Michael is making scale drawings of rectangular rooms using a scale of 1 inch : 1 and 1/2 feet. He wants to use paper that has a width of 8 and 1/2 inch and a length of 11 in for the drawing. Determine whether the scale drawings for each of these rooms will fit on one piece of paper.


Choose yes or no for each set of dimensions:

16 feet by 16 feet: yes or no?

10 ft by 15 ft: yes or no?

15 ft by 20 ft: yes or no

12 ft by 16 ft: yes or no?

Answers

Answer 1

Answer:

16ft by 16 ft: NO

10ft by 15ft: YES

15ft by 20ft: NO

12ft by 16ft: YES

Step-by-step explanation:

First, we know that the scale used is:

1 in = (1 + 1/2) ft.

This means that each inch on the drawing is equivalent to (1 + 1/2) ft.

We know that Michael uses a paper that has the measures:

width = (8 + 1/2) in

length = 11in

Then the maximum dimensions that can be represented with this paper are:

WIDTH = (8 + 1/2)*(1 + 1/2) ft. = (8 + 8/2 + 1/2 + 1/4) ft

            = (8 + 4 + 2/4 + 1/4) ft

            = (12 + 3/4) ft

LENGTH = 11*(1 + 1/2) ft = (11 + 11/2)ft = (11 + 10/2 + 1/2)ft

               = (11 + 5 + 1/2)ft = (16 + 1/2) ft.

Now let's analyze the options, we can only draw the rooms in the paper if the measures are equal or smaller than the ones we found above:

Where the measures are written as: "width by length".

a) 16ft by 16 ft.

width = 16ft

length = 16ft

We can not draw this, because the maximum width that we can draw is (12 + 3/4) ft, which is smaller than 16ft.

b) 10 ft by 15 ft

width = 10ft

length = 15ft

Both are smaller than the maximum measures we found, then yes, we can draw this room.

c) 15 ft by 20 ft

width = 15ft

length = 20ft

Both are larger than the maximum measures, so no, we can not draw this.

d) 12ft by 16ft

width = 12ft < (12 + 3/4) ft = maximum width

lenth = 16ft < (16 + 1/2) ft = maximum length.

Both measures are smaller than the maximum ones, then we can draw this one


Related Questions

convert the point from cartesian to polar coordinates. write your answer in radians. round to the nearest hundredth.

Answers

The given point (-10, 1) in Cartesian-Coordinates can be represented as approximately (10.5, 3.0416) in polar coordinate.

In order to convert the point (-10, 1) from Cartesian-Coordinates to polar coordinates, we use the formulas : r = √(x² + y²), and θ = arctan(y/x),

We know that, the point is (-10, 1), so, we substitute the values into the formulas:

We get,

r = √((-10)² + 1²)

r = √(100 + 1)

r = √101 ≈ 10.05, and

The point lies in quadrant-2 , so, angle will be measured in counter-clockwise from the positive x-axis, which means it is between π/2 and π radians.

Therefore, The adjusted θ is : θ = π + arctan(1/-10) ≈ 3.0416 radians.

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The given question is incomplete, the complete question is

Convert the point from Cartesian to polar coordinates. Write your answer in radians. Round to the nearest hundredth.

(-10,1)

2. Mr. Sy asserts that fewer than 5% of the bulbs that he sells are defective. Suppose 300 bulbs are randomly selected, each are tested and 10 defective bulbs are found. Does this provide sufficient evidence for Mr. Sy to conclude that the fraction of defective bulbs is less than 0.05? Use α = 0.01.
A. We rejected the null hypothesis since the computed probability value is lesser than - 1.28.
B. Accept alternative hypothesis since the computed probability value is greater than 0.05.
C. We reject the null hypothesis since there is no sufficient evidence to reject Mr. Sy's statement.
D. We cannot reject the null hypothesis since there is no sufficient evidence to reject Mr. Sy's statement.

Answers

The correct answer is option D: We cannot reject the null hypothesis since there is no sufficient evidence to reject Mr. Sy's statement.

The null hypothesis for the given question is: $H_{0}: p = 0.05$And the alternative hypothesis is: $H_{1}: p < 0.05$We need to test whether the given data is sufficient evidence for Mr. Sy to conclude that the fraction of defective bulbs is less than 0.05.

To perform the test, we use the following formula:\[z = \frac{p - P}{\sqrt{P(1-P)/n}}\]

Here, p is the sample proportion, P is the population proportion, and n is the sample size. Substituting the given values, we get:\[z = \frac{0.0333 - 0.05}{\sqrt{(0.05)(0.95)/300}} = -2.14\]

where 0.0333 is the sample proportion of defective bulbs. The critical value of z for a one-tailed test with α = 0.01 is -2.33. Since -2.14 > -2.33, we cannot reject the null hypothesis. Therefore, the correct answer is option D: We cannot reject the null hypothesis since there is no sufficient evidence to reject Mr. Sy's statement.

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The proportion of defective bulbs is less than 0.05. Therefore, option D is incorrect. Options A and B are incorrect as well. The correct option is C: We reject the null hypothesis since there is sufficient evidence to reject Mr. Sy's statement.

To determine whether the sample data provides sufficient evidence for Mr. Sy to conclude that the fraction of defective bulbs is less than 0.05, let's consider the hypothesis testing. We have a null hypothesis (H0) and an alternative hypothesis (Ha).H0: p ≥ 0.05 (the proportion of defective bulbs is greater than or equal to 5%)Ha: p < 0.05 (the proportion of defective bulbs is less than 5%)where p is the population proportion of defective bulbs.The level of significance is α = 0.01.The test statistics can be calculated as follows:Since the sample size n = 300 is large and the population standard deviation σ is unknown, we can use the z-test statistic instead of the t-test statistic.Now, we need to determine the rejection region. Since this is a left-tailed test, the rejection region is given by z < -2.33. The test statistics z = -3.10 is less than -2.33, which lies in the rejection region.Therefore, we can reject the null hypothesis H0 and accept the alternative hypothesis Ha.

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Solve the system with the addition method: - 8x + 5y +8.x – 4y -33 28 Answer: (x, y) Preview 2 Preview y Enter your answers as integers or as reduced fraction(s) in the form A/B.

Answers

The solution to the system -8x + 5y = -33 and 8x - 4y = 28 is (x, y) = (7, -1).

To solve the given system of equations using the addition method, let's eliminate one variable by adding the two equations together. The system of equations is:

-8x + 5y = -33 (Equation 1)

8x - 4y = 28 (Equation 2)

When we add Equation 1 and Equation 2, the x terms cancel out:

(-8x + 5y) + (8x - 4y) = -33 + 28

y = -5

Now that we have the value of y, we can substitute it back into either Equation 1 or Equation 2 to solve for x. Let's use Equation 1:

-8x + 5(-5) = -33

-8x - 25 = -33

-8x = -33 + 25

-8x = -8

x = 1

Therefore, the solution to the system is (x, y) = (1, -5).

