Shawrya Singh moved from India to Australia on 1 December 201W on a permanent residency visa to work for an Australian auditing firm. He is also a shareholder in a number of Australian companies, none of which is a base rate entity.

During the 201W/1X year he received the following distributions:

01/10/201W

70% franked distribution from CSL

$2,000

01/03/201X

60% franked distribution from BHP

$4,000

13/04/201X

Fully franked distribution from NAB

$3,200

15/06/201X

Unfranked distribution from ANZ

$4,500

Shawrya also received a salary of $57,000 paid by his Australian employer in the 201X/1W year.

Required

Assuming Shawrya does not have any allowable deductions in the current year, calculate his taxable income and tax liability for the year ending 30 June 201X, stating relevant legislation to support your answer.

Answers

Answer 1

The taxable income of Shawrya Singh for the year ending 30 June 201X is $18,871.43, and the tax liability is $6,039.98.

Calculation of Shawrya Singh's taxable income and tax liability for the year ending 30 June 201X:

The following distributions were received by Shawrya Singh during the year 201W/1X:01/10/201W: 70%

franked distribution from CSL: $2,000

Franking Credit = 2,000 * 0.7 = $1,400

Grossed-up dividend = $2,000 + $1,400 = $3,40001/03/201X: 60%

franked distribution from BHP: $4,000 13/04/201X

Credit = 4,000 * 0.6 = $2,400

Grossed-up dividend = $4,000 + $2,400 = $6,400

13/04/201X: Fully franked distribution from NAB: $3,200

Franking Credit = 3,200

Grossed-up dividend = $3,200 / (1 - 0.3) = $4,571.43* 15/06/201X: Unfranked distribution from ANZ: $4,500

Grossed-up dividend = $4,500 / (1 - 0) = $4,500

Total Grossed-up Dividend = $3,400 + $6,400 + $4,571.43 + $4,500 = $18,871.43*

The franking rate is assumed to be 30% because Shawrya is not a base rate entity. Deducting the Deductions: No deductions are allowable; thus, the taxable income is equivalent to the grossed-up dividend of $18,871.43.

Tax Payable = $18,871.43 * 0.32 = $6,039.98 (Marginal tax rate is 32%)

Therefore, the taxable income of Shawrya Singh for the year ending 30 June 201X is $18,871.43, and the tax liability is $6,039.98. Relevant legislation to support the answer is available in the Income Tax Assessment Act 1997.

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Related Questions

Assume that the probability of any newborn baby being a boy is 1/2 and that all births are independent. If a family has five children (no twins). what is the probability of the event that none of them are boys? The probability is __
(Simplify your answer)

Answers

The probability of any newborn baby being a boy is 1/2, and since all births are assumed to be independent, we can use the probability of a girl (1 - 1/2 = 1/2) to calculate the probability of none of the five children being boys.

The probability of having a girl for each child is 1/2. Since all births are independent, the probability of having all five children be girls is calculated by multiplying the individual probabilities:

(1/2) * (1/2) * (1/2) * (1/2) * (1/2) = (1/2)^5 = 1/32

Therefore, the probability of none of the children being boys is 1/32.

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Find the value of the variable for each polygon​. Please

Answers

The value of measure of variable r is,

⇒ r = 164 degree

Since, We know that,

The sum of all the angles of Octagon is,

⇒ 1080 degree

Here, All the angles are,

⇒ 132°

⇒ 125°

⇒ 140°

⇒ r°

⇒ 113°

⇒ 120°

⇒ 145°

⇒ 141°

Hence, We get;

132 + 125 + 140 + r + 113 + 120 + 145 + 141 = 1080

916 + r = 1080

r = 1080 - 916

r = 164

Thus, The value of measure of variable r is,

⇒ r = 164 degree

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Give an example of a problem that can be made easy to solve
mentally by using the
commutative property of multiplication. Write a relevant
equation.

Answers

We can simplify the equation:

a * b + b * a = 2 * a * b

By applying the commutative property of multiplication, we reduced the equation to a simpler form, making it easier to solve mentally.

Let's consider the problem of finding the sum of the product of two numbers, where the order of multiplication does not matter.

Example problem:

Find the sum of the product of two numbers, regardless of the order of multiplication.

Equation:

Let's say we have two numbers, a and b. We want to find the sum of their products, regardless of the order in which they are multiplied:

a * b + b * a

Using the commutative property of multiplication, we know that the order of multiplication can be switched without affecting the result. Therefore, we can simplify the equation:

a * b + b * a = 2 * a * b

By applying the commutative property of multiplication, we reduced the equation to a simpler form, making it easier to solve mentally.

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similar to 4.1.23 in rogawski/adams. use the linear approximation to estimate δf=e−0.3−1. what is f(x)? f(x)=

Answers

To estimate δf = [tex]e^(-0.3)[/tex] - 1 using linear approximation, we can start by finding the tangent line to the curve of the function f(x) at the given point x = -0.3. This can be done by calculating the derivative of f(x) and evaluating it at x = -0.3.

Let's assume the function f(x) is given by f(x) = [tex]e^x[/tex]. Taking the derivative of f(x) with respect to x, we have f'(x) = [tex]e^x.[/tex]

Now, we can evaluate the derivative at x = -0.3:

f'(-0.3) = e^(-0.3).

This gives us the slope of the tangent line at x = -0.3. Next, we use the point-slope form of a line to find the equation of the tangent line:

y - f(-0.3) = f'(-0.3) * (x - (-0.3)).

Since f(-0.3) = [tex]e^(-0.3)[/tex], we have:

y - e^(-0.3) = e^(-0.3) * (x + 0.3).

This equation represents the linear approximation of f(x) near x = -0.3. To estimate δf = e^(-0.3) - 1, we can evaluate the above equation at x = -0.3:

[tex]f(x) = e^(-0.3) * (x + 0.3) + e^(-0.3).[/tex]

Hence, [tex]f(x) = e^(-0.3) * x + e^(-0.3) * 0.3 + e^(-0.3).[/tex]

[tex]f(x) = e^(-0.3) * x + 2 * e^(-0.3).[/tex]

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a. If a, b, c and d are integers such that a|b and c|d, then a + d|b + d. b. if a, b, c and d are integers such that a|b and c|d, then ac|bd. e. if a, b, c and d are integers such that a b and b c, then a c

Answers

The answers to the three mentioned statements on integers is given here:

a. False.

b. True.

e. True.

Reasons for the statements to be true/false?

a. The statement "If a, b, c, and d are integers such that a|b and c|d, then a + d|b + d" is false. Counter example: Let a = 2, b = 4, c = 3, and d = 6. Here, a|b and c|d, but a + d = 2 + 6 = 8 does not divide b + d = 4 + 6 = 10.

b. The statement "If a, b, c, and d are integers such that a|b and c|d, then ac|bd" is true. This can be proven using the property of divisibility: If p|q and r|s, then pr|qs. Applying this property, since a|b and c|d, we have ac|bd.

e. The statement "If a, b, c, and d are integers such that a<b and b<c, then a<c" is true. This is known as the transitive property of inequality. If a is less than b and b is less than c, then it follows that a is less than c.

