Question Two

The concept of sets underlies every branch of modern mathematics for economics. Suppose the universal set is a set of positive integers, Z + , and let

X={ x € Z + :x<=20 and x^ 2 € Z +}

Y={ x € Z + :x<=24 and sqrt x € Z +}

a) Determine X U Y and X n Y in enumeration and functional form.

b) Determine sets X n Z +, X U Z + ,Y n Z +, Y U Z + .

Answers

Answer 1

The sets X and Y are defined based on specific conditions on positive integers. In functional form, X n Y can be represented as X n Y = {x € Z + : x ≤ 20, x ≤ 24, and x^2 € Z +, sqrt(x) € Z +}.

a) To find X U Y (the union of X and Y), we need to identify all the positive integers that satisfy either the condition for X or the condition for Y. In enumeration form, X U Y = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 24}. In functional form, X U Y can be represented as X U Y = {x € Z + : (x ≤ 20 and x^2 € Z +) or (x ≤ 24 and sqrt(x) € Z +)}.

To find X n Y (the intersection of X and Y), we need to identify the positive integers that satisfy both the condition for X and the condition for Y. In enumeration form, X n Y = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16}. In functional form, X n Y can be represented as X n Y = {x € Z + : x ≤ 20, x ≤ 24, and x^2 € Z +, sqrt(x) € Z +}.

b) To determine the sets X n Z + and Y n Z +, we need to identify the positive integers that satisfy the conditions for X and Y, respectively, and also belong to the universal set of positive integers, Z +. Since X and Y are subsets of Z +, X n Z + = X and Y n Z + = Y.

To find X U Z +, we need to identify all the positive integers that satisfy either the condition for X or belong to Z +. In this case, X U Z + = Z + since all positive integers are included in X. Similarly, Y U Z + = Z + since all positive integers are included in Y.

In summary, X U Y = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 24} and X n Y = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16}. The sets X n Z + and Y n Z + are equal to X and Y, respectively, while X U Z + and Y U Z + are both equal to Z +.

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Related Questions

1 3/4 cups of flour for one batch but he wants to make 1 1/2 batches. How many more cups of flour will he need

Answers

Answer:

[tex]2\frac{5}{8} cups = 1\frac{1}{2}\ batches[/tex]

Step-by-step explanation:

Given

[tex]1\frac{3}{4} cups = 1\ batch[/tex]

Required

Number of cups for [tex]1\frac{1}{2}[/tex] batches

[tex]1\frac{3}{4} cups = 1\ batch[/tex]

Multiply both sides by [tex]1\frac{1}{2}[/tex]

[tex]1\frac{1}{2} * 1\frac{3}{4} cups = 1\ batch * 1\frac{1}{2}[/tex]

[tex]1\frac{1}{2} * 1\frac{3}{4} cups = 1\frac{1}{2}\ batches[/tex]

Express fractions as improper fractions

[tex]\frac{3}{2} * \frac{7}{4} cups = 1\frac{1}{2}\ batches[/tex]

[tex]\frac{21}{8} cups = 1\frac{1}{2}\ batches[/tex]

Express fraction as improper fraction

[tex]2\frac{5}{8} cups = 1\frac{1}{2}\ batches[/tex]

en que consiste la jerarquía de operaciones?

Answers

Answer:

La jerarquía de operaciones es un método para resolver operaciones con múltiples operadores; saber realizarla te servirá para resolver los diversos problemas que te presenten en tu examen CENEVAL EXANI-II.  En primer lugar, se deben resolver las operaciones de potencias y raíces.

Step-by-step explanation:

solve for x round to your nearest tenth

Answers

Answer:

x ≈ 5.98

Steps:

tan(50.1°) = x/5

1.19.. = x/5

x = 5 × 1.19 ..

x = 5.97.. ≈ 5.98

Please help! Will give Brainliest! SHOW ALL WORK
Factor:
2x^(2)+ay-ax^(2)-2y

Answers

Answer:

(2 - a) (x² - y)

Step-by-step explanation:

2x² + ay - ax² - 2y

=> 2x² - 2y + ay - ax²

=> 2 (x² - y) + -a (-y + x²)

=> 2 (x² - y) + -a (x² - y)

=> (2 - a) (x² - y)

A package of 12 pencils costs $0.96. At this rate, how much would 100 pencils cost?



