Answer:
gg
Step-by-step explanation:
gfg
Recall the auction models from the class. There is single object to be
sold to one of the n potential buyers. Each buyer i has a valuation of vi for
the object. Consider the auction rule where the winner is the highest bidder,
and pays the average of the second highest bid and the minimum
of all the bids, that is, the highest bidder pays b2+min{bi : i∈N}/
The auction rule you mentioned is known as the "Vickrey-Clarke-Groves" (VCG) auction. In the VCG auction, the highest bidder wins the object but pays the externality they impose on others.
The payment made by the highest bidder is equal to the difference between the social cost with them participating and the social cost without them participating.
In the case of a single object auction with n potential buyers, the VCG auction proceeds as follows:
Each buyer i submits their bid vi for the object.This payment rule ensures that the winner pays the externality they impose on others, which incentivizes truthful bidding. In other words, it encourages buyers to bid their true valuations because bidding higher or lower than their true valuation would not affect the outcome of the auction but could impact their payment.
The VCG auction is a theoretical construct and may not be practically implemented in all scenarios due to various complexities and practical considerations. However, it serves as a benchmark for understanding desirable properties of auction mechanisms, such as efficiency and truthfulness.
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is 0.2857 a rational number?Explain
Answer:
0.2857 is not a rational number.
Step-by-step explanation:
Because rational numbers have to be greater than 1. Decimals are not over 1 so it is not a rational number. Your welcome!
There are three candidates for student council secretary: Greg, Brittany, and Eliza. There are also three candidates for treasurer: Trey, Fabian, and Paulina. An experiment using two dice is conducted to simulate the probability of Greg or Fabian being elected. The first die represents the secretary election. The numbers 1 and 2 represent Greg winning, 3 and 4 represent Brittany winning, and 5 and 6 represent Eliza winning. The second die represents the treasurer election. The numbers 1 and 2 represent Trey winning, 3 and 4 represent Fabian winning, and 5 and 6 represent Paulina winning. The experiment was performed eight times, and the results are recorded in the following table.Based on the simulation, what is the probability that Greg or Fabian will win the election?
Answer:
5/8
Step-by-step explanation:
I have the same problem and this answer was correct.
The table shows the number of games a team won and lost last season with a ratio of win to loss as 3:2. Therefore the tool most appropriate for use is a 5-section spinner with congruent sections, 3 representing a win and 2 representing a loss.
What is ratio?Ratio, in math, is a term that is used to compare two or more numbers. It is used to indicate how big or small a quantity is when compared to another. In a ratio, two quantities are compared using division.
here, we have,
To calculate a win-to-loss ratio, divide the number of wins by the number of losses.
According to the given data:
Greg is creating a simulation, using previous year’s wins and losses, to foretell the team's conclusion.
Wins in the last season = 24
losses in the last season = 16
Ratio of wins and losses = 24:16 = 3:2
Chances of the team winning out of 5 matches is 3 and losing is 2.
The device which is most suitable for application in a simulation that implements the data is a 5-section spinner with congruent sections, 3 representing a win and 2 representing a loss.
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complete question:
the table shaws the number of games a team won and lost last season. Wins and losses last season number of games wins 24 losses 16 greg has tickets to six of the team’s games this season. He is designing a simulation, using last year’s wins and losses, to predict whether the team will win or lose each of the games he attends. Which tool is most appropriate for use in a simulation that fits the data?
1 a coin with one side representing a win and the other representing a loss
2 a 6-section spinner with congruent sections, 4 representing a win and 2 representing a loss
3 a 5-section spinner with congruent sections, 3 representing a win and 2 4representing a loss an 8-sided die with 5 sides representing a win and 3 sides representing a loss
Which of the following equations is represented by a line passing through (-9, 7) and (3, 3) in the
standard (x, y) coordinate plane?
Answer:
y = -1/3x + 4
Step-by-step explanation:
(-9, 7) and (3, 3)
Slope:
m=(y2-y1)/(x2-x1)
m=(3-7)/(3+9)
m=(-4)/12
m= -1/3
Slope-intercept:
y - y1 = m(x - x1)
y - 7 = -1/3(x + 9)
y - 7 = -1/3x - 3
y = -1/3x + 4
Step-by-step explanation:
[tex]soln \\ \frac{3 - 7 }{3 - - 9} \\ = \frac{ - 4}{ - 12} \\ = \frac{1}{3 } \\ \frac{y - 7}{x - 3} = \frac{1}{3} \\ then \: you \: cross \: multiplication. \\ 3(y - 7) = 1(x - 3) \\ 3y - 7 = x - 3 \\ 3y = x - 3 + 7 \\ 3y = x + 4 \\ \frac{3y}{3} = \frac{x}{3} + \frac{4}{3} \\ y = \frac{x}{3} + \frac{4}{3} [/tex]
OK IF YOU KNOW THE ANSWER PLEASE TYPE IN COMMENTS!
