Solve the following equation. 6x−15=4x+55 6 x − 15 = 4 x + 55

Answers

Answer 1

Answer:

x = 35

Step-by-step explanation:

Solve for x:

6 x - 15 = 4 x + 55

Hint: | Move terms with x to the left hand side.

Subtract 4 x from both sides:

(6 x - 4 x) - 15 = (4 x - 4 x) + 55

Hint: | Combine like terms in 6 x - 4 x.

6 x - 4 x = 2 x:

2 x - 15 = (4 x - 4 x) + 55

Hint: | Look for the difference of two identical terms.

4 x - 4 x = 0:

2 x - 15 = 55

Hint: | Isolate terms with x to the left hand side.

Add 15 to both sides:

2 x + (15 - 15) = 15 + 55

Hint: | Look for the difference of two identical terms.

15 - 15 = 0:

2 x = 55 + 15

Hint: | Evaluate 55 + 15.

55 + 15 = 70:

2 x = 70

Hint: | Divide both sides by a constant to simplify the equation.

Divide both sides of 2 x = 70 by 2:

(2 x)/2 = 70/2

Hint: | Any nonzero number divided by itself is one.

2/2 = 1:

x = 70/2

Hint: | Reduce 70/2 to lowest terms. Start by finding the GCD of 70 and 2.

The gcd of 70 and 2 is 2, so 70/2 = (2×35)/(2×1) = 2/2×35 = 35:

Answer: x = 35


Related Questions

Solve for b: 15 - 2b = -9
pleasee help:(

Answers

Answer:

b = 12

Step-by-step explanation:

15 - 2b = -9

Minus 15 to both sides

-2b = -24

Divide both sides by -2

b = 12

A bakery wants to determine the best placement for day-old goods. What type of data collection source do you think the bakery should use? Choose the correct answer below. A. The bakery should conduct an experiment. B. The bakery should collect information from operational or transactional systems. C. The bakery should conduct an observational study. D. The bakery should obtain information that was distributed by an organization or individual. E. The bakery should conduct a survey

Answers

Answer: C. The bakery should conduct an observational study

Step-by-step explanation:

From the question, we are informed that a bakery wants to determine the best placement for day-old goods. The type of data collection source that the bakery should use is an observational study.

An observational study is a form of study whereby the individuals who are to be observed are being studied by the researcher and certain conclusions are derived about them. When the bakery conductd an observational study, the behavior of the customers regarding goods placement can be observed.

C is the midpoint of segment AB. Find the value of m+k.

A(-3,m)

B (4, -1)

C (k, 2)

Answers

Answer:

The value of m + k = [tex]5+\frac{1}{2}[/tex] = [tex]\frac{11}{2}[/tex].

Step-by-step explanation:

We are given that C is the midpoint of segment AB where A(-3,m) , B (4, -1) , and C (k, 2).

As we know that the mid-point formula states that;

Mid-point = [tex]\frac{a+b}{2}[/tex]

This means that;

Mid-point of AB = [tex]\frac{A+B}{2}[/tex]

C(k, 2) = [tex](\frac{-3+4}{2}, \frac{m+(-1)}{2} )[/tex]

C(k, 2) = [tex](\frac{1}{2}, \frac{m-1}{2} )[/tex]

This means that;

[tex]k = \frac{1}{2}[/tex]  and  [tex]2=\frac{m-1}{2}[/tex]

[tex]k = \frac{1}{2}[/tex]  and  [tex]m-1=4[/tex]

[tex]k = \frac{1}{2}[/tex]  and  [tex]m = 4+1 = 5[/tex]

So, the value of m + k = [tex]5+\frac{1}{2}[/tex] = [tex]\frac{11}{2}[/tex].

please help me out with this ​

Answers

Answer:

up is equal to 5/ 6

left side is equal to 3/4

Step-by-step explanation:

1/6 + 1/6+ 1/6+ 1/6+ 1/6= 5/6

1/4 + 1/4 + 1/4= 3/4

Israel started to solve a radical equation in this way:

square root of x plus 6 − 4 = x
square root of x plus 6 − 4 + 4 = x + 4
square root of x plus 6 = x + 4
(square root of x plus 6)2 = (x + 4)2
x + 6 = x2 + 8x + 16
x + 6 − 6 = x2 + 8x + 16 − 6
x = x2 + 8x + 10
x − x = x2 + 8x + 10 − x
0 = x2 + 7x + 10
0 = (x + 2)(x + 5)

x + 2 = 0 x + 5 = 0
x + 2 − 2 = 0 − 2 x + 5 − 5 = 0 − 5
x = −2 x = −5

Solutions = −2, −5

What error did Israel make?