A. $8.35


B. $10.80


C. $9.60


D. $8.00

Answers

Answer:

B

Step-by-step explanation:

Please Give brainliest

Answer:

D

Step-by-step explanation:

a manufacturer is designing a new container for their chocolate-covered almonds. Their original container was a cylinder with the height of 18 cm and a diameter of 14 cm. the new container can be modeled by a rectangular prism with a square base and will contain the same amount of chocolate-covered almonds. if the new container's height is 16 cm, determine and state, to the nearest tenth of a centimeter, the side length of the new container if both containers contain the same amount of almonds

Answers

Answer:

answer is 24

Step-by-step explanation:

The side length of the rectangular prism with a square base is 13.2 cm if the original container was a cylinder with the height of 18 cm and a diameter of 14 cm.

What is a cylinder?

In geometry, it is defined as the three-dimensional shape having two circular shapes at a distance called the height of the cylinder.

We know the volume of the cylinder is given by:

[tex]\rm V = \pi r^2 h[/tex]

The radius of the cylinder r = 14/2 = 7 cm

The volume of the cylindrical container V = π(7)²(18) = 882π cubic cm

Let's suppose the side length is L:

Then the volume of the rectangular prism is the same as the cylindrical container:

882π = L×L×16       (h = 16 cm)

882π = 16L²  

L = 13.15 ≈ 13.2 cm

Thus, the side length of the rectangular prism with a square base is 13.2 cm if the original container was a cylinder with the height of 18 cm and a diameter of 14 cm.

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Paper lanterns are $3.50 each. Write
a direct proportion equation using p
for paper lanterns and c for total
cost.
A. 3.50c = p
B. 3.5pc
C. 3.50 + p = C
D. 3.50p = 0

Answers

Answer:

it's probably C

Step-by-step explanation:

️‍♀️

Question is in picture

Answers

I think it’s b but I’m not rlly sure sorry

Use these equations to find ∂z/∂x and ∂z/∂y for the following.
x8 + y8 + z5 = 6xyz

Answers

For the given equation x⁸ + y⁸ + z⁵ = 6xyz, the value of partial derivatives are ∂z/∂x = (6yz - 8x⁷) / (5z⁴ - 6xz) and ∂z/∂y = (6xz) / (8y⁷ - 6xy)

To find the partial derivatives ∂z/∂x and ∂z/∂y for the equation x⁸ + y⁸ + z⁵ = 6xyz, we need to differentiate the equation with respect to x and y while treating y and z as constants.

Taking the partial derivative with respect to x (∂z/∂x), we differentiate each term separately:

8x⁷ + 0 + 5z⁴ (∂z/∂x) = 6yz + 6xz(∂z/∂x)

Simplifying the equation, we get:

8x⁷ + 5z⁴ (∂z/∂x) = 6yz + 6xz(∂z/∂x)

Now, let's take the partial derivative with respect to y (∂z/∂y):

0 + 8y⁷ + 0 (∂z/∂y) = 6xz + 6xy(∂z/∂y)

Simplifying further:

8y⁷ (∂z/∂y) = 6xz + 6xy(∂z/∂y)

To find the values of ∂z/∂x and ∂z/∂y, we need to isolate the partial derivatives:

∂z/∂x = (6yz - 8x⁷) / (5z⁴ - 6xz)

∂z/∂y = (6xz) / (8y⁷ - 6xy)

These equations give the partial derivatives of z with respect to x and y for the given equation x⁸ + y⁸ + z⁵ = 6xyz.

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Among various populations of plants or animals, diseases spread exponentially. Use the function y = 6000(1 - e^-0.154)
to model the spread of the Avian Bird Flu disease among a flock of 6000 chickens on a chicken farm, with t equal to
the number of days since the first case of the disease. How many birds will be infected with the Flu after 6 days?
3560 chickens
C. 1280 chickens
356 chickens
d. 516 chickens
a.

Answers

Answer: A. 3560 chickens

Step-by-step explanation:

Plugged in the 6 days into the equation provided

Birds will be infected with the Flu after 6 days will be 3560 chickens

What is exponential?

An exponential function is a mathematical function of the following form: f ( x ) = a^x. where x is a variable, and a is a constant called the base of the function.

Given function: y = 6000(1 - [tex]e^{-0.15t}[/tex])

Total birds are =6000

Now, take t= 6 days.

So, y = 6000(1 - [tex]e^{-0.15t}[/tex])

y= 6000(1- [tex]e^{-0.15 * 6}[/tex])

 = 6000 (1-0.40656)

 = 6000*0.59343

 = 3560.58204

 = 3560 birds

Hence, 3560 birds get infected in 6 days.