Timothy has 2 turtles named Buster and Bubbles. Buster is 75 millimeters long and Bubbles is 6 centimeters long. Buster is longer. Is this true or false?
Group of answer choices
1.True
1.False
Answer: True
Explanation:
1 centimeter = 10 millimeters
Buster = 75 millimeters long
Bubbles = 60 millimeters long
Rob bought a hat and 3 shirts for $35. Dan bought 2 hats and a shirt for $20.
Which system of equations can be used to find s , the cost of one shirt, and h , the cost of one hat?
Answer:
1 shirt costs $11.2 1 hat costs $10.
Step-by-step explanation:
35 divided by 3
20 divided by 2
A cylinder has a height of 14 centimeters and a radius of 11 centimeters. What is its
volume? Use 3.14 and round your answer to the nearest hundredth
what did Isabella do incorrectly
Answer:she added another 3000 to the answer
Step-by-step explanation:she was supposed to add the same amount as the first time so the amount should be $7591.92. hope this helps and I want brainliest.
Sao can text 1500 words per hour. He needs to text a message with 85 words. He only has 5 minutes between classes to complete the text. Can he do it in 5 minutes?
Assume that both populations are normally distributed (a) Test whether 4 Hy at the a= 0.05 level of significance for the given sample data (b) Construct a 96% confidence interval about 14 - 12. n Population 1 19 17 3.9 Population 2 19 13.8 4.6 X 10. Moth H12 Detemine the P-value for this hypothesis test. P=0.027 (Round to three decimal places as needed) Should the null hypothesis be rejected? G A Do not reject He, there is suffichent evidence to conclude that the two populations B. Reject M, there is sufficient evidence to conclude that the two populations have different means Oc Reject He, there is not sufficient evidence to conclude that the two populations have different means . Do not reject He, there is not sufficient evidence to conclude that the two populations have different means (b) Construct a 95% confidence interval about ve different means We are 95% confident that the mean difference is between 0.027 and 0.05 (Round to two decimal places as needed, Use ascending order.)
As per the given details, we are 95% confident that the mean difference between the two populations is between -8.86 and 9.86.
Testing whether the means of two populations are significantly different, we can perform a two-sample t-test.
Given that:
Sample data for Population 1: 19, 17, 3.9
Sample data for Population 2: 19, 13.8, 4.6
Using a significance level of α = 0.05, we can conduct the two-sample t-test.
Calculating the sample means:
X1 = (19 + 17 + 3.9) / 3 = 13.3
X2 = (19 + 13.8 + 4.6) / 3 = 12.8
Calculating standard deviations (s₁ and s₂):
s₁ = sqrt(((19 - 13.3)² + (17 - 13.3)² + (3.9 - 13.3)²) / 2) ≈ 8.16
s₂ = sqrt(((19 - 12.8)² + (13.8 - 12.8)² + (4.6 - 12.8)²) / 2) ≈ 5.44
Calculating the test statistic:
t = (X1 - X2) / sqrt((s₁² / n₁) + (s₂² / n₂))
= (13.3 - 12.8) / sqrt((8.16² / 3) + (5.44² / 3))
≈ 0.489
Degrees of freedom (df) = n₁ + n₂ - 2 = 3 + 3 - 2 = 4
Since |t| = 0.489 < 2.776, we fail to reject the null hypothesis.
Constructing a 95% confidence interval for the mean difference, we can use the formula:
Confidence Interval = (X1 - X2) ± t * sqrt((s₁² / n₁) + (s₂² / n₂))
Using the given values and a confidence level of 95%:
X1 - X2 = 13.3 - 12.8 = 0.5
t (with df = 4, α/2 = 0.025) ≈ 2.776
The standard error:
SE = sqrt((s₁² / n₁) + (s₂² / n₂)) = sqrt((8.16² / 3) + (5.44² / 3)) ≈ 3.37
Confidence Interval = 0.5 ± 2.776 * 3.37
= 0.5 ± 9.36
≈ (-8.86, 9.86)
Thus, we are 95% confident that the mean difference between the two populations is between -8.86 and 9.86.
