HELP ASAP I WILL GIVE BRAINLIEST IF I CAN

Answer:

$1159.69

Step-by-step explanation:

A = P (1 + r/n)^nt

A = 1000 (1 + 0.05/2)^2(3)

A = $1159.69

Answer:

You mean how many centimerters are in a meter?

In that case 100.

Step-by-step explanation:

Answer:

Surface area of prism = 1301 cm²

Step-by-step explanation:

A triangular pyramid has 3 rectangular sides and 2 triangular sides.

Now, we are told that the triangular side is isosceles.

This means that two of the rectangular sides which share a side with the equal side of the triangle are equal as well as the 2 triangular sides.

Surface area of prism = 2(area of triangular face) + 2(area of rectangle sharing one side with the equal side of the triangle) + (area of rectangle sharing side with the unequal side of the triangle).

Area of triangle = ½ × base × height

Area of triangle = ½ × 9 × 13 = 58.5 cm²

Since height of prism is 32 cm, then;

area of rectangle sharing one side with the equal side of the triangle = 32 × 14 = 448 cm²

area of rectangle sharing side with the unequal side of the triangle = 32 × 9 = 288 cm²

Thus;

Surface area of prism = 2(58.5) + 2(448) + 288

Surface area of prism = 1301 cm²

Answer:

B.

Step-by-step explanation:

the three sticks of butter were divided among six people

To indicate a strong correlation between variables, the correlation coefficient will be close to its extreme values of -1 or 1, suggesting a high degree of linear relationship between the variables.

The correlation coefficient, also known as Pearson's correlation coefficient, ranges from -1 to 1.The correlation coefficient quantifies both the magnitude and direction of the linear association between two variables, providing a measure of the strength of their relationship.

When the correlation coefficient is close to -1, it suggests a strong inverse relationship between the variables, indicating that as one variable increases, the other variable tends to decrease consistently.

On the other hand, a correlation coefficient close to 1 indicates a strong positive correlation, where an increase in one variable is associated with an increase in the other variable.

A correlation coefficient near 0, or close to 0.5, does not indicate a strong correlation between the variables. A value close to 0 suggests a weak or no linear relationship between the variables, while a value close to 0.5 indicates a moderate correlation.

Therefore, to indicate a strong correlation between variables, we look for correlation coefficients that are near -1 or 1, indicating a strong negative or positive linear relationship, respectively.

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To determine the value of c such that the random variable cY follows a chi-squared (x²) distribution, we need to compare the moments of cY with the moments of a standard x² distribution.

The random variable Y is defined as Y = (X₁ + X₃ + X₅ + X₇)² + (X₂ + X₄ + X₆ + X₈)², where X₁, X₃, X₅, X₇, X₂, X₄, X₆, and X₈ are independent standard normal random variables.

The x² distribution is characterized by its degrees of freedom, which determine the shape and variability of the distribution. For a standard x² distribution, the degrees of freedom are equal to the number of squared independent standard normal variables that are summed together.

In this case, Y is a sum of squared independent standard normal variables. By expanding Y, we can see that it consists of two terms, each squared separately. Each term represents the sum of four independent standard normal variables. Therefore, each term follows a x² distribution with 4 degrees of freedom.

To make cY follow a x² distribution, we need to equate the degrees of freedom of cY with 4. By comparing the moments of cY with the moments of a standard x² distribution with 4 degrees of freedom, we can solve for the value of c. The moments of cY will depend on the value of c, and by setting them equal to the corresponding moments of a x² distribution, we can find the specific value of c.

In summary, to determine the value of c such that the random variable cY follows a x² distribution, we need to compare the moments of cY with the moments of a standard x² distribution. By equating the degrees of freedom and comparing the corresponding moments, we can find the value of c.

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The type of transformation in this problem is given as follows:

Vertical translation.

The four translation rules are defined as follows:

For this problem, we have a translation of 2 units up, which is called a vertical translation.

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Answer:

When A is less than 0 the parabola flips downward. When A becomes larger than 1, the parabola becomes more narrow. When A becomes smaller, until 0, the parabola widens.

Step-by-step explanation:

Complete question :

From Monday through Friday, James works in the library on 2 days and in the cafeteria on another day. On Saturday and Sunday, James washes cars 50% of the days. How many days does James work in a week? What percent of the days from Monday through Friday does he work?

Answer:

4 days ;

60%

Step-by-step explanation:

From Monday to Friday

Number of days in library = 2

Number of days in cafeteria = 1

50% of days in weekends

Number of weekend days = 2

50% of 2 = 0.5 * 2 = 1 day

Total. Number of days worked = (2 +1 + 1) = 4 days

What percent of the days from Monday through Friday does he work?