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how might larcom’s initial impression of the mill have been different if she had started as a machine worker?

Answers

If Harriet Hanson Robinson (Larcom) had started her career in the mill as a machine worker instead of as a doffer, her initial impression of the mill may have been significantly different.

Here are a few ways her perspective might have been altered:

Physical Experience: As a machine worker, Larcom would have been directly involved in operating the machinery. She would have experienced the physical demands and potentially dangerous conditions associated with working with heavy machinery. This hands-on experience might have given her a greater appreciation for the risks and challenges faced by the workers. Social Interaction: Machine workers often worked in close proximity to each other, tending to the machines and coordinating their tasks. By working alongside her fellow machine workers, Larcom would have had more direct contact and interaction with her peers. This could have provided her with a deeper understanding of the camaraderie, unity, and challenges faced by the workers as a community.

Skill Development: Operating the machines required a certain level of technical skill and knowledge. If Larcom had started as a machine worker, she would have gained expertise in machine operation and maintenance. This technical knowledge could have given her a different perspective on the machinery, its intricacies, and its impact on the workers. Perspective on Management: As a machine worker, Larcom might have had more direct interactions with mill managers and overseers. This could have given her insights into the management practices, decision-making processes, and power dynamics within the mill. Such firsthand experiences might have influenced her initial impression of the mill's management and their treatment of workers.

Overall, starting as a machine worker would have provided Larcom with a different vantage point and firsthand experience of the mill's operations. This could have shaped her understanding of the work environment, the challenges faced by the workers, and the dynamics between management and labor.

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Classify the following expression by degree and number of terms. 6 - 3x - 2

Answers

Answer:

in terms of degree it is linear equation

in terms of number of terms it is binomial

Which graph represents the function f(x) = 4|x|?

Answers

i’m pretty sure it’s A

Answer:

A

Step-by-step explanation:

got it correct in edu

Drag each sign or value to the correct location on the equation. Each sign or value can be used more than once, but not all signs and values will
be used.
The focus of a parabola is (-4,-5), and its directrix is y=-1. Fill in the missing terms and signs in the parabola's equation in standard form.

Answers

Answer: (x+4)² = -8 (y+3)

Step-by-step explanation: I got this correct on Edmentum.

i need to know what -2(3x)+56

Answers

Answer:

-6x + 56

Step-by-step explanation:

-2(3x) + 56

-6x + 56

hehe guess it right;)

Answers

Answer:

I don't understand this at all but I wanted to take a stab at it anyway.

It's not an even number, it's less than 50, it has to be divisible by six or three in order to be 5 more than a perfect square, and it has to be two or three digits that equal 40.

Sounds hard.

Okay first I want to get all the odd numbered equations that could equal 40

1+39      19+21

3+37      17+23

5+35      15+25

7+33      

9+31      

11+29    

13+27    

This is taking so much brain power, wow... So none of those so far would work, which makes me think that it would be a single digit equation to make it double digit, but nothing, not even 9+9 equals 40, so at least one of the numbers would have to be double digit but that makes no sense because then the number would have to have three digits, which makes it more than 100!

This is impossible. I think I have to rephrase my answer above in saying that the number has to be more than 100, but that means I have no idea what that first line means...

I'm so frustrated by this imao... Asker of the question, if you've figured out the answer please let me know because I am so confused.

Answer:

I DONT KNOW

Step-by-step explanation:

hehe

Use cylindrical coordinates. ∭_e x^2 dv .where E … solid thati x2 dV, where E is the solid that lies within the cylinder x^2 + y^2=4, above the plane z = 0, and below the cone z^2 4x^2 + 4y^2

Answers

The value of the triple integral ∭_E x² dV over the given solid E is 64π/5.

To evaluate the triple integral ∭_E x^2 dV, where E is the solid that lies within the cylinder x² + y² = 4, above the plane z = 0, and below the cone z² = 4x² + 4y², we can express the integral in terms of cylindrical coordinates.