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e) Discuss with illustrations the terms Deterministic, Stochastic and Least squares as used in regression analysis. [6]
Regression analysis is a statistical technique used to examine the relationship between a dependent variable (Y) and one or more independent variables (X). This analysis is used to establish whether the dependent variable is affected by changes in the independent variables.
When performing regression analysis, we use various terms such as deterministic, stochastic, and least squares. Let us examine these terms and their implications in regression analysis:
Deterministic regression
Deterministic regression is a type of regression that assumes a perfect relationship between the dependent and independent variables. This type of regression analysis assumes that the independent variables have a direct linear relationship with the dependent variable. The regression equation in deterministic regression is of the form: Y=a + bX. The term a is the Y-intercept of the regression line, while b represents the slope of the regression line. A change in the value of X by one unit will result in a change in Y by b units.
Stochastic regression
Stochastic regression is a type of regression that assumes a probabilistic relationship between the dependent and independent variables. In this type of regression, the independent variable is considered to be random. The relationship between the dependent and independent variables is not perfect, but it is characterized by some random error. The regression equation in stochastic regression is of the form: Y=a + bX + ε. The term ε represents the error term in the regression equation. The error term is a random variable that represents the difference between the predicted value and the actual value.
Least squares regression
Least squares regression is a statistical method that is used to estimate the parameters of a linear regression model. This method aims to find the line of best fit for the given data set. The line of best fit is the line that minimizes the sum of the squared residuals. The residuals are the differences between the observed values and the predicted values. The least squares regression method is used in both deterministic and stochastic regressions. This method ensures that the regression line passes as close as possible to all the data points. This method can be used to estimate the values of the parameters a and b in the regression equation Y=a + bX. In conclusion, the terms deterministic, stochastic, and least squares are used in regression analysis to explain the relationship between the dependent and independent variables. These terms are crucial in regression analysis because they help us to understand the nature of the relationship between the variables.
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Question 4 - (5+5=10 marks) [For probabilities keep 4 decimal places]
Fifty boxes labeled with numbers from 1 to 50 are laid on a table. In each box there is a blue ball and a red ball. Since a blue ball is bigger than a red ball, we should assume the chance of randomly drawing a blue ball from any box is twice that of a red ball. From each box that you randomly choose, you draw only one ball randomly, without looking into the box or at the drawn ball. Right after a ball is drawn, its corresponding box is moved away from the table to avoid choosing the same box again. You continue this process until 25 boxes are chosen.
a) What is the probability of drawing 17 red balls and 8 blue balls from boxes with even numbered labels? (5 marks)
b) If accidentally you see the fifth ball after being drawn is red, what would be the probability of drawing 17 red balls and 8 blue balls, everything else being the same as mentioned above in the statement of problem. (5 marks)
a) The probability of drawing 17 red balls and 8 blue balls from boxes with even-numbered labels is 0.0051.
b) The probability of drawing 17 red balls and 8 blue balls from boxes with even-numbered labels, given that the fifth ball drawn was red, is 0.1926.
a) The probability of drawing 17 red balls and 8 blue balls from boxes with even-numbered labels can be calculated as follows:
P(drawing 17 red balls and 8 blue balls from boxes with even-numbered labels) = (C(25, 17) × C(25, 8)) / C(50, 25)
= (12620256 / 2462624626080)
= 0.0051 (approx)
Therefore, the probability of drawing 17 red balls and 8 blue balls from boxes with even-numbered labels is 0.0051 (approx).
b) If accidentally, you see the fifth ball after being drawn is red, then the corresponding box will be removed, and there are now 49 boxes remaining on the table.
The number of even-numbered boxes among these 49 boxes is 24.
Therefore, the probability of drawing 17 red balls and 8 blue balls from boxes with even-numbered labels, given that the fifth ball drawn was red, can be calculated as follows:
P(drawing 17 red balls and 8 blue balls from boxes with even-numbered labels, given that the fifth ball drawn was red)
= (C(24, 16) × C(25, 7)) / C(49, 23)
= (8751600 / 45379690908)
= 0.1926 (approx)
Therefore, the probability of drawing 17 red balls and 8 blue balls from boxes with even-numbered labels, given that the fifth ball drawn was red, is 0.1926 (approx).
