Data Tables Practices
Table 1 Information: Allison wanted to find out if the color of soda affected whether her friends would
choose a particular one. She collected the following data:
Orange Soda - 5 friends
Yellow Soda - 7 friends
Green Soda - 2 friends
Clear Soda - 1 friend
Brown Soda - 15 friends
Table 1 Title:
Independent Variable:
Dependent Variable:
Make a data table in this space, include labels for variables and the title:
Page
2
+
/ 5

Answer:

Malleability

Explanation:

Answer:

Malleability is not chemical property

Answer:

There can be error in millimetres.

Explanation:

The rounding off can create errors in exact measurement. There can be errors in the measured value and actual measurement of the object. Alexander has rounded his calculation to nearest centimetre then it is possible he can make errors in millimetre calculations. The measured width of the object will not be the actual measurement and it might differ slightly.

Answer:

When you heat an atom, some of its electrons are "excited* to higher energy levels. When an electron drops from one level to a lower energy level, it emits a quantum of energy. ... The different mix of energy differences for each atom produces different colours. Each metal gives a characteristic flame emission spectrum.

Explanation:

Answer:

The figure is a molecule and a compound

Explanation:

Because it have 2 cluster molecules

Answer:

1. electrons and neutrons protons

2. true

3. electrons are negative and neutrons are neutral

4. true

5. the total number of neutrons and protons

Explanation:

Answer:

a) ²²⁴Ra₈₈ ---> α + ²²⁰Rn₈₆ + Q

b) the Q-value of this reaction is 5.789 MeV

c) the energies (in MeV) of the two associated alpha particles are; 5.69 MeV and 5.449 Mev

Explanation:

a)

The decay equation for the alpha decay is expressed as;

²²⁴Ra₈₈ ---> α + ²²⁰Rn₈₆ + Q

b)

Calculate the Q-value (in MeV) of this reaction.

Q = Mparent - Mdaughter -Mg

Q = MRa - MRn -Mg

= 224.020202 - 220.011384 - 4.00260305

= 0.00621495 amu

= 5.789 MeV

therefore the Q-value of this reaction is 5.789 MeV

c)

Energy of alpha particle is expressed as;

E∝ = MQ / ( m + M)

now this is the maximum energy available for the daughter, ²²⁰Rn going to the ground state;

The energy of the alpha particle gives;

E∝  = 220(5.789) / ( 4 + 220) = 5.69 MeV

as given in the question,The other less frequent alpha occurring 5.5% of the time leaves the daughter nucleus in an excited state of 0.241 MeV above the ground state.

Therefore the energy of this alpha is

E∝ = 5.69 - 0.241 = 5.449 Mev

Therefore the energies (in MeV) of the two associated alpha particles are; 5.69 MeV and 5.449 Mev

d)

Sketch of the nuclear decay scheme have been uploaded along side this answer.

(a)[tex]^{224}Ra_{_{88}}=^4\alpha_{_2}+^{220}Rn_{_{86}}+Q[/tex]

(b) the Q-value of the reaction is 5.789 MeV

(c) The alpha particles have energies of 5.69 MeV and 5.449 MeV

(a) The alpha decay of the radioisotope 224Ra is given by:

         [tex]^{224}Ra_{_{88}}=^4\alpha_{_2}+^{220}Rn_{_{86}}+Q[/tex]

(b) The Q-value  of a reaction is given by:

Q = {mas of reactants - mass of products}c²

[tex]Q = [M_{224Ra} - M_{\alpha} - M_{220Rn}]c^2[/tex]

Q = (224.020202 - 220.011384 - 4.00260305) amu.c²

Q = 0.00621495 × 931.5 MeV   ( since 1 amu.c² = 931.5 MeV)

Q = 5.789 MeV

(c) The energy of the alpha particle is expressed as;

E(α) = MQ / ( m + M)

it is the maximum energy available for the daughter nucleus, ²²⁰Rn going to the ground state.

If the daughter nucleus is at rest then all the energy is carried by the alpha particle.

The energy of the alpha particle is:

E(α)  = 220(5.789) / ( 4 + 220) = 5.69 MeV

Now, for the alpha particle occurring 5.5% of the time and leaving the daughter nucleus in an excited state of 0.241 MeV :

The energy of this alpha particle is

E(α) = 5.69 - 0.241 = 5.449 Mev

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Given :

Three block of same mass name A , B and C .

