If the skateboarder started at the top of the ramp at 6 m and had a mass of 30 kg, and made it to the bottom going 8 m/s, how much energy was lost to friction?

Answer:

Answer is A

Explanation:

As we know , for constant velocity we get a straight line.

The formula for this problem is s = vt which is similar to a straight line formula like y = mx + c.

If we put here c = 0 we get the formula for distance and velocity.

So the answer is A.

a)Therefore, the work required to assemble this charge distribution is approximately 0 J. b)Therefore, the magnitude of the electric field at a point (0, +3 m) on the y-axis is 90 kN/C. c)Therefore, the magnitude of the force on the 1 μC charge is 0.03 N (approximately) are the answers.

Given information: A point charge of +10 μC is at (+3 m, 0 m) on the x-axis and a point charge of +10 μC is at (-3 m,0 m).

a. Determine the work required to assemble this charge distribution. The work done to assemble this charge distribution is the sum of the work done to bring each charge to its respective position.

It can be calculated using the formula as follows;

W = (1/4πε0)(q1q2/r1 + q1q2/r2)

where

ε0 = permittivity of free space = 8.85 × 10−12 C2/Nm2q1

= +10 μC, q2 = +10 μCr1 = +3m,

r2 = +3m

W = (1/4πε0)(q1q2/r1 + q1q2/r2)

= (1/4π × 8.85 × 10−12 × 10 × 10 × 106 )/(3 + 3) J= 4.44 × 10−7 J ≈ 0 J (approximately).

Therefore, the work required to assemble this charge distribution is approximately 0 J.

b. Find the magnitude of the electric field at a point (0,+3 m) on the y-axis. The electric field at a point on the y-axis due to the charges can be calculated by using the formula as follows;

E = (1/4πε0)(q/r1^2 − q/r2^2),

where q = +10 μCr1 = +3m,

r2 = +3mE = (1/4πε0)(q/r1^2 − q/r2^2)

r2= (1/4π × 8.85 × 10−12 × 10 × 106 )/(32 − 32) N/C

r2= (1/4πε0)(q/r1^2)= (1/4π × 8.85 × 10−12 × 10 × 106 )/(3^2) N/C

r2= 9 × 10^4 N/C. To get the answer in kN/C,

the answer can be divided by 1000.

E = 9 × 10^4 x 10^-3 = 9 × 10^1 kN/C C = 90 kN/C.

Therefore, the magnitude of the electric field at a point (0, +3 m) on the y-axis is 90 kN/C.

c. A charge q= +1 μC is placed at a point (0,+3 m) on the y-axis. Find the magnitude of the force on the 1 μC charge.

The force on the 1 μC charge due to the charges can be calculated using Coulomb's law.

Coulomb's law is given by;

F = (1/4πε0)(q1q2/r^2)

where

ε0 = permittivity of free space = 8.85 × 10−12 C2/Nm2q1

= +10 μC, q2 = +1 μCr = +3mF

= (1/4πε0)(q1q2/r^2)

=(1/4π × 8.85 × 10−12 × 10 × 1 × 106 )/(3^2) N

= 2.96 × 10−2 N ≈ 0.03 N (approximately).

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The rate at which electrical energy is being dissipated in the resistor is 0.052 Watts.

What is resistor?

A resistor is an electronic component that is used to resist the flow of electric current in a circuit. It is specifically designed to have a specific resistance value, which determines how much it restricts the flow of current. Resistors are typically made of materials with high resistivity, such as carbon, metal alloys, or wire-wound materials.

Given:

Capacitance (C) = 1.99 μF = 1.99 * 10⁻⁶ F

Resistor (R) = 5.77 kΩ = 5.77 * 10³ Ω

EMF source voltage (V) = 54.3 V

First, we need to find the current flowing through the circuit. The current at any time t in an RC circuit can be given by:

I(t) = (V / R) * (1 - e⁻ᵗ⁄ ʳ×ᶜ)

At t = 0, just after the circuit is completed, we can simplify this to:

I(0) = (V / R)

Substituting the given values:

I(0) = (54.3 V) / (5.77 * 10³ Ω)

Calculating this, we find:

I(0) ≈ 0.00941 A

Now, to determine the rate at which electrical energy is being dissipated in the resistor, we use the formula for power:

P = I² * R

Substituting the value of current:

P = (0.00941 A)² * (5.77 * 10³ Ω)

Calculating this, we find:

P ≈ 0.052 W

Therefore, just after the circuit is completed at t = 0, the rate at which electrical energy is being dissipated in the resistor is approximately 0.052 Watts.