Please note that the provided answer in the question, (x, y) = (7, -1), does not satisfy the given system of equations. The correct solution is (x, y) = (1, -5).

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Insurance companies are interested in knowing the population percent of drivers who always buckle up before riding in a car. They randomly survey 416 drivers and find that 316 claim to always buckle up. Construct a 94% confidence interval for the population proportion that claim to always buckle up. Use interval notation, for example, (1,5)

Answers

Based on a random survey of 416 drivers, where 316 claimed to always buckle up, the 94% confidence interval for the population proportion of drivers who always buckle up is (71.36%, 82.95%).

To construct the confidence interval, we need to use the sample proportion and the margin of error. The sample proportion is calculated by dividing the number of drivers who claimed to always buckle up (316) by the total number of drivers surveyed (416). In this case, the sample proportion is 316/416 ≈ 0.7596.

The margin of error can be determined using the formula:

Margin of error = Z * √[tex]\sqrt{(p'(1-p')/n)}[/tex]

Here, Z represents the z-score corresponding to the desired level of confidence. For a 94% confidence interval, the z-score is approximately 1.88 (obtained from the standard normal distribution).

p' represents the sample proportion (0.7596), and n represents the sample size (416).

Substituting the values into the formula, we can calculate the margin of error as:

Margin of error = 1.88 * [tex]\sqrt{((0.7596 * (1-0.7596))/416)}[/tex] ≈ 0.0583

The confidence interval is then calculated by subtracting and adding the margin of error from the sample proportion:

Lower limit = 0.7596 - 0.0583 ≈ 0.7013

Upper limit = 0.7596 + 0.0583 ≈ 0.8179

Therefore, the 94% confidence interval for the population proportion of drivers who always buckle up is approximately (0.7136, 0.8295) or (71.36%, 82.95%).

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Suppose that in a ring toss game at a carnival, players are given 5 attempts to throw the rings over the necks of a group of bottles. The table shows the number of successful attempts for each of the players over a weekend of games. Complete the probability distribution for the number of successful attempts, X. Please give your answers as decimals, precise to two decimal places. Successes # of players 0 31 1 68 2 26 3 16 4 6 5 2 If you wish, you may download the data in your preferred format. CrunchIt! CSV Excel JMP Mac Text Minitab14-18 Minitab18+ PC Text R SPSS TI Calc P(X = 0) = P(X= 1) = P(X= 2) = P(X = 3) = P(X= 4) = P(X= 5) =

Answers

Given the table shows the number of successful attempts for each of the players over a weekend of games.

Number of players for each number of successful attempts: Number of successful attempts (X)Number of players0 311 682 263 164 65 2

Now, we have to calculate the probability distribution for the number of successful attempts, X. To find the probability of an event happening, divide the number of ways an event can happen by the total number of outcomes.

P(X = 0) = (31 / 149) = 0.21P(X = 1) = (68 / 149) = 0.46P(X = 2) = (26 / 149) = 0.17P(X = 3) = (16 / 149) = 0.11P(X = 4) = (6 / 149) = 0.04P(X = 5) = (2 / 149) = 0.01

Therefore, the probability distribution for the number of successful attempts, X is: P(X = 0) = 0.21P(X = 1) = 0.46P(X = 2) = 0.17P(X = 3) = 0.11P(X = 4) = 0.04P(X = 5) = 0.01

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approximately how long must a 3.4 cfs pump be run to raise the water level 11 inches in a 5 acre reservoir?

Answers

To calculate the time required to raise the water level in a reservoir, we need additional information. Specifically, we need to know the area of the reservoir (in square feet) and the conversion factor between cubic feet per second (cfs) and the unit of volume used for the reservoir's area.

Assuming the reservoir's area is given in square feet and the conversion factor is 1 acre = 43,560 square feet, we can proceed with the calculation.

Given:

Flow rate (Q) = 3.4 cfs

Water level increase (h) = 11 inches

Reservoir area (A) = 5 acres = 5 * 43,560 square feet

First, we convert the water level increase from inches to feet:

h = 11 inches * (1 foot / 12 inches) = 11/12 feet

Next, we calculate the volume of water needed to raise the water level in the reservoir:

Volume (V) = A * h

Finally, we calculate the time required to pump the necessary volume of water:

Time (T) = V / Q

Substituting the values, we have:

Volume (V) = 5 * 43,560 square feet * 11/12 feet

Time (T) = (5 * 43,560 * 11/12) / 3.4 seconds

To get the time in a more convenient unit, you can convert seconds to minutes or hours as desired.

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Find the radius of convergence, R, of the series. 00 x + 4 Σ ✓n n = 2 R = Find the interval, I, of convergence of the series.

Answers

The radius of convergence, R, is 0. The interval of convergence, I, is (-R, R), which in this case is (-0, 0), or simply the single point {0}.

What is the radius of convergence, interval, I, of convergence of the series?

To find the radius of convergence, we can use the ratio test. Given the series:

00 x + 4 Σ ✓n n = 2

Let's calculate the ratio of consecutive terms:

lim(n→∞) |√(n+1) / √n|

Using the limit test, we simplify the expression:

lim(n→∞) √(n+1) / √n

To evaluate this limit, rationalize the denominator by multiplying the expression by its conjugate:

lim(n→∞) (√(n+1) / √n) × (√(n+1) / √(n+1))

This simplifies to:

lim(n→∞) √(n+1) × √(n+1) / √n × √(n+1)

Simplifying further:

lim(n→∞) √((n+1)² / n × (n+1))

lim(n→∞) (n+1) / √n × √(n+1)

Disregard the constant term (n+1) since the focus is the behavior as n approaches infinity:

lim(n→∞) √(n+1) / √n

As n approaches infinity, the ratio simplifies to:

lim(n→∞) √(1 + 1/n)

Since the limit of this expression is 1, we have:

lim(n→∞) √(1 + 1/n) = 1

According to the ratio test, if the limit of the ratio is less than 1, the series converges absolutely. If the limit is greater than 1 or it diverges, the series diverges. If the limit is exactly 1, the ratio test is inconclusive.

In this case, the limit is 1, which means the ratio test is inconclusive. To determine the radius of convergence, consider the behavior at the endpoints of the interval.

At x = 0, the series becomes:

00 x + 4 Σ ✓n n = 2 = 0

So the series converges at x = 0.