Sides of block A , B and C is 3.0 cm , 5.0 cm and 10.0 cm .

To Find :

Which block has the higher  density .

Solution :

We know , density [tex]\rho[/tex] is given by :

[tex]\rho=\dfrac{M}{V}[/tex]   ......1 )

Here , V is volume .

Now , volume V for cube is given :

[tex]V=a^3[/tex]    .......2 )

(  Here , a is the side of cube )

Now ,form equation 1 we can see if mass remains constant then density decrease with increase in volume.

Therefore , cube with minimum side will have higher density , in this case it is 3 cm block .

Hence , this is the required solution .

Answer:

B. Chlorine has more than one stable isotope that occurs naturally.

D. As fluorine only has one isotope the atomic mass is identical to the mass of the isotope.

Explanation:

The reason for the difference seen between the atomic mass provided in the periodic table and the atomic mass of each element is that most naturally occurring elements have more than one isotope (isotopes are atoms that have the same atomic number but different mass numbers). This means that when we measure the atomic mass of an element, we must generally settle for the average mass of the naturally occurring mixture of isotopes.

¹⁹F is the only stable isotope of fluorine, and its abundance is 100%. Therefore, its atomic mass is identical to that of the isotope.

On the other hand, chlorine has two stable isotopes ³⁵Cl (75.77%) and ³⁷Cl (24.23%). The atomic mass of  ³⁵Cl has been determined to be 34.96885 amu, and the atomic mass of ³⁷Cl has been determined to be 36.96590 amu. Thus, the average atomic mass  of chlorine can be calculated as follows:

average atomic mass  of natural chlorine = (0.7577)×(34.96885 amu) + (0.2423)×(36.96590 amu)  = 35.45 amu

Note that in calculations involving percentages, we need to convert percentages to  fractions.

Answer:

the average atomic mass in amu of X is 25.39 amu

Explanation:

The computation of the average atomic mass in the amu of X is shown below:

Average mass is

= Product sum + atomic mass of each and every isotope

Now the average mass

= (80.5 ÷ 100 × 25 amu) + (19.5 ÷ 100 × 27 amu)

= 20.125 + 5.265

= 25.39 amu

Hence, the average atomic mass in amu of X is 25.39 amu

The average atomic mass of X is 25.39 amu.

It is the quantity of matter present within an atom of an element.

Based on the given information,

• The unknown element X has the isotopes, 25X (80.5% abundant) and 27X (19.5% abundant).

Now the atomic mass of X can be calculated by using the formula,

[tex]=\frac{(M1*A1)+(M2*A2)}{A1+A2}[/tex]

Here, M1 and M2 are the atomic masses, and A1 and A2 are their  abundances.

Now putting the values we get,

[tex]= \frac{(25*80.5)+(27*19.5)}{80.5+19.5} \\\\= \frac{2012.5+526.5}{100} \\= \frac{2539}{100} \\= 25.39 amu[/tex]

Thus, the average atomic mass of X is 25.39 amu.

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Answer:

[tex]\rho =0.9g/mL[/tex]

Explanation:

Hello,

In this case, due to the volume displacement caused the by the object's submersion, it's volume is:

[tex]V=11.8mL-4.5mL=7.3 mL[/tex]

In such a way, considering the mathematical definition of density, it turns out:

[tex]\rho =\frac{m}{V}=\frac{6.5g}{7.3mL}\\ \\\rho =0.89g/mL[/tex]

Rounding to the nearest tenth we finally obtain:

[tex]\rho =0.9g/mL[/tex]

Regards.

Answer:

Hydronium ion

The conjugate acid of water is the hydronium ion ; [tex]H_3O^+,[/tex]

Explanation:

It is an ion formed by the association of a hydrogen ion with a water molecule.

Answer:

B. Tell the instructor

Explanation:

Always to the instructor about any accidents happens in a lab.

Answer:

B

Explanation:

Just helping out:)

Answer:

- Take 3.3 mL of 3.0-M hydrochloric acid and subsequently add 76.7 mL of water to complete the 100.00 mL.

