I NEED HELP WITH MATH PLS
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To find the partial sum S₁7 for the arithmetic sequence with a first term (a) of 3 and a common difference (d) of 2, we can use the formula for the sum of an arithmetic sequence. Therefore, the partial sum S₁7 for the arithmetic sequence with a first term of 3 and a common difference of 2 is 323.

The formula for the sum of an arithmetic sequence is given by:

Sn = (n/2)(2a + (n-1)d)

In this case, we want to find the partial sum S₁7, which means we need to substitute n = 17 into the formula.

Plugging in the values, we have:

S₁7 = (17/2)(2(3) + (17-1)(2))

Simplifying the equation inside the parentheses, we get:

S₁7 = (17/2)(6 + 16(2))

Simplifying further:

S₁7 = (17/2)(6 + 32)

S₁7 = (17/2)(38)

Finally, evaluating the expression, we have:

S₁7 = 17(19)

S₁7 = 323

Therefore, the partial sum S₁7 for the arithmetic sequence with a first term of 3 and a common difference of 2 is 323.

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Answer:

quadratic equation

Step-by-step explanation:

Answer:

the equation shown here is a quadratic equation

Using a Normal distribution table , the value of the given probability is 0.0359

Find the row corresponding to the tenths digit of -1.8, which is -1.8 rounded to -1.9.

Find the column corresponding to the hundredths digit of -1.8, which is -1.8 rounded to -1.80.

The value in the intersection of the row and column is the probability of Z being less than -1.8.

Therefore, we find that the probability is approximately 0.03593

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After considering the given data we conclude the x term of h(x) is [tex]44 + 5*2 = 26.[/tex]We can continue this process for the [tex]x^2[/tex] term, the [tex]x^3[/tex] term, and the [tex]x^4[/tex] term, using the appropriate terms from f(x) and g(x) and adding up the products and  the quotient q(x) is [tex]x^2 - x,[/tex] and the remainder r(x) is [tex]3x^2 + 8x + 5,[/tex]

To evaluate the product h(x) of the two polynomials f(x) and g(x) manually, we can apply a table [tex]T_3[/tex] to show line by line how each term is computed.
The table possess columns for the term from f(x), the term from g(x), and the product of the two terms. The rows of the table will correspond to the different powers of x, starting from [tex]x^0[/tex].
For instance , to compute the constant term of h(x), we need to multiply the constant terms of f(x) and g(x). The constant term of f(x) is 5, and the constant term of g(x) is 4, so the constant term of h(x) is 54 = 20.
Similarly, to compute the x term of h(x), we need to multiply the x term of f(x) (which is 4) by the constant term of g(x) (which is 4), and add it to the constant term of f(x) (which is 5) multiplied by the x term of g(x) (which is 2).
Therefore, the x term of h(x) is [tex]44 + 5*2 = 26.[/tex]We can continue this process for the [tex]x^2[/tex] term, the [tex]x^3[/tex] term, and the [tex]x^4[/tex] term, using the appropriate terms from f(x) and g(x) and adding up the products.

To evaluate the quotient q(x) and remainder r(x) when f(x) is divided by g(x), we can use polynomial long division.
We apply division the highest degree term of f(x) by the highest degree term of g(x) to get the first term of q(x).
Then we multiply g(x) by this term of q(x) and subtract the result from f(x) to get the first remainder. We repeat this process with the next highest degree term of the remainder until the degree of the remainder is less than the degree of g(x).
The coefficients of the terms in q(x) are the quotients obtained in each step of the division, and the coefficients of the terms in the remainder are the final remainder obtained after all the steps of the division.
For instance , to compute the quotient q(x) and remainder r(x) when [tex]f(x) = x^4 + 2x^3 + 3x^2 + 4x + 5[/tex] is divided by [tex]g(x) = x^2 + 2x + 4,[/tex]
we first divide [tex]x^4[/tex] by [tex]x^2[/tex] to get [tex]x^2[/tex] as the first term of q(x).
We then multiply g(x) by [tex]x^2[/tex] to get [tex]x^4 + 2x^3 + 4x^2,[/tex] and subtract this from f(x) to get[tex]-x^3 - x^2 + 4x + 5[/tex] as the first remainder.
We then divide [tex]-x^3[/tex] by [tex]x^2[/tex] to get -x as the second term of q(x).
We multiply g(x) by -x to get[tex]-x^3 - 2x^2 - 4x[/tex], and subtract this from the first remainder to get [tex]3x^2 + 8x + 5[/tex]as the final remainder.
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0%

