper, may be it is used for identification of another minerals. If there is copper in the lake sample but can't be detected in the test so it means that the instrument which is used for detection is not the right one  or having error in that instrument. Every mineral has a specific type of instrument that detect its presence, if we use incorrect instrument for the mineral then we can't detect the presence of that specific mineral.

The mole fraction of water in the solution is 0.62.

To calculate the mole fraction of water in the solution, we need to determine the moles of water and methanol present.

Mass of water = 140 g

Mass of methanol = 91 g

Molar mass of water (H2O) = 18.015 g/mol

Molar mass of methanol (CH3OH) = 32.04 g/mol

Step 1: Calculate the number of moles of water and methanol.

Moles of water = Mass of water / Molar mass of water

Moles of water = 140 g / 18.015 g/mol ≈ 7.773 mol

Moles of methanol = Mass of methanol / Molar mass of methanol

Moles of methanol = 91 g / 32.04 g/mol ≈ 2.840 mol

Step 2: Calculate the total moles of the solution.

Total moles = Moles of water + Moles of methanol

Total moles = 7.773 mol + 2.840 mol = 10.613 mol

Step 3: Calculate the mole fraction of water.

Mole fraction of water = Moles of water / Total moles

Mole fraction of water = 7.773 mol / 10.613 mol ≈ 0.732

The mole fraction of water in the solution is approximately 0.732.

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The linear atomic density in atoms per millimeter can be calculated for different crystallographic directions in bcc tantalum, which has a lattice constant of 0.33026 nm. The linear atomic density for the [100], [110], and [111] directions can be determined by dividing the number of atoms along the direction by the length of the direction.

The linear atomic density in atoms per millimeter can be calculated by dividing the number of atoms along a specific crystallographic direction by the length of that direction. In bcc (body-centered cubic) crystals, there are specific arrangements of atoms along different crystallographic directions.

(a) For the [100] direction, there is one atom per unit cell. The length of the [100] direction can be determined using the lattice constant, which is 0.33026 nm. Therefore, the linear atomic density for the [100] direction is 1 atom / (0.33026 nm) = 3.027 atoms/nm or 30.27 atoms/mm.

(b) For the [110] direction, there are two atoms per unit cell. The length of the [110] direction can be calculated by multiplying the lattice constant by the square root of 2. Therefore, the linear atomic density for the [110] direction is 2 atoms / (0.33026 nm √2) = 6.054 atoms/nm or 60.54 atoms/mm.

(c) For the [111] direction, there are three atoms per unit cell. The length of the [111] direction can be calculated by multiplying the lattice constant by the square root of 3. Therefore, the linear atomic density for the [111] direction is 3 atoms / (0.33026 nm √3) = 9.090 atoms/nm or 90.90 atoms/mm.

Thus, the linear atomic density in atoms per millimeter for the [100], [110], and [111] directions in bcc tantalum are approximately 30.27 atoms/mm, 60.54 atoms/mm, and 90.90 atoms/mm, respectively.

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