Answer:
the answer would be, 355000 mm/s.
The density of gold is 19.3 grams per milliliter. What would that be in pounds per cup?
Answer:
[tex]\rho =10.07\frac{lb}{cup}[/tex]
Explanation:
Hello,
In this case, given that 1 cup equals 236.588 mL and 1 pound equals 453.6 g, the required density in pounds per cup turns out:
[tex]\rho =19.3\frac{19.3g}{mL}*\frac{1lb}{453.6g}*\frac{236.588mL}{1cup}\\ \\\rho =10.07\frac{lb}{cup}[/tex]
Best regards.
What type(s) of intermolecular forces are expected between PF2Cl3 molecules?a. dispersion.b. dipole-dipole.c. ion-ion.d. hydrogen bonding.
Answer:
dispersion.
Explanation:
The molecule, PF2Cl3 is trigonal bipyramidal. The dipoles in the molecule cancel out since there is a symmetric charge distribution around the molecule hence the resultant dipole moment of the molecule is zero.
If the molecule is nonpolar, then the dominant intermolecular forces present are the weak dispersion forces, hence the answer above.
What is the symbol for the ion that contains 12 protons, 10 electrons, and 12 neutrons?
A 30ml sample of a liquid has a mass of 50 grams. What is the density of the liquid?
Answer:
Density = 1.67 g/mLExplanation:
The density of a substance can be found by using the formula
[tex]Density = \frac{mass}{volume} [/tex]
From the question
mass = 50 g
volume = 30 mL
Substitute the values into the above formula and solve for the density
That's
[tex]Density = \frac{50}{30} \\ = \frac{5}{3} \\ = 1.66666...[/tex]
Wr have the final answer as
Density = 1.67 g/mLHope this helps you
Storing sugar as long chains for later use is an example of a(n) ____________ chemical reaction.
Answer:
Endothermic
Explanation:
Storing sugar for later use is an example of an endothermic reaction because that energy is being absorbed.
A medium-sized banana (118g) on average contains 422 mg of potassium - a nutrient needed to maintain fluid balance. If someone eats a medium-sized banana each day for a week, how many total grams of potassium are ingested in that week?
Answer:
2.954grams of pottasium for that week
Explanation:
According to this question, a medium-sized that weighs 118grams contains 422 milligrams (mg) of potassium nutrient.
If someone eats a medium-sized banana each day for a week, this means that the person has consumed 422mg of pottasium that day.
Since there are 7days in a week, the person will consume 422 × 7 = 2954 mg of pottasium that week.
The question asks for the total pottasium intake in grams for that week, hence, we need to convert 2954 milligrams to grams.
1000mg = 1 g
Hence, 2954mg will be 2954/1000
= 2.954grams
Therefore, 2.954grams of pottasium are ingested by that person that week.
What is the edge length of a face-centered cubic unit cell made up of atoms having a radius of 175 pm
Answer:
495 pm (see the relationship between the edge length (a) and radius (r) of atoms in attachment).
Explanation:
A crystalline solid possess rigid and long-range order; its atoms, molecules, or ions occupy specific positions. A unit cell is the basic repeating structural unit of a crystalline solid. Each sphere in the unit cell represents an atom, ion, or molecule and is called a lattice point. The way the spheres are arranged in layers determines what type of unit cell we have.
In the face-centered cubic cell, there are spheres at the center of each of the six faces of the cube, in addition to the eight corner spheres (see the second picture in the attachment). Each sphere in this arrangement is said to have a coordination number of 12 since each sphere is in contact with six spheres in its own layer, three spheres in the layer above, and three spheres in the layer below. The coordination number is defined as the number of atoms (or ions) surrounding an atom (or ion) in a crystal lattice.
In the first picture in the attachment we can see that the relationship between the atomic radius r and the edge length a face-centered cubic cell is:
a=√8*r
Therefore, the edge length will be √8*175 pm = 495 pm
FCC Stands for Face Centered Cubic
It is a type of atomic arrangement and is relatively "tightly" packed.FCC is formally defined as a cubic lattice with the face positions fully equivalent to each of the eight corners.This unit cell uses 14 atoms, eight of which are corner atoms (forming the cube) with the other six in the center of each of the faces.The formula that is used to find edge length is:
[tex]a=\sqrt{8}*r[/tex]
where
a= edge length
r= radius
Given:
r= 175 pm
Substituting the values in the above formula.
[tex]a=\sqrt{8}*175\\\\a=495 pm[/tex]
Therefore, the edge length will be 495 pm.