Number of days workwd from. Monday to Friday = 3

Total number of days from Monday to Friday = 5

Percentage of days worked from Monday to Friday

= number of days worked / total number of days

= 3 /5 * 100%

= 0.6 * 100%

= 60%

Answer:

110 paper plates

Step-by-step explanation:

Given values:

1 Pack of paper cups (50) = 1.89

1 pack of paper plates (10) = 0.49

Anton has 15.00 to spend

If Anton were to buy 250 paper cups, that would cost him 5 packs since each pack is 50 cups. 5 packs would cost him 1.89 x 5 or 9.45. He now has 5.55 left to spend on paper plates.

Each pack of paper plates is 0.49. To find how many packs he can buy with the remaining amount of money, divide the money buy the cost.

5.55/0.49 ≈ 11.32

Since you can't buy .32 packs, Anton can buy 11 packs, or 110 paper plates.

Among the given options, none of them correctly represent v₃ as a linearly independent vector.

To determine if a set of vectors is linearly independent,we can set up a linear combination equation where the   coefficients are variables.

In this case,we will introduce a   third vector v₃ = [a, b] and check if there exist non-zero values for a and b that satisfy the equation -

c₁ * v₁ + c₂ * v₂ + c₃ * v₃   = 0

where c₁, c₂, and c₃ are the coefficients  of the vectors.

Let's substitute the given   vectors into the equation  -

c₁ * [3, 2] + c₂ *   [-3, -2] + c₃ * [a, b]  = [0, 0]

[3c₁ -   3c₂ + ac₃, 2c1 - 2c₂ + bc₃] = [0, 0]

To determine if there exist   non-zero values for a and b that satisfy the equation,we can set up a system of equations -

3c₁ - 3c₂ +   ac₃ = 0

2c₁ - 2c₂ + bc₃ = 0

Solving   the system of equations, we find that for any non-zero values of a and b,the coefficients c₁, c₂, and c₃ must be zero to satisfy the equation.

This means that the   vectors v₁ = [3, 2] and v₂ = [-3, -2] are linearly independent.

Among the given options, none of them correctly represent v₃ as a linearly independent vector.

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5cm

Step-by-step explanation:

volume of cube= l³

125 =l³

3root over 125 =l

l = 5

Answer:

So the length of the edge of a cube with a volume of 125 is 5.

Step-by-step explanation:

Answer:

x= -3

Step-by-step explanation:

5x + 2 = x - 10

4x + 2 = -10

4× = 10 - 2

4x = -12

x= -3

Answer: the one in the bottom right

Step-by-step explanation: each month which is the x axis ( the bottom line) the y axis (line on the left) goes up by 5

so when the x axis is 1 the y axis should be at 5

Answer:

The rate of change is 12ft/s

Step-by-step explanation:

Given

[tex]h(t) = -16t^2 + 20t[/tex]

Required

Rate of change from when she jumps till 1/2s

The time she jumps is represented as: t = 0

So, calculate h(0)

[tex]h(t) = -16t^2 + 20t[/tex]

[tex]h(0) = -16 * 0^2 + 20 * 0 = 0[/tex]

At t = 1/2

[tex]h(t) = -16t^2 + 20t[/tex]

[tex]h(1/2) = -16 * 1/2^2 + 20 * 1/2 = 6[/tex]

Rate of change is calculated as:

[tex]Rate = \frac{f(b) - f(a)}{b - a}[/tex]

In this case:

[tex]Rate = \frac{h(b) - h(a)}{b - a}[/tex]

Where

[tex](a,b) = (0,1/2)[/tex]

So, we have:

[tex]Rate = \frac{h(b) - h(a)}{b - a}[/tex]

[tex]Rate = \frac{h(1/2) - h(0)}{1/2 - 0}[/tex]

[tex]Rate = \frac{6 - 0}{1/2 - 0}[/tex]

[tex]Rate = \frac{6}{1/2}[/tex]

[tex]Rate =12[/tex]

The rate of change is 12ft/s

Answer:.

Step-by-step explanation:

Answer:

Option C is correct.

(3x)² - 2²

Answer: It is D or C

Step-by-step

I think it is D or C because 9 times 2 is 18. 18 minus 4 is 14. And all the other equations equal something else. The first one is 3- 2times 2 and that is 4 so that would be one. The second is x minus 4 that would be 8. Then the next would be 9 minus 4. That is 5 so it is either C or D.

Answer:

So the odds of flipping a coin 5 times and getting 5 heads are 1/2 ^5 (half to the power of 5). Which gives us 1/32 or just over a 3% chance.

Step-by-step explanation:

Answer:

s

Step-by-step explanation:

Answer:

fourth option) 5/8 lb

Answer:

300°

Step-by-step explanation:

That'd be 5pi/3 radians.  Note that 3pi/3 radians corresponds to 180° and that 6pi/3 corresponds to 360°.  Thus 5pi/3 is in Quadrant IV, meaning that the angle in degrees is between 270° and 360°.  