He subtracted 6 before subtracting x.
He added 4 before squaring both sides.
He factored x2 + 7x + 10 incorrectly.
He did not check for extraneous solutions.

Answers

Answer:

He did not check for extraneous solutions.

Step-by-step explanation:

He solved the equation correctly and obtained solutions -2 and -5, but there is one final step he did not do.

Every time you square both sides of an equation to solve it, you must check for extraneous solutions. If he did, he would have eliminated x = -5.

Answer: He did not check for extraneous solutions.

please help me with this problem​

Answers

Answer:

A) sin 70 = x/10

Step-by-step explanation:

From the angle 70 degrees, 10 is the hypotenuse and x is the opposite and if we go by SOH-CAH-TOA I have an O and a H so its sin.

so we know it's sin so we need to figure out the equation. since we have a hypotenuse as a factor it is on top. and the other number is on the bottom.

so,

A) sin 70 = x/10

Please help 4+(-10)-(-9)

Answers

Answer:

-15

Step-by-step explanation:

-10+-9=-19+4=-15

The answer is 3 if you need me to tell you how (text back)

please help Spotting Axis Intercepts

Answers

Answer:

Coordinate A ins not intercepting any axis.

Step-by-step explanation:

For a coordinate to intercept an axis, it will be in the form [tex](a, b)\ such\ that:\ a=0, b \in \mathbb{R},\ or:a\in \mathbb{R}, b=0.[/tex]

Since in (3, 6), none of the components are 0, it is not intercepting any axes.

The product of -4 and d

Answers

Answer:

-4d

Step-by-step explanation:

The answer is -4d, hope this helped

ILL GIVE YOU BRAINLIST !!!

Evaluate the expression given the replacement values.

Answers

Answer:

24

Step-by-step explanation:

[tex]a^{2}[/tex]= 49 because any number squared is positive.

Since b=2,

2(-4)= -8.

Then this is 49-8-17, which equals 24.

Answer:

24

Step-by-step explanation:

Find an equation of the sphere with center (-3, 2 , 5) and radius 4. What is the intersection of this sphere with the yz-plane.

Answers

Answer:

The equation of the sphere with center (-3, 2 , 5) and radius 4 is [tex](x+3)^{2} +(y-2)^{2} + (z-5)^{2} = 16[/tex]

The intersection of the sphere with the yz- plane gave the equation [tex](y-2)^{2} + (z-5)^{2} = 7[/tex] which is a 2D- circle with center (0,2,5) and radius [tex]\sqrt{7}[/tex].

Step-by-step explanation:

The equation of a sphere of radius r, with center (a,b,c) is given by

[tex](x-a)^{2} +(y-b)^{2} + (z-c)^{2} = r^{2}[/tex]

where, [tex]x,[/tex] [tex]y,[/tex] and [tex]z[/tex] are the coordinates of the points on the surface of the sphere.

Hence, the equation of the sphere with center,  (-3, 2 , 5) and radius 4 becomes

[tex](x-a)^{2} +(y-b)^{2} + (z-c)^{2} = r^{2}[/tex]

[tex](x-(-3))^{2} +(y-(2))^{2} + (z-(5))^{2} = 4^{2}[/tex]

Then,

[tex](x+3)^{2} +(y-2)^{2} + (z-5)^{2} = 16[/tex]

This is the equation of the sphere with center (-3, 2 , 5) and radius 4,

Now, for the intersection of this sphere with the yz- plane,

The [tex]yz -[/tex]plane is where [tex]x = 0[/tex], then we set [tex]x = 0[/tex]

Them the equation [tex](x+3)^{2} +(y-2)^{2} + (z-5)^{2} = 16[/tex] becomes

[tex](0+3)^{2} +(y-2)^{2} + (z-5)^{2} = 16[/tex]

[tex](3)^{2} +(y-2)^{2} + (z-5)^{2} = 16\\9 +(y-2)^{2} + (z-5)^{2} = 16\\(y-2)^{2} + (z-5)^{2} = 16 - 9\\(y-2)^{2} + (z-5)^{2} = 7[/tex]

This equation is the equation of a 2D- circle with center (0,2,5) and radius [tex]\sqrt{7}[/tex]

This is the part of the sphere that intersects with the yz-plane.

