If arc ED=(9x-3) , arc BF=(15x-39) and angle BCF=(11x-9) find arc ED

Answer:

[tex]23\frac{1}{16}[/tex] pulgada

Step-by-step explanation:

[tex]\frac{16}{9} =\frac{41}{y}[/tex]

16 × y = 9 × 41

16y = 369

16y ÷ 16 = 369 ÷ 16

[tex]y=23\frac{1}{16}[/tex]

Answer:

9

Step-by-step explanation:

I'm not sure, the answer is still 9, 1+2 is 3 so

6/2(3)

and 6/2 simplified is 3

so 3(3) is 9

Answer:

9

Step-by-step explanation:

1. Simplify the parantheses

(1+2) = 3

2. Turn 3 into a fraction

3 = 3/1

3. Multiply the fractions

6   x    3    =  18

2    x   1         2

4. What is 18/2?

18/2 = 9

Hiii, so I REALLY want to rank up, and I just need 5 more Branliests, so if you liked my answer, can you please give me one? Thank you so much, and thanks for the points!!

Answer:

30 x 4 + 4 x 4 and 4 x 4 + 4 x 30

Step-by-step explanation:

Answer:

B

Step-by-step explanation:

D) - y = (x + 5)(x - 3)(x + 1).

Table in this case would look like this:

Write coefficients of x³, x² ,x and the constant in a row and divisor would be the x value obtained by equation x + 5 = 0.

The sequence of multiplications would be as shown in picture.

x² - 2x - 3

x² - 3x + x - 3

x(x - 3) + 1(x - 3)

(x + 1)(x - 3)(x + 5).

1. This is a valid approach to prove the argument.

2. This is the first step of the contrapositive proof.

3. This statement is true since if one of them is rational, the other one could also be rational or irrational.

4. This statement is true because rational numbers are those numbers that can be expressed as a ratio of two integers.

5. This is true because any rational number can be expressed as a fraction of two integers.

6. This is true since it's the sum of two fractions.

7. This is also true since the sum and product of two integers are always integers.

8. This is true since the product of any non-zero number with another non-zero number is also non-zero.

9. This statement is true since x+y is the quotient of two integers, and since both integers are non-zero, then the quotient is also non-zero and therefore rational.

Therefore, the given argument is correct.

Each step in the argument is logically valid, and the argument follows a correct proof by contrapositive to show that if x is rational and y is rational, then x + y is rational.

The given argument is correct. Let us evaluate each line of the proof and make sure that it is accurate and logical.

Proposition: For every pair of real numbers x and y, if x + y is irrational, then x is irrational or y is irrational

1. We proceed by contrapositive proof.

This is a valid approach to prove the argument.

2. We assume for real numbers x and y that it is not true that x is irrational or y is irrational and we prove that x + y is rational.

This is the first step of the contrapositive proof.

3. If it is not true that x is irrational or y is irrational then neither x nor y is irrational.

This statement is true since if one of them is rational, the other one could also be rational or irrational.

4. Any real number that is not irrational must be rational. Since x and y are both real numbers then x and y are both rational.

This statement is true because rational numbers are those numbers that can be expressed as a ratio of two integers.

5. We can therefore express x as a/b and y as c/d as a, where a, b, c, and d are integers and b and d are both not equal to 0.

This is true because any rational number can be expressed as a fraction of two integers.

6. The sum of x and y is: x + y = a/b + c/d = (ad+bc)/bd

This is true since it's the sum of two fractions.

7. Since a, b, c, and d are integers, the numerator ad + bc and the denominator bd are integers.

This is also true since the sum and product of two integers are always integers.

8. Furthermore since b and d are both non-zero, bd is also non-zero.

This is true since the product of any non-zero number with another non-zero number is also non-zero.

9. Therefore, x + y is a rational number.

This statement is true since x+y is the quotient of two integers, and since both integers are non-zero, then the quotient is also non-zero and therefore rational.

Therefore, the given argument is correct.