The "radians to degrees" conversion factor is (180°/pi), and so

5pi/3 radians works out to:

5pi/3 · 180°       5· 180°

----------------- = ---------- = 300°

          3 pi             3

Answer:

I think the answer would be -2 . hope it helps u .

Answer:

4/5=0.8×7=5.6

5.6 is the answer

Hey there!

4/5 × 7

= 4×7/5

= 28/5

= 5.6

Hope it helps ya!

Answer:

11.375

Step-by-step explanation:

Answer:

4

Explanation:

The amount of calculation, if done by hand, will be quite effortful to input.

Ordered pair (0, 6) and  (2, 7)  satisfy both inequalities in the system and are solutions to the system.

To identify the graph that represents the given system of inequalities y > x + 5 and y ≥ 2x + 3, we need to graph the individual inequalities and find the region where they overlap.

When we plot the graph of inequality separately:

    2. y ≥ 2x + 3:

The overlapping shaded region represents the solution to the system of inequalities.

To find two ordered pairs that are solutions to the system, we can choose any points within the overlapping region. Let's select two points:

Ordered pair 1: (0, 6)

Ordered pair 2: (2, 7)

These two points satisfy both inequalities in the system and are solutions to the system.

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The correct question is given below -

Identify the graph that represents the given system of inequalities. Also identify two ordered pairs that are solutions to the system.

y > x + 5

y ≥ 2x + 3

Given,Test at 20% significance level whether one of the drugs is more effective than the other.

We need to calculate the absolute value of the critical value of this test, the absolute value of the calculated test statistic, and the p-value of this test.Solution:(a) The absolute value of the critical value of this test isThe level of significance is 20%.The degree of freedom is (r-1)(c-1) = (3-1)(2-1) = 2

From the chi-square table, the critical value for a chi-square distribution with 2 degrees of freedom and a level of significance of 0.20 is 3.219(i.e. critical value = 3.219)The absolute value of the critical value of this test is 3.219.(b) The absolute value of the calculated test statistic

The table is shown below:  We have, Total = 69 Test at 20% significance level whether one of the drugs is more effective than the other.To check the difference in effectiveness, we will use a chi-square goodness of fit test.

The null hypothesis H0: The two drugs are equally effective.

The alternative hypothesis Ha: One of the drugs is more effective.

The expected values of the two drugs are:  Expected Value of Drug A = (32+18) / 3 = 16 Expected Value of Drug B = (32+1) / 3 = 11 The calculations are summarized in the table below:  The formula to calculate the chi-square value is, chi-square = ∑ (O - E)2 / E The calculated value of chi-square is 6.07.The absolute value of the calculated test statistic is 6.07.(c) The p-value of this test isThe degree of freedom is (r-1)(c-1) = (3-1)(2-1) = 2

The level of significance is 20%.From the chi-square table, the p-value for a chi-square distribution with 2 degrees of freedom and a chi-square value of 6.07 is 0.047 (i.e. p-value = 0.047)The p-value of this test is 0.047.

Answer:(a) The absolute value of the critical value of this test is 3.219.(b) The absolute value of the calculated test statistic is 6.07.(c) The p-value of this test is 0.047.

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We fail to reject the null hypothesis and conclude that there is not enough evidence to suggest that one drug is more effective than the other at the 20% level of significance.

Below is the table of values for the drugs drug A and drug B

Group A 7 10 13 15 8 7 6 10 9 11 10 11

Group B 6 12 9 11 8 8 9 12 10 14

(a) The absolute value of the critical value of this test

The absolute value of the critical value of this test is given by the formula:

[tex]`z = |zα/2|`[/tex]

where α = 0.2;

degree of freedom = `n1+n2-2` = `12+10-2` = `20`

From the standard normal table, the value of zα/2 at 0.2 is 1.645

Therefore, the absolute value of the critical value of this test is; `|1.645| = 1.645`.

