if 23.1g of O2 occupies a volume of 5.0L at a particular temperature and pressure, what volume will 2.50g of Oxygen gas occupy under the same conditions?

Answer: It decreases

Answer: It decreases.

Explanation: a p e x :)

Answer:

5. 56.5217

Explanation:

Calculate percent yield by (actual yield / theoretical yield) times 100

(13/23) x 100 = 56.52173913

potassium chloride from potassium hydroxide and hydrochloric acid

Answer:

1-bromobutane

Explanation:

The reaction of butane with aqueous HBr at reflux is an SN2 reaction. The reaction passes through a single transition state in which the bond between carbon and the leaving group as well as the bond between carbon and the incoming nucleophile are being broken and formed simultaneously. It is a synchronous reaction.

The nuclephile attacks from the backside while the leaving group departs. This leads to inversion of configuration of the product.

Answer:

5 atm

Explanation:

add boh partial pressures and subtract from total pressure

Answer:

A. predict whether you will be able to make a solution with pentane and tetrachloromethane

Explanation:

Sana nakatulong

Answer:

C. ElectricalElectrical

Explanation:

( it might be wrong pls dont report me just let me kno y its wrong )

Answer:

The total amount of energy required is 25,515.2 J.

Explanation:

Calorimetry is the measurement and calculation of the amounts of heat exchanged by a body or a system.

When a system absorbs (or gives up) a certain amount of heat, it can happen that:

To calculate the latent heat the formula is used:

Q = m. L

Where

To calculate sensible heat the following formula is used:

Q = m. c. ΔT

where:

In this case, you have in the first place a heat to raise the temp of the water from 35.0 C to 100 C, where the specific heat value for water is  4.184 [tex]\frac{J}{g*C}[/tex]:

q1 = m*c*(Tfinal-Tinitial)

q1 = 10.0 g *(4.184 [tex]\frac{J}{g*C}[/tex])* (100 - 35.0 C) = 2719.6 J

Now you have the heat to vaporize the water, where the heat of vaporization is 2259.36 [tex]\frac{J}{g}[/tex]:

q2 = m*(heat of vaporization)

q2 = 10.0 g*(2259.36 [tex]\frac{J}{g}[/tex]) = 22593.6 J

Finally, you have the heat to raise temp of steam to 110 C, where the specific heat value for steam is  2.02 [tex]\frac{J}{g*C}[/tex] :

q3 = m*c*(Tfinal-Tinitial)

q3 = 10.0 g*(2.02 [tex]\frac{J}{g*C}[/tex])*(110-100 C) = 202 J

The total amount of energy can be calculated as:

Q= q1 + q2 + q3

Q= 2719.6 J + 22593.6 J + 202 J

Q=25,515.2 J

The total amount of energy required is 25,515.2 J.

Answer:

Forests are renewable

Explanation:

Forests can grow again, but it takes forever to grow a new one so it shouldn't be taken for granted! You can remake a whole new forest, but it will take around 50 years and a lot of animals will die without them before that time comes!

But then again, it could be a non-renewable resources; because it takes so long to grow a new one!

Hope this helps!

Answer:

-1,300 kJ

I don't want to explain it brainly AAAAA

The standard enthalpy of the reaction is the enthalpy change which occurs in a system when a matter is transformed by a chemical reaction under standard conditions. Here the enthalpy of the overall chemical reaction is  -1,300 kJ. The correct option is B.

In any general chemical reaction, the reactants undergo chemical changes to form products. The change in enthalpy is represented as ΔrH and is termed as the reaction enthalpy. It can be calculated by subtracting the sum of enthalpies of all the reactants from that of the products.

ΔrH  = ∑ aiH products - ∑ bi H reactants

Here we should reverse the first reaction and also multiply its ΔH by (- 1):

P₄O₆(s) → P₄(s) + 3O₂(g), ΔH₁' = 1640.1 kJ.

The second reaction is also reversed and also multiply its ΔH by (- 1):

P₄(s) + 5O₂(g) → P₄O₁₀(s), ΔH₂' = - 2940.1 kJ.

If we add the two reactions after modification, we get:

P₄O₆(s) → P₄O₁₀(s).

Therefore,  ΔH = ΔH₁' + ΔH₂' = 1640.1 kJ + (- 2940.1 kJ) = - 1300 kJ.

Thus the correct option is B.