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Which function has an axis of symmetry of x = −2?

f(x) = (x − 1)2 + 2
f(x) = (x + 1)2 − 2
f(x) = (x − 2)2 − 1
f(x) = (x + 2)2 − 1

Answers

Answer:

(x + 2)^2 - 1

Step-by-step explanation:

The parent function of a quadratic function is y = x^2 with an axis of symmetry at x = 0. All of the given possible answer choices show transformations being applied to the parent function. Transforming the function left or right also changes the axis of symmetry. Thus, we need to find the transformed function that shifts the parent function two times to the left (this means a positive two is applied inside the parentheses to x):

(x - 1)^2 + 2 shifts the function right 1 and up 2, thus the axis of symmetry is x = 1

(x + 1)^2 - 2 shifts the function left 1 and down 2, thus the axis of symmetry is x = -1

(x - 2)^2 - 1 shifts the function right 2 and down 1, thus the axis of symmetry is x = 2

(x + 2)^2 - 1 shifts the function left 2 and down 1, thus the axis of symmetry is x = -2

You compare downloading speeds for 3 internet providers in various places for each to compare their download speeds and to see if they are different. You go to a bunch of friends' homes and ask which provider they use and measure download speed. Seven friends use internet provider A and got speeds of: 31, 29, 26, 29, 30, 29, 35. Friends with provider B had speeds of: 22, 27, 31, 39, 29, 30, 34. Friends with provider C had speeds of: 28, 31, 21, 25, 24, 22, 23.

Which test did you use?

Group of answer choices

regression

matched samples

completely randomized design

randomized block design

two-factor factorial

Answers

The test used in this scenario is a completely randomized design.

A completely randomized design is a type of experimental design where the subjects or participants are randomly assigned to different treatment groups. In this case, the different treatment groups are the internet providers A, B, and C.

The speeds recorded for each group of friends are independent and not matched or paired in any way.

In a completely randomized design, the random assignment of subjects to treatment groups helps to minimize bias and ensure that the results are not influenced by any specific characteristics of the participants.

This design allows for a direct comparison of the performance of each internet provider without any confounding factors.

Therefore, based on the given information, the speeds of the friends using different internet providers A, B, and C, were compared using a completely randomized design.

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Citizen registration and voting varies by age and gender. The following data is based on registration and voting results from the Current Population Survey following the 2012 election. A survey was conducted of adults eligible to vote. The respondents were asked in they registered to vote. The data below are based on a total sample of 849. • We will focus on the proportion registered to vote for ages 18 to 24 compared with those 25 to 34. • The expectation is that registration is lower for the younger age group, so express the difference as P(25 to 34) - P(18 to 24) • We will do a one-tailed test. • Use an alpha level of .05 unless otherwise instructed. The data are given below. Age Registered Not Registered Total 18 to 24 58 51 109 25 to 34 93 47 140 35 to 44 96 39 135 45 to 54 116 42 158 55 to 64 112 33 145 65 to 74 73 19 92 75 and over 55 15 70 Total 603 246 849 If we want to conduct a hypothesis test for the difference of the proportion registered for 18 to 24 compared with 25 to 34, and this difference is equal to zero, what is the standard error? O SQRT[(-5321 .4679)/109 + (.6643*.3357)/140] O SQRT[(6081.3919)/97 +(6081*.3919)125] O 0659 O SQRTIL6064*.3936)/109+ (.6064.3936)140)

Answers

Standard error of difference of proportion in 18 to 24 and 25 to 34 is `0.0659`.

Solution: It is given that, P(25 to 34) - P(18 to 24) We will do a one-tailed test. Use an alpha level of .05 unless otherwise instructed.

Standard error can be calculated using the following formula:\[\large SE = \sqrt{\frac{\hat{p_1}(1-\hat{p_1})}{n_1} + \frac{\hat{p_2}(1-\hat{p_2})}{n_2}}\]Where, \[\large\hat{p_1}\] is the sample proportion of population 1, \[\large\hat{p_2}\] is the sample proportion of population 2, \[\large n_1\] is the sample size of population 1, \[\large n_2\] is the sample size of population 2.

Here, sample proportion of population 1 (18 to 24) is 0.5321 and sample proportion of population 2 (25 to 34) is 0.6643.So, Standard error can be calculated as:\[\large SE = \sqrt{\frac{0.5321(1-0.5321)}{109} + \frac{0.6643(1-0.6643)}{140}}\]\[\large = \sqrt{\frac{0.2487}{109} + \frac{0.2223}{140}}\]\[\large = 0.0659\]So, the standard error of difference of proportion in 18 to 24 and 25 to 34 is `0.0659`.Option C is correct.

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Use the formula {tnf(t)}(s)=(−1)ndsndn(f{f}(s)) to help determine the following the expressions. (a) L{tcosbt} (b) L{t2cosbt} (a) f{tcosbt)(s)=

Answers

the Laplace transforms are:
(a) L{tcos(bt)} = -2b^2 / (s^2 + b^2)^2.
(b) L{t^2cos(bt)} = 6b^2s^2 / (s^2 + b^2)^3.

To determine the Laplace transforms of the given expressions, we can use the formula provided: {tnf(t)}(s) = (-1)^n * d^n/ds^n [d^n/ds^n(f * f)(s)].

(a) For L{tcos(bt)}, we have n = 1, f(t) = cos(bt). Plugging these values into the formula, we get:

{tcos(bt)}(s) = (-1)^1 * d/ds [d/ds(cos(bt) * cos(bt))(s)].

Differentiating twice, we obtain:

{tcos(bt)}(s) = -d^2/ds^2 [cos^2(bt)] = -2b^2 / (s^2 + b^2)^2.

(b) For L{t^2cos(bt)}, we have n = 2, f(t) = cos(bt). Using the formula, we have:

{t^2cos(bt)}(s) = (-1)^2 * d^2/ds^2 [d^2/ds^2(cos(bt) * cos(bt))(s)].

Differentiating twice, we get:

{t^2cos(bt)}(s) = d^4/ds^4 [cos^2(bt)] = 6b^2s^2 / (s^2 + b^2)^3.

Therefore, the Laplace transforms are:
(a) L{tcos(bt)} = -2b^2 / (s^2 + b^2)^2.
(b) L{t^2cos(bt)} = 6b^2s^2 / (s^2 + b^2)^3.

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Justin flips a fair coin 8 times. What is the that he gets an odd amount of probability heads?

Answers

The probability that Justin gets an odd amount of heads when flipping a fair coin 8 times is 1/2 or 50%.

To calculate the probability of getting an odd number of heads when flipping a fair coin 8 times, we can use combinatorics.

The total number of possible outcomes when flipping a coin 8 times is [tex]2^8[/tex] = 256, as each flip has 2 possible outcomes (heads or tails).

To determine the number of outcomes that result in an odd number of heads, we need to consider the different combinations of heads and tails that would yield an odd sum. An odd number can only be obtained by having an odd number of heads (1, 3, 5, 7) because the number of coin flips is even.

We can break it down as follows:

Number of outcomes with 1 head: C(8,1) = 8

Number of outcomes with 3 heads: C(8,3) = 56

Number of outcomes with 5 heads: C(8,5) = 56

Number of outcomes with 7 heads: C(8,7) = 8

Summing up these possibilities, we get:

8 + 56 + 56 + 8 = 128

Therefore, there are 128 outcomes that result in an odd number of heads out of the total 256 possible outcomes.