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If under a given set of conditions the reaction A → B occurs with ΔG = -14 kJ/mol, and the reaction C→ B occurs with ΔG =- 16 kJ/mol, then:_______ a. Conversion of A to C is exergonic. b. A and C can never be at equilibrium, even under different reaction conditions. c. Oconversion of A to C is entropically driven. d. Conversion of C to A is freely reversible.
Answer:
a. Conversion of A to C is exergonic.
Explanation:
In the problem: C→ B occurs with ΔG = + 16 kJ/mol
It is possible to sum ΔG of reactions to obtain ΔG of another related reaction:
A → B ΔG = -14kJ/mol
C → B ΔG = +16kJ/mol
A → C ΔG = -14kJ/mol - (+16kJ/mol) = -30kJ/mol
As ΔG < 0
The reaction is exergonic
Under these condition, the reaction occurs. But under another conditions, the reaction will be at equilibrium (ΔG = 0)
A reaction is entropically driven if ΔG < 0 and ΔS is high. But we don't have information of ΔS.
As ΔG <0, the reaction is not spontaneous in the reverse direction
Right option is:
a. Conversion of A to C is exergonic.First two drop down menus choices:
1. treasury
2. ionic
3. matrimonial
4. covalent
Third drop down menu choices:
1. 40kJ/mol
2. 4000kJ/mol
3. 400kJ/mol
4. 40000kJ/mol
What are likely formulas for the following molecules?
A) NH?OH.
B) AlCl?.
C) CF2Cl?.
D) CH?O.
Answer:
a
Explanation:
a the answers you welcome
The likely formulas for the molecules are NH₄OH, AlCl₃, CF₂Cl₂, CH₃O.
What is molecule ?According to the context, the term may or may not include ions that meet this requirement. A molecule is a collection of two or more atoms held together by the attractive forces known as chemical bonds.
A molecule is the smallest unit of any material that is composed of one or more elements and is capable of existing independently while maintaining all the substance's physical and chemical properties. Further atom division occurs within molecules. For instance, the symbols for the oxygen atom and molecule are O and O2, respectively.
The smallest identifiable unit into which a pure substance may be divided while retaining its composition and chemical properties is a molecule, which is a collection of two or more atoms.
Thus, The likely formulas for the molecules are NH₄OH, AlCl₃, CF₂Cl₂, CH₃O.
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1. If a student needed to calculate the density of irregularly shaped metal beads give a brief explanation of the best way to do so with a graduated cylinder, water and a balance.2. Using the method described above, calculate the density of a quantity of copper beads. The initial volume of the graduated cylinder with water was 35 ml, the volume of the water plus the beads 40.7 ml and the mass of the beads 50.217 g. What is the density of the beads and what is the percent error.
Answer:
See explanation
Explanation:
The density of an irregular object can be determined using a graduated cylinder, water and a balance as follows.
The irregularly shaped object is weighed in a balance and its mass is recorded. The graduated cylinder is then filled with a given volume of water. This volume of water is also recorded. The irregularly shaped object is then introduced into the graduated cylinder containing the water and the change in volume of the water is recorded.
Volume of the object= change in volume of the water
Density= mass/volume
b)
If the beads weigh 50.217 g
Volume of beads = change in volume of water= 40.7 ml - 35.0ml = 5.7 ml
Density= mass/volume = 50.217 g/5.7 ml = 8.81 g/ml
Accepted value of the density of copper in g/ml = 8.94 g/ml
% error in density = |8.81-8.94|/8.94 ×100
% error in density = 1.45%
What is 1.5 converted
Answer:
3/5
Explanation:
A waste treatment pond is 50 m long and 25 m wide, and has an average depth of 2 m. The density of the waste is 75.3lbm/ft^3 .Calculate the weight of the pond contents in lbf ,using single dimensional equation for your calculation.
Answer:
[tex]W = 6.65 \cdot 10^{6} lbf[/tex]
Explanation:
To find the weight (W) of the pond contents first we need to use the following equation:
[tex] W = m\cdot g [/tex] (1)
Where m the mass and g is the gravity
Also, we have that the mass is:
[tex]m = \rho*V[/tex] (2)
Where ρ is the density and V the volume
We cand calculate the volume as follows:
[tex] V = L*w*d [/tex] (3)
Where L is the length, w is the wide and d is the depth
By entering equation (2) and (3) into (1) we have:
[tex]W = \rho*L*w*d*g[/tex]
[tex] W = 75.3 lbm/ft^{3}*50 m*25 m*2 m*9.81 m/s^{2} [/tex]
[tex]W = 75.3 lbm/ft^{3}*\frac{(1 ft)^{3}}{(0.3048 m)^{3}}*\frac{0.454 kg}{1 lbm}*50 m*25 m*2 m*9.81 m/s^{2} = 2.96 \cdot 10^{7} N}*\frac{0.2248 lbf}{1 N} = 6.65\cdot 10^{6} lbf[/tex]
Therefore, the weight of the pond is 6.65x10⁶ lbf.