In cylindrical coordinates, we have:

x = r cos(theta)

y = r sin(theta)

z = z

The limits for the cylindrical coordinates are as follows:

0 ≤ r ≤ 2 (limits for the radius)

0 ≤ theta ≤ 2π (limits for the angle)

0 ≤ z ≤ sqrt(4r²) = 2r (limits for the height, as per the cone equation)

Now let's express the integral in cylindrical coordinates:

∭_E x² dV = ∭_E (r cos(theta))² r dz dr d(theta)

Let's evaluate the integral step by step:

∫[0 to 2π] ∫[0 to 2] ∫[0 to 2r] (r³ cos²(theta)) dz dr d(theta)

We can simplify the innermost integral with respect to z:

∫[0 to 2π] ∫[0 to 2] [r³ cos²(theta)z] |[0 to 2r] dr d(theta)

= ∫[0 to 2π] ∫[0 to 2] (r³ cos²(theta)(2r)) dr d(theta)

= 2 ∫[0 to 2π] ∫[0 to 2] (2r⁴ cos²(theta)) dr d(theta)

Now, let's integrate with respect to r:

2 ∫[0 to 2π] [(1/5) r⁵ cos²(theta)] |[0 to 2] d(theta)

= 2 ∫[0 to 2π] [(1/5)(32 cos²(theta))] d(theta)

= (64/5) ∫[0 to 2π] cos²(theta) d(theta)

To evaluate the remaining integral, we can use the identity cos²(theta) = (1 + cos(2theta))/2:

(64/5) ∫[0 to 2π] [(1 + cos(2theta))/2] d(theta)

= (64/10) ∫[0 to 2π] (1 + cos(2theta)) d(theta)

= (64/10) [(theta + (1/2)sin(2theta))] |[0 to 2π]

= (64/10) [(2π + (1/2)sin(4π)) - (0 + (1/2)sin(0))]

= (64/10) (2π + 0 - 0)

= (64/10) (2π)

= 128π/10

= 64π/5

Therefore, the value of the triple integral ∭_E x² dV over the given solid E is 64π/5.

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What is the time complexity of binary search?
a) O(N^2)
b) O(N)
c) O(NLogN)
d) None

Answers

The time complexity of the binary search is c) O(NLogN)

An effective searching technique that uses sorted arrays is a binary search. The search space is continually divided in half until the target element is located or the search space is empty, using a divide-and-conquer strategy. It makes the necessary adjustments to the search bounds at each stage by comparing the target element to the centre element of the active search area.

The divide-and-conquer strategy is logarithmic, hence binary search has an O(log n) time complexity. This implies that number of operations needed to discover the target element rises at a logarithmic rate as input size increases. When compared to linear search algorithms with O(n) complexity, where each element must be evaluated sequentially, binary search is significantly more efficient for big arrays due to its logarithmic time complexity.

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Find the general solution of the third order equation, in real form without using Laplace Transform ỹ + 343y = 0

Answers

Given equation is y''' + 343y = 0 which is a third-order linear differential equation. To find the general solution of the equation, we can use the characteristic equation of the differential equation as follows;

Let y = erx be the trial solution of the differential equation, where e is the exponential function and r is an unknown constant to be determined. Substituting the trial solution into the differential equation, we have; y''' + 343y = 0 y' = rerx, y'' = rerx, y''' = rerx. Substituting into the differential equation, we have;r³erx + 343erx = 0. Factorizing out erx, we have erx(r³ + 343) = 0For erx ≠ 0;r³ + 343 = 0r³ = -343r = (-343)¹/³ = -7 (r = -7, since we are working with real forms of the equation). Therefore, the general solution of the third order linear differential equation is;

y = c₁e^-7x + c₂e^-7x cos(12.124x) + c₃e^-7x sin(12.124x) where c₁, c₂, and c₃ are arbitrary constants.

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Find the perimeter of rectangle with length 6 inches and width 3 inches.

Answers

Answer:

18

Step-by-step explanation:

Formula

P = 2 * (L + W)

Solution

L = 6

W = 3

P = 2 (6 + 3)

P = 2 (9)

P = 18

Mr. Singh needed to understand the trend of his students’ latest test scores. Find the mean and median for each set of data, and then determine which gives a better picture of the scores.

Scores: 89, 99, 80, 5, 90, 0, 100, 95

Answers

Answer:

See explanations below

Step-by-step explanation:

Mean is the average of the data

Mean = sum of data/sample size

Sum of data = 89+99+80+5+90+0+100+95

Sum of data = 558

Sample size = 8

Mean = 558/8

Mean = 69.75

Median is the data value in the middle after rearrangement

Rearrange

0 , 5, 80) 89, 90, (95, 99 100

Median = 89+90/2

Median = 89.5

The parameter that gives a better picture of the scores is the Mean since all the given datas are taken into consideration

The mean test score is

✔ 69.75

.