The probability of getting an odd amount of heads is given by:

Probability = Number of outcomes with odd heads / Total number of outcomes

Probability = 128 / 256

Probability = 1/2

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a) Let f : R → R by f(x) = ax + b, where a + 0 and b are constants. Show that f is bijective and hence f is invertible, and find f-1. b) Let R be the relation with ordered pairs (Aaron, 25), (Brenda, 24), (Caleb 23), (Desire, 22), (Edwin 22), (Felicia 24). Here each pair consists of a graduate student and the student's age. Specify a function determined by this relation.

Answers

a) The inverse function f^(-1)(y) is given by f^(-1)(y) = (y - b)/a.

b) The function f determined by the relation R maps each student's name to their respective age.

a) To show that the function f(x) = ax + b is bijective and invertible, we need to prove both injectivity (one-to-one) and surjectivity (onto).

Injectivity:

Let x1 and x2 be arbitrary elements in the domain R such that f(x1) = f(x2). We need to show that x1 = x2.

Using the definition of f(x), we have ax1 + b = ax2 + b.

By subtracting b from both sides and then dividing by a, we get ax1 = ax2.

Since a ≠ 0, we can divide both sides by a to obtain x1 = x2.

Thus, the function f is injective.

Surjectivity:

Let y be an arbitrary element in the codomain R. We need to show that there exists an element x in the domain R such that f(x) = y.

Given f(x) = ax + b, we solve for x: x = (y - b)/a.

Since a ≠ 0, there exists an element x in R such that f(x) = y for any given y in R.

Thus, the function f is surjective.

Since the function f is both injective and surjective, it is bijective. Therefore, it has an inverse function.

To find the inverse function f^(-1), we can express x in terms of y:

x = (y - b)/a.

Now, interchange x and y:

y = (x - b)/a.

Therefore, the inverse function f^(-1)(y) is given by f^(-1)(y) = (y - b)/a.

b) The relation R with ordered pairs (Aaron, 25), (Brenda, 24), (Caleb, 23), (Desire, 22), (Edwin, 22), (Felicia, 24) can be represented as a function by considering the student's name as the input and the age as the output.

Let's define the function:

f(name) = age.

Using the given relation R, the function f determined by this relation is:

f(Aaron) = 25,

f(Brenda) = 24,

f(Caleb) = 23,

f(Desire) = 22,

f(Edwin) = 22,

f(Felicia) = 24.

So, the function f determined by the relation R maps each student's name to their respective age.

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Preliminary data analyses indicate that you can reasonably consider the assumptions for using pooled i procedures satisfied. Independent random samples of released prisoners in the fraud and firearms offense categories yielded the following information on time served in months. Obtain a 90% confidence interval for the difference between the mean times served by prisoners in the fraud and firearms offense categories
(Note X_1=8.94. s-1= 3.87 x_2 = 17.62 and s_2 = 4.12)
The 90% contidence interval is from ____ to ______
(Round to three decimal places as needed)

Answers

The 90% confidence interval is from  −11.447 to −5.913.

Given that: Sample size of fraud, n1 = 26

Sample size of firearms, n2 = 35

Sample mean of fraud, x1 = 8.94 months

Sample mean of firearms, x2 = 17.62 months

Sample standard deviation of fraud, s1 = 3.87 months

Sample standard deviation of firearms, s2 = 4.12 months T

he two samples are independent

We need to find the 90% confidence interval for the difference between the mean times served by prisoners in the fraud and firearms offense categories. Now, the point estimate of the difference in means of two populations is:

x1 − x2 = 8.94 − 17.62 = −8.68

Using the pooled t-interval formula, we get:

[8.68 − tα/2  × Sp(1/n1 + 1/n2), 8.68 + tα/2 × Sp(1/n1 + 1/n2)]

Here, the degrees of freedom is df = n1 + n2 - 2 = 59 at the 0.10 level of significance. tα/2 = t0.05 = 1.671,

from t-distribution table Pooled variance Sp

= [(n1 - 1) × s1² + (n2 - 1) × s2²] / (n1 + n2 - 2)= [(26 - 1) × 3.87² + (35 - 1) × 4.12²] / (26 + 35 - 2)≈ 17.07

Therefore, the 90% confidence interval is given as follows:

[8.68 - 1.671 × (sqrt(17.07) × sqrt(1/26 + 1/35)), 8.68 + 1.671 × (sqrt(17.07) × sqrt(1/26 + 1/35))]=[−11.447, −5.913] (rounded to three decimal places)

Hence, the required confidence interval is from −11.447 to −5.913.

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the hourly wages of a sample of eight individuals is given below. individual hourly wage ($) a 27 b 25 c 20 d 10 e 12 f 14 g 17 h 19 for the above sample, determine the following measures: a. mean b. standard deviation c. 25th percentile

Answers

The mean hourly wage is $18.The standard deviation is approximately $5.31.The 25th percentile is $13.

The hourly wages of a sample of eight individuals:Individual Hourly wage ($)a 27b 25c 20d 10e 12f 14g 17h 19a) Mean of hourly wages:Mean is calculated by taking the sum of all values and dividing by the total number of values.mean = (a + b + c + d + e + f + g + h) / 8= (27 + 25 + 20 + 10 + 12 + 14 + 17 + 19) / 8= 144 / 8= 18Therefore, the mean hourly wage is $18.

Standard deviation of hourly wages:Standard deviation is a measure of the amount of variation or dispersion of a set of values. It is calculated by taking the square root of the variance. Variance is calculated by taking the average of the squared differences of each value from the mean. Here, we will use the formula of sample standard deviation.S = √[Σ(xi - x)² / (n - 1)]Where,S is the standard deviation.x is the mean hourly wage.n is the number of observations.Σ is the sum of.xi is the ith observation.Substituting the values in the above formula:S = √[(27 - 18)² + (25 - 18)² + (20 - 18)² + (10 - 18)² + (12 - 18)² + (14 - 18)² + (17 - 18)² + (19 - 18)² / 7]S = √[198 / 7]S = √28.29Therefore, the standard deviation is approximately $5.31.

25th percentile of hourly wages:The 25th percentile is the value below which 25% of the observations fall. Here, we will calculate the 25th percentile by arranging the hourly wages in ascending order and then finding the value that corresponds to the 25th percentile. Therefore, the values are:10, 12, 14, 17, 19, 20, 25, 27Total observations = 8As we need the value for the 25th percentile, we need to find out which observation is at that point.25% of 8 = 0.25 × 8 = 2As the value 2 is a whole number, we can say that the 25th percentile falls between the 2nd and 3rd observations.Therefore, the 25th percentile can be approximated as the average of the 2nd and 3rd observations.(12 + 14) / 2 = 13Therefore, the 25th percentile is $13.

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Assume that a consumer consumes two commodities X and Y and makes five combinations for the two commodities
Combinations. X. Y.
A. 25. 3
B. 20. 5
C. 16. 10
D. 13. 18
E. 11. 28
Calculate the Marginal Rate of substitution and explain your answer

Answers

MRS between A and B: -2.5, B and C: -0.8, C and D: -0.375, D and E: -0.2. Negative values indicate the diminishing marginal rate of substitution.

The Marginal Rate of Substitution (MRS) measures the rate at which a consumer is willing to trade one commodity for another while keeping the same level of satisfaction. To calculate the MRS between X and Y, we can use the formula: MRS = (Change in quantity of X) / (Change in quantity of Y).