- Take 11.7mL of 6.0-M hydrochloric acid and subsequently add 88.3 mL of water to complete the 100.00 mL

Explanation:

Hello,

In this case, given that the dilutions are preparedfrom 3.0-M and 6.0-M hydrochloric acid, we must proceed as follows:

- 3.0-M stock: when using this stock, the aliquot you must take is computed as shown below:

[tex]V_1=\frac{M_2V_2}{M_1}=\frac{100.00mL*0.70M}{3.0M}=23.3mL[/tex]

It means that you must take 23.3 mL of 3.0-M hydrochloric acid and subsequently add 76.7 mL of water to complete the 100.00 mL.

- 6.0-M stock: when using this stock, the aliquot you must take is computed as shown below:

[tex]V_1=\frac{M_2V_2}{M_1}=\frac{100.00mL*0.70M}{6.0M}=11.7mL[/tex]

It means that you must take 11.7mL of 6.0-M hydrochloric acid and subsequently add 88.3 mL of water to complete the 100.00 mL.

Regards.

Answer:

Explanation:

A student obtains a clean, dry graduated cylinder. She weighs the cylinder and finds the mass to be 32.64 g. She then fills the cylinder with a certain volume of water. She weighs the water-filled cylinder and finds the total mass to be 61.57 g. If the density of the water in the laboratory is 0.9975 g / mL , what is the volume of the water in the graduated cylinder?

Answer:

Volume of water =29.00mL

Explanation:

mass of cylinder (Mc)=32.64g

mass of water-filled cylinder (Mw+c)=61.57g

mass of water (Mw)= (Mw+c) - (Mc).

=(61.57 - 32.64)g = 28.93g

However:

Density = mass÷volume

hence Volume of water = mass of water÷density of water.

28.93g÷0.9975g/mL = 29.00mL

Answer:

N,N-dimethylacetamide < Methyl acetate < Acetaldehyde

Acetaldehyde - least acidic

Methyl acetate -  acidic

N,N-dimethylacetamide - most acidic

Explanation:

The order of acidity of the organic compound under study is primarily influenced by their resonance effect. The resonance effect explains how polar a particular molecule is from the interaction between pi -bonds or a lone electron pair and a pi-bond in a molecule.

In acetaldehyde popularly known as ethanal, the CH₃CHO functional group -CHO is attached to an adjacent end of the compound, which has a lesser resonance effect than methyl acetate.

Methyl acetate, also known as methyl ethanoate, is an ester family with the formula CH₃COOCH₃ is also lesser in its acidity compared to N,N-dimethylacetamide.

Therefore, the order of acidity from the least acidic to the most is:

N,N-dimethylacetamide < Methyl acetate < Acetaldehyde

Acetaldehyde - least acidic

Methyl acetate - acidic

N,N-dimethylacetamide - most acidic

Answer:

The reaction is endothermic.

Yes, absorbed

3.06x10¹kJ are absorbed

Explanation:

In the reaction:

2HgO(s) → 2Hg(l) + O₂(g) ΔH = 182kJ

As ΔH >0,

The reaction is endothermic

As the reaction is endothermic, when the reaction occurs,

the heat is absorbed.

Now, based on the equation, when 2 moles of HgO (Molar mass: 216.59g/mol), 182kJ are absorbed.

72.8g are:

72.8g * (1mol / 216.59g) = 0.3361 moles HgO.

that absorb:

0.3361 moles HgO * (182kJ / 2 moles) =

Answer:

the scientific study of matter i believe

Explanation:

because the definition says the branch of science that deals with the identification of the substances of which matter is composed

Answer:

When the cube was placed in the water, the volume of the water changed. When the liquid was poured from the bowl, the shape changed.

Explanation:

When a cube is placed inside water, the volume of the water will change due to the introduction of the cube as the cube will displace some water. Remember that the shape of a liquid is the shape of its container so the shape of the water remains the same.

When the water is poured into a glass, its shape changes as it now assumes the shape of the glass as explained above.

Answer: When the cube was placed in the water, the shape of the cube stays the same. When the liquid was poured from the bowl into the glass, the shape changed

Explanation:

Answer:

You may assume that the same metal is used in each situation. Light is emitted by electrons when they drop from one energy level to a lower level.