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US 90 According to the American Automobile Association (AAA), 9.35 of Americans plan to travel by car over the next holiday weekend and 88.6% plan to stay home. What is the probability that a randomly selected American plans to stay home or travel by car over the next holiday weekend? P travel by car or stay home) 0.0897 This probability does not equal 1 because some Americans traveled by other means
The probability that a randomly selected American plans to stay home or travel by car over the next holiday weekend given the information that 9.35% of Americans plan to travel by car and 88.6% plan to stay home. The probability of staying home or traveling by car over the next holiday weekend is given by the addition of probabilities of these events.
P(stay home or travel by car) = P(stay home) + P(travel by car)P(stay home or travel by car) = 0.886 + 0.0935P(stay home or travel by car) = 0.9795Therefore, the probability that a randomly selected American plans to stay home or travel by car over the next holiday weekend is 0.9795.
The value of probability does not equal 1 because some Americans traveled by other means.
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What is the measure of the other acute angle
Answer:
77 degrees
Step-by-step explanation:
All triangle add up to 180 degrees and right triangle all have one angle that is 90 degrees so 90 + 14 is 104 and 180 - 104 is 77.
Answer:
76 degrees
Step-by-step explanation:
What we know:
1. the triangle is a right triangle, meaning on angle has to be 90 degrees
2. One angle is 14 degrees
3. A triangle's angles add up to 180 degrees.
----------------------------------------------------------------------------------------------------
90+14+x=180
104+x=180
x=76
I need this answer I’ll give brainliest
sorry if it’s too blurry but i need help with this
Select the graph of the solution. Click until the correct graph appears. {x | x < 4} ∩ {x | x > -2}
Answer:
It converges
Step-by-step explanation:
dx/dy = x∧4 + 9x∧21
f(x) = ∫(x∧4 + 9x∧21)dy 0 > f(x) > ∞
= x∧5/5 + 9x∧22/22 + c
x = ∞ and x = 0
∴ c = 1 /5 + 9/22 = 27/22
Which of the following graphs best represents a function that has a minimum value and x-intercepts of 3 and -1?
Answer:
a
Step-by-step explanation:
In a large population of college-educated adults, the mean IQ is 112 with standard deviation 25. Suppose 30 adults from this population are randomly selected for a market research campaign. The probability that the sample mean IQ is greater than 115 is 0.019 b.0.256 c 0.461. d.0.328 QUESTION 15 In a large population of college-educated adults, the mean IQ is 112 with standard deviation 50.62. Suppose 30 adults from this population are randomly selected for a market research campaign. The distribution of the sample mean IQ is a approximately Normal, with mean 112 and standard deviation 1.44). bapproximately Normal, with mean 112 and standard deviation 4.564. c approximately Normal, with mean 112 and standard deviation 9.241. Cd approximately Normal, with mean equal to the observed value of the sample mean and standard deviation 25.
The correct answer is:
D. 0.981.
To calculate the probability that the sample mean IQ is greater than 115, we need to use the concept of sampling distribution and the central limit theorem.
Given:
Population mean (μ) = 112
Population standard deviation (σ) = 25
Sample size (n) = 300
The mean of the sampling distribution of the sample means (μx) will be the same as the population mean (μ) which is 112.
The standard deviation of the sampling distribution (σx) can be calculated using the formula:
σx = σ / √(n)
Plugging in the values:
σx = 25 / √(300)
≈ 1.443
Now, we can use the z-score formula to standardize the sample mean:
z = (x - μx) / σx
where x is the sample mean.
Plugging in the values:
z = (115 - 112) / 1.443
≈ 2.08
Next, we need to find the probability that the standardized sample mean (z) is greater than 2.08.
This can be done by looking up the z-score in the standard normal distribution table or by using a calculator or statistical software.
Using a standard normal distribution table or calculator, we find that the probability associated with a z-score of 2.08 is approximately 0.981.
Therefore, the correct answer is:
D. 0.981.
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Geographic information systems can assist the location decision by:
A updating transportation method solutions.
B. computerizing factor-rating analysis.
C. automating center-of-gravity problems
D. combining geography with demographic analysis.
E. providing good Internet placement for virtual storefronts.
GIS can assist in location decision-making by combining geography with demographic analysis, automating center-of-gravity problems, providing spatial data for transportation planning, enhancing factor-rating analysis with spatial considerations, and indirectly informing Internet placement for virtual storefronts.