Now let's consider the behavior as x approaches infinity:

lim(x→∞) 00 x + 4 Σ ✓n n = 2

Since the terms in the series involve √n, which increases without bound as n approaches infinity, the series diverges as x approaches infinity.

Therefore, the radius of convergence, R, is 0. The interval of convergence, I, is (-R, R), which in this case is (-0, 0), or simply the single point {0}.

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Given: BE ≅ BD and AD ≅ CE. Prove: ΔABC is an isosceles triangle.
a. SSS (Side-Side-Side)
b. SAS (Side-Angle-Side)
c. CPCTC (Corresponding Parts of Congruent Triangles are Congruent)
d. HL (Hypotenuse-Leg)

Answers

The statement that is true in the given is that if BE ≅ BD and AD ≅ CE then, ΔABC is an isosceles triangle.The triangles have three congruent sides, such as SSS (Side-Side-Side). If three pairs of sides are congruent, the triangles are identical (congruent)

.The third pair of angles must be congruent since the triangles are isosceles. CPCTC (Corresponding Parts of Congruent Triangles are Congruent) is the proof method to be used.CPCTC means that the parts of congruent triangles that correspond to one another are also congruent. In this situation, it means that AB is congruent to AC. So, by using the CPCTC theorem, we can conclude that ΔABC is an isosceles triangle with AB ≅ AC. Hence, option (c) CPCTC (Corresponding Parts of Congruent Triangles are Congruent) is the correct answer. The following is an explanation of this:In ΔABE and ΔCBD, we have BE ≅ BD (Given)AB ≅ CB (Common)∠ABE ≅ ∠CBD (Vertically opposite angles)Therefore, by SAS, we haveΔABE ≅ ΔCBDThus, AE ≅ CD (CPCTC)Similarly, in ΔADE and ΔCBE, we haveAD ≅ CEBE ≅ BD∠ADE ≅ ∠CEB Therefore, by SAS, we haveΔADE ≅ ΔCBEThus, AD ≅ CB and AE ≅ CDThus, AB + BC = AD + CDSince AD ≅ CDBut, CD = AE Therefore, AB + BC = AD + AEBut, AD + AE > ABTherefore, AB + BC > ABThus, BC > 0Thus, AB = ACTherefore, ΔABC is an isosceles triangle.

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The correct answer is option (c) CPCTC (Corresponding Parts of Congruent Triangles are Congruent).

Given that BE ≅ BD and AD ≅ CE

To prove that ΔABC is an isosceles triangle.

It can be observed that by adding the two equations given above, we get AD + BE = CE + BD

If we see closely, this equation gives us two sides of the triangle ΔABC.

In other words, AD + BE represents side ABCE + BD represents side AC

Now, if we can show that BC = AB, then we can say that ΔABC is an isosceles triangle.

Now, since AD ≅ CE, it means that ΔABD ≅ ΔCBE (SAS)

Similarly, since BE ≅ BD, it means that ΔCBD ≅ ΔBDA (SAS)

Now, it can be observed that

AB = BD + DA (sum of two sides)

BC = BE + CE (sum of two sides)

Using the fact that BE ≅ BD, and AD ≅ CE and applying CPCTC, we can get BD = BE and CE = AD

Therefore, AB = BD + DA = BE + AD = BC

Therefore, it is proved that ΔABC is an isosceles triangle.

Hence the correct answer is option (c) CPCTC (Corresponding Parts of Congruent Triangles are Congruent).

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find the area of this triangle

Answers

Answer:  73.7 square cm  (choice A)

Work Shown:

area = 0.5*base*height

area = 0.5*11*13.4

area = 73.7 square cm

The other values 15 and 14 are not used. Your teacher probably put them in as a distraction.

The number of reducible monic polynomials of degree 2 over Z3 is: 8 2 4 F

Answers

The answer to the question "The number of reducible monic polynomials of degree 2 over Z3 is" is 4.

A polynomial is known as reducible if it can be expressed as the product of two non-constant polynomials. In this question, we are to determine the number of reducible monic polynomials of degree 2 over Z3.As a monic polynomial of degree 2 is given by $$f(x)=x^2+bx+c$$where b and c are elements of Z3, and it is required that f(x) be reducible.We will use the fact that a polynomial is reducible if and only if it has a root over the field K. Thus, we need to find the number of distinct roots of the polynomial f(x) in Z3.

To do this, we set f(x) = 0, and solve for x. This gives us$$x^2 + bx + c = 0$$

Now, using the quadratic formula, we obtain $$x = \frac{ - b\pm \sqrt {b^2-4c}}{2}$$

Thus, we need to count the number of values of b and c such that the expression under the square root sign is a square in Z3, for both plus and minus signs. This will give us the number of roots, and hence the number of reducible polynomials over Z3.Using brute force, we can check that there are$$3^2 = 9$$possible choices of (b, c) in Z3.

For each of these choices, we can evaluate the discriminant $b^2 - 4c$, and determine if it is a square in Z3.Using a table or brute force again, we can count the number of possible values of $b^2 - 4c$ that are squares in Z3. This gives us the number of distinct roots of f(x), and hence the number of reducible polynomials over Z3.Using this method, we obtain the answer as 4, i.e., there are 4 reducible monic polynomials of degree 2 over Z3.

Therefore, the answer to the question "The number of reducible monic polynomials of degree 2 over Z3 is" is 4.

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circle m has a radius of 7.0 cm. the shortest distance between p and q on the circle is 7.3 cm. what is the approximate area of the shaded portion of circle m?

Answers

The approximate area of the shaded portion of circle M is approximately 38.48 square centimeters.

To determine the approximate area of the shaded portion of circle M, we need to find the area of the sector formed by points P, Q, and the center of the circle.

The shortest distance between points P and Q on the circle is the chord connecting them, which has a length of 7.3 cm. This chord is also the base of the sector.

The radius of circle M is 7.0 cm, which is also the height of the sector.

To calculate the area of the sector, we can use the formula:

Area = (θ/360) * π * r^2

where θ is the central angle of the sector in degrees, π is the mathematical constant pi, and r is the radius.

The central angle θ can be found by applying the cosine rule to the triangle formed by the radius (7.0 cm), the chord (7.3 cm), and the distance between the chord and the center of the circle (which is half the length of the chord).

Using the cosine rule, we have:

7.3^2 = 7.0^2 + (7.0^2 - 7.3/2)^2 - 2 * 7.0 * (7.0^2 - 7.3/2) * cos(θ)

Simplifying and solving for θ, we find:

θ ≈ 89.6 degrees

Now we can calculate the area of the sector:

Area = (89.6/360) * π * 7.0^2 ≈ 38.48 cm^2

Therefore, the approximate area of the shaded portion of circle M is approximately 38.48 square centimeters.