Subtract. Fill in the missing numbers. 11-4=? 4=3+1 So, 11-4=

Answers

Answer:

7

Step-by-step explanation:

what is 12.3 -(-9.6) =12.3 + 9.6 simplified?

Answers

Answer:

Step-by-step explanation:

12.3 + 9.6 = 21.9

The expression 12.3 - (-9.6) is equivalent to 21.9.

Given is an expression 12.3 -(-9.6) = 12.3 + 9.6, we need to simplify it,

To simplify the expression 12.3 - (-9.6), we can rewrite it as 12.3 + 9.6.

When subtracting a negative number, it is equivalent to adding the positive value of that number.

So, -(-9.6) becomes +9.6.

Therefore, 12.3 - (-9.6) simplifies to 12.3 + 9.6.

Adding 12.3 and 9.6 gives us 21.9.

So, 12.3 - (-9.6) = 21.9.

Learn more about expression click;

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-4.5 x (-2)???????????????????????

Answers

Answer:

9

Step-by-step explanation:

-4.5 x (-2) is equal to 9

Match the vocabulary to the correct operation

Answers

Product=Multiplication
Sum= Addition
Difference=Subtraction
Quotient=Division
Quantity=Parenthesis

Answer:

Step-by-step explanation:

Product—Multiplication

Sum— Addition

Difference—Subtraction

Quotient—Division

Quantity— Parenthesis

Select the measurement scale in the right column that best matches the description in the left column. Note that each scale (nominal scale, ordinal scale, interval scale, and ratio scale) will be used exactly once. 1. Values measured on this scale can be compared such that you can say, for example, one value is twice as big as another value. 2. The values of data measured on this scale can be rank ordered and have meaningful differences between scale points.3. The values of data measured on this scale can be a number or a name, but they cannot be rank ordered. 4. The values of data measured on this scale can be rank ordered.

Answers

Answer:

1. RATIO SCALE

2. INTERVAL SCALE

3. NOMINAL SCALE

4. ORDINAL SCALE

Step-by-step explanation:

The scales are:

- Nominal Scale

- Ordinal Scale

- Interval Scale

- Ratio Scale

Rule: Each scale will be used exactly once.

For number 1, the description is that of a Ratio Scale because size comparisons can be made between values on the scale, such as the example given - that one value is twice as big as another value.

For number 2, the description is that of an Interval Scale because the values of data measured on the scale can be ranked e.g. Yes ranks as 1, No ranks as 2, Indifferent ranks as 3 and there is meaningful difference (not numerical difference) between scale points.

For number 3, the description is that of a Nominal Scale, because it says obviously that the values of data measured on this scale can be in form of names (watch out for keywords like this when reading through) and cannot be rank ordered! A good example is the following data set:

- Yellow, Brown, Purple, Cream, Fustian Pink

For number 4, the description is that of an Ordinal Scale. A keyword "rank" is to be given attention here, even as the statement is straightforward and gives just a simple information.

the question can been seen in the picture

Answers

Answer:

(2)

Step-by-step explanation:

When three professors are seated in a restaurant, the hostess asks them: "Does everyone want coffee?" The first professor says: "I do not know." The second professor then says: "I do not know." Finally, the third professor says: "No, not everyone wants coffee."
The hostess comes back and gives coffee to the professors who want it. How did she figure out who wanted coffee?

Answers

the first two professors did not know if everyone wanted coffee because the third professor had to choose yes or no if he wanted coffee. the first two professors were waiting for the third to say something, and when he said no, they knew he did not want coffee. if one of the first two professors said no, the answer would be no.

salesperson receives 16.7% commission. If her total sales for the month are $4900, what is her commission?

Answers

Answer:

$818,3

Step-by-step explanation:

16.7% in decimal is 0.167

= 0.167 x $4900

= $818,3

Algebra 1A, I need help

Answers

Answer:

for the first question at the top, x=10

Step-by-step explanation:

x+3+9x=8x+23

(subtract 8x from both sides)

x+3+x=23

(combine the x terms)

2x+3=23

(subtract 3 from both sides)

2x=20

(divide by 2 from each side)

x=10

Write an equation in slope-intercept form (y = mx + b).

Perpendicular to 7x - 2y = 16 passing through (-7, 5).

Answers

Answer:

y = 2/7x + 7

Step-by-step explanation:

We start off by putting the original equation into slope-intercept form. Subtract 7x from both sides, then divide both sides by -2. Your new equation should be y = -7/2x - 8. It's important to know that when two lines are perpendicular, their slopes (m) are opposite reciprocals of each other.  So -7/2 becomes 2/7. The first part of your final equation is y = 2/7x + b.