Geographic Information Systems (GIS) can assist in location decision-making by combining geography with demographic analysis (D). GIS technology enables the integration and analysis of various spatial data, including demographic information such as population density, income levels, and consumer behavior.
By overlaying geographic data with demographic data, decision-makers can gain valuable insights into the characteristics and preferences of target markets, helping them identify suitable locations for their businesses.
GIS can automate center-of-gravity problems (C) by applying spatial analysis techniques to determine optimal locations based on factors such as customer demand, transportation networks, and supply chain considerations.
By utilizing GIS, businesses can identify central points or distribution hubs that minimize transportation costs and maximize accessibility to target markets.
While GIS doesn't directly update transportation method solutions (A), it can provide valuable spatial data and analysis that inform transportation planning. This includes mapping and visualizing existing transportation infrastructure, identifying traffic patterns, and optimizing routes for efficient logistics.
Although GIS doesn't computerize factor-rating analysis (B) per se, it can enhance this process by providing a spatial dimension. Factor-rating analysis involves evaluating potential locations based on multiple factors such as cost, labor availability, and market proximity. GIS can incorporate spatial data, such as the proximity of suppliers or competitors, into the factor-rating analysis, enabling more informed decision-making.
GIS may indirectly contribute to providing good Internet placement for virtual storefronts (E). By analyzing factors such as population density, internet infrastructure, and connectivity patterns, GIS can help businesses identify areas with a high potential for online customer engagement. However, the direct responsibility of Internet placement lies more within the realm of network infrastructure and internet service providers.
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The weight of one serving of trail mix is 2.5 ounces. How many servings are there in 22.5 ounces of trail mix?
9.0
25.0
11.5
56.25
Answer:
9 servings
There should be an answer to that. Answer: There are 9 servings. step- by- step Explanation: We would first divide 22.5/2.5. This will give us the amount of time 2.5 will go into 22.5, providing us with the amount of servings
Step-by-step explanation:
HELP IM GONNA GIVE YOU A BRAINLEST!!!
Without graphing, determine whether the function represents exponential
growth or exponential decay. Then find the y-intercept.
y=2/3 (1/2)^x
Answer:
y intercept is (0, 2/3)
Step-by-step explanation:
the y-inetercept is 0
i don’t know the exponential
growth or exponential decay but you can use math.way to help you answer the question
Help please please help help please help!!!
Answer:
standard
Step-by-step explanation:
Suppose a person is riding a plane 154ft above the ground and drops a box of supplies. The height of the box
is given by the formula:
h = -16+2 + 154
After how many seconds does the box hit the ground? (round to the nearest hundredth of a second)
Symbolization in predicate logic. Put the following statements into symbolic notation, using the given letters as predicates. Existential quantifier and logical symbols are here for you to copy and paste: ∃x, ,V, ~, ,
Px: x is a strictly physical thing
Cx: x has consciousness
Sx: x has subjectivity
Mx: x is a mind
1. Nothing strictly physical has consciousness.
2. Minds exist.
3. All minds have consciousness and subjectivity.
4. No minds are strictly physical things.
The statements with symbolic notation using the given predicates logic are:
1. Nothing strictly physical has consciousness. ∀x(Px → ¬Cx)
2. Minds exist. ∃x(Mx)
3. All minds have consciousness and subjectivity. ∀x(Mx → (Cx ∧ Sx))
4. No minds are strictly physical things. ∀x(Mx → ¬Px)
What is a predicate logic and it's symbols?Predicate logic is a formal system of symbolic logic that extends propositional logic by introducing variables, predicates, quantifiers, and quantified statements. It allows for the representation and manipulation of relationships between objects, properties, and relations.
In predicate logic, symbols are used to represent various components:
1. Variables: Variables are used to represent individual elements or objects in a domain of discourse. They are typically denoted by lowercase letters such as x, y, z, and so on.
2. Predicates: Predicates are used to express properties or relations between objects. They are represented by uppercase letters followed by parentheses, such as P(x), Q(x, y), R(x, y, z), where x, y, z are variables.
3. Quantifiers: Quantifiers are used to express the scope of variables in a logical statement. The two main quantifiers are:
- Universal quantifier (∀): It is used to express that a statement holds for all elements in the domain. For example, ∀x P(x) means "For all x, P(x)."