Using the given combinations:

MRS between A and B: (25 - 20) / (3 - 5) = 5 / -2 = -2.5

MRS between B and C: (20 - 16) / (5 - 10) = 4 / -5 = -0.8

MRS between C and D: (16 - 13) / (10 - 18) = 3 / -8 = -0.375

MRS between D and E: (13 - 11) / (18 - 28) = 2 / -10 = -0.2

The negative values indicate that the consumer is willing to trade less of one commodity for more of the other. The magnitude of the MRS represents the rate of substitution, where larger absolute values indicate a higher rate of substitution.

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Approximate the following binomial probabilities by the use of normal approximation. 80% of customers of a bank keep a minimum balance of $500 in their checking accounts. What is the probability that in a random sample of 100 customers a. exactly 80 keep the minimum balance of $500? b. 75 or more keep the minimum balance of $500?

Answers

a. The probability of exactly 80 customers keeping the minimum balance of $500 can be approximated using the normal approximation to the binomial distribution.  b. The probability of 75 or more customers keeping the minimum balance of $500 can also be approximated using the normal approximation to the binomial distribution.

a. To approximate the probability of exactly 80 customers keeping the minimum balance of $500 in a random sample of 100 customers, we can use the normal approximation to the binomial distribution. The mean (μ) is equal to the product of the sample size (n) and the probability of success (p), which is 100 * 0.8 = 80. The standard deviation (σ) is the square root of n * p * (1 - p), which is sqrt(100 * 0.8 * 0.2) ≈ 4. In this case, we can use a continuity correction since we are approximating a discrete probability with a continuous distribution. Thus, we can calculate the probability using the normal distribution with a mean of 80 and a standard deviation of 4.

b. To approximate the probability of 75 or more customers keeping the minimum balance of $500, we need to calculate the cumulative probability of 75 or fewer customers not keeping the minimum balance. Using the same normal approximation, we can calculate the z-score for 75 customers and use the cumulative distribution function of the normal distribution to find the probability. The z-score is given by (75 - 80) / 4 ≈ -1.25. We can then use the normal distribution table or software to find the cumulative probability associated with the z-score of -1.25 and subtract it from 1 to obtain the probability of 75 or more customers keeping the minimum balance.

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A bacteria triples every hour. A population of 150 bacteria were placed in a jar [2 a) Create an equation for this situation. [2 b) How much bacteria will there be after 12 hours?

Answers

Answer:

5400

Step-by-step explanation:

To form an equation we need to replace the words by letters, let's just use x and y for this.

Let hour = y and bacteria = x

1 hour = 3 bacteria

So this can be written as:

(a) y = 3x

Now we're told that there are 150 bacteria.

Bacteria = 150 and, x will be as well.

(b) x = 150

y = 3x = 3(150) = 450

y = 3x = 3(150) = 450 12y = 450 × 12 = 5400

y = 3x = 3(150) = 450 12y = 450 × 12 = 540013 hours = 5400 bacteria

y=A + C/x is the general solution of the exact DEQ: y dx + x dy 40dx. Determine A.

Answers

The exact value of A in the general solution y = A + c/x is 40

How to determine the value of A in the general solution

From the question, we have the following parameters that can be used in our computation:

y = A + c/x

The differential equation is given as

y dx + x dy = 40dx.

Divide through by dx

So, we have

y + x dy/dx = 40

When y = A + c/x is differentiated, we have

dy/dx = -cx⁻²

So, we have

y - x cx⁻² = 40

This gives

y - c/x = 40

Recall that

y = A + c/x

So, we have

A + c/x - c/x = 40

Evaluate the like terms

A = 40

Hence, the value of A in the general solution is 40

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Evaluate the integral using correct limit notation limit e¹dx.

Answers

How to Evaluate Integral Using Limit Notation

We can recast the integral as a definite integral with appropriate limits of integration in order to evaluate the integral ex dx using the proper limit notation.

With respect to x, the indefinite integral of ex is equal to ex + C, where C is the integration constant.

We must establish the bounds of integration in order to find the definite integral. We can indicate the limitations of integration using a general notation because no precise constraints are given.

Let's evaluate the integral using limit notation:

∫[a to b] e^x dx

Here, [a to b] represents the limits of integration from a to b.

By subtracting the antiderivative of the function evaluated at the upper limit from the antiderivative of the function evaluated at the lower limit, we may calculate the definite integral using the calculus fundamental theorem:

∫[a to b] e^x dx = [e^x] from a to b = e^b - e^a

In this case, since the limits of integration are not specified, we cannot provide a numerical value for the integral.

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The following table gives the number of drinks and the resulting blood alcohol percent for a man of a certain weight legally considered driving under the influence (DUI) a. The average rate of change in blood alcohol percent with respect to the number of drinks is a constant. What is it? b. Write an equation of a linear model for this data, Number of Drinks 5 6 7 8 10 Blood Alcohol 0.19 0.22 0.25 0.28 0.31 0.34 9 Percent a. What is the rate of change in blood alcohol percent? 0.03% b. What is the equation that models blood alcohol percent as a function of x, where x is the number of drinks?

Answers

a) The rate of change in blood alcohol percent is: 0.03%

b) The equation that models blood alcohol percent as a function of x is:

y = 0.03x + 0.04

How to solve the Linear Model?

a) We are told that the average rate of change in blood alcohol percent with respect to the number of drinks is a constant.

The constant is also referred to as the slope and can be gotten from the formula:

Constant = (y₂ - y₁)/(x₂ - x₁)

Taking two coordinates as (5, 0.19) and (6, 0.22), we have:

Constant = (0.22 - 0.19)/(6 - 5)

Constant = 0.03

b) If we assume that x is number of drinks and y is blood alcohol percent, then we say that using the equation format y = kx + b, that:

k = 0.03

Using the first coordinate gives:

0.19 = 0.03(5) + b

b = 0.19 - 0.15

b = 0.04

Thus, the linear model is:

y = 0.03x + 0.04

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3. A research desires to know if the age of a child is related to the number of cavities he or she has. The data are shown. If there is a significant relationship,predict the number of cavities for an 11-year-old child.
Age of child No.of cavities
6 2
8 1
9 3
10 4
12 6
14 5

Answers

We can predict that an 11-year-old child will have approximately 4 cavities.