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By reading off the graph as shown in the question, we can see that the time that is required is 20 minutes.

The half life is the time that it taken for only half or 50% of the isotopes that were originally present in the sample to remain. We know that the half life does differ by the kind of sample that is used.

In this case, we want to determine  how long does it take a sample of francium-223 to decay by 50%. This could easily be done from the graph of the decay as shown in the question.

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Answer:

1. B. $20

2.C. 19%

3. D. not here

Step-by-step explanation:

1.  info we know

25+45+10+25+15+10 = 130

we need 20 more dollars

2.  25/130   x/100

cross multiply

2500/ 130x

divide

19 = x

3.  same steps as last time

35/130 x/100

3500/130x

29%

Answer:

0

Step-by-step explanation:

-9 x (0/-3)

-9 x 0

0

Answer:

The desired product is (x + 2)(x + 4).

Step-by-step explanation:

If x is an even integer, x + 2 is the next consecutive even integer and x + 4 the next.  

The desired product is (x + 2)(x + 4).

Answer:

D. 42

2X3X7=42

Step-by-step explanation:

It's just volume baseXwidthXhight. Hope this helps.

Answer:

1/6 or 16.67% chance

Step-by-step explanation:

Assuming its a normal six sided dice. You would have a 16.67% chance of getting a 3.

Answer:

7/15

Step-by-step explanation:

7+8=15

there's 7 girls so you have 7/15 chance of getting a girl

Answer:

8/15

Step-by-step explanation:

possibilities/sample size= 8 girls/ 15 students

Answer:

3

Step-by-step explanation:

the scale is 2 so you need to figure out 3y + 5 = 14

Answer:

y=0.12/1(x-5)^2 -3

y=1/10(x-10)^2 -4

Step-by-step explanation:

Given the directrix and focus of the parabolas, the equation of the parabolas are [tex]y=\frac{1}{6}(x^{2} +10x - 2)[/tex] and [tex]y=\frac{1}{20}(-x^{2} +20x - 80)[/tex].

Equation of a parabola is given by-

Distance of a point (x, y) on parabola from directrix =  Distance of a point (x, y) on parabola from focus

focus = (-5, -3)

directrix = y = -6

[tex]\sqrt{(x+5)^{2}+(y+3)^{2} } = (y+6)\\\\ (x+5)^{2}+(y+3)^{2} = (y+6)^{2}\\\\x^{2} +25+5x = 6y+27\\\\y=\frac{1}{6}(x^{2} +10x - 2)[/tex]

focus = (10,-4)

directrix = y = 6

[tex]\sqrt{(x-10)^{2}+(y+4)^{2} } = (y-6)\\\\ (x-10)^{2}+(y+4)^{2} = (y-6)^{2}\\\\x^{2} +100-20x = -20y+20\\\\y=\frac{1}{20}(-x^{2} +20x - 80)[/tex]

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The estimate of the number of gallons of oil in the tank at t = 14 hours is 100.8 gallons. The correct answer is option C.

To estimate the number of gallons of oil in the tank at t = 14 hours using a trapezoidal approximation,

we need to calculate the total change in oil volume over the given time period.

The trapezoidal approximation involves dividing the time interval into subintervals and approximating the change in volume as the sum of trapezoidal areas.

Let's calculate the approximate volume of oil at t = 14 hours using the given data and the trapezoidal approximation: Interval 1 (2 to 5 hours):

Average rate = (R(2) + R(5)) / 2 = (8.2 + 7.8) / 2 = 16 / 2 = 8 gallons per hour.

Volume change =

[tex]Average rate \times time = 8 \times (5 - 2)[/tex]

= 24 gallons.

