Answer:
A. Known variables include
Wavelength = 600nm
Theta= 65°
m= 2
B.
d= m x wavelength / sin theta
= 2 * 600*10^-9 /sin 65°
= 1.3*10^-6m
C.
N = 1/d
So N = 1/1.3*10^-6m
=76.9 lines per micro meter
What unit is time usually measured in?
according to the law , naturalized amrican citizens
what will happen to the fieldof view for each resultant magnification as you change objectives from 4 to 10 to 43
Answer:
The field of view is reduced.
Explanation:
Given that,
The field of view for every resultant magnification like you change objectives from 4 to 10 to 43.
We know that,
Field of view :
When the view is observed at a point in a defined field then these field called field of view.
The normal angle of field of view is 90°.
The formula of field of view is define as,
[tex]field\ of\ view = \dfrac{field\ number}{magnification}[/tex]
We can say that,
The field of view is inversely proportional to the magnification.
When magnification is low then field of view will be large.
When magnification is higher then field of view will be small .
According to question,
When the magnification adjust from 4 to 10 to 43, the field of view is reduced.
Hence, The field of view is reduced.
What is the magnite of the net displacement of the mouse?
Complete Question
A field mouse trying to escape a hawk runs east for 5.0m, darts southeast for 3.0m, then drops 1.0m down a hole into its burrow. What is the magnitude of the net displacement of the mouse?
Answer:
The values is [tex]s = 7.49 \ m[/tex]
Explanation:
From the question we are told that
The distance it travels eastward is [tex]x = 5.0 \ m[/tex]
The distance it travel towards the southeast is [tex]l = 3.0\ m[/tex]
The distance it travel towards the south is [tex]z = 1 \ m[/tex]
Let x-axis be east
y-axis south
z-axis into the ground
The angle made between east and south is [tex]\theta = 45^o[/tex]
The displacement toward x-axis is
[tex]x = 5 + 3cos(45)[/tex]
[tex]x = 7.12[/tex]
The displacement toward the y-axis is
[tex]y = 3 * sin (45)[/tex]
[tex]y = 2.123[/tex]
Now the overall displacement of the rat is mathematically evaluated as
[tex]s = \sqrt{7.12^2 + 2.12^2 + 1^2}[/tex]
[tex]s = 7.49 \ m[/tex]
Which graph shows a negative acceleration
Answer:
It's d on edg
Explanation:
Lightning occurs when there is a flow of electric charge (principally electrons) between the ground and a thundercloud. The maximum rate of charge flow in a lightning bolt is about 20,000 C/s this lasts for 100 μs or less.1. How much charge flows between the ground and the cloud in this time? (Q= ? C)2. How many electrons flow during this time? (n_e = ?)
Answer:
a
The charge is [tex]Q = 2.0*10^8 \ C[/tex]
b
The number of electrons [tex]N = 1.25 *10^{27} \ electrons[/tex]
Explanation:
From the question we are told that
The maximum rate of charge flow is [tex]\frac{dq}{dt} = I = 20000 \ C/s[/tex]
Here I means current
The time interval is [tex]t=100 \mu s = 100*10^{-6}[/tex]
Generally the amount of charge is mathematically represented as
[tex]Q = \frac{I}{t}[/tex]
=> [tex]Q = \frac{20000}{ 100*10^{-6}}[/tex]
=> [tex]Q = 2.0*10^8 \ C[/tex]
The number of electrons that flow during that time is evaluated as
[tex]N = \frac{Q}{e}[/tex]
Here e is the charge on a single electron with value [tex]e= 1.60*10^{-19} \ C[/tex]
So
[tex]N = \frac{2.0*10^8}{ 1.60*10^{-19}}[/tex]
[tex]N = 1.25 *10^{27} \ electrons[/tex]
You are driving along the New York State Thruway in a line of cars all travelling at a constant speed of 108.5 km/hr. The car in front of you applies its brakes for maximum acceleration. You then apply your brakes to achieve the same maximum acceleration after only a 1 s delay due to reaction time. What distance behind the car in front of you must you be to avoid a collision?
Answer:
Car first should be 30.13 m behind the second car.
Explanation:
Given that,
Constant speed = 108.5 Km/hr
Time = 1 sec
Let the distance covered by second car S and by first car S'
We need to calculate the distance covered by second car
Using equation of motion
[tex]S=ut-\dfrac{1}{2}at^2[/tex].....(I)
The distance covered by first car to avoid collision
[tex]S''=S'+S[/tex]
Put the value into the formula
[tex]S'+S=ut+ut-\dfrac{1}{2}at^2[/tex]...(II)
We need to calculate the distance covered by first car
Using equation (I) and (II)
[tex]S'=ut[/tex]
Put the value into the formula
[tex]S'=108.5\times\dfrac{5}{18}\times1[/tex]
[tex]S'=30.13\ m[/tex]
Hence, Car first should be 30.13 m behind the second car.
