Suppose a change of coordinates T:R2→R2 from the uv-plane to the xy-plane is given by x=e−2ucos(5v), y=e−2usin(5v). Find the absolute value of the determinant of the Jacobian for this change of coordinates.

Answer:

To vote you need to be a US citizen and be at least 18 years old by election day

Answer:

18 years old to vote

Step-by-step explanation:

You must be 18 years old to vote and you have to be a citizen. Also to vote, you have to be a resident of Florida. So therefore, yes you have to be 18 years old to vote.

Hope this Helps!

Answer:

$38.64

Step-by-step explanation:

so the equation needed to solve is $56*0.25 and that number is 14. Since it is a coupon you subtract 14 from 56 and end up with 42. Now multiply 0.08*42 and you got your sales tax, $3.36. now subtract that from 42 and you have your answer

Answer:

He paid 50 dollars

Step-by-step explanation:

25% off = 75/100 x 56 = 42

42 + 8 = 50

if this question is about what percentage the tax is, then the answer would be 19.05%

x/100 x 42 = 50

42x/100 = 50

42x = 5000

x = 5000/42

x = 119.05

119.05 - 100 = 19.05%

Answer

about 15 min to 1 hour

Answer:

BC, BD, BQ, CB, CD, CQ, DB, DC, DQ, QB, QC, QD

Step-by-step explanation:

"BC, BD, BQ, CB, CD, CQ, DB, DC, DQ, QB, QC, QD" Are all the possible rays on line c.

Answer:

Calculated t=  0.011659

t ≥ t ( 0.025,11) = 2.201

So the null hypothesis is accepted.

Step-by-step explanation:

Student     Math      Writing            Difference                            d²

                                             math score − writing score

1                 540          474               66                                      4356

2                432         380                52                                      2704

3               528           463              65                                       4225

4               574             612             -38                                  1444

5               448            414              34                                    1156

6               502            526            -24                                   576

7               480            430              50                                 2500

8              499            453             46                                    2116

9              610             615             -5                                       25

10             572             541             31                                      961

11              390             335            55                                  3025

12             593             613          -20                                     400            

∑              6168          5856          312                                     23488                

1) We state our null and alternative hypothesis as

H0: ud= 0                   Ha: ud≠0

2) The significance level alpha is set at α= 0.05

3) The test statistic under H0 is

t= d`/ sd/√n

which has t distribution with n-1 degrees of freedom.

4) The critical region is t ≥ t ( 0.025,11) = 2.201

5) Computations

d`= ∑di/n= 312/12= 31.2

Variance = ∑(di- d`)²/n-1= 1/n-1 [ ∑di²-( ∑di)²/n]

= 1/11[ 23488- (312)²/12]

= 1/11[ 23488- 8112] = 1/11[15376]= 5976.7272

Standard Deviation= √ 5976.7272= 77.2510= 77.25

Now t= 3.12/77.25/√12= 0.011659

The calculated t value= 0.011659 falls in the acceptance region . So we accept our null hypothesis  and reject the alternative hypothesis.

Answer:

the EOQ cost function [tex]\mathbf{g(Q)= \dfrac{h}{2 \lambda Q}( Q- \sqrt{\dfrac{2 \lambda K }{2}})^2 + \sqrt{\dfrac{2 h K}{\lambda}}}[/tex]

Step-by-step explanation:

Given that:

[tex]g(Q) = \dfrac{h}{2 \lambda Q} \begin {pmatrix} Q- \sqrt{\dfrac{2 K \lambda}{h}} \end {pmatrix}^2 + \sqrt{\dfrac{2 Kh}{\lambda}}[/tex]

Total cost = Purchase Cost + Ordering Cost + Holding Cost

i.e

T = [tex]P \lambda + h \dfrac{Q}{2}+\dfrac{\lambda K}{Q}[/tex]

By differentiating with respect to Q and equating to zero, we have:

[tex]0 = 0 +\dfrac{h}{2}- \dfrac{\lambda K}{Q^2}[/tex]

[tex]Q* = \sqrt{\dfrac{2 k \lambda}{h}}[/tex]

Now;

[tex]T = P \lambda + \dfrac{h}{2Q}(Q-Q^*)^2 + hQ^*[/tex]

[tex]T = \dfrac{h}{2Q}(Q- \sqrt{\dfrac{2 \lambda K}{h}})^2 + \sqrt{2 hK \lambda } + P \lambda[/tex]

[tex](\dfrac{T - P \lambda}{\lambda }) = \dfrac{h}{2 \lambda Q}( Q- \sqrt{\dfrac{2 \lambda K }{2}})^2 + \sqrt{\dfrac{2 h K}{\lambda}}[/tex]

Therefore:

the EOQ cost function [tex]\mathbf{g(Q)= \dfrac{h}{2 \lambda Q}( Q- \sqrt{\dfrac{2 \lambda K }{2}})^2 + \sqrt{\dfrac{2 h K}{\lambda}}}[/tex]

Answer:

The system has NO solution

Answer C in your list

Step-by-step explanation:

Notice that the lines are parallel, they will not intercept, and therefore there is no answer to the system

Hey there! I think the answer is (-1,3)

Answer: The answer is D

Step-by-step explanation:

I divided 24 by 3 and it gave me 8 which is a whole number.