Interval 2 (5 to 10 hours):

Average rate = (R(5) + R(10)) / 2 = (7.8 + 8.6) / 2 = 16.4 / 2 = 8.2 gallons per hour

Volume change =

[tex]Average rate \times time = 8.2 \times (10 - 5) [/tex]

= 41 gallons

Interval 3 (10 to 14 hours):

Average rate = (R(10) + R(14)) / 2 = (8.6 + 9.3) / 2 = 17.9 / 2 = 8.95 gallons per hour

Volume change =

[tex]Average rate \times time = 8.95 \times (14 - 10)[/tex]

= 35.8 gallons.

Total volume change = Interval 1 + Interval 2 + Interval 3 = 24 + 41 + 35.8 = 100.8 gallons.

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Answer:

Is that your answer

To determine whether the function f(z) = 1/(z^2 + 1) has an antiderivative on a given domain, we need to check if the function is analytic on that domain.

(a) For the domain G = C\{i, -i}, the function f(z) = 1/(z^2 + 1) is analytic on G. This is because it is a rational function and does not have any singularities (poles) within the domain. Hence, it has an antiderivative on G.

(b) For the domain G = {z Re(z) > 0}, the function f(z) = 1/(z^2 + 1) does not have an antiderivative on G. This is because the function has singularities at z = i and z = -i, which lie on the imaginary axis. Since the domain excludes these points, f(z) is not analytic on G and does not have an antiderivative on G.In summary, the function f(z) = 1/(z^2 + 1) has an antiderivative on the domain G = C\{i, -i} but does not have an antiderivative on the domain G = {z Re(z) > 0}.

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Answer:

4,370

Step-by-step explanation:

.....just round the tenths place (6) up sense 8 is above 5 it rounds up so

4,370

sorry for bad explanation

Answer:

D.1767.1 in³

Step-by-step explanation:

volume of a sphere=4/3πr³

where r=radius of the sphere

Given diemeter= 15in

so radius=15/2=7.5in

volume=4/3×π×(7.5)³

=4/3×22/7×(7.5)³

=1767.1in³

hope it helps...

have a great day!!

Answer:

D

Step-by-step explanation:

A and C are what we've always been taught so it's not them. B is just side time side so with a square that works. D is the only one what I'm not sure of or doesn't seem familiar. So personally I'd say D. Good luck!

Answer:

D

explanation

a finds area of rectangle

b area of square

c of rhombus

The equation of the median PM in triangle PQR with vertices P(2, 3), Q(-3, 7), and R(-1, -3) is y = (1/3)x + 7/3.

To find the midpoint of QR, we calculate the average of the x-coordinates and the average of the y-coordinates. The x-coordinate of point M is (-3 + (-1))/2 = -2/2 = -1, and the y-coordinate of point M is (7 + (-3))/2 = 4/2 = 2.

Therefore, the coordinates of point M are (-1, 2). Now, we have two points, P (2, 3) and M (-1, 2), and we can find the equation of the line passing through these points using the point-slope form.

The slope of the line passing through P and M is (2 - 3)/(-1 - 2) = -1/-3 = 1/3. Using the point-slope form, we have:

y - 3 = (1/3)(x - 2)

Expanding and rearranging the equation, we get:

y = (1/3)x + 7/3

Therefore, the equation of the median PM in triangle PQR is y = (1/3)x + 7/3.

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Answer:

y=3x+25

Step-by-step explanation:

For the equation y=3x+5, the slope is 3. Since the line will be parallel to it then this is the slope of the new line as well. Use the point-slope form to write the equation, then simplify and convert into the slope intercept form.

(y-13)=3(x--4)

y-13=3x+12

y=3x+25

Answer:

$4.99

Step-by-step explanation:

20 - 5.03 = 14.97

Since that is how much was paid you then divide by how many socks were bought

14.97 ÷ 3 = 4.99

Answer:

4.99/pair

Step-by-step explanation:

Solve

$20 - $5.03 = $14.97 substract

$14.97 ÷ 3 = $4.99 divide

20 - 5.03 = 14.97 = total cost. 14.97÷3 = 4.99/pair.

Therefore, the cost in dollars and cents for each pair of socks is 4.99/pair.