I hope it helps you!
Determine the number of moles of the compound and determine the number of moles of each type of atom in
each of the following:
(a) 2.12 g of potassium bromide, KBr
(b) 0.1488 g of phosphoric acid, H3PO4
(c) 23 kg of calcium carbonate, CaCO3
(d) 78.452 g of aluminum sulfate, Al2(SO4)3
(e) 0.1250 mg of caffeine, C8H10N4O2
Answer:
a. 0.0178 moles of KBr
0.0178 moles of K
0.0178 moles of Br
b. 1.52×10⁻³ moles of acid
4.55×10⁻³ moles of H
1.52×10⁻³ moles of P
6.07×10⁻³ moles of O
c. 229.8 moles of calcium carbonate
229.8 moles of Ca
229.8 moles of C
689.4 moles of O
d. 0.229 moles of aluminum sulfate
0.458 moles of Al
0.687 moles of S
2.75 moles of O
e. 6.43×10⁻⁷ moles of C₈H₁₀N₄O₂
5.14×10⁻⁶ moles of C
6.43×10⁻⁶ moles of H
2.57×10⁻⁶ moles of N
1.28×10⁻⁶ moles of O
Explanation:
To determine the moles of each compound we need to know the molar mass of them
Subscripts number of compounds are the number of moles, of each atoms.
For example, H₂O. 1 mol of water has 2 moles of H and 1 mol of O.
a. KBr → 119 g/mol
We convert the mass to moles (mass/molar mass)
2.12 g / 119 g/mol = 0.0178 moles of bromide
1 mol of potassium bromide has 1 mol of K and 1 mol of Br, then 0.0178 moles of salt, will have:
0.0178 moles of K
0.0178 moles of Br
b. H₃PO₄ → 97.97 g/mol
0.1488 g / 97.97 g/mol = 1.52×10⁻³ moles of acid.
1 mol of phosphoric acid has 3 moles of H, 1 mol of P and 4 moles of O
Then 1.52×10⁻³ moles of acid. will have:
(1.52×10⁻³ . 3) / 1 = 4.55×10⁻³ moles of H
1.52×10⁻³ moles of P
(1.52×10⁻³ . 4) / 1 = 6.07×10⁻³ moles of O
c. CaCO₃ → 100.08 g/mol
23000g / 100.08 g/mol = 229.8 moles
(notice, we convert the kg to g, before)
1 mol of calcium carbonate has 1 mol of Ca, 1 mol of C and 3 moles of O
Then 229.8 moles of salt will have
229.8 moles of Ca
229.8 moles of C
(229.8 . 3) / 1 = 689.4 moles of O
d. Al₂(SO₄)₃ → 342.15 g/mol
78.452 g / 342.15 g/mol = 0.229 moles
1 mol of Al₂(SO₄)₃ has 2 moles of Al, 3 moles of S and 12 moles of O
Then 0.229 moles of sulfate will have:
(0.229 . 2) / 1 = 0.458 moles of Al
(0.229 . 3) / 1 = 0.687 moles of S
(0.229 . 12) / 1 = 2.75 moles of O
e. C₈H₁₀N₄O₂ → 194.19 g/mol
0.0001250 g / 194.19 g/mol = 6.43×10⁻⁷ moles
(Notice, we convert mg to g)
1 mol of caffeine has 8 moles of C, 10 moles of H, 4 moles of N and 2 moles of O
Then, 6.43×10⁻⁷ moles of caffeine will have:
(6.43×10⁻⁷ . 5) / 1 = 5.14×10⁻⁶ moles of C
(6.43×10⁻⁷ . 10) / 1 = 6.43×10⁻⁶ moles of H
(6.43×10⁻⁷ . 4)/1 = 2.57×10⁻⁶ moles of N
(6.43×10⁻⁷ . 2)/ 1 = 1.28×10⁻⁶ moles of O
What problem would a human have if the nucleric acid in a cell was damaged
Answer:
a human mat not be able to reproduce
Explanation:
i think this is right
The density of tin is 5.75 g/cm3. What is the mass of object 1 in kg if the rectangular block has a volume of 1.3 L?
Answer:
m=7.475 kg
Explanation:
Given that,
The density of tin is 5.75 g/cm³.
We need to find the mass of the object if the volume of the rectangular block is 1.3 L.