The method of correlational research is used to examine the relationship between variables. When two variables are compared to determine if they are related, correlational research is employed. One variable is plotted on the x-axis and the other is plotted on the y-axis. The scatter plot is utilized to see whether a relationship exists between the two variables.In this question, we will be using correlational research to determine whether there is a relationship between the age of a child and the number of cavities he or she has. The given data are:

| Age of child | No. of cavities |
| ------------ | --------------- |
| 6            | 2               |
| 8            | 1               |
| 9            | 3               |
| 10           | 4               |
| 12           | 6               |
| 14           | 5               |
We will begin by drawing a scatter plot of the data to see whether a relationship exists between the two variables. As seen in the scatter plot above, there appears to be a positive relationship between age and the number of cavities. This means that as age increases, the number of cavities appears to increase as well. The correlation coefficient between the two variables is r = 0.8426. A correlation of +1 indicates a perfect positive correlation, whereas a correlation coefficient of -1 indicates a perfect negative correlation. A correlation coefficient of 0 indicates that there is no correlation between the two variables. As a result, a correlation coefficient of 0.8426 indicates that there is a strong positive correlation between the two variables.Now that we have established that there is a relationship between age and the number of cavities, we can predict the number of cavities for an 11-year-old child. Using the line of best fit, we can determine the expected value of y for a given value of x.Using the equation for the line of best fit, y = 0.3902x - 0.2837, we can predict the number of cavities for an 11-year-old child.
y = 0.3902x - 0.2837
y = 0.3902(11) - 0.2837
y = 4.1115

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Determine the value in each of the cases Click the icon to view the table of areas under the distribution 28 (a) Find the value such that the area in the right that is 0.10 with 28 degrees of freedom Round to three decimal places as needed) (b) Find the value such that the area in the right tai is 0.05 with 27 degrees of freedom (Round to three decimal places as needed) (c) Find the t-value such that the area lot of the t-value is 0.15 with 7 degrees of freedom. (Hint: Use symmetry (Round to three decimal places as needed.) (d) Find the critical t-value that corresponds to 98% confidence. As idence. Assume 26 degrees of freedom.

Answers

a. The t-value such that the area in the right tail is 0.10 with 28 degrees of freedom is 1.701.

b. The t-value such that the area in the right tail is 0.05 with 27 degrees of freedom is 2.045.

c. The t-value such that the area to the left of it is 0.15 with 7 degrees of freedom is 1.963.

d. The critical t-value that corresponds to 98% confidence with 26 degrees of freedom is 2.457.

How to explain the values

(a) Since the area in the right tail is 0.10, the area in the left tail is 1 - 0.10 = 0.90.

Using the t-table, we find that the t-value with 28 degrees of freedom and an area of 0.90 in the left tail is 1.701.

(b) Since the area in the right tail is 0.05, the area in the left tail is 1 - 0.05 = 0.95.

Using the t-table, we find that the t-value with 27 degrees of freedom and an area of 0.95 in the left tail is 2.045.

(c) Since the area to the left of the t-value is 0.15, the area in the right tail is 1 - 0.15 = 0.85.

Using the t-table, we find that the t-value with 7 degrees of freedom and an area of 0.85 in the right tail is 1.963.

Therefore, the t-value such that the area to the left of it is 0.15 with 7 degrees of freedom is 1.963.

(d) Since the confidence level is 98%, the significance level is 1 - 0.98 = 0.02.

Using the t-table, we find that the t-value with 26 degrees of freedom and an area of 0.02 in the right tail is 2.457.

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Show that as x → 2, the function, f(x), x3 - 2x2 f(x) X-2 for x € R, has limit 4.

Answers

After considering the given data we conclude that as x reaches 2, the function [tex]f(x) = x^3 - 2x^2 + 4/(x-2)[/tex]has limit 4.

To express that as x → 2, the function [tex]f(x) = x^3 - 2x^2 + 4/(x-2)[/tex]has limit 4, we can factor the numerator as [tex](x-2)^2(x+2)[/tex] and apply simplification of the function as follows:
[tex]f(x) = [(x-2)^2(x+2)] / (x-2)[/tex]
[tex]f(x) = (x-2)(x-2)(x+2) / (x-2)[/tex]
[tex]f(x) = (x-2)(x+2)[/tex]
Since the denominator of the function is (x-2), which approaches 0 as x approaches 2, we cannot simply substitute x=2 into the simplified function.
Instead, we can apply the factored form of the function to cancel out the common factor of (x-2) and evaluate the limit as x approaches 2:
[tex]lim(x- > 2) f(x) = lim(x- > 2) (x-2)(x+2) / (x-2)[/tex]
[tex]lim(x- > 2) f(x) = lim(x- > 2) (x+2)[/tex]
[tex]lim(x- > 2) f(x) = 4[/tex]
Therefore, as x approaches 2, the function [tex]f(x) = x^3 - 2x^2 + 4/(x-2)[/tex]has limit 4.
This can be seen in the diagram given below
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Find the general solution to the equation:
x dy/dx = 3(y+x^2) = Sin x / x

Answers

the general solution to the differential equation [tex]x dy/dx = 3(y+x^2)[/tex] can be obtained  [tex]|y + x| = K .|x|^3[/tex], where K is a positive constant. typographical error is considered here since there are 2 equal signs.

The given differential equation is [tex]x(dy/dx) = 3(y + x^2) = sin(x)/x.[/tex]  Notice that the equation contains two equal signs, which seems to be a typographical error. Assuming it is intended to be a single equation, we will consider it as [tex]x(dy/dx) = 3(y + x^2)[/tex].

To solve this equation, we start by rearranging it:

[tex]x(dy/dx) - 3(y + x^2) = 0[/tex].

Next, we can further simplify by dividing through by x:

[tex](dy/dx) - 3(y/x + x) = 0.[/tex]

Now, we have a separable differential equation. We can rewrite it as:

(dy/(y + x)) - 3(dx/x) = 0.

Separating the variables, we get:

[tex]dy/(y + x) = 3dx/x.[/tex]

Integrating both sides with respect to their respective variables, we obtain:

[tex]\[ \int_{}^{} 1(/y+x) \,dy \] =[/tex][tex]\[ \int_{}^{} 3/x \,dx \][/tex]

The integral on the left side can be evaluated as [tex]ln|y + x|[/tex], while the integral on the right side is [tex]3ln|x| + C,[/tex] where C is the constant of integration.

Therefore, we have:

[tex]ln|y + x| = 3ln|x| + C[/tex].

To simplify further, we can use logarithmic properties to rewrite the equation as:

[tex]ln|y + x| = ln|x|^3 + C[/tex].

Taking the exponential of both sides, we get:

|[tex]y + x| = e^{(ln|x|^3 + C)[/tex].

Simplifying the expression, we have:

[tex]|y + x| = e^{(ln|x|^3)}.e^C[/tex].

Since e^C is a positive constant, we can rewrite it as K, where K > 0.

[tex]|y + x| = K . |x|^3[/tex],

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The Sandhill Boat Company's bank statement forth f November showed a balance per bank of $8.100. The company's Cash account in the general ledger had a bonne of $600 at November 30. Other information is as follows:
(1) Cash receipts for November 30 recorded on the company's books were $6.070 but this amount does not appear on the bank statement.

(2) The bank statement shows a debit memorandum for $50 for check printing charges

(3) Check No. 119 payable to Carla Vista Company was recorded in the cash payments journal and cleared the bank for $258. A review of the accounts payable subsidiary ledger show a $27tredit Balance in the account of Carla Vista Company and that the payment to them should have been for $285.

(4) The total amount of checks still outstanding at November 30 amounted to $6,020

(5) Check No 198 was correctly written and paid by the bank for $406. The cash payment journal reflects an entry for check no.138 as a debit to accounts payable and a credit to cash in bank for $460

(6) The bank returned an NSF check from a customer for $630.

(7) The bank included a credit memorandum for $2.680 which represents a collection of a customer's note by the bank for the company: the principal amount of the note was $2.546 and interest was $134. Interest has not been accrued

Answers

The adjusted bank balance is $9,989 after considering unrecorded cash receipts, check printing charges, reconciling discrepancies in payments, outstanding checks, corrected check entries, NSF checks, and the credit memorandum for the customer's note collection.