Answer:

Not always but sometimes

Step-by-step explanation:

The product of two irrational numbers is sometimes and not always an irrational number.

So, Let us take two Example:

Example # 1:

Let the two irrational numbers be [tex]\sf \sqrt{37} \ and \ \sqrt{2}[/tex]

So, Multiplying these will give us

=> [tex]\sf \sqrt{37} * \sqrt{2}[/tex]

=> [tex]\sf \sqrt{74}[/tex]

Which is an irrational number.

Example # 2:

Let the two irrational numbers be [tex]\sf \sqrt{2} \ and \ \sqrt{2}[/tex]

So, Multiplying them would give us:

=> [tex]\sf \sqrt{2} * \sqrt{2}[/tex]

=> [tex]\sf (\sqrt{2} )^2[/tex]

=> 2

Which is a rational number.

This means that the product of two irrational numbers is not always an irrational number but sometimes an irrational number.

Answer:

32x-5

Step-by-step explanation:

6x^2-4x-5

36x-4x-5

32x-5

Answer:

Variance = 0.1645

Standard deviation = 0.4056

Step-by-step explanation:

Kindly check attached picture for detailed explanation

Answer:

276,108 < x < 271,680

Step-by-step explanation:

*Hope this helped*

Step 1) Set up a proportion to find how much Peter spent

45 cards / x dollars = 3 cards / 2 dollars

Step 2) Cross-multiply to solve the proportion

3x = 90

x = $30

Step 3) Set up a proportion to find how much Peter made

45 cards / x dollars = 5 cards / 4 dollars

5x = 180

x = $36

Step 4) Subtract the amount Peter made by the amount he spent

36 - 30 = $6

Answer: Peter made $6

($2/3) * 45 = $30

($4/5) * 45 = $36

$36 - $30 = $6

Answer:

Thus, when both S-jams and C-tunes have 20 songs downloaded in a month  , the cost will be same.

an expression for the cost of S-Jams $0.99n + $16

Step-by-step explanation:

For

S-Jams

cost of 1 song = $1.29

let there be n songs downloaded in a month

then

cost of n songs = n*cost of 1 song  = $1.29n

monthly fee = $10

Total cost of S-Jams = $1.29n+$10

________________________________________

For

C-Tunes

cost of 1 song = $0.99

let there be n songs downloaded in a month

then

cost of n songs = n*cost of 1 song  = $0.99n

monthly fee = $16

Total cost for C-Tunes= $0.99n + $16

we have to find When will the company’s plans cost the same.

Total cost of S-Jams = Total cost of C- Tunes

1.29n+10 = 0.99n + 16

=> 1.29n - 0.99n = 16-10

=> 0.30n = 6

=> n = 6/0.3 = 20

Thus, when both S-jams and C-tunes have 20 songs downloaded in a month  , the cost will be same.

an expression for the cost of S-Jams $0.99n + $16

Answer:

Options A, C and D.

Step-by-step explanation:

It is given that, we need 1 tablespoon of butter for every 6 eggs to make a quiche.

Ratio that compares these two quantities [tex]=\dfrac{6\text{ eggs}}{1\text{ tablespoons} }[/tex]

We need to find the ratios which are equivalent to this ratio.

[tex]\dfrac{6\text{ eggs}}{1\text{ tablespoons} }\times \dfrac{2}{2}=\dfrac{12\text{ eggs}}{2\text{ tablespoons} }[/tex]

[tex]\dfrac{6\text{ eggs}}{1\text{ tablespoons} }\times \dfrac{3}{3}=\dfrac{18\text{ eggs}}{3\text{ tablespoons} }\neq \dfrac{15\text{ eggs}}{3\text{ tablespoons} }[/tex]

[tex]\dfrac{6\text{ eggs}}{1\text{ tablespoons} }\times \dfrac{4}{4}=\dfrac{24\text{ eggs}}{4\text{ tablespoons} }[/tex]

[tex]\dfrac{6\text{ eggs}}{1\text{ tablespoons} }\times \dfrac{1.5}{1.5}=\dfrac{9\text{ eggs}}{1.5\text{ tablespoons} }[/tex]

Therefore, the correct options are A, C and D.

Answer:

A,C,D

HOPE THIS HELPS!

Answer:

  22

Step-by-step explanation:

In order to get one of the answer choices, it appears we need to interpret your input as ...

  [tex](q^{16}q^{-5})^2 = (q^{16-5})^2=q^{11\cdot 2}=q^{22}[/tex]

The value of n is 22.

__

The applicable rules of exponents are ...