- Existential quantifier (∃): It is used to express that there exists at least one element in the domain for which a statement holds. For example, ∃x P(x) means "There exists an x such that P(x)."
4. Logical symbols: Predicate logic uses logical symbols to represent logical connectives, negation, implication, and equivalence. The main logical symbols are:
- Conjunction (∧): Represents logical "and."
- Disjunction (∨): Represents logical "or."
- Negation (¬): Represents logical "not."
- Implication (→): Represents logical "if-then."
- Equivalence (↔): Represents logical "if and only if."
These symbols are used to construct complex logical statements by combining predicates, variables, and quantifiers. The goal is to provide a precise and formal language for reasoning about relationships and properties within a domain of discourse.
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⚠️⚠️⚠️⚠️help⚠️⚠️⚠️⚠️
a steady wind blows a kite due west. the kite’s height above ground from horizontal position x − 0 to x − 80 ft is given by y − 150 2 1 sx 2 50d2. find the distance trav eled by the kite.
The equation y = 150 - 0.01x^2 represents the height of the kite above the ground as a function of its horizontal position x. The kite travels a distance of 80 ft.
The equation y = 150 - 0.01x^2 represents the height of the kite above the ground as a function of its horizontal position x. This is a downward-opening parabola, with the vertex at (0, 150) and the axis of symmetry along the y-axis.
To find the distance traveled by the kite, we need to determine the range of x over which the kite is flying. In this case, the range is from x = 0 to x = 80 ft.
The distance traveled by the kite is the difference between the initial and final positions of x. In this case, it is 80 - 0 = 80 ft.
Therefore, the kite travels a distance of 80 ft.
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A formula for converting degrees Celsius ( C ) (C) to degrees Fahrenheit ( F ) (F) is given by the formula F = 9 5 C + 32. F= 5 9 C+32. Solve the formula for C C in terms of F.
Answer:
C = (5F - 160)/9
Step-by-step explanation:
Given:
F = 9/5C + 32
Solve the formula for C in terms of F
F = 9/5C + 32
F - 32 = 9/5C
C = (F - 32) ÷ 9/5
C = (F - 32) × 5/9
= (5F - 160)/9
C = (5F - 160)/9
what's the answer to this?
Answer:
126 yds will be your answer.
Step-by-step explanation:
30+(24+24)+4+2+(3+3)+(4+30+2)=126
just add all of the sides up.
Chapter 07, Problem 075 (See Fluids in the News article titled Ice engineering.) A model study is to be developed to determine the force exerted on bridge piers due to floating chunks of ice in a river. The piers of interest have square cross sections. Assume that the force, R, is a function of the pier width, b, the depth of the ice, d, the velocity of the ice, V, the acceleration of gravity, g, the density of the ice, rho, and a measure of the strength of the ice, Ei, where Ei has the dimension FL-2. (a) Based on these variables determine a suitable set of dimensionless variables for this problem 2 d gd E,b, b, gb、 E, (b) The prototype conditions of interest include an ice thickness of 12 in. and an ice velocity of 11 ft/s. What model ice thickness and velocity would be required if the length scale is to be 1/21? in FRI (c) If the model and prototype ice have the same density can the model ice have the same strength properties as that of the prototype ice? nswer- the tolerance is +/-2% Answer * 2: the tolerance is +/-2%
(a) Using these variables, the dimensionless variables that can be used for this problem are as follows:2d/gdgb/EiE/b
(b) If the density is the same, the model ice can have the same strength properties as that of the prototype ice.
(a) The suitable set of dimensionless variables for this problem includes: g, the acceleration of gravityd, depth of the iceb, pier width Ei, the strength of the ice ρ, density of the ice
Using these variables, the dimensionless variables that can be used for this problem are as follows:2d/gdgb/EiE/b
(b) Given that the length scale is 1/21, and prototype ice thickness and velocity are 12 in. and 11 ft/s, respectively.
We can determine the model ice thickness and velocity using the length scale as follows:
For ice thickness, Model ice thickness = Prototype ice thickness × Length scale= 12 in. × (1/21)= 0.571 in.
For ice velocity, Model ice velocity = Prototype ice velocity × (Length scale)-0.5= 11 ft/s × (1/21)-0.5= 0.765 ft/s≈ 0.77 ft/s(c)
The model ice can have the same strength properties as the prototype ice if their strengths are identical, although the densities are the same.
Therefore, if the density is the same, the model ice can have the same strength properties as that of the prototype ice.
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