We know that,
1 L = 1000 cm³
1.3 L=1300 cm³
The formula of density,
[tex]\rho=\dfrac{m}{V}\\\\m=\rho\times V[/tex]
[tex]m=5.75\ g/cm^3\times 1300\ cm^3\\\\\m=7475\ g[/tex]
or
m=7.475 kg
So, the mass off the object is 7.475 kg.
Translate each number into standard notation, maintaining the same number of significant figures.a. 1.72x10^3b. 9.07x10^-2
Answer:
a. 1720.
b. 0.0907.
Explanation:
Hello,
In this case, when translating scientific notation to standard notation one should move the decimal place the times the power indicates, that is for a, three places to the right (add zeros to complete it) and for b, two places to the left, therefore, we obtain:
a. 1720.
b. 0.0907.
Best regards.
Do ions with more valence electrons become stable?
Answer:
yes!!!!!!!!!!
Explanation:
now go learn son
Place the following elements in order of decreasing ionization energy. Their elemental symbols will be listed
below,
Barlum (Ba), Neon (Ne), Calcium (Ca), and Bromine (Br)
A. Ne, Br, Ca, Ba
B. Ne, Ca, Br, Ba
C. Ba, Ca, Br. Ne
D. Ba, Br, Ca, Ne
Answer:
A. Ne, Br, Ca, Ba
Explanation:
Ionization energy is the minimum amount of energy required to remove n electron from an atom.
The general trend is increase in moving from left to right across periods in the periodic table and decreasing down the group.
Barium, Ba belongs to period 6, so it is expected to have the lowest ionization energy.
Neon, Ne belongs to period 2, it would have the highest ionization energy.
Calcium, Ca and Bromine, Br both belongs to the same period, however bromine is in group 7, bromine would have the higher ionization energy.
Inorder of decreasing ionzation enrgy;
Ne, Br, Ca, Ba
A 1-L soda bottle contains dissolved carbon dioxide gas. Which bottle would have the highest concentration of dissolved gas? a bottle that is sealed a bottle that was opened 1 minute ago a bottle that was opened 1 hour ago a bottle that was opened 1 day ago
Answer: The correct answer would be : "A bottle that is sealed".
I hope that this helps you !
A 1-L soda bottle contains dissolved carbon dioxide gas then the bottle which have the highest concentration of dissolved gas is a bottle that is sealed.
Why carbon dioxide is present in soda?Carbon dioxide is easily dissolved in water or soda to make tiny bubbles and it prevents the growth of bacteria during the preservation of sodas.
This dissolved carbon dioxide gas coming out in the form of effervescence when we open a bottle of soda. So, in the sealed bottle of soda higher concentration of dissolved carbon dioxide gas is present. And if we open the seal then the amount of dissolved carbon dioxide decreases from the bottle.
Hence option (A) is correct.
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Covalent bonding is important between atoms of biological molecules, but other factors are important for self-assembly. For example, hydrogen bonds between base-pairs in DNA hold the two strands together. Complete the sentences describing the general principles regarding how groups or molecules interact.
Match the words in the left column to the appropriate blanks in the sentences on the right.
1. When deciding which side of a biomolecule would orient itself toward the water in cytoplasm, the groups would be directed toward the water.
a. molecules.
b. polar
nonpolar
2. When deciding which biomolecules would interact with a hydrocarbon chain, the portions of a biomolecule would orient themselves toward the c.
c. chain
d. carbon
repelled by
3. Polar groups in biomolecules are often characterized by functional groups containing elements such
e. attracted to
f. nitrogen
4. Nonpolar groups in biomolecules are often characterized by functional groups containing the element
5. When looking at ionizable groups, two ions of the same charge, such as two cations, are each other while two ions of the opposite charge, such as one cation and one anion each other.
Answer:
1. Polar
2 nonpolar
3. Nitrogen or oxygen
4.carbon
5.Repelled by and attracted to
SO2 can act as both oxidising and reducing agent
Answer:
No, it acts only as a reducing agent
Explanation:
Sulphur dioxide is a strong reducing agent. It is mainly used to prevent dried fruit from being oxidised and discoloured.
In one to two sentences, explain a similarity and a difference between the particles in liquid water at 100ºC and the particles in steam at 100ºC. PLEASSSSSSSSSSSSSSSE HELPPPPPPPPPPPPPPP ASAPPPPPPPPPP........................
WOW! I have the same question! Again lol.
A similarity is that both are at the same temperature and a difference is both are at different states of matter between the particles in liquid water at 100ºC and the particles in steam at 100ºC.