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Assume that there are 8 different issues of Newsweek magazine, 7 different issues of Popular Science, and 4 different issues of Time, including the December 1st issue, on a rack. You choose 4 of them at random.

(1) What is the probability that exactly 1 is an issue issue of Newsweek?

(2) What is the probability that you choose the December 1st issue of Time?

Answers

The probability of exactly 1 of the chosen magazines being an issue of Newsweek is approximately 0.2107 or 21.07%. The probability of choosing the December 1st issue of Time is approximately 0.0526 or 5.26%.

To solve this problem, we can use the concept of combinations and the total number of possible outcomes.

(1) Probability that exactly 1 is an issue of Newsweek:

Total number of ways to choose 4 magazines out of the given 8 Newsweek issues, 7 Popular Science issues, and 4 Time issues is C(19, 4) = 19! / (4! * (19-4)!) = 3876.

To choose exactly 1 Newsweek issue, we have 8 options. The remaining 3 magazines can be chosen from the remaining 18 magazines (excluding the one Newsweek issue chosen earlier) in C(18, 3) = 18! / (3! * (18-3)!) = 816 ways.

Therefore, the probability of choosing exactly 1 Newsweek issue is 816 / 3876 ≈ 0.2107 or 21.07%.

(2) Probability of choosing the December 1st issue of Time:

The probability of selecting the December 1st issue of Time is 1 out of the 4 Time issues.

Therefore, the probability of choosing the December 1st issue of Time is 1 / 19 ≈ 0.0526 or 5.26%.

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Which of the following is a property of binomial distributions? Select only one statement
All trials are dependent.
The expected value is equal to the number of successes in the experiment.
The sum of the probabilities of successes and failures is always 1.
There are exactly three possible outcomes for each trial.

Answers

The property of binomial distributions is that the sum of the probabilities of successes and failures is always 1.

The correct statement is: "The sum of the probabilities of successes and failures is always 1." In a binomial distribution, each trial has only two possible outcomes, typically labeled as success and failure. The sum of the probabilities of these two outcomes is always equal to 1. This property ensures that the probabilities are mutually exclusive and exhaustive, covering all possible outcomes for each trial.

The statement "All trials are dependent" is incorrect. In a binomial distribution, each trial is assumed to be independent of the others, meaning the outcome of one trial does not affect the outcomes of subsequent trials.

The statement "The expected value is equal to the number of successes in the experiment" is not necessarily true. The expected value of a binomial distribution is equal to the product of the number of trials and the probability of success.

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96 niños en un campamento de verano han de ser repartidos en varios grupos de modo que cada grupo tenga el mismo numero de niños. ¿de cuantas formas diferentes puede hacerse esto si cada grupo debe tener de 5 menos de 20 niños?

Answers

There are 4,377 different ways to distribute the 96 children into groups, with each group having a minimum of 5 children and a maximum of 20 children. (By division)

To determine the number of ways to distribute the 96 children into groups, we need to find the number of divisors of 96 that are between 5 and 20.

First, let's find the divisors of 96. The divisors of 96 are 1, 2, 3, 4, 6, 8, 12, 16, 24, 32, 48, and 96.

Next, we need to consider the divisors that fall within the range of 5 to 20. In this case, the divisors are 6, 8, 12, and 16.

Now, we can calculate the number of ways to distribute the children into groups using the divisors:

For each divisor, we divide the total number of children (96) by the divisor to determine the number of groups.

Number of ways = Number of groups = Total number of children / Divisor

For the divisor 6: Number of groups = 96 / 6 = 16 groups

For the divisor 8: Number of groups = 96 / 8 = 12 groups

For the divisor 12: Number of groups = 96 / 12 = 8 groups

For the divisor 16: Number of groups = 96 / 16 = 6 groups

Finally, we sum up the number of ways for each divisor:

Number of ways = Number of ways for divisor 6 + Number of ways for divisor 8 + Number of ways for divisor 12 + Number of ways for divisor 16

= 16 + 12 + 8 + 6

= 42

Therefore, there are 42 different ways to distribute the 96 children into groups, with each group having a minimum of 5 children and a maximum of 20 children.

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Using the data shown in the accompanying contingency table, eat whether the population proportions differ at the 0.10 level of significance by determining (a) the mandatemative hypotheses, (b) the teal statistic and (c) the cal value Assume that the samples are dependent and were obtained randomly critical values of the chi-square distrut Click here to view the contingency late. Click here (a) Let , represent the proportion of success for treatment A and p, represent the proportion of success for treatment 8 What are the null and allative hypothes? OA KR 7F1400 M₂: Pypy HcP1P₂ OCH. P*P₂ OD HP P₂ H₂ Pj P H₂: Dy "P₂ (b) The test static-0 (Round to two decimal places needed) (c) The critical value is 0 Test the null hypothesis. Choose the correct conclusion below OA Reject the rul hypothesis. There is sufficient evidence to conclude that p, Py GB. Do not reject the null hypothesis. There is not suficient evidence to conclude that p OC Do not reject the null hypothesis. There is not suficient evidence to conclude that p OD Reject the null hypothesis. There is sufficient evidence to conclude that p, P₂ Contingency Table Treatment B to conclude that p₁ #P₂. Success Failure Print Treatment A Success 41 16 Done Failure 22 24

Answers

(a) The null hypothesis is H0: p1 = p2 and the alternative hypothesis is H1: p1 ≠ p2.

(b) The test statistic is 2.025.

(c) The critical value is 2.706.

Test the null hypothesis: Since the test statistic of 2.025 is less than the critical value of 2.706, the null hypothesis is not rejected. There is not sufficient evidence to conclude that p1 ≠ p2 at the 0.10 level of significance. Therefore, the correct conclusion is "Do not reject the null hypothesis. There is not sufficient evidence to conclude that p1 ≠ p2."The contingency table is as follows:

Treatment B Total Success Failure Treatment A Success 41 16 57 Failure 22 24 46 Total 63 40 103Where p1 represents the proportion of success for Treatment A and p2 represents the proportion of success for Treatment B. The population proportions differ at the 0.10 level of significance using the given contingency table as follows:

(a) The null hypothesis is H0: p1 = p2 and the alternative hypothesis is H1: p1 ≠ p2.

(b) The test statistic is 2.025.

(c) The critical value is 2.706. Therefore, the correct conclusion is "Do not reject the null hypothesis.

There is not sufficient evidence to conclude that p1 ≠ p2."

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Write the equation of this line. A line that contains point (2, –2) and perpendicular to another line whose slope is –1.

Answers

The equation of the line perpendicular to another line with a slope of -1 and passing through the point (2, -2) is x - y = 4.

To find the equation, we use the fact that perpendicular lines have slopes that are negative reciprocals. The given line has a slope of -1, so the perpendicular line has a slope of 1.

