In a recent year, a research organization found that 228 of the 350 respondents who reported earning less than $30,000 per year said they were social networking users. At the other end of the income scale, 290 of the 472 respondents reporting earnings of $75,000 or more were social networking users. Let any difference refer to subtracting high-income values from low-income values. Complete parts a through d below. Assume that any necessary assumptions and conditions are satisfied. a) Find the proportions of each income group who are social networking users. The proportion of the low-income group who are social networking users is 0.6514 The proportion of the high-income group who are social networking users is 0.6144 (Round to four decimal places as needed.)

Answer:

17

Step-by-step explanation:

by Pythagoras

[tex]8 {}^{2} + 15 {}^{2} = {x}^{2} [/tex]

x=17

Answer: See attachment below (graphing)

Step-by-step explanation:

INFORMATION:

The slope-intercept is when y=mx+b

mx=the slope

b=y-intercept

REPHRASE EQUATION:

y=mx+b

y=-3-x

y=(-1)x-3

CONCLUSION:

Slope=-1

Y-intercept=-3

Hope this helps!! :)

Please let me know if you have any questions

Answer:

the graph​: y = -3 - x

Answer:

Step-by-step explanation:

How to write numbers in standard form:

Write the first number 8.

Add a decimal point after it: 8.

Now count the number of digits after 8. There are 13 digits.

So, in standard form: 81 900 000 000 000 is 8.19 × 10¹³

In a two-tail hypothesis test, if the calculated test statistic (z-statistic) is -1.58 and the level of significance is used, the decision will depend on comparing the z-statistic to the critical values of the standard normal distribution corresponding to the desired level of significance.

Explanation: In a two-tail hypothesis test, the null hypothesis assumes that there is no significant difference between the sample and population parameters. The alternative hypothesis, on the other hand, suggests a significant difference. The level of significance, denoted as α, determines the critical values that divide the rejection and non-rejection regions.

If the calculated test statistic, in this case -1.58, falls within the rejection region, which is determined by the critical values, we reject the null hypothesis. If the test statistic falls outside the rejection region, we fail to reject the null hypothesis.

To make a decision, we compare the z-statistic to the critical values corresponding to the level of significance. If the z-statistic of -1.58 falls outside the critical values, it means it is not extreme enough to reject the null hypothesis, and we fail to reject it. However, if the z-statistic falls within the critical values, we reject the null hypothesis in favor of the alternative hypothesis.

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Answer:

Hey kid stop cheating XDDDDDDDDDDDDDDDDDDD

Step-by-step explanation:

The probability of F'UA is 0.9458.

According to the given data; the probability of ovont F is 0.2907, the probability of event A is 0.1849 and the probability of the driver is female and is 24 years old or less is 0.0542.

Here are the required probabilities;

a. The probability of FUA:F: Female U: 24 years old or less A: Fatal vehicle accident We can find the probability of FUA using the formula; P(FUA) = P(F ∩ U ∩ A)

We know that the probability of the driver in a fatal vehicle accident is female is 0.2907P(F) = 0.2907 Also, we know that the probability that the driver is 24 years old or less is 0.1849.P(U) = 0.1849

We also know that the probability that the driver is female and is 24 years old or less is 0.0542.P(F ∩ U) = 0.0542Now we can use the formula; P(FUA) = P(F ∩ U ∩ A)= P(F) x P(U) x P(A|FU)= 0.2907 × 0.1849 × (0.0542 / 0.2907)= 0.0542

So, the probability of FUA is 0.0542.

b. The probability of F'UA: It can be calculated by using the complement of FUA.P(F'UA) = 1 - P(FUA)= 1 - 0.0542= 0.9458

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Answer:

Step-by-step explanation:

Given data: The probability that the driver in a fatal vehicle accident is female (event F) is 0.2907. The probability that the driver is 24 years old or less (event A) is 0.1849. The probability that the driver is female and is 24 years old or less is 0.0542.

a) The probability of FUA is 0.4214.

b) The probability of F'UA is 0.5786.

a) The probability of FUA can be calculated as follows:

P(FUA) = P(F) + P(A) - P(F ∩ A) [By Addition Law], Where P(F) = 0.2907, P(A) = 0.1849, P(F ∩ A) = 0.0542.

By putting these values in the above equation we get:

P(FUA) = P(F) + P(A) - P(F ∩ A)

= 0.2907 + 0.1849 - 0.0542

= 0.4214

Therefore, the probability of FUA is 0.4214.

b) The probability of F'UA can be calculated as follows:

P(F'UA) = P(F' ∩ A') [By Complement Law], Where

P(F' ∩ A') = 1 - P(FUA)

= 1 - 0.4214

= 0.5786

Therefore, the probability of F'UA is 0.5786.

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Answer:

15 ft

Step-by-step explanation:

If every 1/4 of an inch is a foot, than every inch is 4 feet.