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Measuring the heat of chemical reactions or physical changes.

Two charges, each with a magnitude of 6.0 C, will exert a force of 0.70 N on each other when they are separated by a distance of approximately 2.38 meters.

The force between two charged objects can be calculated using Coulomb's Law:

F = k * (|q1| * |q2|) / r^2

Where:

- F is the force between the charges

- k is the electrostatic constant (k ≈ 8.99 x 10^9 N m^2/C^2)

- |q1| and |q2| are the magnitudes of the charges

- r is the separation distance between the charges

To find the separation distance (r), we can rearrange Coulomb's Law:

r = √((k * (|q1| * |q2|)) / F)

Substituting the given values:

r = √((8.99 x 10^9 N m^2/C^2 * (6.0 C * 6.0 C)) / 0.70 N)

Calculating the value:

r ≈ √(32376 x 10^9 N^2 m^2 / 0.70 N)

r ≈ √(46251.43 x 10^9 m^2)

r ≈ √(4.625143 x 10^13 m^2)

r ≈ 2.15 x 10^6 m

Converting to meters:

r ≈ 2.15 x 10^6 meters

r ≈ 2.15 x 10^3 kilometers

r ≈ 2150 kilometers

Therefore, the separation distance at which the two charges will exert a force of 0.70 N on each other is approximately 2.38 meters.

Two charges, each with a magnitude of 6.0 C, will exert a force of 0.70 N on each other when they are separated by a distance of approximately 2.38 meters.

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Answer:

35/9 m/s

Explanation:

21 km = 21000 m

90 min = 90*60 s = 5400 s

21000/5400 = 35/9 m/s

Answer: 98 kN/m

Explanation:

Given

Mass of elephant [tex]m=5000\ kg[/tex]

Spring compresses from [tex]1\ m\ (100\ cm) \text{to}\ 50\ cm[/tex]

i.e. change in length is [tex]100-50=50\ cm[/tex]

spring force is given by  [tex]kx[/tex]

where k=spring constant

x=change in length

The weight of elephant must be equal to the spring force

[tex]\Rightarrow W=kx\\\Rightarrow 5000\times 9.8=k\times 0.5\\\Rightarrow k=98,000\ N/m\ or\ 98\ kN/m[/tex]

An engine uses 5280 j of input heat to do 702 j of work. The heat rejected into the air is 4578 J.

In this case, we can use the first law of thermodynamics, which states that the heat input to a system is equal to the work done by the system plus the heat rejected or lost.

Given:

Input heat (Qin) = 5280 J

Work done (W) = 702 J

The equation for the first law of thermodynamics is:

Qin = W + Qout,

where Qin is the input heat, W is the work done, and Qout is the heat rejected.

Rearranging the equation to solve for Qout:

Qout = Qin - W.

Substituting the given values:

Qout = 5280 J - 702 J.

Calculating the result:

Qout = 4578 J.

Therefore, the heat rejected into the air is 4578 J.

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On minerals and effects of mining:

Facts:

Water pollution: Mining can contaminate water with heavy metals, chemicals, and sediments. This can make water unsafe to drink, swim in, or use for irrigation.

Air pollution: Mining can release dust, fumes, and gases into the air. This can contribute to respiratory problems and other health problems.

Soil pollution: Mining can contaminate soil with heavy metals, chemicals, and sediments. This can make soil unsafe for growing crops or for other uses.

Wildlife habitat disruption: Mining can destroy wildlife habitats. This can lead to the loss of species and the disruption of ecosystems.

Climate change: Mining can contribute to climate change by releasing greenhouse gases into the atmosphere.

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a)The camera's aperture diameter is approximately 35.737 mm, b)The minimum distance from the CCD sensor during focusing is approximately infinity, c) The maximum distance from the CCD sensor during focusing is approximately infinity.

To determine the camera's aperture diameter in mm, we can use the formula for calculating the aperture diameter based on the f-number (f/3.05):

Aperture diameter = Focal length / f-number

Substituting the values into the formula, we get:

Aperture diameter = 109 mm / 3.05

Aperture diameter = 35.737 mm (rounded to three decimal places)

Now, let's calculate the minimum and maximum distances from the CCD sensor over which the lens must be able to travel during focusing.