  (a^b)(a^c) = a^(b+c)

  (a^b)^c = a^(bc)

Answer:

6

Step-by-step explanation:

Answer:

The answer is 3

Step-by-step explanation:

Answer:

Total length of shoes in feet = 2 feet

Length of each shoe = 1 feet

Step-by-step explanation:

Given:

Length of each shoe = 12 inches

Find:

Total length of shoes in feet

Computation:

Total length of shoes = [12 + 12] inches

Total length of shoes = 24 inches

12 inches = 1 feet

Total length of shoes in feet = 24 / 12

Total length of shoes in feet = 2 feet

Length of each shoe = 1 feet

Answer:

Verbal expression x more than 7 can be represented ... If a team scores 27 points in a game, then 6T + p ... Algebraic expressions include variables, numbers, ... the sides of a cube all have the same length, V = x • x • x, or x ... Write a sentence describing what the length of ... REASONING Explain how to evaluate a[(b − c)

Step-by-step explanation:

Step-by-step explanation:

Mile Per Hour to Foot Per Second Conversion Table

Miles Per Hour Feet Per Second

16 mph 23.47 ft/s

17 mph 24.93 ft/s

18 mph 26.4 ft/s

19 mph 27.87 ft/s

Answer:

15.05

Step-by-step explanation:

8.6 is 100% of 8.6.

To increase it by 75%, you'll end up with 175% of 8.6

175% of 8.6 =

= 1.75 * 8.6

= 15.05

Answer:

1.5 MPH

Step-by-step explanation:

3/4 = 0.75

3/4 x 2 = 0.75 x 2 = 1.5

Answer:

The missing number is:

22

Step-by-step explanation:

There are 3 numbers and one more

4 numbers and your average is 17

then:

17*4 = 68

then:

11 + 17 + 18 + a = 68

46 + a = 68

a = 68 - 46

a = 22

Check:

(22 + 11 + 17 + 18)/4 = 17

68/4 = 17

Answer:

No, I do not agree with them. Both are wrong.

Step-by-step explanation:

For a shape or figure to be considered a scaled copy of another, the length of all the segments of scaled copy must be equal to the length of all corresponding segments of the original figure multiplied by the same scale factor.

By examining the scaled copies B, C, and D, we would conclude that only D can be referred to as a scaled copy of D, because all the segments are exactly twice the corresponding segments of A. C and B do not have all its segment scaled in the same proportion.

Therefore, we cannot agree with Priya, nor Tyler. They are both wrong.

Answer:

two raised to the power of -3

Two to the power of negative 3

Step-by-step explanation:

[tex]2^-^3 = \frac{1}{2^3}[/tex]

1 divided by 2 to the power of 3

Answer:

A) 0.2967

B) 0.0747

C) 0.2637

D)0.6933

Step-by-step explanation:

We are told the box contains four 40-watt light bulbs, five 60-watt bulbs, and six 75-watt bulbs.

Thus, total number of bulbs = 4 + 5 + 6 = 15 bulbs

This is a combination problem.

Thus;

A) probability that exactly one of the selected bulbs are rated 75-watt will be = ((6C2) × (9C1))/(15C3)

= (15 × 9)/455

= 0.2967

B) probability that all three of the elected bulbs have the same rating;

Number of ways to select three 40 watt bulbs out of the 4 in the box = 4C1 = 4!/(3! × 1!) = 4

Number of ways to select three 60 watt bulbs out of the 5 in the box = 5C1 =

5!/(3! × 2!) = 10

Number of ways to select 75 watt bulbs out of the 6 in the box = 6C1 = 6!/(3! × 3!) = 20

Total number of ways = 4 + 10 + 20 = 34.

Thus, probability that all three of the elected bulbs have the same rating = 34/15C3 = 34/455

= 0.0747

C) probability that one bulb of each type is selected =

[(4C1) × (5C1) × (6C1)]/(15C3)

= (4 × 5 × 6)/455

= 0.2637

D) probability that at least two of the selected bulbs are rated 75-watt =

[(4C1 × 5C1 × 6C2)/15C3] + 6C3/15C3

= (4 × 5 × 15/455) + 20/455

= 0.6493 + 0.044

= 0.6933

Answer:

– 2

Step-by-step explanation:

From the question given above, the following data were obtained:

P(x) = polynomial

P(–5) = – 2

P(5) = –1

Remainder when P(x) is divided by

(x + 5) =?

To obtain the remainder when P(x) is divided by (x + 5), we shall apply the reminder theorem as follow:

Let (x + 5) be equal to 0

(x + 5) = 0

x + 5 = 0

Subtract 5 from both side

x + 5 – 5 = 0 – 5

x = –5

Replace x in P(x) with –5 as shown below:

P(x) = polynomial

x = – 5

P(–5)

From the question given above,

P(–5) = – 2

Therefore, when P(x) is divided by

(x + 5), the remainder is – 2.

Answer:

Y=- 6

3(y-5)+2=5

multiply

3y-15+2=5

add

3y-13=5

add pos 13 to the neg 13 to

cancel it out and add +13 to 5

3y=18

divide -3 to pos 3 and 18 to cancel it out

y= -6