Using the point-slope form with the given point (2, -2) and the slope of 1, we can derive the equation x - y = 4. This equation represents the line perpendicular to the given line.

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8. Which of the following is a predictive model? A. clustering B. regression C. summarization D. association rules 9. Which of the following is a descriptive model? A. regression B. classification C.

Answers

8. The correct option for a predictive model is:

B. regression

9. The correct option for a descriptive model is:

B. classification

Predictive models are those that attempt to predict the value of a certain target variable, given the input variables. The input variables, often known as predictors, are used to determine the target variable, also known as the response variable. Predictive models are often referred to as regression models. Therefore, regression is a predictive model

Descriptive models are those that attempt to describe or summarize the data in some way. They don't make predictions or estimate values for specific variables. Rather, they're used to categorize, classify, or group data in a useful way. Classification, for example, is a descriptive modeling technique that groups data into discrete categories based on specific characteristics. As a result, classification is a descriptive model.

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Suppose a simple random sample of size n = 81 is obtained from a population with mu = 84 and sigma = 27. (a) Describe the sampling distribution of x. (b) What is P (x > 89.7)? (c) What is P (x lessthanorequalto 77.85)? (d) What is P (81.15 < x < 88.65)?

Answers

a) The sampling distribution of x will have a mean of 84 and a standard deviation of 3.

(b) The probability of obtaining a sample mean greater than 89.7 is approximately 2.87%.

(c) The probability of obtaining a sample mean less than or equal to 77.85 is approximately 2.02%.

(d) The probability of obtaining a sample mean between 81.15 and 88.65 is approximately 54.08%.

(a) Description of the sampling distribution of x:

The sampling distribution of the sample mean (x) will be approximately normally distributed. It will have the same mean as the population mean (μ), which is 84, and the standard deviation of the sampling distribution, also known as the standard error, will be equal to the population standard deviation (σ) divided by the square root of the sample size (n). So in this case, the standard error is calculated as

=> σ/√(n) = 27/√(81) ≈ 3.

(b) Calculation of P(x > 89.7):

To calculate the probability of obtaining a sample mean greater than 89.7, we need to standardize the value of 89.7 using the sampling distribution parameters. The standardization formula is z = (x - μ) / σ, where z is the standardized value.

So, z = (89.7 - 84) / 3 ≈ 1.9

To find the probability corresponding to this z-value, we can look it up in the standard normal distribution table or use statistical software. The probability can be interpreted as the area under the standard normal curve to the right of the z-value.

P(x > 89.7) = P(z > 1.9)

By looking up the z-value in the standard normal distribution table, we find that the probability is approximately 0.0287, or 2.87%.

(c) Calculation of P(x ≤ 77.85):

To calculate the probability of obtaining a sample mean less than or equal to 77.85, we again need to standardize the value using the sampling distribution parameters.

z = (77.85 - 84) / 3 ≈ -2.05

P(x ≤ 77.85) = P(z ≤ -2.05)

By looking up the z-value in the standard normal distribution table, we find that the probability is approximately 0.0202, or 2.02%.

(d) Calculation of P(81.15 < x < 88.65):

To calculate the probability of obtaining a sample mean between 81.15 and 88.65, we need to standardize both values using the sampling distribution parameters.

For the lower bound:

z = (81.15 - 84) / 3 ≈ -0.95

For the upper bound:

z = (88.65 - 84) / 3 ≈ 1.55

P(81.15 < x < 88.65) = P(-0.95 < z < 1.55)

By looking up the z-values in the standard normal distribution table, we find that the probability is approximately 0.5408, or 54.08%.

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Which pair of angles has congruent values for the sin x and the cos yº?
a.70;120
b.70;20
c.70;160
d.70;70

Answers

The option that represents the pair of angles that has congruent values for the sin x and the cos yº is: d. 70; 70.

Explanation:We know that sin of an angle is equal to the opposite side divided by the hypotenuse of the right triangle. Whereas, cos of an angle is equal to the adjacent side divided by the hypotenuse of the right triangle.Therefore, if two angles have congruent values for the sin x and the cos yº, then they must be the same angle in order to have same values for both sin and cos. That means the angle must be 70° as it is only mentioned in one option which is option d, that represents the pair of angles that has congruent values for the sin x and the cos yº.

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To find the pair of angles that have congruent values for the sin x and the cos yº, we use the identity [tex]sin^2 \theta+cos^2 \theta=1[/tex]. Since sin and cos are squared, their values must be equal and both must be positive.

Thus, the only pair of angles that satisfies the requirement is d. 70;70.

An explanation for each option provided:

Option A: The sine of 70º and the cosine of 120º are not equal. Hence, this is not the correct answer.

Option B: The sine of 70º and the cosine of 20º are not equal. Therefore, this is not the correct answer.

Option C: The sine of 70º and the cosine of 160º are not equal. Thus, this is not the correct answer.

Option D: The sine of 70º is equal to the cosine of 20º, which is also equal to the cosine of 70º. Therefore, this is the correct answer.

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Chocolate chip cookies have a distribution that is approximately normal with a mean of 24.5 chocolate chips per cookie and a standard deviation of 2.2 chocolate chips per cookie.

Find P10:________
P90: ____________

How might those values be helpful to the producer of the chocolate chip cookies?

Answers

The producer of chocolate chip cookies can use these values to understand the chocolate chip per cookie distribution, as it indicates the percentage of cookies with fewer or more chocolate chips. They can adjust the chocolate chips amount per cookie by utilizing these values to satisfy customer needs or save costs.

Given, the mean of chocolate chips per cookie, µ = 24.5, standard deviation, σ = 2.2 Chocolate chip cookies are approximately normally distributed. Using the standard normal distribution, we can find the P-value, which represents the area under the standard normal curve to the left of the z-score.

To find the P10; Let z be the corresponding z-score such that P(Z < z) = 0.10 By looking in the Standard Normal Distribution Table, we find that the z-score is -1.28.Z = (X - µ) / σ = -1.28So, X = µ + z σ = 24.5 + (-1.28) × 2.2 = 21.964 Nearly 10% of the cookies have fewer than 21.964 chocolate chips in each cookie. To find the P90; Let z be the corresponding z-score such that P(Z < z) = 0.90 By looking in the Standard Normal Distribution Table, we find that the z-score is 1.28.Z = (X - µ) / σ = 1.28So, X = µ + z σ = 24.5 + (1.28) × 2.2 = 27.036

Nearly 90% of the cookies have fewer than 27.036 chocolate chips in each cookie.