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Answer:

i)  Buffer absorbs  H^+ and OH^- ions preventing large changes in pH when small amounts of acid or base is added but when large amounts of acid or base is added there will be a change in pH

ii) absorption of liquid is related to a chemical reaction for a buffer system but it is not related a chemical reaction for a proton( H ) sponge.

Explanation:

i) Buffer like a proton ( H ) sponge

Buffer absorbs  H^+ and OH^- ions preventing large changes in pH when small amounts of acid or base is added but when large amounts of acid or base is added there will be a change in pH

The pH of a Buffer follows the Henderson-Hasselbach model

pH = pKa + Log ([A-]/[HA])

when base is added

HA + OH^-   -------> A- + H2O

when acid is added

A^- + H^+   ---------> HA

ii) Buffer not like a proton ( H ) sponge

absorption of liquid is related to a chemical reaction for a buffer system but it is not related a chemical reaction for a proton( H ) sponge.

Answer:

1 : one that carries : bearer, messenger. 2a : an individual or organization engaged in transporting passengers or goods for hire. b : a transportation line carrying mail between post offices.

Answer:

"0.60 g" is the appropriate solution.

Explanation:

The given values are:

Volume of base,

= 30 ml

Molarity of base,

= 0.05 m

Molar mass of acid,

= 400 g/mol

As we know,

⇒  [tex]Molarity=\frac{Number \ of \ moles \ of \ base}{Number \ of \ solution}[/tex]

On substituting the values, we get

⇒           [tex]0.05=\frac{Number \ of \ moles \ of \ base}{30\times 10^{-3}}[/tex]

⇒  [tex]Number \ of \ moles \ of \ base=0.05\times 30\times 10^{-3}[/tex]

⇒                                             [tex]=1.5\times 10^{-3}[/tex]  

hence,

⇒  [tex]Moles \ of \ acid=\frac{Mass \ of \ acid}{Molar \ mass \ of \ acid}[/tex]

On substituting the values, we get

⇒  [tex]1.5\times 10^{-3}=\frac{Mass \ of \ acid}{400}[/tex]

⇒  [tex]Mass \ of \ acid=1.5\times 10^{-3}\times 400[/tex]

⇒                         [tex]=0.60 \ g[/tex]

Answer:

221.22K or -51°C

Explanation:

We will be using the Ideal Gas Law to calculate the temperature of the gas. It is a mathematical relationship that describes the behavior of ideal gas ample for any combo of varying pressure, volume, temperature, and # of moles (n). It is derived by combing Boyle's Law, Charles' Law, Gay-Lussac's & Avogadro's Law.

Note: As always, remember that temperature must be in Kelvin not Celsius when using this equation.

Ideal Gas Law: [tex]PV = nRT[/tex], where P = pressure, V = volume (in Liters), n = # of moles, R = the ideal gas constant, and T = temperature (in Kelvin).

Based on the problem, we are given the pressure, volume, and # of moles. We are asked to find the temperature. What about R you ask? Well, R is a constant that is the value of 1 mole of gas at STP. R has various values depending on the pressure units. In this case, our pressure is in atm so the R value = 0.0821.

Onto the math - all that needs to be done now is to plug and chug. Plug in the given values to find the temperature:

Set up: [tex](7.6 atm)(12L) = (5 mol)(0.0821 L*atm/(mol*K))(T)[/tex]

==> [tex]T = \frac{(7.6 atm)(12L)}{(5 mol)(0.0821 L*atm/(mol*K))}[/tex]

==> T = 221.17K

The answer is 221.17K. To convert into Celsius, subtract by 273.15 to get -50.99 or -51°C.

Answer:

1.02 M

Explanation:

Solution contains 65g of sodium nitrate

Volume of solution = 750 ml

Now, Molar mass of sodium nitrate from online values = 84.9947 g/mol

Thus, it means 84.9947 g/mol of sodium nitrate dissolved in 1000 mL of water will be equal to 1 M molarity.