The solution to the triple integral in spherical coordinates is 22000π. This can be obtained by evaluating the integral in three steps: integrating with respect to r, then with respect to θ, and finally with respect to φ.

To change the triple integral to spherical coordinates, we need to express the integrand and the limits of integration in terms of spherical coordinates.

The given integrand is f(x, y, z) = 6x² + y² + z².

In spherical coordinates, the integrand becomes f(r, θ, φ) = 6(rsinθcosφ)² + (rsinθsinφ)² + (rcosθ)².

The limits of integration are as follows:

- The bounds for r are from 0 to 10, as the region Q is bounded by the upper hemisphere x² + y² + z² = 100.

- The bounds for θ are from 0 to π/2, as we are considering the upper hemisphere.

- The bounds for φ are from 0 to 2π, as φ covers a complete revolution around the z-axis.

The triple integral in spherical coordinates is then given by:

∭Q f(r, θ, φ) r² sinθ dr dθ dφ,

which becomes:

∫(φ=0 to 2π) ∫(θ=0 to π/2) ∫(r=0 to 10) [6(rsinθcosφ)² + (rsinθsinφ)² + (rcosθ)²] r sinθ dr dθ dφ.

To solve the given triple integral, we'll start by evaluating the innermost integral with respect to r, then the middle integral with respect to θ, and finally the outer integral with respect to φ.

The integrand is:

[6(rsinθcosφ)² + (rsinθsinφ)² + (rcosθ)²] r² sinθ

First, let's evaluate the innermost integral with respect to r, while treating θ and φ as constants:

∫(r=0 to 10) [6(rsinθcosφ)² + (rsinθsinφ)² + (rcosθ)²] r² sinθ dr

= ∫(r=0 to 10) [6(sin²θcos²φ)r⁴ + (sin²θsinφ)r⁴ + (cos²θ)r⁴] sinθ dr

= ∫(r=0 to 10) [(6sin²θcos²φ + sin²θsin²φ + cos²θ) r⁴] sinθ dr

= [(6sin²θcos²φ + sin²θsinφ + cos²θ) ∫(r=0 to 10) r⁴] sinθ dr

= [(6sin²θcos²φ + sin²θsin²φ + cos²θ) * (10^5/5)] sinθ

= [(6sin²θcos²φ + sin²θsin²φ + cosθ) * 2 × 10⁵] sinθ

Next, let's evaluate the middle integral with respect to θ, while treating φ as a constant:

∫(θ=0 to π/2) [(6sin²θcos²φ + sin²θsin²φ + cos²θ) * 2 × 10⁵] sinθ dθ

= 2 × 10⁵ ∫(θ=0 to π/2) [6sin²θcos²φ + sin²θsin²φ + cos²θ] sinθ dθ

= 2 × 10⁵ [2/3cos²φ + 1/4 + 1/3]

= 2 × 10⁵ [2/3cos²φ + 7/12]

Finally, let's evaluate the outer integral with respect to φ:

[tex][\int_{0}^{2\pi} 2\times10^5 \left( \frac{2}{3}\cos^2\phi + \frac{7}{12} \right) d\phi \\\\= 2\times10^5 \left( \frac{2}{3}\pi + \frac{7}{12}(2\pi) \right)][/tex]

= 22π × 10000

= 22000π

Therefore, the solution to the given triple integral is 22000π.

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Complete question :

Change the triple integral to spherical coordinates: SIS 6x2 + y2 + z2) av (༴ AV Where Q is bounded by the upper hemisphere: x2 + y2 +22=100 : 21 10 ("S", p's p. sino dpdooo 2T pº sino dododo 21 10 2 3 sino doopde 0 0 0 10 ["S" p2 sino apdoce

Answer:

Marcy paid $4.15

Step-by-step explanation:

Given

Represent hotdogs with x and chips with y.