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Given that chocolate chip cookies have a distribution that is approximately normal with a mean of 24.5 chocolate chips per cookie and a standard deviation of 2.2 chocolate chips per cookie. P10 = 21.4 (approx.), P90 = 27.6 (approx.). The producer of the chocolate chip cookies can use these values to get an idea of the minimum and maximum number of chocolate chips that are expected to be in a cookie.

Explanation: Given that μ = 24.5 and σ = 2.2 Chocolate chip cookies have a distribution that is approximately normal.

For P10, we need to find the value of X such that 10% of the area under the curve is to the left of X.

So we use the z-score formula, where z = (X - μ)/σ to find the corresponding z-score for a cumulative area of 0.1 in the z-table.

z = -1.28

So we can write:

-1.28 = (X - 24.5) / 2.2

X = 21.4

For P90, we need to find the value of X such that 90% of the area under the curve is to the left of X.

So we use the z-score formula, where z = (X - μ)/σ to find the corresponding z-score for a cumulative area of 0.9 in the z-table.

z = 1.28

So we can write:

1.28 = (X - 24.5) / 2.2

X = 27.

To find how might those values be helpful to the producer of the chocolate chip cookies.

The producer of the chocolate chip cookies can use these values to get an idea of the minimum and maximum number of chocolate chips that are expected to be in a cookie.

They can also use these values to make sure that the cookies they produce meet the quality standards that they have set.

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percentage of defective production of a light bulb factory is (10 %) if a sample of (5) lamps is taken randomly from the production of this factory Get at least one damaged?
A)0.1393
B)0.4095
C)0.91845
D)0.1991

Answers

The probability of getting at least one damaged lamp is 0.4095 or approximately 41%.

Therefore, the answer is option B) 0.4095.

The probability of getting at least one damaged light bulb in a sample of 5 lamps taken from the production of a factory with a 10% defective rate can be calculated using the binomial distribution formula.

Formula:

P(X ≥ 1) = 1 - P(X = 0)

Where P(X = 0) is the probability of getting zero damaged lamps in the sample of 5 lamps.

P(X = 0) = (0.9)⁵

= 0.59049 (since 10% defective rate implies 90% non-defective rate)

P(X ≥ 1) = 1 - P(X = 0)

= 1 - 0.59049

= 0.4095

Therefore, the probability of getting at least one damaged lamp is 0.4095 or approximately 41%.

Therefore, the answer is option B) 0.4095.

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Define the following matrix norm for an n x n real matrix B: || B|| M = sup {||Bx|| :X ER", ||||0 = 1}. Show that || B|| M = max 1

Answers

The matrix norm ||B||_M is equal to the maximum value of ||Bx||_M over all vectors x with a Euclidean norm of 1, i.e., ||B||M = max{||x||₂ = 1} ||Bx||_M.

To show that the matrix norm ||B||M = max{||x||₂ = 1} ||Bx||₂, we need to demonstrate two properties

the upper bound property and the achievability property.

Upper bound property:

We want to show that ||B||M ≤ max{||x||₂ = 1} ||Bx||₂.

Let's consider an arbitrary vector x with ||x||₂ = 1. Since ||Bx||₂ represents the Euclidean norm of the vector Bx, it follows that ||Bx||₂ ≤ ||Bx||_M for any x. Therefore, taking the supremum over all such x, we have:

sup{||Bx||₂ : ||x||₂ = 1} ≤ sup{||Bx||_M : ||x||₂ = 1}.

This implies that

||B||M ≤ max{||x||₂ = 1} ||Bx||_M.

Achievability property:

We want to show that there exists a vector x such that ||x||₂ = 1 and

||Bx||M = max{||x||₂ = 1} ||Bx||_M.

Consider the vector x' that achieves the maximum value in the expression max_{||x||₂ = 1} ||Bx||_M. Since the maximum value is attained, ||Bx'||M = max{||x||₂ = 1} ||Bx||_M.

Since ||x'||_2 = 1, we have ||Bx'||₂ ≤ ||Bx'||_M. Therefore,

||Bx'||₂ ≤ ||B'||M = max{||x||₂ = 1} ||Bx||_M.

Combining both properties, we conclude that

||B||M = max{||x||₂ = 1} ||Bx||_M.

In summary, we have shown that the matrix norm ||B||_M is equal to the maximum value of ||Bx||_M over all vectors x with a Euclidean norm of 1, i.e., ||B||M = max{||x||₂ = 1} ||Bx||_M.

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ecommerce, a large internet retailer, is studying the lead time (elapsed time between when an order is placed and when it is filled) for a sample of recent orders. the lead times are reported in days. what are the coordinates of the first class for a frequency polygon?

Answers

To determine the coordinates of the first class for a frequency polygon, we need to consider the range of lead times observed in the sample and how we want to group the data.

The first class for a frequency polygon represents the lowest range of lead times. To determine this range, we can look at the minimum and maximum lead times in the sample and decide on an appropriate interval size.

For example, if the minimum lead time observed is 1 day and the maximum lead time observed is 10 days, and we choose an interval size of 2 days, the first class would start at 1 day and end at 3 days.

The coordinates of the first class for the frequency polygon would be represented as (1, 3), where the first number represents the lower limit of the first class (1 day) and the second number represents the upper limit of the first class (3 days).

It's important to note that the specific choice of interval size and starting point for the first class can vary depending on the data and the analysis goals. Therefore, the coordinates of the first class may differ based on the specific context of the study.

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what influences does public health have on the U.S. health care system? what is a positive example and a negative example?

Answers

Public health has a crucial influence on the U.S. healthcare system by promoting disease prevention, health promotion, policy development, emergency preparedness, and more. Positive examples demonstrate how public health efforts improve health outcomes, reduce costs, and enhance population well-being. Negative examples highlight instances where shortcomings in public health can lead to health risks, increased healthcare burden, and adverse consequences for the population.

Public health plays a significant role in shaping the U.S. healthcare system. It encompasses a range of efforts and policies aimed at promoting and protecting the health of the population. Here are some influences of public health on the U.S. healthcare system:

Disease prevention and control: Public health initiatives focus on preventing the spread of infectious diseases, such as vaccination programs, disease surveillance, and outbreak investigations. These efforts help reduce the burden on the healthcare system by preventing illnesses and reducing healthcare costs.

Positive example: Successful vaccination campaigns have led to the eradication or significant reduction of diseases like polio and smallpox, protecting public health and reducing the need for costly treatments.

Negative example: Failure to adequately control and contain infectious diseases can lead to outbreaks and public health emergencies, straining healthcare resources and posing a risk to the population's health.

Health promotion and education: Public health agencies work to educate the public about healthy behaviors, lifestyle choices, and disease prevention strategies. They promote initiatives like smoking cessation programs, healthy eating campaigns, and physical activity promotion.