The median test score is

✔ 89.5

.

Which measure of center best represents the test data?

✔ median

I hope this helps!

a hiker goes 6 miles east and then turns south. if the hiker finishes 7.2 miles from the starting point. how far south did the hiker go?

Answers

Answer:

1.2

Step-by-step explanation:

You have to subtract 7.2 - 6 = 1.2

East and south direction motion are perpendicular to each other. The hiker went approx 4 miles in south.

How are directions related?

East or west are perpendicular (forming 90° ) to north or south directions.

North is 180° to south, and east is 180 degrees to west.

What is Pythagoras Theorem?

If ABC is a triangle with AC as the hypotenuse and angle B with 90 degrees then we have:

[tex]|AC|^2 = |AB|^2 + |BC|^2[/tex]

where |AB| = length of line segment AB.


Considering the diagram attached below, we deduce that the triangle ABC is right angled triangles, and thus, its sides' lengths will follow Pythagoras theorem.

The movement the hiker did in the south direction is the length of the side BC, denoted by |BC| = x miles (assume)

Then, by applying Pythagoras theorem, we get:

[tex]|AC|^2 = |AB|^2 + |BC|^2\\(7.2)^2 = 6^2 + x^2\\51.84 = 36 + x^2\\\\\text{Subtracting 36 from both the sides and taking root, we get}\\\\x = \sqrt{15.86} \approx 3.98 \approx 4 \: \rm miles[/tex]

(took positive root since distance is a non-negative quantity)

Thus, the hiker went approx 4 miles in south.

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Plz help ASAP and thank you!

Answers

Answer:

Plot attached

Step-by-step explanation:

We want to locate √36 and ∛36 on the given number line

Now, √36 = 6.

And ∛36 = 3.3

I have attached a plot number line both values as we are told in the question


Use the appropriate substitution to find the explicit solution
to the Bernoulli DE dy/dt-y=e^(-2t)*y^2

Answers

[tex]y = (e^{(-2t)} + C . e^{(-t)})^{(-1)}[/tex].  is the explicit solution to the given Bernoulli differential equation. we used an appropriate substitution to transform it into a linear differential equation.

The given Bernoulli differential equation is in the form [tex]dy/dt - y = e^{(-2t)} . y^2[/tex]. Bernoulli equations can be transformed into linear equations by using a substitution. In this case, we can let [tex]v = y^{(-1)[/tex]be our substitution.

Differentiating v with respect to t gives dv/dt = -y^(-2) * dy/dt. Substituting this into the original equation, we have:

[tex]-dv/dt - v = e^{(-2t)}.[/tex]

Now, we have transformed the Bernoulli equation into a linear first-order differential equation. We can solve this equation using standard methods. Multiplying through by -1, we get [tex]dv/dt + v = -e^{(-2t)}[/tex].

The integrating factor for this linear equation is given by [tex]e^{ \[ \int_{}^{}1\,dt \] = e^t[/tex]. Multiplying both sides of the equation by e^t, we have:

[tex]e^t. (dv/dt + v) = -e^{(t-2t)[/tex].

Simplifying further, we get [tex]d/dt (e^t.v) = -e^{(-t)[/tex].

Integrating both sides with respect to t, we obtain:

[tex]e^t . v = \[ \int_{}^{} -e^{(-t)} \,dt \][/tex].

Evaluating the integral, we get:

[tex]e^t . v = e^{(-t) }+ C[/tex],

where C is the constant of integration.

Finally, solving for v, we have:

[tex]v = e^{(-2t)} + C .e^{(-t)[/tex].

Since [tex]v = y^{(-1)[/tex], we can take the reciprocal of both sides to find the explicit solution for y:

[tex]y = (e^{(-2t) }+ C .e^{(-t)})^{(-1)}[/tex].

This is the explicit solution to the given Bernoulli differential equation.

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The equation of a line in the form y = a number creates this kind of line.

Answers

Answer:

a diagonal one??? like its linear uhm okay here i have a picture one sec

Step-by-step explanation:

A graph line would be the core answer








Given the differential equation: dy/dx +xy = 3x- e+ 2 with the initial condition y(O) = 1, find the values of y corresponding to the values of Xo+0.1 and Xo+0.2 correct to four decim

Answers

the approximate values of y at x = X₀ + 0.1 and x = X₀ + 0.2 are:

y ≈ 0.9282 at x = 0.1

y ≈ 0.8281 at x = 0.2

To solve the given differential equation, we will use an appropriate method, such as the Euler's method, to approximate the values of y at specific points.