What are states of matter?There are only 3 states in which matter is present in the universe that is solid, liquid and gas, and on the basis of molecular space, they are differentiated in their respective category.
The water present both at 100ºC first is in a liquid state where molecules of water are more close as compared to the molecules of the steam water but the temperature for both is the same.
Therefore, the similarity is that both are at the same temperature and a difference is both are at different states of matter between the particles in liquid water at 100ºC and the particles in steam at 100ºC.
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A cylinder container can hold 2.45 L of water. It’s radius is 4.00 cm. What is the volume of it in cubic centimeters?
Answer:
2450 cm3
Explanation:
Volume of cylinder = V=πr2h
2.45L = 2450mL
1mL = 1 cm cubed
2450mL = 2450 cm cubed
The volume of the cylinder container in cubic centimeters is 2.45 × 10³ cm³.
We usually can find the volume of a cylinder applying the following expression.
[tex]V = \pi r^{2} h[/tex]
where,
r: radiush: heightSince we don't know the height, we will have to use the information that it can hold 2.45 L of water. We can convert liters to cubic centimeters using the following conversion factors:
1 L = 1000 mL1 mL = 1 cm³[tex]2.45 L \times \frac{1000mL}{1L} \times \frac{1cm^{3} }{1mL} =2.45 \times 10^{3} cm^{3}[/tex]
The volume of the cylinder container in cubic centimeters is 2.45 × 10³ cm³.
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A 10.0 cm3 sample of copper has a mass of 89.6 g. What is the density of copper
Answer:
Density = 8.96 g/cm³Explanation:
The density of a substance can be found by using the formula
[tex]Density = \frac{mass}{volume} [/tex]
From the question
mass of copper = 89.6 g
volume = 10 cm³
Substitute the values into the above formula and solve
That's
[tex]Density = \frac{89.6}{10} [/tex]
We have the final answer as
Density = 8.96 g/cm³Hope this helps you
Write the symbol for every chemical element that has an atomic number less than 13 and atomic mass greater than 19.3 u
Answer:
The symbol of each element is, Ne, Na, Mg, and Al.
Explanation:
Below is the list of elements that has an atomic mass of less than 19.3 u.
The atomic mass of Neon is 20.1797 u and the atomic number is 10.
The atomic mass of Sodium is 22.989769 u and the atomic number is 11.
The atomic mass of Magnesium is 24.305 u and the atomic number is 12.
The atomic mass of Aluminium is 26.981539 u and the atomic number is 13.
Here, the symbol of each element is, Ne, Na, Mg, and Al.
We do we mean when we say a substance is pure
Answer:
ot means that contains only one kind of matter.
Find the volume (in mL) of a substance that has a mass of 11.6 g and a density of 0.81 g/mL. Give your answer with two decimals.
Answer:
14.83mL
Explanation:
11.6/0.81=14.3
If the percent yield for the following reaction is 75.0%, and 40.0 g of NO2 are consumed in the reaction, how many grams of nitric acid, HNO3(aq) are produced? 3 NO2(g) + H2O(l) → 2 HNO3(aq) + NO(g) If the percent yield for the following reaction is 75.0%, and 40.0 g of NO2 are consumed in the reaction, how many grams of nitric acid, HNO3(aq) are produced? 3 NO2(g) + H2O(l) 2 HNO3(aq) + NO(g)
Answer:
[tex]m_{HNO_3}=27.4gHNO_3[/tex]
Explanation:
Hello,
In this case, for the chemical reaction:
[tex]3 NO_2(g) + H_2O(l) \rightarrow 2 HNO_3(aq) + NO(g)[/tex]
The first step is to compute the theoretical yield of nitric acid via stoichiometry in terms of the 3:2 ratio between nitrogen dioxide (molar mass = 46 g/mol) and nitric acid (molar mass = 63 g/mol) respectively:
[tex]m_{HNO_3}^{theoretical}=40.0gNO_2*\frac{1molNO_2}{46gNO_2}* \frac{2molHNO_3}{3molNO_2} *\frac{63gHNO_3}{1molHNO_3} \\\\m_{HNO_3}^{theoretical}=36.52gHNO_3[/tex]
Now, the actual amount is computed by taking into account the 75.0-% percent yield:
[tex]m_{HNO_3}=0.75*36.5gHNO_3\\\\m_{HNO_3}=27.4gHNO_3[/tex]
Best regards.
student desing an experiment to see if the thermo energy is transfer at the same rate in different liquids the students safely heat 2 different room temperatures liquids on a hot plate an measure the temperature after 10 minutes what variable such the student control
Answer:
www.doe.virginia.gov/testing/sol/standards_docs/...
Explanation:
did you get the answer??