A 68 kg deer has a momentum of 952 kg∙m/s. What is its velocity?
All we need to do is divide the momentum and weight to find the velocity:
v = m / w
Solve using the values we are given.
v = 952/68 = 14 m/s
Best of Luck!
What is a primary source?
Answer:
provides a first hand account of an event or time period and are considered to be authoritative
Answer:
main source
Explanation:
A rigid rod of length L rotates about an axis perpendicular to the rod, with one end of the rod fixed to the axis. Which of the following must always be equal at all points on the rod?
1. Angular position.
2. Angular velocity.
3. Angular acceleration.
4. Tangential acceleration.
A. 1 and 2.
B. 1, 2 and 4.
C. 1 and 3.
D. 1, 2, 3 and 4.
Answer:
D
Explanation:
The Angular Position: The angular position is also called the angular displacement, and it is the angle through which a point revolves around the centre line that has been rotated in a particular manner about a given axis.
The Angular Velocity: The angular velocity of an object is the measure of the speed, or say, how fast an object rotates at one point with respect to a point.
The Angular Acceleration: This is very simple as it's a derivative of angular velocity. They both share the same relationship velocity and acceleration share. Angular acceleration is the rate of change of angular velocity.
The only options that are equal at all points on the rod are;
1. Angular position.
2. Angular velocity.
3. Angular acceleration.
Let us look at each of the options;
1) Angular Position: This is also referred to as angular displacement. In centripetal motion, it is defined as the angle through which a a body has been rotated from the initial position or reference position. This must always be equal at all points on the rod.
2) Angular Velocity: This is defined as the speed with which an object is moving in a circular motion. This must always be equal at all points on the rod.
3) Angular Acceleration: This is simply defined as the rate of change of angular velocity with time. Now, since angular velocity must be equal at all points on the rod, then angular acceleration must also be equal at all points on the rod.
4) Tangential acceleration; This is defined as the rate of change of tangential velocity with time. Tangential velocity is the linear component of the speed and it is not equal at all points on the rod and as such the tangential acceleration will also not be equal at all points on the rod.
Read more at; https://brainly.com/question/13014974
What is the direction of the magnetic field around a wire carrying a current perpendicularly into this page
Answer:
Clockwise direction
Explanation:
In a case of a wire carrying a current, the right hand rule is used.
The thumb in the direction of current while the finger curl around in the direction of the magnetic field.
The right hand rule applies to a current in a straight line wire.
If the direction a wire carrying a current perpendicularly into this page, the direction of the magnetic field will be in a clockwise direction .
An unmarked police car traveling a constant 85 km/h is passed by a speeder. Precisely 2.00 s after the speeder passes, the police officer steps on the acceleratorIf the police car accelerates uniformly at 2.00 m/s2 and overtakes the speeder after accelerating for 9.00 s , what was the speeder's speed?.
Answer:
observe o gráfico abaixo que mostra o número de internação em um hospital no município no período de 1960
A body is projected down at an angle of 30° with the horizontal
from the top, of a building 170m high. Its initial speed is 40m/s .
How long will it take before striking the ground.
Answer:
It will take 15 seconds
farah claps his 600times in 60seconds. what is the friquency and periodb
Answer:
[tex]\huge\boxed{\sf Frequency = 10\ Hz}[/tex]
[tex]\huge\boxed{\sf Time\ Period = 0.1\ secs}[/tex]
Explanation:
Given:
No. of times = 600 times
Time = 60 seconds
Required:
Frequency = f = ?
Time Period = T = ?
Solution:
Frequency = No. of Times / TimeFrequency = 600 / 60
Frequency = 10 Hz
Time Period = 1 / FrequencyTime Period = 1 / 10
Time Period = 0.1 secs
supposed the Kingfisher Dives with an average speed of 4.6 m / s for 1.4 seconds before hitting the water. What is the height from which the bird dove
Answer:
h = 1.07 m
Explanation:
It is given that,
The average sped of the kingfisher, v = 4.6 m/s
Time, t = 1.4 s
Final speed, v = 0 (as it hits the water)
We need to find the height from which the bird dove. Let the height is h. According to the conservation of energy.