The Euler's method uses the equation:

y₍ₙ₊₁₎ = yₙ + h * f(xₙ, yₙ),

where:

yₙ is the value of y at xₙ

h is the step size,

f(x, y) is the derivative of y with respect to x (i.e., dy/dx), and

y₍ₙ₊₁₎ is the approximation of y at the next point x₍ₙ₊₁₎ = xₙ + h.

Let's apply Euler's method to find the values of y at x = X₀ + 0.1 and x = X₀ + 0.2, where X₀ is the initial condition x = 0 and y(X₀) = 1.

Given the differential equation:

dy/dx + xy = 3x² - [tex]e^y[/tex] + 2

Rewriting the equation in the form:

dy/dx = -xy + 3x² - [tex]e^y[/tex] + 2

We have the initial condition:

y(0) = 1

Using Euler's method with a step size of h = 0.1:

1. At x = X₀ + 0.1:

  y₁ = y₀ + h * [ -x₀ * y₀ + 3 * x₀² - [tex]e^y_0[/tex] + 2 ]

      = 1 + 0.1 * [ -(0) * (1) + 3 * (0)² - e¹ + 2 ]

      = 1 + 0.1 * (0 - e + 2)

      = 1 + 0.1 * (-e + 2)

      = 1 + 0.1 * (-2.7183 + 2)

      = 1 + 0.1 * (-0.7183)

      = 1 - 0.07183

      ≈ 0.9282

2. At x = X₀ + 0.2:

  y₂ = y₁ + h * [ -x₁ * y₁ + 3 * x₁² - [tex]e^y_1[/tex] + 2 ]

      = 0.9282 + 0.1 * [ -(0.1) * (0.9282) + 3 * (0.1)₂ - [tex]e^{0.9282}[/tex] + 2 ]

      = 0.9282 + 0.1 * (-0.009282 + 0.003 - [tex]e^{0.9282}[/tex] + 2)

      ≈ 0.8281

Therefore, the approximate values of y at x = X₀ + 0.1 and x = X₀ + 0.2 are:

y ≈ 0.9282 (correct to four decimal places) at x = 0.1

y ≈ 0.8281 (correct to four decimal places) at x = 0.2

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Find the critical​ t-value that corresponds to 95​% confidence. Assume 15 degrees of freedom.

Answers

The critical t-value that corresponds to a 95% confidence level with 15 degrees of freedom is approximately 2.131.

To find the critical t-value that corresponds to a 95% confidence level with 15 degrees of freedom, we can use a t-table or a statistical software.

Using a t-table or a statistical software, we look up the critical t-value for a two-tailed test with a confidence level of 95% and 15 degrees of freedom.

For a two-tailed test, we divide the desired confidence level by 2 to account for both tails of the t-distribution. In this case, we divide 95% by 2, which gives us 0.475.

Looking up the critical t-value for a confidence level of 0.475 and 15 degrees of freedom, we find that the critical t-value is approximately 2.131.

Therefore, the critical t-value that corresponds to a 95% confidence level with 15 degrees of freedom is approximately 2.131.

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Write the equation of the line based on the given information explain the answer in slope intercept form

Answers

Answer:

y = 2/3 x - 3

Step-by-step explanation:

substitute the given slope and the coordinate into the slope-intercpet form:

y = mx + b  to solve for b,

-1 = 2/3(3) + b

=> b = -3

y = 2/3 x - 3

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Read the question and answer below. Remember that one measure of center is better than another when you have outliers in the data set. *

A. A
B. B
C. C
D. D

Answers

Answer:

C

Step-by-step explanation:

C is the answer to your question

Libby can finish a paper in 2 hours. Ethan can finish the same paper in 4 hours. How
long will it take them to finish a paper if they work together?

Answers

Answer:

1.33333 hours

Step-by-step explanation:

Given :

Time taken by Libby = 2 hours

Time taken by Ethan = 4 hours

rate = 1 / time taken

Libby's rate = 1 /2

Ethan's rate = 1/4

Combined rate = Libby's rate + Ethan's rate

Combined rate = 1/2 + 1/4 = 3/4

Time taken = 1 / combined rate

Time taken = 1 / (3/4)

Time taken = 4 /3

Time taken = 1.33333 hours

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