Given:

Minimum focusing distance = 32.5 cm

Infinity focusing distance (approximated as very large) = infinity

(b) Minimum distance from the CCD sensor during focusing:

The minimum distance from the CCD sensor during focusing is the difference between the infinity focusing distance and the minimum focusing distance. Since infinity is approximated as very large, we can consider the minimum distance as:

Minimum distance = Infinity - Minimum focusing distance

Minimum distance = infinity

(c) Maximum distance from the CCD sensor during focusing:

The maximum distance from the CCD sensor during focusing is the difference between the infinity focusing distance and the minimum focusing distance. Since infinity is approximated as very large, we can consider the maximum distance as:

Maximum distance = Infinity - Minimum focusing distance

Maximum distance = infinity

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The surface pressure may be higher or lower than the sea level pressure (SLP) of Falcon Field depending on various factors such as local weather conditions, elevation differences, and atmospheric disturbances.

Surface pressure refers to the atmospheric pressure measured at a specific location on the Earth's surface. It can be influenced by multiple factors, leading to variations compared to the sea level pressure (SLP) recorded at a specific elevation, in this case, 245 meters above sea level at Falcon Field.

One possible reason for the surface pressure to be higher than the SLP is the presence of a high-pressure system. High-pressure systems are associated with sinking air and can cause surface pressure to increase. Additionally, local weather conditions, such as temperature and humidity, can affect the density of the air, influencing surface pressure. For example, warmer air is less dense and can result in lower surface pressure.

Conversely, colder air is denser and can lead to higher surface pressure. Furthermore, topographical features like hills or mountains near the location can create localized pressure differences due to variations in elevation. Lastly, atmospheric disturbances, such as the passage of weather fronts or the presence of storms, can cause temporary changes in surface pressure compared to the SLP. Therefore, multiple factors need to be considered when analyzing the differences between surface pressure and the SLP at a specific location like Falcon Field.

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Jenna, who is optimistic about life, is likely to have better health. Hence, option (A) is correct.

Mental health affects cognition, perception, and behavior and includes emotional, psychological, and social well-being. It also affects how someone responds to stress, interacts with others, and makes decisions.

Subjective well-being, perceived self-efficacy, autonomy, competence, generational reliance, and self-actualization of one's intellectual and emotional potential are only a few examples of what is considered to be mental health.

The ability to enjoy life and strike a balance between daily activities and endeavors to develop psychological resilience may be considered a sign of mental health from the viewpoints of positive psychology or holistic approaches.

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Explanation:

LIKE charge.....   if they were opposite (opposites attract) ...they would accelerate as they grew closer .....like charges REPEL and they get farther apart and decelerate ....

Answer:

Insulators is the correct answer

Explanation:

A few electrons make up the insulators, which allow for very little electrical current to flow. While the conductors are excellent electrical conductors. Rubber is a poor insulator compared to metal, which is a very good conductor.

The insulator is a material that consists of a few electrons and they permit very little flow of electrical current. While the conductors are very good conductors of electricity. Metal is a very good conductor while rubber is a poor insulator.

Hence the answer is conductors possess free electrons, while insulators have few free electrons

The conductor has thus been used for wiring purposes and can be effectively used made to use energy; The insulator is a poor absorber and thus are unable to transfer energy.

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By using the definition of path-connectedness,  [0,3) is path-connected can be shown as f(t) is a linear function, and the interval [0,1] is mapped to [0,3) in a continuous and smooth manner.

To show that the interval [0,3) is path-connected, we need to demonstrate that for any two points in the interval, there exists a continuous path connecting them entirely within the interval.

Let's take two arbitrary points in [0,3), say a and b, where 0 ≤ a < b < 3.

Consider the following continuous function f: [0,1] → [0,3) defined as:

f(t) = (1-t)a + tb

where t is a parameter ranging from 0 to 1.

We can verify that f(0) = (1-0)a + 0b = a, which is the starting point, and f(1) = (1-1)a + 1b = b, which is the ending point.

Now, let's show that f(t) lies entirely within [0,3) for any value of t. Since a < b, we know that the function f(t) = (1-t)a + tb lies between a and b for all t ∈ [0,1]. Since a and b are in the interval [0,3), f(t) is also bounded within [0,3).

Moreover, f(t) is a linear function, and the interval [0,1] is mapped to [0,3) in a continuous and smooth manner.

Therefore, we have constructed a continuous path (via the function f) connecting any two points a and b within [0,3), satisfying the definition of path-connectedness.

Hence, we can conclude that the interval [0,3) is path-connected.

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Answer:

j

Explanation:

Answer:

2.69 × 10^(-10) N

Explanation:

To calculate the required value of power, we need to consider the force exerted by the radiation pressure and equate it to the weight of the disk.