Step 1: Initial Balances

The bank statement shows a balance per bank of $8,100, while the company's Cash account in the general ledger has a balance of $600 at November 30.

Step 2: Unrecorded Cash Receipts

The company's books recorded cash receipts of $6,070 on November 30, but this amount does not appear on the bank statement. We need to add this amount to the bank balance.

Bank Balance: $8,100 + $6,070 = $14,170.

Step 3: Debit Memorandum for Check Printing Charges

The bank statement shows a debit memorandum of $50 for check printing charges. We need to deduct this amount from the bank balance.

Bank Balance: $14,170 - $50 = $14,120.

Step 4: Discrepancy in Check to Carla Vista Company

Check No. 119, payable to Carla Vista Company, was recorded in the cash payments journal and cleared the bank for $258. However, a review of the accounts payable subsidiary ledger shows a $27 credit balance in Carla Vista Company's account, and the payment should have been for $285. We need to adjust for this discrepancy.

Bank Balance: $14,120 + $285 - $258 = $14,147.

Step 5: Outstanding Checks

The total amount of checks still outstanding at November 30 is $6,020. We need to deduct this amount from the bank balance.

Bank Balance: $14,147 - $6,020 = $8,127.

Step 6: Corrected Check No. 198

Check No. 198 was correctly written and paid by the bank for $406. However, the cash payment journal reflects an entry for check No. 138 as a debit to accounts payable and a credit to cash in the bank for $460. This entry needs to be adjusted.

Bank Balance: $8,127 - ($460 - $406) = $8,073.

Step 7: NSF Check

The bank returned an NSF check from a customer for $630. We need to deduct this amount from the bank balance.

Bank Balance: $8,073 - $630 = $7,443.

Step 8: Credit Memorandum for Customer's Note Collection

The bank included a credit memorandum for $2,680, representing the collection of a customer's note by the bank for the company. The principal amount of the note was $2,546, and the interest was $134. Since interest has not been accrued, we need to add the principal amount to the bank balance.

Bank Balance: $7,443 + $2,546 = $9,989.

Therefore, the adjusted bank balance is $9,989.

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Define a sequence a,, so that ao = 2, a₁ = 3, and a₁ = 6an-1-8an-2. (a) Write a generating function for (a) in the form of a rational function. That is, find a rational function f such that f(x) = 0 anx".

Answers

The generating function for the sequence a is given by the rational function f(x) = (a₀ + (6a₀ - a₁)x) / (1 - 6x + 8x²), where f(x) = ∑anxⁿ.

The given sequence a is defined recursively as ao = 2, a₁ = 3, and an = 6an-1 - 8an-2. To find a generating function for the sequence, we can represent the sequence as a power series and express it in the form of a rational function.

To find a generating function for the sequence a, we can consider the terms of the sequence as coefficients of a power series. Let's define A(x) as the generating function for the sequence a, where A(x) = a₀ + a₁x + a₂x² + a₃x³ + ...

Using the given recursive relation an = 6an-1 - 8an-2, we can express it in terms of the generating function A(x). Multiplying the equation by xn and summing over n, we get:

A(x) - a₀ - a₁x = 6(xA(x) - a₀) - 8(x²A(x) - a₀)

Simplifying the equation, we have:

A(x) - a₀ - a₁x = 6xA(x) - 6a₀ - 8x²A(x) + 8a₀

Rearranging the terms, we get:

A(x) - 6xA(x) + 8x²A(x) = a₀ + (6a₀ - a₁)x

Factoring out A(x), we have:

A(x)(1 - 6x + 8x²) = a₀ + (6a₀ - a₁)x

Finally, dividing both sides by (1 - 6x + 8x²), we obtain:

A(x) = (a₀ + (6a₀ - a₁)x) / (1 - 6x + 8x²)

Therefore, the generating function for the sequence a is given by the rational function f(x) = (a₀ + (6a₀ - a₁)x) / (1 - 6x + 8x²), where f(x) = ∑anxⁿ.

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A 45g golf ball is hit off a tee with an initial speed of 65 m/s. The force applied can be modeled by the equation: F = C(t - 2) Where C is a constant, and t is the time after the hit in seconds. The duration the force is applied is 0.5 ms. Determine the value of the constant C in Si base units.

Answers

After considering all the given data we conclude that the value of the constant c is 5850 N.

To evaluate the value of the constant C in Si base units, we need to apply the equation [tex]F = C(t - 2)[/tex]and the given information that the duration the force is applied is 0.5 ms.
It is known to us that the force applied is what causes the golf ball to accelerate, so we can apply the equation for acceleration:
[tex]a = F/m[/tex]
Here,
m = mass of the golf ball.
We can restructure the equation
F = ma to find out C:
[tex]F = C(t - 2)[/tex]
[tex]ma = C(t - 2)[/tex]
[tex]C = ma/(t - 2)[/tex]
Staging the given values, we get:
[tex]C = (0.045 kg)(65 m/s)/(0.0005 s - 2 s)[/tex]
Applying simplification , we get:
C = 5850 N
Hence, the value of the constant C in Si base units is 5850 N.
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10. For each of the following pairs of integers a and d, find the quotient and remainder when a is divided by d. (a) a = 100, d=6 (b) a=-200, d= 7

Answers

(a) The quotient is 16 and remainder is 4. (b) The quotient is (-28) and remainder is (-4).

The quotient and remainder when a is divided by d of the following pairs of integers are:

(a) Quotient is the result of division between two integers. It is defined as the nearest integer less than or equal to the exact value of the fraction. We can find the quotient by dividing the dividend by the divisor.

So, the quotient for a = 100 and d = 6 is given as follows:quotient = a ÷ d  = 100 ÷ 6= 16Therefore, the quotient is 16.

Remainder is the leftover part of a division. It is the integer that remains after the division operation.

The remainder can be found by taking the dividend and subtracting it by the product of the quotient and divisor.

So, the remainder for a = 100 and d = 6 is given as follows:remainder = a - (quotient × d)remainder = 100 - (16 × 6)= 4.Therefore, the remainder is 4.

(b) The quotient and remainder for this pair of integers can be calculated by using the above method.

quotient = a ÷ d = -200 ÷ 7Quotient is -28. The nearest integer less than or equal to -28 is -28.

remainder = a - (quotient × d)remainder = -200 - (-28 × 7)= -200 + 196= -4Therefore, the remainder is -4.

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Assume that there are 18 board members: 11 females, and 7 males including Carl. There are 3 tasks to be assigned. Note that assigning the same people different tasks constitutes a different assignment

. (1) Find the probability that both males and females are given a task.

(2) Find the probability that Carl and at least one female are given tasks.

Answers

The probability that both males and females are given a task is (7 * 6 * 11) / (18 * 17 * 16). The probability that Carl and at least one female are given tasks is (3 * 11 * 10) / (18 * 17 * 16).

(1) To compute the probability that both males and females are given a task, we need to consider the total number of possible assignments.

Since there are 18 board members, there are 18 choices for the first task, 17 choices for the second task (since one person has already been assigned a task), and 16 choices for the third task.

The total number of possible assignments is 18 * 17 * 16.

Now, for both males and females to be given a task, we can consider the number of favorable outcomes. There are 7 males, so the first task can be assigned to any of them, giving 7 choices.