So, we have:

Jamal

[tex]3x + 2y = 4.85[/tex]

Kenny

[tex]5x + 6y = 9.55[/tex]

See attachment for complete question

Required

Determine the amount for 2x and 3y

From Jamal's and Kenny's orders we have:

[tex]3x + 2y = 4.85[/tex] --- (1)

[tex]5x + 6y = 9.55[/tex] --- (2)

Multiply (1) by 3

[tex]3 * [3x + 2y = 4.85][/tex]

[tex]9x + 6y = 14.55[/tex] --- (3)

Subtract (2) and (3)

[tex]9x - 5x + 6y - 6y = 14.55 - 9.55[/tex]

[tex]9x - 5x = 5[/tex]

[tex]4x = 5[/tex]

Solve for x

[tex]x = \frac{5}{4}[/tex]

[tex]x = 1.25[/tex]

Substitute [tex]x = 1.25[/tex] in [tex]3x + 2y = 4.85[/tex]

[tex]3 * 1.25 + 2y = 4.85[/tex]

[tex]3.75 + 2y = 4.85[/tex]

Solve for y

[tex]y = \frac{4.85 - 3.75}{2}[/tex]

[tex]y = \frac{1.10}{2}[/tex]

[tex]y = 0.55[/tex]

So, the cost of 2x and 3y is:

[tex]Cost = 2x + 3y[/tex]

[tex]Cost = 2*1.25 + 3*0.55[/tex]

[tex]Cost = \$4.15[/tex]

Answer:The probability of the complement of an event is one minus the probability of the event. Since the sum of probabilities of all possible events equals 1, the probability that event A will not occur is equal to 1 minus the probability that event A will occur.

Step-by-step explanation:Complement of an Event: All outcomes that are NOT the event. So the Complement of an event is all the other outcomes (not the ones we want). And together the Event and its Complement make all possible outcomes.

Answer:

Option 1: 4h

Step-by-step explanation:

perimeter of square = 4 × length

h × 4 = 4h

Answer:

Fraction = 120/100 | Decimal = 1.2

Step-by-step explanation:

Fraction:

100% is 100/100 but 120% is 20% over so the fraction is now 120/100 (20% = 20/100)

Decimal:

100% is 1 but as I said earlier, 120% is 20% over so the decimal is now 1.2 (20% = 0.2)

If A is equal to [0, 4] and I is equal to [1, 0], [0, 1], then [0 -  4][1 0] equals 0 and [0 -  4] equals 0 and [2 - 4] equals 0. Accordingly, the eigenvalues of the matrix

[dt/dy] + [0, 4] [x] = [0] can be written as the differential equation above in a matrix. Here, [0, 4] is the coefficient network and [x] is the variable grid. Given, arrangement of differential conditions, dt/dy + 4x = 0. Let [0, 4] be the framework's eigenvalue, and then [0, 4] [x] = [x] => (A-I) [x] = 0, where An represents the coefficient grid, I represents the character lattice, and x represents the variable network.

The determinant of [A-I] is 0 if for a non-trivial solution, [A-I] [x] = 0. On the off chance that An is equivalent to [0, 4] and I is equivalent to [1, 0], [0, 1], then [0 - 4][1 0] equivalents 0 and [0 - 4] equivalents 0 and [2 - 4] equivalents 0. As a result, the matrix's eigenvalues

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They have different end behavior as x approaches -∞ but the same end behavior as x approaches ∞. Option A is correct.

Given that,
Function g is a decreasing exponential function with a y-intercept of 5 and no x-intercept.

Functions are the relationship between sets of values. e g y=f(x), for every value of x there is its exists in a set of y. x is the independent variable while Y is the dependent variable.

The function which is in format f(x) = [tex]e^X[/tex]   where, a is constant and x is variable,  the domain of this exponential function lies   (-∞, ∞).  

Here, the solution shown in the graph implies that they have different end behavior as x approaches -∞ but the same end behavior as x approaches ∞.

Thus, they have different end behavior as x approaches -∞ but the same end behavior as x approaches ∞. Option A is correct.

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