Where rolling a pair of die, a pair is two so there is two die. Now we have to look at the sample space for the two dice.

1 2 3 4 5 6

1 l 2l 3l 4l 5l 6l 7l

2l 3l 4l 5l 6l 7l 8l

3l 4l 5l 6l 7l 8l 9l

4l 5l 6l 7l 8l 9l 10l

5l 6l 7l 8l 9l 10l 11l

6l 7l 8l 9l 10l 11l 12l

there is 36 outcomes in the sample space none of them include getting 15.

Answer:

y=9

Step-by-step explanation:

12/y=4/3

3×12/y=3×4/3

36/y=4

y×36/y= 4×y

36=4y

36/4=4y/4

9=y

Answer:

1: x = 6

2: There is no solution. Sorry. (because the ending equation will be 0 = 7)

3: I can't see the other part of the equation, I need to see what the fraction is in order to solve it. If you can retake the picture, I can edit my response :)

Step-by-step explanation:

#1: 3(x-1) is pretty much just 3x-3. Simple.

Now, your equation becomes 3x-3 = 2x+9.

Arrange them so that the like terms are together.

Since you will be taking the 2x from 2x+9 over to the other side, it becomes 3x-2x-3 = 9.

Now, bring the 3 over to the side with the 9.

x = 6.

#2: Same as before, -2(x+1) is (-2x) - 2.

So, -2x-2 = -2x+5.

As I said before, you need to group the like terms together.

-2x and -2x go together, and -2 and 5 go together.

-2x+2x=5+2

0=7.

There is no solution.

#3: Like the other two, 4(x-1) is 4x-4. As for the other part, I cannot see the fraction before (x-8).

9514 1404 393

Answer:

  (d)  (-3, 1)

Step-by-step explanation:

We assume a typo in the problem statement, and that the equations are supposed to be ...

  [tex]2x -3y = -9\\-x +3y = 6[/tex]

Adding the two equations gives ...

  x = -3

Substituting for x in the second equation gives ...

  3 +3y = 6

  1 + y = 2 . . . . divide by 3

  y = 1 . . . . . . . subtract 1

The solution is (x, y) = (-3, 1).

Answer: $45

Step-by-step explanation:

Let the original price be x.

Since there was a discount of 20%, it means the person bought the frying pan at (100% - 20%) = 80% of the original price. This can then be formed into an equation as:

80% × x = $36

0.8 × x = $36

0.8x = $36

x = $36/0.8

x = $45

The original price was $45

Answer:

2:40

Step-by-step explanation:

Add 85 minutes to 45 minutes and then add that to 12:30

Answer:

Prism B has a larger base area

Step-by-step explanation:

Given

Base dimensions:

Prism A:

Lengths: 6cm, 8cm and 10cm

Prism B:

Lengths: 5cm and 5cm

Required [Missing from the question]

Which prism has a larger base area

For prism A

First, we check if the base dimension form a right-angled triangle using Pythagoras theorem.

The longest side is the hypotenuse; So:

[tex]10^2 = 8^2 + 6^2[/tex]

[tex]100 = 64 + 36[/tex]

[tex]100 = 100[/tex]

The above shows that the base dimension forms a right-angled triangle.