Next, we need to find the y intercept (b). You need to plug the x and y values from the given coordinate point (-7,5) into your final equation. You should end up with: 5 = 2/7(-7) + b. Then, solve for b.

5 = -14/7 + b

5 = -2 + b

7 = b

Finally, plug the b value into your final equation and you will have your answer.

Help please if u can

Answers

Answer:

Negative infinity

Step-by-step explanation:

The line points down infinitely in the graph.

Which answer describes the type of numbers that are dense? whole numbers and integers whole numbers but not integers rational numbers and irrational numbers rational numbers but not irrational numbers

Answers

Answer:

rational numbers and irrational numbers

Step-by-step explanation:

(-17) (0) what does this equal

Answers

Answer:

-17 × 0 = 0

every number multiplied by 0 is equal to 0

Match the expression on the left when it’s simplified form on the right answer options on the right may be used.more than once

Answers

9 =
• - (-9)
• |-9|
• |9|

-9 =
• - |9|
• - |-9|

i BELIEVE

Here are the expressions on the left matched with the simplifed form on the right:

-(-9) = 9|-9| = 9 -|9| = -9|9| = 9 -|-9| = -9

How can the expressions be simplied?

Here are some mathematical rules:

a negative sign multiplied by a negative sign is equal to a postive sign a postive sign multiplied by a negative sign is equal to a negative sign.a positive sign multiplied by a postive sign is equal to a postive sign.

Also, this sign | | indicates that the number is postive.

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Please hurry! Which expression is equivalent to 2 (5) Superscript 4? 2 times 5 times 4, 2 times 5 times 5 times 5 times 5, 2 times 4 times 4 times 4 times 4 times 4 ,10 times 10 times 10 times 10

Answers

Answer:

10 x 10 x 10 x 10.

Step-by-step explanation:

2(5)^4

10^4

Expanded form; 10*10*10*10.

Answer:

10 x 10 x 10 x 10

Step-by-step explanation:

Evaluate the integral by interpreting it in terms of areas. integral -3 to 0(1+(9-x^2)^1/2)dx

Answers

Answer:

[tex]\int\limits^0_{-3}(1+\sqrt{9-x^{2}})\, dx=3+\frac{9\pi}{4}=10.068[/tex]

Step-by-step explanation:

We need to evaluate the following integral by interpreting it in terms of areas :

[tex]\int\limits^0_{-3}(1+\sqrt{9-x^{2}})\, dx[/tex]

The first step is to separate the integral into two easier integrals

[tex]\int\limits^0_{-3}(1+\sqrt{9-x^{2}})\, dx=\int\limits^0_{-3} 1 \, dx+\int\limits^0_{-3}\sqrt{9-x^{2}}\, dx[/tex]    (Integral of the sum)

Now we can calculate each integral by studying the area below each function.

For the first integral the function is [tex]f(x)=1[/tex]

(I will attach a file with the functions)

The area below this function is the area of a rectangle with sides 1 and 3 ⇒

[tex]\int\limits^0_{-3}1 \, dx=3[/tex]

For the second integral the function is

[tex]f(x)=y=\sqrt{9-x^{2}}[/tex]

If we study this function :

[tex]y=\sqrt{9-x^{2}}[/tex]

[tex]y^{2}=9-x^{2}[/tex] (I)

[tex]x^{2}+y^{2}=9[/tex]

Which is the equation of a circle centered at (0,0) with radius equal to 3

From the equation (I)

[tex]y^{2}=9-x^{2}[/tex]

[tex]|y|=\sqrt{9-x^{2} }[/tex]

The two possible solutions are :

[tex]y=\sqrt{9-x^{2}}[/tex] (II) and [tex]y=-\sqrt{9-x^{2}}[/tex]

We will use (II) to solve the integral (which is the upper part of the circle)

The area of a circle with radius equal to 3 is

[tex]\pi.3^{2}[/tex]

In the integral we only need a quarter of circle ⇒ We divide the total area by 4 ⇒ [tex]\frac{\pi.3^{2}}{4}[/tex] ⇒ [tex]\frac{9\pi }{4}[/tex]

Finally the integral is equal to

[tex]\int\limits^0_{-3}(1+\sqrt{9-x^{2}})\, dx=3+\frac{9\pi}{4}=10.068[/tex]

Thrice the product of two and "Y".