The second task can be assigned to any of the remaining 6 males, and the third task can be assigned to any of the 11 females. Therefore, the number of favorable outcomes is 7 * 6 * 11.

The probability is given by the number of favorable outcomes divided by the total number of possible outcomes:

Probability = (7 * 6 * 11) / (18 * 17 * 16).

(2) To compute the probability that Carl and at least one female are given tasks, we can consider the number of favorable outcomes. Since Carl must be assigned a task, there are 3 choices for the first task.

For the remaining two tasks, there are 17 choices for the second task and 16 choices for the third task. Among the remaining 17 board members, 11 are females, so there are 11 choices for the second task and 10 choices for the third task.

The number of favorable outcomes is 3 * 11 * 10.

The probability is given by the number of favorable outcomes divided by the total number of possible outcomes:

Probability = (3 * 11 * 10) / (18 * 17 * 16).

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(a) Find the derivative y'. given: (i) y= (x^2 + 1) arctan x - x; : - (ii) y = cosh (2x log x). (b) Using logarithmic differentiation, find yif y=x* 7* cosh3.r.

Answers

(a) i. The derivative of y = (x^2 + 1) arctan x - x is: y' = ((2x * arctan x) / (1 + x^2)) - 1.

To find the derivative of y = (x^2 + 1) arctan x - x, we will use the sum and product rules of differentiation.

First, let's find the derivative of (x^2 + 1) arctan x using the product rule:

u = (x^2 + 1) and v = arctan x

u' = 2x and v' = 1 / (1 + x^2)

Using the product rule formula (uv' + vu'), we get:

((x^2 + 1) * (1 / (1 + x^2))) + ((2x * arctan x))

(2x * arctan x) / (1 + x^2)

Next, let's find the derivative of -x using the power rule:

y' = ((2x * arctan x) / (1 + x^2)) - 1

ii. The derivative of y = cosh(2x log x) is: y' = 2x sinh(2 log x) + 2 sinh(2 log x).

By using the chain rule. Let's first rewrite cosh(2x log x) as cosh(u), where u = 2x log x.

The derivative of cosh(u) is sinh(u), and the derivative of u with respect to x is:

u' = 2(log(x)) + 2x(1/x)

= 2(log(x)) + 2

Using the chain rule formula (dy/dx = dy/du * du/dx), we can find the derivative of y with respect to x:

y' = sinh(2x log x) * (2(log(x)) + 2)

y' = 2x sinh(2 log x) + 2 sinh(2 log x)

(b) Using logarithmic differentiation, we have found that: y' = x * 7 * cosh^3(r) * ((1/x) + (tanh(r)) * (dr/dx)).

To find y if y = x * 7 * cosh^3(r), we will use logarithmic differentiation.

First, take the natural logarithm of both sides of the equation:

ln(y) = ln(x * 7 * cosh^3(r))

ln(y) = ln(x) + ln(7) + 3ln(cosh(r))

Next, we will differentiate both sides of the equation with respect to x using the chain rule:

d/dx(ln(y)) = d/dx(ln(x) + ln(7) + 3ln(cosh(r)))

On the left side of the equation, we can use the chain rule and the fact that dy/dx = y': d/dx(ln(y)) = (1/y) * y'

On the right side of the equation, we can use the sum and constant multiple rules of differentiation:

d/dx(ln(x)) = 1/x

d/dx(ln(7)) = 0

d/dx(ln(cosh(r))) = (tanh(r)) * (dr/dx)

(1/y) * y' = (1/x) + (tanh(r)) * (dr/dx)

y' = y * ((1/x) + (tanh(r)) * (dr/dx))

Substituting y = x * 7 * cosh^3(r), we get:

y' = x * 7 * cosh^3(r) * ((1/x) + (tanh(r)) * (dr/dx))

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1. Write each of the following as a sum or a difference of logarithms

a. log(19/20)

b. log9(3 x 8)

2. Each of the following has an error. Identify the error and explain why its wrong

a. log56 + log37 = log542

b. 3 log216 = log2163

= 43

= 64

3. Use the laws of logarithms to simplify the expression S = 10 logl1 - 10logI0

Answers

The  sum or a difference of logarithms are: a)= log-1  (b)  log₉11  2) a) log2072  (b)  log10077696  (3) s= 1

What is the sum and difference of logarithm?

The logarithm of a product is the sum of the logarithms of the factors being multiplied, while the logarithm of the ratio or quotient of two numbers is the difference of the logarithms.  To write the sum or difference of logarithms as a single logarithm, one can use the addition rule, the multiplication rule of logarithm, or the third rule of logarithms that deals with exponents.

the given logarithms are

a. log(19/20)

Applying the law of logarithm to get

log(19-20)

= log-1

b. log9(3 x 8)

log₉3 + log₉8

log ₉(3+8)

= log₉11

2 The logarithm that has error include

a. log56 + log37 = log542

The logarithm is wrong

Applying the law of multiplication we have

log(56*37)