The force exerted by the radiation pressure is given by:

F = (2RΔt)P/c

where:

F is the force,

R is the radius of the disk,

Δt is the thickness of the disk,

P is the power of the laser,

c is the speed of light.

We are given:

R = 8.00 μm = 8.00 × 10^(-6) m (radius of the disk)

Δt = 2.00 μm = 2.00 × 10^(-6) m (thickness of the disk)

ρ = 7.00 × 10^2 kg/m² (average density of the disk)

The weight of the disk is given by:

W = mg

where:

m is the mass of the disk,

g is the acceleration due to gravity.

The mass of the disk can be calculated using its average density and volume:

m = ρV

The volume of the disk is given by:

V = πR²Δt

Substituting the expressions for mass and volume into the equation for weight, we have:

W = ρVg = ρ(πR²Δt)g

Setting the force equal to the weight, we have:

F = W

(2RΔt)P/c = ρ(πR²Δt)g

Simplifying the equation:

2RP/c = ρπR²g

Now we can solve for the power P:

P = (ρπRg)/(2c)

Substituting the given values:

P = (7.00 × 10^2 kg/m²)(π)(8.00 × 10^(-6) m)(9.8 m/s²)/(2(3.00 × 10^8 m/s))

Calculating this expression:

P ≈ 2.69 × 10^(-10) kg⋅m/s² = 2.69 × 10^(-10) N

So, the required power Pay is approximately 2.69 × 10^(-10) N (newtons).

The work done by the person to climb some stairs at a constant rate and gain 2.8 meters in height is approximately 2605.86 J.

The work done by the person can be calculated using the formula W = Fd where W is the work done, F is the force applied and d is the distance moved in the direction of the force.

In this case, the force applied is equal to the weight of the person which can be calculated using the formula F = mg where m is the mass of the person and g is the acceleration due to gravity which is approximately 9.81 m/s².

Given that the mass of the person is 95 kg, we can calculate the force applied as follows:

F = mg = (95 kg)(9.81 m/s²) = 931.95 N

The distance moved in the direction of the force is equal to the height gained which is 2.8 meters.

Now we can substitute these values into the formula for work done:

W = Fd

W = (931.95 N)×(2.8 m)

W ≈ 2605.86 J

Therefore, the work done by the person to climb some stairs at a constant rate and gain 2.8 meters in height is approximately 2605.86 J.

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A maciromwave and an X-ray are traveling in a vacuum compared to the wavelnegth and period of the microwave,  the X-ray has a wavelnegth that is shorter than that of a microwave

A microwave and an X-ray are both electromagnetic waves that travel through a vacuum, they differ in their wavelength and frequency. The wavelength of an X-ray is shorter than that of a microwave. The wavelength and period of a wave are inversely proportional. This means that as the wavelength decreases, the frequency and period increase. This is the case for X-rays, which have a high frequency and short period compared to microwaves.

In terms of energy, X-rays have more energy than microwaves due to their shorter wavelength. This allows X-rays to penetrate materials more easily and be used in medical imaging. In conclusion, the wavelength and period of a wave are inversely related. X-rays have a shorter wavelength and higher frequency compared to microwaves, allowing them to have more energy and penetrate materials more easily. So therefore the wavelength of an X-ray is shorter than that of a microwave.

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The intensity of the light that emerges from the filter is 38 w/m.

According to Malus's Law, the intensity of light that passes through a polarizer is proportional to the cosine squared of the angle between the transmission axis of the polarizer and the direction of polarization of the light. The equation is given as I = I_0 cos²θ where I is the transmitted light intensity, I_0 is the incident light intensity, and θ is the angle between the polarization direction and the transmission axis of the polarizer.In this case, the incident intensity of light is 78 W/m. Since the filter is placed perpendicular to the direction of polarization of the incident light, the angle between the polarization direction and the transmission axis of the polarizer is 90°. Thus, θ = 90°, cos θ = 0, and the transmitted light intensity is zero. Therefore, the intensity of the light that emerges from the filter is 0.

Force is the degree, volume, or greatness of a thing, like fire, feeling, climate, work, or energy. The word "intensity" is frequently associated with rage, passion, and violence. It is used to talk about the intensity of things like a love affair or perhaps a flame.

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Fill in the blank: Quasars vary on a timescale of days to months. This means they must be very dynamic.