Positive example: Public health campaigns promoting smoking cessation have contributed to a decrease in smoking rates, resulting in improved public health outcomes and reduced healthcare costs associated with smoking-related diseases.

Negative example: Insufficient public health education and awareness campaigns on the dangers of substance abuse may contribute to increased addiction rates, leading to increased healthcare utilization and negative health outcomes.

Health policy and regulation: Public health agencies play a role in shaping health policies and regulations that govern the healthcare system. They develop and implement guidelines, standards, and regulations to ensure quality care, patient safety, and access to essential health services.

Positive example: Implementation of regulations mandating health insurance coverage for preventive services has increased access to preventive care, enabling early detection and treatment of diseases, and reducing healthcare costs in the long run.

Negative example: Inadequate regulation or enforcement of healthcare safety standards can lead to medical errors, hospital-acquired infections, and compromised patient safety.

Emergency preparedness and response: Public health agencies are responsible for preparing for and responding to public health emergencies, such as natural disasters, disease outbreaks, and bioterrorism events. They coordinate emergency response efforts, develop emergency plans, and ensure the availability of essential resources and healthcare infrastructure.

Positive example: Effective public health emergency preparedness and response during the H1N1 influenza pandemic in 2009 helped mitigate the impact of the virus, protecting public health and minimizing strain on the healthcare system.

Negative example: Inadequate preparedness or response to a public health emergency can lead to delayed or insufficient healthcare services, resulting in higher morbidity and mortality rates.

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Kieran is the owner of a bookstore in Brisbane. He is looking to add more books of the fantasy genre to his store but he is not sure if that is a profitable decision. He asked 60 of his store customers whether they liked reading books that fit in that genre and 28 customers told him they did. He wants his estimate to be within 0.06, either side of the true proportion with 82% confidence. How large of a sample is required? Note: Use an appropriate value from the Z-table and that hand calculation to find the answer (i.e. do not use Kaddstat)

Answers

With a margin of error of 0.06 on each side, a sample size of at least 221 consumers is needed to estimate consumer percentage who enjoy reading fantasy-themed novels.

Total customers asked = 60

People who like reading = 28

Estimated needed = 0.06

True proportion = 82%

The formula for sample size calculation for proportions is to be used to get the sample size necessary to estimate the proportion of consumers who enjoy reading fantasy novels with a specific margin of error and confidence level.

Calculating using margin of error -

[tex]n = (Z^2 * p * (1 - p)) / E^2[/tex]

Substituting the values -

[tex]n = (1.28^2 * 0.4667 * (1 - 0.4667)) / 0.06^2[/tex]

= 220.4 or 221.

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Which equation has a vertex at (3, –2) and directrix of y = 0?
y + 2 = StartFraction 1 Over 8 EndFraction (x minus 3) squared
y + 2 = 8 (x minus 3) squared
y + 2 = negative StartFraction 1 Over 8 EndFraction (x minus 3) squared
y + 2 = negative 8 (x minus 3) squared

Answers

The equation that has a vertex at (3, -2) and a directrix of y = 0 is:

y + 2 = -1/8(x - 3)^2

The vertex form of a quadratic equation is given by y = a(x - h)^2 + k, where (h, k) represents the vertex of the parabola.

In this case, the given vertex is (3, -2), so we have h = 3 and k = -2. Plugging these values into the vertex form, we get:

y = a(x - 3)^2 - 2

Since the directrix is y = 0, we know that the parabola opens downward. Therefore, the coefficient 'a' must be negative.

Hence, the equation that satisfies these conditions is:

y + 2 = -1/8(x - 3)^2

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Determine whether the relation on the set of all people is reflexive, symmetric, antisymmetric, and/or transitive, where (a. b) E Rif and only if ind b have a common grandparent.

Answers

The relation on the set of all people described as (a, b) E Rif if and only if a and b have a common grandparent is reflexive and transitive, but not symmetric or antisymmetric.

Reflexive: A relation is reflexive if every element in the set is related to itself. In this case, every person would have a common grandparent with themselves, so the relation is reflexive.

Symmetric: A relation is symmetric if whenever (a, b) is in the relation, then (b, a) is also in the relation. However, having a common grandparent is not necessarily symmetric. For example, if person A has a common grandparent with person B, it does not imply that person B has a common grandparent with person A. Therefore, the relation is not symmetric.

Transitive: A relation is transitive if whenever (a, b) and (b, c) are in the relation, then (a, c) is also in the relation. In this case, if person A has a common grandparent with person B, and person B has a common grandparent with person C, then it follows that person A has a common grandparent with person C. Therefore, the relation is transitive.

Antisymmetric: A relation is antisymmetric if whenever (a, b) and (b, a) are in the relation, then a = b. In this case, if two people have a common grandparent, it does not imply that they are the same person. Therefore, the relation is not antisymmetric.

To summarize, the relation is reflexive and transitive, but not symmetric or antisymmetric.

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Complete question:

This is a multi-part question. Once an answer is submitted, you will be unable to return to this part Determine whether the relation on the set of all people is reflexive, symmetric, antisymmetric, and/or transitive, where (a. b) E Rif and only if ind b have a common grandparent. (Check all that apply)

reflexive

symmetric

transitive

antisymmetric

USE CRAMERS RULE TO X - X2 +4x3 = -4 - 8x, +3x2 + x3 = 8,2X1- X2 + X3 = 0.

Answers

Answer: Cramer’s Rule is a method for solving systems of linear equations using determinants. The given system of equations can be written in matrix form as:

​1−82​−13−1​411​​​x1​x2​x3​​​=​−480​​

Let A be the coefficient matrix and let D be its determinant. Then, according to Cramer’s Rule, the solution to the system is given by:

x1​=det(A)det(A1​)​,x2​=det(A)det(A2​)​,x3​=det(A)det(A3​)​

where A1​, A2​, and A3​ are the matrices obtained by replacing the first, second, and third columns of A with the right-hand side vector, respectively.

First, we calculate the determinant of A:

det(A)=​1−82​−13−1​411​​=1​3−1​11​​−(−1)​−82​11​​+4​−82​3−1​​=(3+1)+(8+2)+4(−8+6)=4+10−8=6

Next, we calculate the determinants of A1​, A2​, and A3​:

det(A1​)=​−480​−13−1​411​​=(−4)​3−1​11​​−(−1)​80​11​​+4​80​3−1​​=(−4)(3+1)+(8)+4(−8)=−16+8−32=−40

det(A2​)=​1−82​−480​411​​=(1)​80​11​​−(−4)​−82​11​​+(4)​−82​80​​=(8)+(32)+(64)=104

det(A3​)=​<IPAddress>−4<IPAddress><IPAddress>​​=(0)(3+<IPAddress>)−(<IPAddress>)+(<IPAddress>)=<IPAddress>

So, the solution to the system is given by:

x<​IPAddress>=<IPAddress>=<IPAddress>,x<​IPAddress>=<IPAddress>=<IPAddress>,x<​IPAddress>=<IPAddress>=<IPAddress>

Therefore, the solution to the system of equations is (x<​IPAddress>,x<​IPAddress>,x<​IPAddress>)=(<IPAddress>,<IPAddress>,<IPAddress>).