= log2072

b. 3 log216 = log2163

This logarithm is wrong because applying the power law of logarithm

log216³ = log10077696

3) S = 10 logl1 - 10logI0

Using the low of logarithm we have

s= log11¹⁰/log10¹⁰

log(11/10)¹⁰⁺¹⁰

log(1.1)⁰

Any number raised to power zero is 1

therefore s= 1

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Which of the following microtubule behaviors is observed during anaphase?(+)-end polymerization(+)-end depolymerizationBoth (+)-end polymerization and depolymerizationNeither (+)-end polymerization nor depolymerization The Blinkelman Corporation has just announced that it plans to introduce a new solar panel that will greatly reduce the cost of solar energy. As a result, analysts now expect the companys earnings, currently (year 0) $1.00 per share to grow by 60 percent per year for the next three years, by 30 percent per year for the following 3 years, and by 7 percent per year thereafter. Blinkelman does not currently pay a dividend, but it expects to pay out 20 percent of its earnings beginning 2 years from now. The payout ratio is expected to become 45 percent in 5 years and to remain at that level. The companys marginal tax rate is 40 percent. If you require a 22 percent rate of return on a stock such as this, how much would you be willing to pay for it today? Use Table II to answer the question. Round your answer to the nearest cent. Jamal has a drawer containing 6 green socks, 18 purple socks, and 12 orange socks. After adding more purple socks, Jamal noticed that there is now a 60% chance that a sock randomly selected from the drawer is purple. How many purple socks did Jamal add?A 6B 9C 12D 18E 24 We collect the impact strength of five pieces of steel. Let "X" be their strengths in foot-pound/inch. Table 1: Impact Strength (ft-lb/in) 1 1 2 3 4 5 5 Point Values 55 56 55 50 46 O pt x-X 2.6 3.6 2.6 -2.4 -6.4 0.5 pt each 0.5 pt cach 6.76 12.96 6.76 5.76 40.96 Note: Carry at least 5 decimal precision for any intermediate calculations. Then, for all numeric entries, round your answer to 3 decimal precision - Leading Os don't count : 3 Part 1: (a) Fill in the missing table cells. (b) The Sum of Squares equals: 73.2 C) This variance equals: 18.3 D) The standard deviation equals: 4.278 E) The deviation for the first observations equals: 2.6 F) The Z-score for the fifth observation equals: -1.4961 Z- Part 2: We wish to convert from foot-pound/in to l/m, so let y be the strength in J/m. There is 1 ft-lb/in for every 53.35 J/m. Note that if Y = a*X+b, then y = a*x + b and sy = 32*sx G) - H) s2y = I) Sy = J) The Z-score for the fifth transformed observation is: Sheffield Corp. produces only one product. Monthly fixed expenses are $13000, monthly unit sales are 3000, and the unit contribution margin is $10. How much is monthly net income? O $30000 O $43000 O (q14) Ron is studying the income of people in a particular state. He finds out that the Lorenz curve for that state can be given as . Find the gini coefficient. Uning the Principle of Time Symmetry. what could you predict about the gravitational force you would experience if you traveled back in time to the age of the Dinosaurs? You would welche less than you do now You would always have the same weight as you do now You would wolph more than you do now Your weight could be calculated using Newton's Universal Law of Gravitation 0 You would love to ww to predict gravitational forces until you arrived on the planet he heat of vaporization of benzene is . calculate the change in entropy when of benzene boils at . be sure your answer contains a unit symbol. round your answer to significant digits. Sickle-cell anemia is a disease that occurs when a person is homozygous for a particular allele; $, and this condition is very often fatal. It might seem odd that there would be an allele that causes a fatal disease. You probably wonder why selection hasn 't gotten rid of this allele, and we're going to help you figure that out. Follow the steppingstones. A The Hardy-Weinberg Equilibrium is: 1 = (p? + 2pq + q). Please define each of the four terms in the equation (1,p' , 2pq, 4); what does each represent? p: the frequency of the m allele: q: the frequency of the e allele 1: the total possibility p2: the frequency of the homozygous dominant genotype Zpq: the frequency of the heterozygous genotype 92: the frequency of the recessive genotype B. Now let'$ dig into the sickle-cell problem. Let '$ assume that a small proportion of the homozygote SS individuals do survive and reproduce, but on average they 'produce only 10% aS many offspring as homozygote SS and heterozygote Ss individuals Clearly they are experiencing strong negative selection. Let'$ also assume that the SS and Ss types don't differ from each other in their reproductive success. Finally, let'$ specify that the starting frequencies of the S and $ alleles (p and 9) are 0.7 and 0.3,respectively: Given these values, please solve for p' and q' (the frequencies of S and $ gfter one generation of selection) " After one generation, has anything changed? Does that answer make sense? Please showour_workl p'= p2 + 0.5*(2pq) = 0.49 + 0.21 = 0.74 9'= 92 + 0.5*(2pq) = 0.09 + 0.21 = 0.3 (here jcnochanoe after one goneration C: If selection were t0 operate in this same way for many generations, what would be the eventual frequency of the (recessive) $ allele? The eventual frequency of the recessive allele will still be 0.3 base on the Hardy-Weinberg Equilibrium. D. Now let '$ add a key real-world observation: Heterozygote individuals (who have one copy of the $ allele) have some resistance to malaria, an insect-transmitted disease which can also be fatal. Let '$ Say that in a particular area where malaria is common, these heterozygotes (Ss) have the highest reproductive success; SS individuals still only do 10% aS well as the heterozygotes; but now SS homozygotes also suffer (from malaria) and do only 40% as well as the heterozygotes: In other words; selection is acting against both homozygotes, though not with equal: intensity: Start with the same initial frequencies of S and $ aS in question IB (0. and 0.3). In this case what will the frequencies of S and $ be after one generation of selection? Please showyour_workl 0.6(p?) 2pq + 0.9(q2)=0.6*0.49+0.21+0.9*0.09-0.585 E. Under this new selective regime (heterozygote superiority) would your answer to question IC change? How and why? Yes; the natural selection can affect the frequency of alleles F. Given that malaria is a tropical disease, transmitted by tropical mosquitoes, and comparing your answers to IC and IE, do you expect sickle-cell anemia to be more common in West Africa Or in Siberia? Why? two cars are traveling at the same speed and hit the brakes at the same time. one car has double the deceleration of the other. by what factor does the time required to stop that car compare with that for the other car? question 1 options: it takes half as long to stop. it takes twice as long to stop. they stop at the same time. none of the above. Identify each of the following as either sexism or androcentrism. oWomen do a disproportionate amount of housework and childcare. oWomen are paid less, on average, than men. oTeachers tend to identify boy students as smarter than girl students.oBoys who are interested in ballet tend to face teasing and other forms of regulation and punishment.oWomen who get ahead are perceived as more masculine.oMen are more constrained in their behavior because they avoid being perceived as feminine A running balance is the total in the account from last period.true or false consider the cell: ni(s) | ni2 (aq, ?m) || cu2 (aq, 0.136 m) | cu(s) ni2 (aq)/ni(s) e = -0.257 v cu2 (aq)/cu(s) e = 0.340 v the measured potential of the cell is 0.621 v. what is [ni2 ] at 25 c? from a consideration of the masses of water measured in part c, and given that the density of water is 1 glml, which is the most acurate method of volume measurement--cylinder, pipet, or buret Casinos attain a profit by collecting the bets/wagers placed by guests, but giving back on average a % of revenues as winnings for the customers and incurring costs of running the operations in a casino utilizing various resources. In a typical month, the casinos gambling area (excluding the food, beverages and lodging) had the following revenues and expenses: There were 500,000 guests. You can assume that all guests will wager the average amount always.Revenues (wagers by guests) $10,000,000Winnings given back to Guests $3,000,000 (as a % of revenues)Labor Costs (salaries) $1,000,000Commissions for employees $700,000 (as a % of revenues)Utilities (unrelated to the number of guests) $600,000Utilities (related to the number of guests) $300,000Depreciation on Casino buildings $2,000,000 and equipmentOther monthly admn. and facility costs $400,000The casino pays combined state and federal taxes equal to 25% of profit before taxes.1. What is the breakeven in dollars?2. How many Diamond Jubilee guests are needed or how much should be the total wagers by guests in a month for the casino to earn an after-tax income of $2,000,000?3. What is the operating leverage in a typical month? What will be the operating leverage if the number of guests were to drop by 50% because of an outbreak? Which of the following is the correct assumption under variable and absorption costing? O Variable manufacturing costs per unit remain constant, while fixed costs vary O Variable manufacturing costs per unit remain constant, and fixed manufacturing costs remain constant O Variable costs remain constant, while fixed costs are ignored O Variable costs are ignored while fixed costs remain constant help me please im struggiling with this A researcher found that conclusions regarding his research were incorrect because a Type 1 error had been made. His error represents a type of wyattsmith avatarwyattsmith25.02.2021HistoryPrimary SchoolansweredThe Indian Reorganization Act of 1934 led to all of the following reforms EXCEPT:A.established a system of credit for Native AmericansB.established Native Americans' right to form businessesC.gave Native Americans the right to intertribal marriageD.gave Native Americans training to enter the American workforce The attached image shows the two projects that Lawn & Order Property Maintenance Company is currently considering. Because of past financial difficulties, the company has a high cost of capital of 15%. Determine the highest cost of capital at which both projects would be acceptable. Projects Initial Investment Year Project-A $70,000 Cash Inflows $30,000 $30,000 $30,000 Project-B $90,000 Cash Inflows $40,000 $40,000 $45,000 1 2 3 Select one: O a. 18.00% O b. 13.70% OC. 15.00% O d. 15.89%