1 inch = 4ft

3 inches = 12ft

1/4 + 1/4 + 1/4 = 3/4

3/4=3 ft

12+3=15ft

Answer:

A. Strong

Step-by-step explanation:

I took the test

Have a great day! ;)

This trend line is a strong fit for these data. Then the correct option is A.

A linear system is one in which the parameter in the equation has a degree of one. It might have one, two, or even more variables.

Bridget has captured many purple-footed bog frogs.

She weighs each one and then counts the number of yellow spots on its back.

This trend line is a strong fit for these data.

Because all the points are closer to the line.

Then the correct option is A.

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Jordan has run 21/4 miles after 6 days.

Jordan runs to the end of his street and back home every day and the total distance of a trip to the end of the street and back home is 7/8 mile.

Since Jordan runs to the end of the street and back home every day, the distance he runs in one day is given by;

2 × (distance to the end of the street)

= 7/8 mile (distance to the end of the street)

= 7/16 mile

The distance Jordan runs in 6 days is;

6 × (distance to the end of the street and back home)

= 6 × 7/8 miles

= 42/8 miles

= 21/4 miles

Therefore, Jordan has run 21/4 miles after 6 days.

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Answer:

8. center: (-7,5)

radius: 9

Step-by-step explanation:

8. to find the center, you need to get the equation in the form of (x-h)^2+(y-k)^2=r^2

you can do this by completing the square:

x^2+y^2+14x-10y-7=0

x^2+14x+49+y^2-10y+25=7+49+25

(x+7)^2+(y-5)^2=81

so, the center is (-7,5) and the radius is 9

The center of the circle is point: C=(−2,−7).

Answer: i would say B because it makes the most sence

Step-by-step explanation:

The estimated flow rate is approximately 3.94 cm3/s.

To estimate the flow rate at t=9s, we can use the formula:

flow rate = change in volume / change in time.

Using the data given, we can calculate the change in volume and change in time for the interval between t = 8s and t = 11s.

Change in volume = 36.04 - 24.23 = 11.81 cm³

Change in time = 11 - 8 = 3s

Now, we can plug these values into the formula to find the flow rate:

flow rate = change in volume / change in time = 11.81 cm3 / 3s ≈ 3.94 cm3/s

Therefore, the estimated flow rate at t=9s is approximately 3.94 cm3/s.

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Answer:

hh

Step-by-step explanation:

Step-by-step explanation:

Reduce 5/35 to lowest terms

The simplest form of 535 is 17.

Answer:

1/7

Step-by-step explanation:

divide both sides by 5

The variance of the sampling distribution of means, on the other hand, is equal to the variance of all possible sample means of the same size taken from the population.

Since a sample size is always less than the population size, the variance of the population distribution is greater than the variance of the sampling distribution of means.

Therefore, option B is correct.
The probability of selecting one data value less than 190 IS (C)31%

When the variances of the population distribution and the sampling distribution of means are compared, the (B) population variance is larger than the sampling distribution variance.

The probability of selecting one data value less than 190 given the mean and standard deviation of a population of 200 and 20 respectively is 31% (option C).

Solution: Given,

mean (μ) = 200,

standard deviation (σ) = 20

We need to find the probability of selecting one data value less than 190.

P(x < 190) = ?

Z = (X - μ)/σ

Taking X = 190,

Z = (190 - 200)/20

= -0.5

From the standard normal table, the probability of

Z = -0.5 is 0.3085

Therefore,

P(x < 190) = P(Z < -0.5)

= 0.3085

= 31%

Hence, option C is correct.

When the variances of the population distribution and the sampling distribution of means are compared, the population variance is larger than the sampling distribution variance.

This can be explained as follows;

The population distribution is the distribution of an entire population, while the sampling distribution of the mean is the distribution of the means of all possible samples of a specific size drawn from that population.

The variance of the population distribution is equal to the variance of a single observation of the population.

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Answer:

Taxes are money paid to the government, you need to pay these for the army , teachers, and it forms a better economy etc.!:) Have a nice day friend.

Step-by-step explanation:

rylee1015, it does matter because you are copying answers just to get points, and it might be wrong which is not fair, so stop it!!!:(

Answer:

The answer is A 56.25

Step-by-step explanation:

Since a square has 4 sides, divide 225 by 4 to get 56.25. To check your answer multiply 56.25 x 4 to get 225 in^2.

Hope this helps! Pls mark Brainliest!

Answer:

a.56.25

Step-by-step explanation:

Answer:

Step-by-step explanation:

As triangles are similar

The ratio of the sides must be equal

so..

[tex]\frac{x}{8} =\frac{9}{5}[/tex]

[tex]x=\frac{9*8}{5}[/tex]

[tex]x=14.4[/tex]

hope it helps...

have a great day!!

Answer:

Each month Bill reads 3 novels so you get

N = 3m

If you plug in 6 for m we get

N = 3(6) = 18

Bill needs to read 18 novels in 19 months

Step-by-step explanation:

Answer: She's wrong.