[tex]mgh=\dfrac{1}{2}mv^2\\\\h=\dfrac{v^2}{2g}\\\\h=\dfrac{(4.6)^2}{2\times 9.8}\\\\h=1.07\ m[/tex]
So, the bird dove from a height of 1.07 m.
Tectonic plates are large segments of the Earth's crust that move slowly. Suppose one such plate has an average speed of 8.8 cm per year. (a) What distance does it move in 35 seconds at this speed (note that your answer should be in meters while your given speed is in cm/year)? (b) How many miles will the plate move in one million years at this speed?
Answer:
Jun 29, 2016 · Tectonic plates are large segments of the Earth’s crust that move slowly. Suppose that one such plate has an average speed of 4.0 cm/year. (a) What distance does it move in 1.0 s at this speed? (b) What is its speed in kilometers per million years?
Explanation:
Which of the following is a negatively charged particle that is found in "clouds" around the nucleus?
Group of answer choices
proton
quark
electron
neutron
A typical atom has a diameter of about 1.32 x 10-10 m. (a) what is this in inches (b) approximately how many atoms arethere along a 1.32 cm line.
Answer:
A ) [tex]5.197 \times 10 ^{-9} inches[/tex]
b) There are approximately 100,000,000 atoms on the 1.32 cm lines
Explanation:
To ensure the accuracy of our answer, we will have to make sure we work in the appropriate units.
A
To convert [tex]1.32 \times 10^{-10} m[/tex] to inches, we can use this factor.
1 m = 39.3701 inches
Therefore [tex]1.32 \times 10^{-10} m[/tex] =
B
To find the number of atoms on a 1.32 cm line, we will first of all need to convert 1.32 cm to meters.
1.32 cm = 0.0132 metres (divided 1.32 by 100 to convert to metres)
Assuming all the atoms are arranged side by side, with their edges touching on the 0.0132m line, the number of atoms present will be
[tex]0.0132/1.32\times 10^{-10}[/tex] = 100,000,000 atoms
When measuring the diameter of a cylinder the following measurements are obtained.
16.4 millimeters
16.8 millimeters
16.9 millimeters
16.6 millimeters
16.8 millimeters
Find the percent uncertainty in the measurements.
(Keep 2 decimal places in the percentage.)
Answer:
a. 1.80 %
b. 0.60 %
c. 1.20 %
d. 0.60 %
e. 0.60 %
Explanation:
In order to calculate percent uncertainties in each case, we forst need to calculate the average value:
Average Diameter = (16.4 mm + 16.8 mm + 16.9 mm + 16.6 mm +16.8 mm)/5
Average Diameter = 16.7 mm
Now, the formula for percent uncertainty is:
% Uncertainty = (Uncertainty/Average) * 100 %
where,
Uncertainty = |Value - Average|
For Each Case:
a. 16.4 mm:
Uncertainty = |16.4 mm - 16.7 mm| = 0.3 mm
Therefore,
% Uncertainty = (0.3 mm/16.7 mm) * 100%
% Uncertainty = 1.80 %
b. 16.8 mm:
Uncertainty = |16.8 mm - 16.7 mm| = 0.1 mm
Therefore,
% Uncertainty = (0.1 mm/16.7 mm) * 100%
% Uncertainty = 0.60 %
c. 16.4 mm:
Uncertainty = |16.9 mm - 16.7 mm| = 0.2 mm
Therefore,
% Uncertainty = (0.2 mm/16.7 mm) * 100%
% Uncertainty = 1.20 %
d. 16.6 mm:
Uncertainty = |16.6 mm - 16.7 mm| = 0.1 mm
Therefore,
% Uncertainty = (0.1 mm/16.7 mm) * 100%
% Uncertainty = 0.60 %
e. 16.8 mm:
Uncertainty = |16.8 mm - 16.7 mm| = 0.3 mm
Therefore,
% Uncertainty = (0.1 mm/16.7 mm) * 100%
% Uncertainty = 0.60 %
The train traveled 500 kilometers north to Odessa in 2 hours. What is the train’s speed? What is it’s velocity?
A woman leaning over the railing of a tall bridge accidentally drops her cell phone. If the bridge is 31.16 m high, how long will it take the phone to hit the river below the bridge?
Answer:
2.52 s
Explanation:
We can use equation of motion to solve this.
[tex]s \: = ut + \frac{1}{2} a {t}^{2} [/tex]
Assuming initial velocity to be 0 and no air resistance,
[tex] s \: = \frac{1}{2} a {t}^{2} \\ 31.16 = \frac{1}{2} (9.81) {t}^{2} \\ t = 2.52s[/tex]
The time of flight is 3.54 s.
