Find f(-5) and f(12) for each piecewise function f(x){-4x+3 if x<3
{-x^3 If 3<_x<_8
{3x^2+1 If x>8
The lines go under the inequality lol but please help !

Answers

Answer 1
Answers:f(-5) = 23f(12) = 433

==================================================

Explanation:

The given piecewise function is

[tex]f(x) = \begin{cases}-4x+3 \ \text{ if } \ x < 3\\-x^3 \ \text{ if } \ 3 \le x \le 8\\3x^2+1 \ \text{ if } \ x > 8\end{cases}[/tex]

At first piecewise functions may be strange confusing things, but they aren't so bad. I like to think of it like this: f(x) is a function that changes its identity based on what the input x is. We have three situations

f(x) = -4x+3 when x < 3f(x) = -x^3 when [tex]3 \le x \le 8[/tex]f(x) = 3x^2+1 when x > 8

In a sense, we have three different functions but they are combined somehow.

If x is smaller than 3, then we go for the first definition. Or if x is between 3 and 8, then we go for the second definition. Or if x is larger than 8, then we go for the third definition.

-----------------------

f(-5) means f(x) when x = -5. We see that -5 is smaller than 3, so x = -5 makes x < 3 true. We'll use the first definition

f(x) = -4x+3

f(-5) = -4(-5)+3

f(-5) = 20+3

f(-5) = 23

------------------------

Now the input is x = 12. This is larger than 8. In other words, x = 12 makes x > 8 true. We'll use the third definition

f(x) = 3x^2+1

f(12) = 3(12)^2+1

f(12) = 3(144)+1

f(12) = 432+1

f(12) = 433

------------------------

Side notes:

We won't use the second definition since we don't have any x inputs between 3 and 8To say "less than or equal to" on a keyboard, you can write "<=" without quotes. For example, [tex]x \le 5[/tex] is the same as x<=5

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Answer:

Ok amigo, entonces es falso porque los miles son 5 ahora, la parte 25 está en la marca de diez mil más inteligente, por favorStep-by-step explanation:

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Answer:

h[tex]\geq[/tex]8

Step-by-step explanation:

h-(-2)[tex]\geq[/tex]10=h+2[tex]\geq[/tex]10

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Answers

Answer:

Part A: 0

Part B: All real numbers

Step-by-step explanation:

Part A:

We have:

[tex](6^2)^x=1[/tex]

First, let's evaluate the square:

[tex]36^x=1[/tex]

Now, what to the xth power will equal 1?

Remember the fact that anything (except for 0) to the zeroth power is 1.

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[tex](6^0)^x=1[/tex]

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[tex]1^x=1[/tex]

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Answers

Answer:

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Step-by-step explanation:

Let the length of the rectangle be l

Area of a rectangle = length × width

From the question

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Substitute the values into the above formula and solve for the length

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Answers

Answer:

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Step-by-step explanation:

65 inches is the diameter  of the screen

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Answers

Answer:

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

Hey there!!

Let's simply solve it.

Given,

[tex] \frac{1}{2} x + \frac{1}{4} x = 16[/tex]

Now, take LCM.

[tex] \frac{2x + x}{4} = 16[/tex]

Multiply 16 by 4.

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Answers

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Answers

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Answer:

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