Thus;

Molarity of solution = (65/750) × (1000) × (1/84.9947) = 1.02 M

Answer:

The value of n is 6

Explanation:

The half-reactions of the problem are:

Cr(s) → Cr³⁺ + 3e⁻

Pb²⁺ + 2e⁻→ Pb(s)

To balance the electrons we must multiply the half-reactions as follows:

2 * (Cr(s) → Cr³⁺ + 3e⁻)

3 * (Pb²⁺ + 2e⁻→ Pb(s))

2Cr(s) → 2Cr³⁺ + 6e⁻

3Pb²⁺ + 6e⁻→ 3Pb(s)

In Nernst equation, the value of n are the electrons used to balance the reaction, as in this problem, the electrons are 6:

Answer:

Explanation:

To find the number of moles in a substance given it's number of entities we use the formula

[tex]n = \frac{N}{L} \\ [/tex]

where n is the number of moles

N is the number of entities

L is the Avogadro's constant which is

6.02 × 10²³ entities

From the question we have

[tex]n = \frac{4.9 \times {10}^{23} }{6.02 \times {10}^{23} } = \frac{4.9}{6.02} \\ = 0.813953...[/tex]

We have the final answer as

Hope this helps you

Answer:

When science educators teach nurses, their primary aim should be to help them to develop understanding of their world of nursing. From a study of registered nurses' conceptions of the physical science underlying their clinical practice, we assert that nurses' understanding of the physical sciences is inadequate in terms of the competencies required of them as nurses.

Explanation: Hopes this helps You A lot :-D

Answer:

Because thats where the animal passed away

Explanation:

Answer:

238000 N

Explanation:

Use F=ma

Mass= 17000 kg

Accel.= 14 m/s²

Answer:

0.54 L

Explanation:

Given that,

Initial volume, V₁ = 0.5 L

Initial temperature, T₁ = 10°C = 283 K

Final temperature, T₂ = 35 C = 308 K

We need to find the final volume. The relation between the volume and temperature is given by :

[tex]\dfrac{V_1}{T_1}=\dfrac{V_2}{T_2}\\\\V_2=\dfrac{V_1T_2}{T_1}\\\\V_2=\dfrac{0.5\times 308 }{283}\\\\V_2=0.54\ L[/tex]

So, the new volume is 0.54 L.

Answer:

The options (A) -The rate law for a given reaction can be determined from a knowledge of the rate-determining step in that reaction's mechanism.  and (C) -The rate laws of bimolecular elementary reactions are second order overall ,is true.

Explanation:

(A) -The rate law can only be calculated from the reaction's slowest or rate-determining phase, according to the first sentence.

(B) -The second statement is not entirely right, since we cannot evaluate an accurate rate law by simply looking at the net equation. It must be decided by experimentation.

(C) -Since there are two reactants, the third statement is correct: most bimolecular reactions are second order overall.

(D)-The fourth argument is incorrect. We must track the rates of and elementary phase that is following the reaction in order to determine the rate.

Therefore , the first and third statement is true.

Answer:

its a.

Explanation:

By using filtration, the sand and fine salt can be effectively separated based on their difference in particle size, providing a clean separation of the two components.

Filtration is a separation technique that takes advantage of the difference in particle size between sand and salt. It involves passing the mixture through a porous material, such as filter paper or a filter funnel, which allows the liquid (saltwater) and small salt particles to pass through while retaining the larger sand particles.

Here's how the filtration process can be carried out:

1. Set up a filter apparatus with a funnel and filter paper or a filter flask.

2. Place the mixture of sand and salt in a beaker or a flask.

3. Slowly pour the mixture into the filter paper or funnel, allowing the liquid (saltwater) to pass through while retaining the sand on the filter paper.

4. Once the liquid has passed through completely, the sand will be left behind on the filter paper or in the filter flask.

5. Carefully remove the sand from the filter paper or filter flask, and the saltwater solution can be collected separately.

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Answer:

to use mass and temperature data to do computations involving heat

to compute a reaction’s enthalpy directly using mass measurements and a calorimeter

To find the enthalpy of a reaction in the lab, you measured the mass

of the reactants

and the

temperature

change during the reaction.

Explanation:

Was that good?

Enthalpy is a thermodynamic system's internal energy total as well as the volume times pressure ratio.

Enthalpy is a property or state function that resembles energy; it has the same dimensions as energy and is therefore measured in joules or ergs. The value of enthalpy is solely dependent on the temperature, pressure, and composition of the system, not on its history.

Enthalpy, denoted by the symbol H, is the sum of the internal energy, denoted by E, and the product of the pressure and volume, denoted by PV.

The change in internal energy is equal to the heat transmitted to, less the work done by, the system, according to the law of energy conservation.

Therefore, Enthalpy is a thermodynamic system's internal energy total as well as the volume times pressure ratio.

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