The base area is then calculated by;

Area = 0.5 * Products of two sides (other than the hypotenuse)

[tex]Area = 0.5 * 8cm * 6cm[/tex]

[tex]Area = 24cm^2[/tex]

For Prism B

[tex]Lengths = 5cm\ and\ 5cm[/tex]

So, the area is:

[tex]Area = 5cm * 5cm[/tex]

[tex]Area = 25cm^2[/tex]

By comparison, prism B has a larger base area because [tex]25cm^2 > 24cm^2[/tex]

Answer:

The circumference is 16π or 50.2654 depending on whether they ask you for an exact value or in terms of pi.

Step-by-step explanation:

2r=d

2(8)=d

16=d

C=πd

C=π16

So, the circumference is 16π or 50.2654 depending on whether they ask you for an exact value or in terms of pi.

Answer:

50.2654

Step-by-step explanation:

Answer:

It would be D

Step-by-step explanation:

Answer:

Where is the number I need to round to?

(Please don't give me a bad rating i'm trying to help :) )

The given integral is: $$\int (-2x^2 + 500)dx$$

To solve the above integral, we integrate both terms separately. Using the integral formulas, $$\int x^n dx= \frac{x^{n+1}}{n+1}+ C$$$$\int kf(x)dx= k\int f(x)dx$$

where C is a constant of integration and k is a constant.

The integral $\int -2x^2 dx$ is:\begin{align*} \int -2x^2 dx &= -2\int x^2 dx\\&= -2\times \frac{x^{2+1}} {2+1} + C\\&= -\frac {2}{3}x^3+ C\end{align*}

The integral $\int 500 dx$ is:\begin{align*}\int 500 dx &= 500\int dx\\&= 500\times x + C\\&= 500x + C\end{align*}

Thus, the integral $\int (-2x^2 + 500) dx$ is:\begin{align*}\int (-2x^2 + 500) dx &= \int -2x^2 dx + \int 500 dx\\&= (-\frac {2}{3}x^3+ C_1) + (500x + C_2)\\&= -\frac {2}{3}x^3+ 500x + C\end{align*}

where C is a constant of integration and $C=C_1+C_2$.

Therefore, the exact value of the integral is $-\frac {2}{3}x^3+ 500x + C$.

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Answer:

Step-by-step explanation:

1.  Not sure...

2. $ 1.44

3. $ 3.70

4. $11 per ticket

Answer:

Mean and IQR

Step-by-step explanation:

The measure of centre gives the central or the measure which gives the best mid term of a distribution. Based in the details of the box plot, the median is the value which divides the box in the box plot.

For company A:

Range = 25 to 80 with a median value at 30 ; this means the median does not give a good centre measure of the distribution ad it is very close to the minimum value. This goes for the Company B plot too; with values ranging from (35 to 90) and the median designated at 40.

Hence, the mean will be the best measure of centre rather Than the median in this case.

For the variability, the interquartile range would best suit the distribution. With the lower quartile and upper quartile both having reasonable width to the minimum and maximum value of the distribution.

Answer:

B

Step-by-step explanation:

Answer:

36

Step-by-step explanation:

To find the area of a triangle, multipy the base and height of a triangle, then divide it in half

8x9=72/2=36

Answer:

For two fractions to be proportional, they must be equivalent. 32=1.5 and 188=2.25 , so these fractions are not proportional.

Step-by-step explanation:

Answer:

Write abt a poem you like or something

Step-by-step explanation:

Answer:

https://brainly.com/question/3677306

Step-by-step explanation:

Answer:

----------------------

DC is the radius and its length is:

DC is the perpendicular bisector of EF.  Hence the half of the segment EF is the leg of a right triangle with the hypotenuse of EC = DC = 70 and other leg of 50 units.

Using the Pythagorean theorem, find the length of EF:

Answer:

#1

#2

#3

#4

Answer:

1350 m³

Step-by-step explanation:

To find the volume of a rectangular prism, we have to multiply its length, width, and height together.

The dimensions of this prism are 9, 10, and 15.

9 · 10 · 15 = 1350

The volume is 1350 meters³.

I hope this helps ^^