Answer:

The numeric value is 1.

Explanation:

We have given that the “a” equal to “b” which means we can replace the “a” with “b” or we can replace the “b” with “a”.  

The given condition or quantity = a/b.

Now it is required to find the numeric value of a/b.  

To find the numeric value we first replace the “b” with “a” and then divide the values. Since we know that if the numeration and denominators are the same then after dividing the value, the resulting value will be 1.

The numerical value = a/b = a/a = 1

Answer:

b

Explanation:

Answer:

319.8 m/min

Explanation:

533 cm/s

We can convert 533 cm/s to m/min by doing the following:

First, we shall convert 533 cm/s to m/s. This can be obtained as illustrated below:

Recall:

100 cm/s = 1 m/s

Therefore,

533 cm/s = 533 cm/s /100 cm/s × 1 m/s

533 cm/s = 5.33 m/s

Finally, we shall convert 5.33 m/s to m/min. This can be obtained as follow:

1 m/s = 60 m/min

Therefore,

5.33 m/s = 5.33 m/s / 1 m/s × 60 m/min

5.33 m/s = 319.8 m/min

Therefore, 533 cm/s is equivalent to 319.8 m/min

Answer:

See explanation

Explanation:

a) A large value of K shows that the reaction is product favoured. It implies that more reactants are converted to products and the equilibrium concentration of products in the system is far higher than that of the reactants. The reaction will proceed towards the right hand side.

b)A small value of K implies that the reaction is reactant favoured. There are more reactants than products present at equilibrium and the reaction will proceed towards the lefthand side.

c) K=1 implies the presence of a significant concentration of reactants and products in the system at equilibrium.

Answer:

True

Explanation: Imagine the Electrons is by the nucleus which give more energy.

Answer:

A. 40N

Explanation:

Answer:

An energy transformation is the change of energy from one form to another. Energy transformations occur everywhere every second of the day. There are many different forms of energy such as electrical, thermal, nuclear, mechanical, electromagnetic, sound, and chemical.

Explanation:

it should be option A. H

[ because H gained oxygen ( O ) ]

Oxidation is defined by :

- the loss of electrons

- the loss of hydrogen ( H )

- the gain of oxygen ( O )

- increase in oxidation state

Reduction is defined by :

- the gain of electrons

- the gain of hydrogen ( H )

- the loss of oxygen ( O )

- decrease in oxidation state

(Basically, oxidation n reduction is opposite of each other)

The species being oxidized in the following reaction is Carbon Dioxide (CO2). This can be determined by looking at the oxidation states of the reactants and products.

In the reactants, Carbon Dioxide (CO2) has an oxidation state of +4, while Hydrogen (H2) has an oxidation state of 0. In the products, Carbon (CO) has an oxidation state of +2, and Water (H2O) has an oxidation state of -2.

The net change in oxidation states between the reactants and products is a decrease of 6, which means that the species that was being oxidized is Carbon Dioxide (CO2). The oxidation state of a species can be determined by looking at the number of electrons it has gained or lost in a reaction.

In this reaction, Carbon Dioxide (CO2) has lost 6 electrons, which is a sign that it is the species being oxidized. This is further evidenced by the fact that Carbon (CO) and Water (H2O) have gained electrons, meaning that they are the species being reduced. Therefore, the species being oxidized in the following reaction is Carbon Dioxide (CO2).

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Answer: The mass number is the sum of the numbers of protons and neutrons present in the nucleus of an atom.

I hope that this helps you !

Answer:

hydrogen dioxide

Explanation:

Hydrogen dioxide  is the name of the binary molecule H2O2 ,therefore option (b) is correct from the image below.

A thick, colorless liquid, H2O2, resembling water, but having a bitter, sour taste, produced by the action of acids on barium peroxide.

It decomposes into water and oxygen, and is manufactured in large quantities for an oxidizing and bleaching agent. Called also oxygenated water.

A colorless, unstable compound of hydrogen and oxygen (H 2 O 2). It is used as an antiseptic and bleaching agent.

Hydrogen dioxide  is the name of the binary molecule H2O2 ,hence option (b) is correct from the image below.

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