Step-by-step explanation:

The null hypothesis is that he can serve 70% of his first serves. Find the observed percentage and the standard error for percentage.

Answers

The given null hypothesis is that he can serve 70% of his first serves. We are to find the observed percentage and the standard error for percentage.

To find the observed percentage, we will need the data on the actual percentage of his first serves. However, to find the standard error, we will need to calculate it using the null hypothesis, which is given as 70%.The formula for standard error is:

Standard error = Square root of (pq/n)where p is the percentage of success, q is the percentage of failure, and n is the total number of trials.Let's assume that he played 100 games.

Then, the number of successful first serves = 70% of 100 = 70

and the number of unsuccessful first serves = 100 - 70 = 30.Hence, the observed percentage of successful first serves is 70%.Now, let's find the standard error:Standard error = sqrt(0.7 × 0.3 / 100)= sqrt(0.021)= 0.145= 14.5% (rounded to one decimal place)

Therefore, the observed percentage of successful first serves is 70%, and the standard error for the percentage is 14.5%.

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The standard error for percentage is

[tex]SE = sqrt [ p(1 - p) / n ][/tex]

The observed percentage and the standard error for percentage can be found as follows:

The null hypothesis is that he can serve 70% of his first serves.

Let the sample percentage be p.

If the null hypothesis is true, then the distribution of the sample percentage can be approximated by a normal distribution with a mean of 70% and a standard deviation of:

Standard deviation = [tex]sqrt [ p(1 - p) / n ][/tex]

Where n is the sample size.

The standard error of percentage is given by the formula:

[tex]SE = sqrt [ p(1 - p) / n ][/tex]

Thus, the standard error for percentage is

[tex]SE = sqrt [ p(1 - p) / n ][/tex]

The observed percentage, p can be found by conducting a survey or experiment.

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Five students took a quiz. The lowest score was 3, the highest score was 10, and the mode was 5. A possible set of scores for the students is:

Answers

After carefully thinking about the given data and applying a set of calculation we announce that the satisfactory sequence of the given students representing the scored achieved from lowest to highest is 1, 3, 4, 5, 7, under the condition that average (mean) is 4

The elaboration for the series of action is that there is one possible set of scores for the five students that goes well with the given conditions (lowest score of 1, highest score of 7, and an average of 4) is 1, 3, 4, 5, 7
We have to keep this in mind that there are exist many possible sets of scores that could satisfy these conditions, so this is just one instance .
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Help please Im trying to go to sleep The moment of inertia of the club head is a design consideration for a driver in golf. A larger moment of inertia about the vertical axis parallel to the club face provides more resistance to twisting of the club face for off-center hits. The mass of one club head is 200 g and its moment of inertia is 5000 g cm2 . What is the radius of gyration of this club head Consider the subtraction problem, 2013 - 40, for which Allie gets the answer 1073. What is most likely Allie's misunderstanding, and, if uncorrected, what would Allie's answer be for 304 - 9? State a decomposition theorem for finite generated modules over the PID a Z(p) = {{ = : a : a,b Z and pb}. An object accelerates uniformly from 3. 0 meters per second east to 8. 0 meters per second east in 2. 0 seconds. What is the magnitude of the acceleration of the object ? Convert each time into conversational time using expressions such as de l'aprs-midi and du soir. Follow the model and write out the times. Modle : 13h00 = une heure de l'aprs-midi . 12h30: ________________________________ . 13h10: ________________________________ . 07h45: ________________________________ . 22h50: ________________________________ . 09h15: ________________________________ . 18h40: ________________________________ . 03h05: ________________________________ . 15h30: ________________________________ Which casual relationship from the story is continuous?One of the dogs almost bites Snowball's tail, but the pig gets free just in time.The animals like Snowballs plan for the windmill, and they want to vote for it.Napoleon advises the animals not to vote for Snowballs plan for the windmill.The dogs chase Snowball away, leaving Napoleon as an unchallenged leader.| a transparent object with an isosceles right triangular cross-section has an index of refraction n2 = 1.2, as shown in the diagram below. A light beam in air is incident on this object, making an angle ?in = 75? with respect to the x-axis, as shown. At what angle (with respect to the x-axis), ?out, does the observer see the light beam exit the object? By inspection, determine if each of the sets is linearly dependent.(a) S = {(1, 3), (3, 2), (-2, 6)}O linearly independentO linearly dependent(b) S = {(1, -5, 4), (4, -20, 16)}O linearly independentO linearly dependent(c) S = {(0, 0), (1, 0)}O linearly independentO linearly dependent Help please question in the picture the most appropriate organizational pattern for the claim ""the state legislature should raise the minimum wage"" would be? Canada's GDP consumption over the last four years datadraw figures which going up and down considering GDP consumption.Find reasons for changing. bro please i need the correct answer i will give u a brainliest to please i really need help Which of the following is the best description of the first law of thermodynamics? The entropy of an isolated system increases until the system reaches thermal equilibriunm Thermal energy flows from the colder object to the warmer object. outside force. The change in thermal energy ofa systemis equal to the energy transferred into An objet will maintain its current state of motion unless acted upon by an or out of the system as work, heat, or both. green < 9 red > 4 red > 4 red > 4 If yellow skin (Y) exhibits incomplete dominance with red skin (y), what color of skin would result from the genotype Yy? pls help 4264(12)3= how would it change the effectiveness of the sentence if we rewrote it as our motives and objects must be clear to all the world while we do these deeply momentous things the difference between the squares of two numbers is 32. twice the square of the first number increased by the square of the second number is 76. find the numbers. Rating the contingency table to the right to (a) calculate the nal frequencies, and (b) find the expected frequency for call in the contingency table. Assume that the variables ndependent Size of restaurant Seats 100 or fewer Seats over 100 Excent 182 185 200 316 + alculate the marginal frequencies and samples stre of restaurant Seats 100 or fewer Seats over 100 Total Excellent 182 186 368 Rating Fair 200 316 516 Poor 161 155 356 Total 513 557 1200 And the expected frequency for each of in the contingency table Rating Excellent Poor e of restaurant Beats 100 or fewer Beats over 100 Round to two decimal places as needed Ip me solve this View an example Get more help Clear all Check on & MacBook Air.