Step-by-step explanation:

Numbers of hours used in solving homework last week = 15

Numbers of hours used in solving homework this week = 18

Percentage increase = (18 - 15) / 15 × 100

= 3/15 × 100

= 1/5 × 100

= 20%

Since Maxie said that she spent 120% more time doing homework this week, she's wrong. She only spent 20% more.

Answer:

C. -6 ≤ y < ∞

C is correct

Step-by-step explanation:

edmentum

Answer:

D)

Step-by-step explanation:

Sana maka tulong po

shout out tga pagadian

Answer:

3

Step-by-step explanation:

To calculate the magnitude of the gravitational force A exerts on B and B exerts on A, we can use Newton's law of universal gravitation:

[tex]F = (G * m1 * m2) / r^2[/tex]

where F is the gravitational force, G is the gravitational constant (approximately [tex]6.67430 *10^-11 N m^2 / kg^2)[/tex], m1 and m2 are the masses of the two spheres, and r is the distance between their centers.

For the force A exerts on B:

[tex]F_AB = (G * m_A * m_B) / r^2[/tex]

Substituting the given values: m_A = 7.5 kg, m_B = 6.3 kg, and r = 0.59 m:

F_AB = (6.67430 × 10^-11 N m^2 / kg^2) * (7.5 kg) * (6.3 kg) / (0.59 m)^2

Calculating the above expression gives the magnitude of the gravitational force A exerts on B.

For the force B exerts on A, we use the same formula:

[tex]F_BA = (G * m_A * m_B) / r^2[/tex]

Substituting the given values: m_A = 7.5 kg, m_B = 6.3 kg, and r = 0.59 m:

[tex]F_BA = (6.67430 * 10^-11 N m^2 / kg^2) * (6.3 kg) * (7.5 kg) / (0.59 m)^2[/tex]

Calculating the above expression gives the magnitude of the gravitational force B exerts on A.

To find the distance between the centers of the spheres when the force between them is 3.50 times 10^-9 N, we rearrange the formula to solve for r:

r = √((G * m_A * m_B) / F)

Substituting the given values: m_A = 7.5 kg, m_B = 6.3 kg, and F = 3.50 × 10^-9 N:

r = √[tex]((6.67430 * 10^-11 N m^2 / kg^2) * (7.5 kg) * (6.3 kg) / (3.50 *10^-9 N))[/tex]

Calculating the above expression gives the distance between the centers of the spheres.

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Answer:

8 × 10⁻⁴

Step-by-step explanation:

The probability of finding four or more tanks in the system at any time is approximately 0.95. The probability of having 6 or more tanks in the system is approximately 0.77.

A. The utilization of the test station is calculated by dividing the average service rate (1 tank per 8 minutes) by the arrival rate (1 tank every 16 minutes). Utilization = Service rate / Arrival rate = 1/2 = 0.5 or 50%.

B. The probability that a tank has to wait in the queue prior to testing can be calculated using the queuing theory formula for the M/M/1 queue. In this case, the utilization (ρ) is 0.5. The formula for the probability of waiting in the queue (Pw) is Pw = ρ^2 / (1 - ρ) = 0.5^2 / (1 - 0.5) = 0.25 / 0.5 = 0.5 or 50%.

C. The mean time a tank spends in the queue can be calculated using Little's Law, which states that the mean number of customers in a stable system (L) is equal to the arrival rate (λ) multiplied by the mean time spent in the system (W). In this case, L = λ * W. The mean number of tanks in the queue (Lq) can be calculated using Lq = λ * Wq, where Wq is the mean time spent in the queue. Given λ = 1/16 tanks per minute and Lq = 8 tanks, we can rearrange the equation to solve for Wq: Wq = Lq / λ = 8 / (1/16) = 128 minutes / 16 = 8 minutes.

D. The mean time a tank spends in the system (queue + test) is equal to the mean time spent in the queue (Wq) plus the mean service time (1/8 tanks per minute). Therefore, the mean time in the system (Ws) is Ws = Wq + 1/μ = 8 + 1/8 = 8.125 minutes.

E. The mean number of tanks expected to be in the queue at any time can be calculated using Little's Law: Lq = λ * Wq. Given λ = 1/16 tanks per minute and Wq = 8 minutes, we can calculate Lq: Lq = (1/16) * 8 = 0.5 tanks.

F. The mean number of tanks expected to be in the system at any time can be calculated using Little's Law: L = λ * Ws. Given λ = 1/16 tanks per minute and Ws = 8.125 minutes, we can calculate L: L = (1/16) * 8.125 = 0.507 tanks.

G. The probability of finding four or more tanks in the system at any time can be calculated using the Poisson distribution formula. By summing the probabilities for four, five, and more tanks, we get 0.043.

H. The probability of having 6 or more tanks in the system can also be calculated using the Poisson distribution formula, which results in a probability of 0.002.

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