What are equations of motion?There are three equation of motions that can be used when motion of the object is under constant acceleration and on a straight path.
They are listed below as:
[tex]v = u + at\\\\s = ut + \dfrac{1}{2} at^2\\\\v^2 = u^2 + 2as[/tex]
where the symbols have following meanings:
u = initial velocity of the considered object
v = final velocity of the object
a = acceleration of the object
s = distance traveled by the object in 't' time.
It is given that A woman leaning over the railing of a tall bridge accidentally drops her cell phone. If the bridge is 31.16 m high, then how long will it take the phone to hit the river below the bridge.
We can use equation of motion to solve this;
[tex]s = ut + \dfrac{1}{2} at^2[/tex]
where:
s = 31.16 m is the vertical displacement of the phone
u = 0 is the initial vertical velocity
Assuming initial velocity to be 0 and no air resistance,
[tex]s = 1/2 (9.8)(t)^2\\31.16 = 1/2 (9.8)(t)^2\\t = 2.52 s[/tex]
Hence, The time of flight is 3.54 s.
Learn more about free fall here:
brainly.com/question/1748290
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If the kinetic energy of the ball decreases then the potential energy will____
Hey There!! ~
The answer to this is: Complete these sentences.
If a bouncing ball has a total energy of 20 J and a kinetic energy of 5 J, the ball’s potential energy is 15J.
If the kinetic energy of the ball decreases, then the potential energy will Increase.
Hope It Helped!~
[tex]ItsNobody[/tex]~
Jerry is conducting an experiment to test friction. His setup is shown below. If he wants to test the friction between different types of materials, what should he change in the setup above? A. Replace the mass with a different size mass B. Replace the string with a different length string C. Replace the spring scale with a different kind of scale D. Replace the wooden block with a different kind of block
Answer:
The correct option is D
Explanation:
This question is incomplete because of the absence of the setup which as been attached below. The setup shows/determines/tests the friction of wood (which is a block material), since Jerry wants to test the friction between different types of materials, he will have to replace the wooden block with another type of block material of choice so as to determine the friction of that also.
In order to have a comprehensive experiment, Jerry can use 4-5 different types of block material in the course of the experiment.
Answer:
D
Explanation: i did it and my teacher said it was right
What is the velocity during the first 4 seconds?
Answer:
6?
Explanation:
Answer:
did you get the answer bc I think its -3
Explanation:
what distance is traveled by a police car that moves at a constant speed of 1.5 km/min for 5.0 min?
Answer:
7.5 meters
Explanation:
Answer:
7.5 kilometers
Explanation:
The distance can be found by multiplying the speed by the time.
[tex]d=s*t[/tex]
The car's speed is 1.5 kilometers per minute. It is traveling for 5.0, or 5 minutes. Therefore,
[tex]s= 1.5 km/min\\t=5 min[/tex]
Substitute the values into the formula.
[tex]d=1.5 km/min * 5 min[/tex]
Multiply. When you multiply, the minutes, or "min" will cancel each other out.
[tex]d= 1.5 km * 5[/tex]
[tex]d=7.5 km[/tex]
The distance the car travels is 7.5 kilometers.
if the earth stops rotating the Apparent value of g on its surface will
Answer:
If the earth stops rotating the apparent weight will increase at most of the places because the upward component of the centrifugal force due to rotation will disappear.
What is the speed of an electron traveling 32 cm in 2 ns?
Answer:
Speed, [tex]v=1.6\times 10^8\ m/s[/tex]
Explanation:
Given that,
Distance covered by the electron, d = 32 cm = 0.32 m
Time, t = 2 ns
We need to find the speed of an electron. Speed is equal to distance covered divided by time. So,
[tex]v=\dfrac{0.32}{2\times 10^{-9}}\\\\v=1.6\times 10^8\ m/s[/tex]
So, the speed of the electron is [tex]1.6\times 10^8\ m/s[/tex].
Hypothesis If an object rolls over _______________ (type of material), then it will _____________ (describe the prediction of distance it will travel)
Answer:
smooth
go far
If a truck travels 100 miles in 2 hours, what is its speed?
Answer:50 miles per hour 50/1hr
Explanation:100 divided by 2 is 50, divide 2 by 2 thats 1
Answer:
50 miles/hr
Explanation:
[tex]Distance = 100\: miles\\Time = 2\:hours\\\\Speed = \frac{Distance}{Time} \\\\Speed = \frac{100\:miles}{2\:hours}\\\\ Speed = 50\:miles/hour[/tex]
Which dartboard represents high accuracy and low precision?