Answers

Answer:

6Y

Step-by-step explanation:

We need to solve the statement ' Thrice the product of two and "Y" '.

Thrice means 3 times and product means multiply. It means we have to multiply 3,2 and Y.

Let the result is R. It can be calculated as follows :

[tex]R=3\times 2\times Y[/tex]

We know that, 3×2 = 6

So,

[tex]R=6Y[/tex]

Hence, Thrice the product of two and "Y" is 6Y.

For the points P1(-2,3,2) and P2(1,2,0) ​, find the direction of P1P2 and the midpoint of line segment P1P2.

Answers

Given :

Two points [tex]P_1(-2,3,2)\ and\ P_2(1,2,0)[/tex] .

To Find :

The direction of [tex]P_1P_2[/tex] and midpoint of line segment [tex]P_1P_2[/tex] .  

Solution :

Direction of [tex]P_1[/tex] and [tex]P_2[/tex] is given by :

[tex]\vec{D}=\dfrac{P_2-P_1}{|P_2-P_1|}\\\\\vec{D}=\dfrac{(-2i+3j+2k)-(i+2j+0)}{P_2-P_1}\\\\\vec{D}=\dfrac{-3i+j+2k}{\sqrt{3^2+1^2+2^2}}\\\\\vec{D}=\dfrac{-3i+j+2k}{\sqrt{14}}[/tex]

Now , mid point is given by :

[tex]M(\dfrac{-2+1}{2},\dfrac{3+2}{2},\dfrac{2+0}{2})\\\\M(\dfrac{-1}{2},\dfrac{5}{2},1)[/tex]

Hence , this is the required solution .

Express each vector as a product of its length and direction.
16–√i−16–√j−16–√k

Answers

Question:

Express each vector as a product of its length and direction.

[tex]\frac{1}{\sqrt{6}}i - \frac{1}{\sqrt{6}}j - \frac{1}{\sqrt{6}}k[/tex]

Answer:

[tex]\frac{1}{\sqrt{2}}[/tex] [tex](\frac{1}{\sqrt{3}}i - \frac{1}{\sqrt{3}}j - \frac{1}{\sqrt{3}}k)[/tex]

Step-by-step explanation:

A vector v can be expressed as a product of its length and direction as follows;

v = |v| u

Where;

|v| = length/magnitude of v

u = unit vector in the direction of v

---------------------------------------------------------------------------------------

Let the given vector be v, i.e

[tex]v = \frac{1}{\sqrt{6}}i - \frac{1}{\sqrt{6}}j - \frac{1}{\sqrt{6}}k[/tex]

(i) The length/magnitude |v| of vector v is therefore,

|v| = [tex]\sqrt{(\frac{1}{\sqrt{6}})^2 + (-\frac{1}{\sqrt{6}})^2 + (-\frac{1}{\sqrt{6}})^2[/tex]

|v| = [tex]\sqrt{(\frac{1}{6}) + (\frac{1}{6}) + (\frac{1}{6})[/tex]

|v| = [tex]\sqrt{(\frac{3}{6})[/tex]

|v| = [tex]\sqrt{(\frac{1}{2})[/tex]

|v| = [tex]\frac{1}{\sqrt{2}}[/tex]

(ii) The unit vector u in the direction of vector v, is therefore,

u = [tex]\frac{v}{|v|}[/tex]

[tex]u = \frac{\frac{1}{\sqrt{6}}i - \frac{1}{\sqrt{6}}j - \frac{1}{\sqrt{6}}k}{\frac{1}{\sqrt{2}}}[/tex]

[tex]u = \sqrt{2}(\frac{1}{\sqrt{6}}i - \frac{1}{\sqrt{6}}j - \frac{1}{\sqrt{6}}k)[/tex]

[tex]u = (\frac{\sqrt{2}}{\sqrt{6}}i - \frac{\sqrt{2}}{\sqrt{6}}j - \frac{\sqrt{2}}{\sqrt{6}}k)[/tex]

[tex]u = (\frac{1}{\sqrt{3}}i - \frac{1}{\sqrt{3}}j - \frac{1}{\sqrt{3}}k)[/tex]

Therefore, the vector can be expressed as a product of its length and direction as:

|v| u = [tex]\frac{1}{\sqrt{2}}[/tex] [tex](\frac{1}{\sqrt{3}}i - \frac{1}{\sqrt{3}}j - \frac{1}{\sqrt{3}}k)[/tex]

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