(b) The absolute value of the calculated test statistic

The formula for the test statistic is given by;

[tex]`t=bar x1 -bar x2)/((s^2/n1)+(s^2/n2))`[/tex]

where `bar x1` and `bar x2` are the sample means of the two groups,

`s^2` is the pooled variance, n1 and n2 are the sample sizes of the two groups

and [tex]`s^2 = ((n1 -1) s1^2 + (n2 -1) s2^2 )/(n1 + n2 - 2)`[/tex]

Using the data given, we get:

Group A 7 10 13 15 8 7 6 10 9 11 10 11

`n1` = 12

[tex]`bar x1` = `(7+10+13+15+8+7+6+10+9+11+10+11)/12 = 9.583`[/tex]

and `s1` = 2.818

Group B 6 12 9 11 8 8 9 12 10 14

`n2` = 10

[tex]`bar x2` = `(6+12+9+11+8+8+9+12+10+14)/10 = 9.9`[/tex]

and `s2` = 2.205

[tex]`s^2` = `((12-1)2.818^2 + (10-1)2.205^2)/(12+10-2)` = `((11)(7.95)+(9)(4.86))/20` = `6.2155`[/tex]

Therefore, [tex]`t= |9.583 - 9.9| / (6.2155[(1/12)+(1/10)])`= 0.3164[/tex]

The absolute value of the calculated test statistic is 0.3164

(c) The p-value of this test is

The p-value of this test is 0.76 (rounded to two decimal places)

This indicates that the p-value is higher than the significance level, 0.2.

Therefore, we fail to reject the null hypothesis and conclude that there is not enough evidence to suggest that one drug is more effective than the other at the 20% level of significance.

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we do not have enough evidence to conclude that cars get better mileage on premium gasoline. Thus, we can conclude that there is no significant difference between the mileages of cars using premium and regular gasoline.

a. What test should be used?

The test that should be used is the Two-sample t-test because we are working with two independent groups.

b. What are the hypotheses?

The null hypothesis is that there is no difference between the mileage of cars using premium and regular gasoline, while the alternative hypothesis is that there is a difference between the two mileages.

Mathematically, this can be stated as follows: Null hypothesis: µ1 = µ2Alternative hypothesis: µ1 > µ2Where µ1 is the population mean for premium gasoline and µ2 is the population mean for regular gasoline.

c. Based on the R outputs, what is your conclusion about hypotheses testing?

From the R outputs, we can see that the p-value is 0.2826. Since this value is greater than the level of significance (α) of 0.05, we fail to reject the null hypothesis. Therefore, we do not have enough evidence to conclude that cars get better mileage on premium gasoline. Thus, we can conclude that there is no significant difference between the mileages of cars using premium and regular gasoline.

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a. The test that should be used is a two-sample t-test.

b. The null hypothesis is "The population mean mileage of cars using regular and premium gasoline are equal."

The alternative hypothesis is "The population mean mileage of cars using premium gasoline is more than the population mean mileage of cars using regular gasoline."

c. We do not have enough evidence to support the claim that cars get better mileage on premium regular gas.

a. To find what test should be used.

The test that should be used is a two-sample t-test.

b. To find the hypotheses.

The null hypothesis is "The population mean mileage of cars using regular and premium gasoline are equal."

The alternative hypothesis is "The population mean mileage of cars using premium gasoline is more than the population mean mileage of cars using regular gasoline."

c. Based on the R outputs, to find the conclusion about hypotheses testing.

The sample mean of the differences in mileage for cars filled with premium and regular gasoline is 0.8. The calculated t-value is -0.59702.

The calculated p-value is 0.2826.The p-value is higher than the significance level of 0.05.

Therefore, we fail to reject the null hypothesis.

We can't conclude that the population mean mileage of cars using premium gasoline is more than the population mean mileage of cars using regular gasoline.

Hence, we do not have enough evidence to support the claim that cars get better mileage on premium regular gas.

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Answer:

2 ≤ x ≤ 8

Step-by-step explanation:

0 ≤ 3x - 6 ≤ 18

0 ≤ 3x - 6

6 ≤ 3x

2 ≤ x

3x - 6 ≤ 18

3x ≤ 18 + 6

3x ≤ 24

x ≤ 8

Combined:

2 ≤ x ≤ 8

Answer:

2 ≤ x≤ 8

2nd option:)

Step-by-step explanation:

Answer:

I couldn't really see the height number (that had to doubled) ir really the radius but I saw 7 for the radius and 3 (×2) for the height so I did the math and the answer is 923.63

Step-by-step explanation:

i could be wrong tho, hope this helped

Answer:

923.63

Step-by-step explanation: hope this helps!!

The number of different groups of subjects possible when randomly selecting from a group of subjects can be determined using the concept of combinations. The total number of possible groups can be calculated by finding the number of combinations of subjects that can be formed from the given group.

When selecting subjects from a group, the order of selection doesn't matter. We can use the combination formula to calculate the number of different groups. If there are 'n' subjects in the group and we want to select 'r' subjects, the number of different groups can be calculated as C(n, r), which is given by

n! / (r! * (n - r)!).

For example, if there are 10 subjects in the group and we want to select 3 subjects, the number of different groups of subjects possible would be

C(10, 3) = 10! / (3! * (10 - 3)!),

which simplifies to 10! / (3! * 7!).

Evaluating this expression will give you the total number of different groups of subjects that can be formed through random selection.

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