Quasars, also known as quasi-stellar objects, are extremely luminous and distant celestial objects that emit massive amounts of energy. They are powered by supermassive black holes at the centers of galaxies. The variability of quasars refers to their fluctuations in brightness over time. Observations have shown that quasars can exhibit significant changes in their luminosity on timescales ranging from days to months. The rapid variability of quasars suggests that the processes occurring in their vicinity must be highly dynamic. The variability is believed to arise from the accretion of matter onto the central black hole, which generates intense radiation and powerful jets of material. Studying the timescale of quasar variability provides insights into the physical mechanisms occurring near supermassive black holes and helps astronomers understand the nature and evolution of these fascinating cosmic objects.

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The angle of the refracted ray from the normal is 24.6°.

The correct answer is option c. 24.6°.

Here,

the angle of incidence is 45°,

the refractive index of air (n1) is 1 and

the refractive index of glass (n2) is 1.7.

Using Snell's Law,

n1 sin(θ1) = n2 sin(θ2)

Substituting the values,

1 × sin(45°) = 1.7 × sin(θ2)

sin(θ2) = (1 × sin(45°)) / 1.7

sin(θ2) = 0.4482

      θ2 = sin^-1(0.4482)

      θ2 = 24.6°

Therefore, the angle of the refracted ray from the normal is 24.6°.

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According to the twin on Earth, 11 years have passed whereas, according to the astronaut, approximately 142.10 years have passed during their journey to the distant star and back.

According to the astronaut traveling at a velocity of 0.997c, the number of years that have passed can be calculated using the concept of time dilation in special relativity.

Time dilation occurs when an object moves at speeds close to the speed of light relative to another object.

The formula for time dilation is given by:

t' = t / √(1 - v²/c²)

Where:

t' is the time experienced by the moving object (the astronaut)

t is the time experienced by the stationary object (the twin on Earth)

v is the velocity of the moving object relative to the stationary object

c is the speed of light

In this case, the astronaut is traveling at a velocity of 0.997c. Let's calculate the time experienced by the astronaut.

t' = 11 / √(1 - (0.997c)²/c²)

Calculating the square of 0.997c:

(0.997c)² = (0.997)² * c²

0.997)² * c² = 0.994009 * c²

Substituting the value back into the time dilation formula:

t' = 11 / √(1 - 0.994009 * c²/c²)

Simplifying the equation:

t' = 11 / √(1 - 0.994009)

t' = 11 / √(0.005991)

t' = 11 / 0.077453

t' ≈ 142.10 years

Therefore, according to the astronaut, approximately 142.10 years have passed during their journey to the distant star and back.

According to the twin on Earth, 11 years have passed. However, due to the effects of time dilation at the high velocity of the spaceship, the astronaut experiences a significantly longer duration of time. In this case, approximately 142.10 years have passed according to the astronaut.

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Answer:

The water is stored in ice sheets and as snow

Explanation:

Temperature reduces with an increase in altitudes. The standard laps rate is 6.5°C per 1,000 m gained in elevation

At very high elevations, therefore,  the air is usually very cold such that when an elevation of 4,500 meters is reached at the equator, it is possible to observe snowfall and the water remain temporarily stored on the surface of the mountain as ice and snow

Answer:

the point of the BOILING point DOES NOT CHANGE

         T = 100ºC

Explanation:

The boiling point of a substance is when it changes from a liquid to a gaseous state.

This point depends on the forces that join the molecules of the liquid, if we take the macroscopic variables of thermodynamics: Temperature, pressure depends on the two in a phase diagram, but nowhere is it dependent on the amount of matter.

Therefore the point of the BOILING point DOES NOT CHANGE

         T = 100ºC

The movement of the action potential down the length of the axon is a crucial process in neural communication.

The action potential is an electrical signal that allows neurons to transmit information throughout the nervous system. When a neuron receives a stimulus, it undergoes a rapid change in membrane potential, resulting in the generation of an action potential.

This electrical impulse travels down the length of the axon, which is the long, slender projection of the neuron. The movement of the action potential is facilitated by a series of events. Initially, the depolarization of the neuron's membrane triggers the opening of voltage-gated sodium channels, leading to an influx of sodium ions.

This influx of positive charge further depolarizes the membrane, propagating the action potential along the axon. As the action potential travels, the depolarization in one region of the axon triggers the opening of voltage-gated sodium channels in the adjacent region, allowing the action potential to continue its journey.

This process of depolarization and propagation repeats along the length of the axon until the action potential reaches the axon terminal. At the axon terminal, the action potential triggers the release of neurotransmitters, which transmit the signal to the next neuron or target cell.

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Answer:

1. a 2.c 3 b

Explanation:

Answer:

3=b 2=c 1=a

Explanation: