The joint PMF for X, Y is given by the following table:
x\y 5/128 9/128 1/64 5/32 9/32 1/16 15/128 27/128 3/64
The joint probability mass function (PMF) of two discrete random variables is a function that maps each pair of outcomes of the random variables to a probability. In particular, the joint PMF gives the probability that the random variables take a certain pair of values on each trial. Therefore, we have to find the probability that the random variables X and Y take each of the six possible values.
Therefore, the joint PMF for X, Y is given as follows:
For x = -1 and y = -1,P(X = -1, Y = -1)
= P(X = -1)P(Y = -1)
= (1/8)(5/16)
= 5/128
For x = -1 and y = 0,P(X = -1, Y = 0) = P(X = -1)P(Y = 0)
= (1/8)(9/16)
= 9/128
For x = -1 and y = 1,P(X = -1, Y = 1) = P(X = -1)P(Y = 1)
= (1/8)(1/8)
= 1/64
For x = 0 and y = -1,P(X = 0, Y = -1) = P(X = 0)P(Y = -1)
= (1/2)(5/16)
= 5/32
For x = 0 and y = 0,P(X = 0, Y = 0) = P(X = 0)P(Y = 0)
= (1/2)(9/16)
= 9/32
For x = 0 and y = 1,P(X = 0, Y = 1) = P(X = 0)P(Y = 1)
= (1/2)(1/8)
= 1/16
For x = 1 and y = -1,P(X = 1, Y = -1) = P(X = 1)P(Y = -1)
= (3/8)(5/16)
= 15/128
For x = 1 and y = 0, P(X = 1, Y = 0) = P(X = 1)P(Y = 0)= (3/8)(9/16)
= 27/128
For x = 1 and y = 1,P(X = 1, Y = 1) = P(X = 1)P(Y = 1)
= (3/8)(1/8)
= 3/64
Therefore, the joint PMF for X, Y is given by the following table:
x\y 5/128 9/128 1/64 5/32 9/32 1/16 15/128 27/128 3/64
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If you get this question right you’ll get points 100+356-123=?????
Answer:
333 :)
Step-by-step explanation:
The count of bacteria in a certain experiment was increasing at a rate of 2.5% per hour. if the experiment started with 1600. find the count of the bacteria at the end of 22 hours.
DONT ADD ANY LINK PLEASE I WILL REPORT AND PLEASE ANSWER CORRECTLY AND FAST I WILL MARK BRAINLIEST
What is the greatest common factor of the numbers
15,30 , and 75 ?
Answer:
15
Step-by-step explanation:
Prime Numbers Check
15: 5 * 3
30: 2 * 3 * 5
75: 3 * 5 * 5
Both 3 and 5 are prime numbers present in all 3 greater numbers, then you multiply them
3*5 = 15
GCF is 15
A rectangle has a perimeter of 150 cm. The length is 3 cm more than twice the width. Find the length and width of the rectangle.
Answer:
Length of rectangle = 51 cm
Width of rectangle = 24 cm
Step-by-step explanation:
Given:
Perimeter of rectangle = 150 cm
Find:
Length and width of the rectangle
Computation:
Assume;
Width of rectangle = a cm
Length of rectangle = 2a + 3 cm
Perimeter of rectangle = 2[l + b]
150 = 2[(2a + 3) + a]
2[3a + 3] = 150
6a + 6 = 150
6a = 144
a = 24
Width of rectangle = 24 cm
Length of rectangle = 2a + 3 cm
Length of rectangle = 2(24) + 3 cm
Length of rectangle = 51 cm
HELP MATH ASAP! I GIVE BRAINLIEST
An object completes one round of circle of radius 7m in 20 sec. find the distance travelled after 10sec.
Answer: 7pi
Step-by-step explanation: If it completes the circumference distance (14pi) of the circle in 20 seconds, in 10 seconds it will complete half of that. or 7pi. Hope this helped!
:.the distance travelled after 10sec. =7πm
Answer:
in 20 sec distance travelled =2πr=2π×7=14πm
in 10 sec distance travelled=14πm×10/20=7πm
Perform a hypothesis test for the following sample, the significance level alpha is 5%. Sample: 3.4,2.5,4.8, 2.9,3.6,2.8, 3.3, 5.5, 3.7, 2.8,4.4,4,5.2,3,4.8 Standard deviation is sd-1.05. Test if mean is greater than 3.16 Assume normality of the data. 1 Formulate the hypothesis by entering the corresponding signs
Based on the given sample, there is sufficient evidence to conclude that the mean is greater than 3.16 at a significance level of 5%.
To perform a hypothesis test, we need to state the null hypothesis and alternative hypothesis.
We want to test if the mean is greater than 3.16.
Null hypothesis (H0): μ ≤ 3.16 (Mean is less than or equal to 3.16)
Alternative hypothesis (Ha): μ > 3.16 (Mean is greater than 3.16)
Now, we can proceed with the hypothesis test.
We'll use a one-sample t-test since we don't know the population standard deviation and our sample size is relatively small.
The sample mean (X) and sample size (n) from the given data.
X= (3.4 + 2.5 + 4.8 + 2.9 + 3.6 + 2.8 + 3.3 + 5.5 + 3.7 + 2.8 + 4.4 + 4 + 5.2 + 3 + 4.8) / 15 = 3.66
n = 15
Now calculate the test statistic (t-value).
t = (X - μ) / (sd / √n)
= (3.66 - 3.16) / (1.05 / √15)
≈ 2.26
Since our alternative hypothesis is one-tailed (μ > 3.16), we need to find the critical value for a significance level of 5% in the right tail of the t-distribution.
Using a t-table, the critical value for a one-tailed test with α = 0.05 and degrees of freedom (df) = n - 1 = 15 - 1 = 14 is 1.761.
If the test statistic is greater than the critical value, we reject the null hypothesis.
t-value (2.26) > critical value (1.761)
Since the test statistic is greater than the critical value, we reject the null hypothesis.
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Which of the following sets of points would create a rectangle when connected?
A.
(1,2) , (2,3) , (3,5) , (5,1)
B.
(2,1) , (3,2) , (5,3) , (1,5)
C.
(1,2) , (3,1) , (3,2) , (1,5)
D.
(1,2) , (3,2) , (3,5) , (1,5)
at time t = 0 the capacitor in the circuit below is fully charged with qmax, and the current through the circuit is 0.
At time t = 0, the capacitor in the circuit is charged to its maximum charge, qmax, and the circuit has zero current.
At t = 0, the capacitor in the circuit is fully charged, which means it has accumulated its maximum charge, qmax. The capacitor acts as a temporary energy storage device in the circuit. When the capacitor is fully charged, it contains potential energy. The charge on the capacitor creates an electric field, which opposes the flow of current through the circuit.
Since the capacitor is fully charged at t = 0, it resists any change in the current. Therefore, the circuit has zero current flowing through it. As time progresses, the capacitor will start to discharge, releasing the stored energy and allowing the current to flow. The discharge process is governed by the relationship between the voltage across the capacitor, the capacitance of the capacitor, and the resistance in the circuit.
Finally, at t = 0, the capacitor in the circuit is charged to its maximum capacity, qmax, and the circuit has zero current flowing through it.
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HELP ME PLS
how do you graph a function??????
Answer:
It depends on the type of function, but essentially the process is the same
Step-by-step explanation:
You gather up all of the y values and x values and plot them onto a coordinate grid. If you are using a calculator, go to the "y=" button and input the function and then hit "graph"
Solve the inequality for d
df+9h>2
Answer:
d=2_f - 9h_f
Step-by-step explanation:
es la segunda opción
was 10 years and 6 months old when I moved to Mumbai. have been living in Mumbai for the past 13
years 11 months. What is my age now?
24 years and 5 months
add 13 years to ten get 23 add 6 to 11 to get 1 year and 5 months
23 plus 1 years and 5 months = 24 years an 5months
have a nice day please mark brainliest
a strain of peas has 3 green and one yellow for every four peas. if 12 peas are rendomly selected, what is the probability that exactly 8 peas are green? provide your answer to three decimal places
The probability of exactly 8 green peas is 0.475, rounded to three decimal places, i.e., 0.475.
We can use the binomial probability formula to solve this problem.
The formula is given as; $$P(X=k)={n\choose k}p^k(1-p)^{n-k}$$
Where;
n= sample size=12
k= number of green peas=8
p= probability of getting a green pea=3/4
q= probability of getting a yellow pea=1/4
Since we want the probability of exactly 8 green peas out of 12 peas,
we will plug in the values in the formula to get;
$$P(X=8)={12\choose 8}(\frac{3}{4})^8 (1-\frac{3}{4})^{12-8}$$$$
P(X=8)={12\choose 8}(\frac{3}{4})^8(\frac{1}{4})^{4}$$$$P(X=8)=495
(0.3164)(0.0039)$$$$P(X=8)=0.4749$$
Therefore, the probability of exactly 8 green peas is 0.475, rounded to three decimal places, i.e., 0.475.
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You measure 40 textbooks' weights, and find they have a mean weight of 42 ounces. Assume the population standard deviation is 3.8 ounces. Based on this, construct a 90% confidence interval for the true population mean textbook weight.
Give your answers as decimals, to two places
__________<μ<__________
The 90% confidence interval for the true population mean textbook weight, based on the given data, is approximately 41.44 ounces to 42.56 ounces.
To construct a confidence interval for the population mean textbook weight, we can use the formula:
Confidence Interval = sample mean ± (critical value * standard error)
Given that the sample mean is 42 ounces and the population standard deviation is 3.8 ounces, we need to determine the critical value and the standard error.
For a 90% confidence interval, the critical value corresponds to a two-tailed z-score of 1.645 (from the standard normal distribution).
The standard error can be calculated as the population standard deviation divided by the square root of the sample size. Since the sample size is not provided, we cannot calculate the exact standard error. However, if we assume a large sample size (usually considered to be greater than 30), we can use the formula for the standard error.
Assuming a large sample size, the standard error would be 3.8 ounces divided by the square root of the sample size.
Using the formula for the confidence interval, we can now calculate the range:
Confidence Interval = 42 ± (1.645 * standard error)
Substituting the values, we get:
Confidence Interval = 42 ± (1.645 * 3.8 / sqrt(sample size))
Since we do not know the sample size, we cannot calculate the exact confidence interval. However, based on the given data, we can conclude that the true population mean textbook weight falls between approximately 41.44 ounces and 42.56 ounces with 90% confidence.
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The hair color of the players on a tennis team would be considered: a. Ratio data b. Ordinal data c. Nominal data d. Interval data
The hair color of the players on a tennis team would be considered nominal data. Therefore, the most appropriate answer is option (c): Nominal data.
In data classification, there are four main levels of measurement: nominal, ordinal, interval, and ratio. Nominal data is the lowest level of measurement and represents categories or labels that cannot be ranked or ordered. Hair color falls into this category as it represents different categories or labels such as blonde, brunette, red, etc. Nominal data does not have any inherent numerical value or order.
On the other hand, ordinal data represents categories that can be ordered or ranked but do not have a consistent interval between them. Interval and ratio data involve numerical values with a consistent interval and a true zero point, with ratio data having a meaningful zero point.
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Evaluate the triple integral. 4xy dV, where E lies under the plane z = 1 + x + y and above the region in the xy-plane bounded by the curves y = , y = 0, and x = 1
The value of the triple integral ∭E 4xy dV is 2/5. The limits of integration for x are from 0 to 1, and for y, the limits are from 0 to 1 - x, as y is bounded by the line x + y = 1.
To evaluate the triple integral ∭E 4xy dV, where E lies under the plane z = 1 + x + y and above the region in the xy-plane bounded by the curves y = 0, y = 1, and x = 1, we need to set up the integral using appropriate limits of integration.
The region in the xy-plane is a triangle bounded by the lines y = 0, y = 1, and x = 1. Therefore, the limits of integration for x are from 0 to 1, and for y, the limits are from 0 to 1 - x, as y is bounded by the line x + y = 1.
Now, let's determine the limits for z. The plane z = 1 + x + y intersects the xy-plane at z = 1, and as we move up in the positive z-direction, the plane extends infinitely. Thus, the limits for z can be taken from 1 to infinity.
Now, we can set up the triple integral:
∭E 4xy dV = ∫[0 to 1] ∫[0 to 1-x] ∫[1 to ∞] 4xy dz dy dx
The innermost integral with respect to z evaluates to z times the integrand:
∭E 4xy dV = ∫[0 to 1] ∫[0 to 1-x] [4xy(1 + x + y)] evaluated from 1 to ∞ dy dx
Simplifying further:
∭E 4xy dV = ∫[0 to 1] ∫[0 to 1-x] (4xy(1 + x + y) - 4xy(1)) dy dx
∭E 4xy dV = ∫[0 to 1] ∫[0 to 1-x] 4xy(x + y) dy dx
Now, we can integrate with respect to y:
∭E 4xy dV = ∫[0 to 1] [2xy²(x + y)] evaluated from 0 to 1-x dx
Simplifying further:
∭E 4xy dV = ∫[0 to 1] 2x(1-x)²(x + (1-x)) dx
∭E 4xy dV = ∫[0 to 1] 2x(1-x)² dx
Evaluating the integral:
∭E 4xy dV = 2/5
Therefore, the value of the triple integral ∭E 4xy dV is 2/5.
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4) A spinner has 8 congruent sections as shown in the diagram. If the
spinner is spun twice, what is the probability that the first spin will land on
a whistle and the second spin will land on a yo-yo?"
a. 1/2
b. 1/8
c. 2/8
d. 1/32
Use the CVP Formulas to solve the following. JBL Speakers has annual fixed costs of $2,450,000, and variable costs of $25 per unit. The selling price per unit is $90. A) What annual revenue is required to break even? BER B) What annual unit sales are required to make a $1,000,000 profit?
Using the CVP Formulas to solve the following. JBL Speakers has annual fixed costs of $2,450,000, and variable costs of $25 per unit. The selling price per unit is $90.
A) 37,692 units
B) 53,077 units
A) To calculate the annual revenue required to break even, we need to find the point where total revenue equals total costs.
Total cost (TC) = Fixed costs (FC) + Variable costs per unit (VC) * Quantity (Q)
Total revenue (TR) = Selling price per unit (SP) * Quantity (Q)
At the break-even point, total revenue equals total cost:
TR = TC
SP * Q = FC + VC * Q
Substituting the given values:
$90 * Q = $2,450,000 + $25 * Q
$90Q - $25Q = $2,450,000
$65Q = $2,450,000
Q = $2,450,000 / $65
Q ≈ 37,692.31
Therefore, approximately 37,692 units need to be sold to break even.
B) To calculate the annual unit sales required to make a $1,000,000 profit, we can use the following formula:
Profit (P) = (SP * Q) - (FC + VC * Q)
Substituting the given values and the desired profit:
$1,000,000 = ($90 * Q) - ($2,450,000 + $25 * Q)
$90Q - $25Q = $1,000,000 + $2,450,000
$65Q = $3,450,000
Q = $3,450,000 / $65
Q ≈ 53,076.92
Therefore, approximately 53,077 units need to be sold to make a $1,000,000 profit.
In conclusion, to break even, JBL Speakers needs to generate an annual revenue of approximately $2,450,000, and to make a $1,000,000 profit, they need to sell approximately 53,077 units annually.
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139°
(17x + 3)
answer
Answer:
x= 8
Step-by-step explanation:
17x + 3 = 139
17x = 136
x = 8
Give an example to show that when two prime numbers are added, the result
may be an odd number.
Answer:
2+3=5
Step-by-step explanation:
prime numbers =2 and 3
sum =5 which is odd
Alex is a faster runner than Carlos. The chart below relates how many laps around the track each runs in the same amount of time.
Number of Laps Run
Alex Carlos
4 3
8 6
12 9
How many laps will Alex have run in the time it take Carlos to run 12 laps?
Answer:
16
Step-by-step explanation:
Alex will run 16 laps in the time it take for Carlos to run 12 laps.
What is Multiplication?Multiplication of two numbers is defined as the addition of one of the number repeatedly until the times of the other number.
a × b means that a is added to itself b times or b is added to itself a times.
Given are the values related to the number of laps run by Alex and Carlos.
The number of laps run by Alex is forming the multiples of 4 or 4x.
Number of laps run by Carlos is forming the multiples of 3 or 3x.
When x = 1,
Alex : 4 × 1 = 4
Carlos : 3 × 1 = 3
When x = 2,
Alex : 4 × 2 = 8
Carlos : 3 × 2 = 6
When x = 3,
Alex : 4 × 3 = 12
Carlos : 3 × 3 = 9
When x = 4,
Alex : 4 × 4 = 16
Carlos : 3 × 4 = 12
Hence Alex ran 16 laps in the same time for which Carlos ran 12 laps.
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Express the function G in the form f o g. (There is more than one correct answer. The function is of the form y = f(g(x)). Use non-identity functions for f(x) and g(x).)
G(x) = 1/x+8
(f(x), g(x) = ([_________])
To express the function [tex]\(G\)[/tex] in the form [tex]\(f \circ g\)[/tex] , where [tex]\(y = f(g(x))\)[/tex] , we need to find suitable non-identity functions [tex]\(f(x)\)[/tex] and [tex]\(g(x)\)[/tex] that can be composed to yield [tex]\(G(x)\)[/tex].
Let's choose [tex]\(g(x) = \frac{1}{x}\)[/tex] and [tex]\(f(x) = x + 8\)[/tex].
Now, we can express [tex]\(G\)[/tex] as [tex]\(G(x) = f(g(x))\)[/tex] , which becomes:
[tex]\[G(x) = f(g(x)) = f\left(\frac{1}{x}\right) = \frac{1}{x} + 8\][/tex]
Therefore, the functions [tex]\(f(x)\)[/tex] and [tex]\(g(x)\)[/tex] that can be composed to yield [tex]\(G(x) = \frac{1}{x} + 8\) are \(f(x) = x + 8\)[/tex] and [tex]\(g(x) = \frac{1}{x}\)[/tex].
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evaluating quadratic functions using equations evaluate the function g(x) = –2x2 3x – 5 for the input values –2, 0, and 3. g(–2) = –2(–2)2 3(–2) – 5 g(–2) = –2(4) – 6 – 5 g(–2) = g(0) = g(3) =
Evaluating the quadratic function we will get:
g(-2) = -3
g(0) = -5
g(3) = 31
How to evaluate the quadratic function?Here we need to evaluate the quadratic function:
g(x) = -2x² + 3x - 5
To do so, just replace the value of x by the correspondent number.
For example, if x = -2
g(-2) = 2*(-2)² + 3*(-2) - 5 = -3
if x = 0
g(0) = 2*(0)² + 3*(0) - 5 = -5
if x = 3
g(3) = 2*(3)² + 3*(3) - 5 = 31
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Factor this expression completely and then placed the factors in the proper location on the grid. Note: please factors alphabetically in the grid!
ab + 4 + a + 4b
PLEASE ANSWER, WILL MARK BRAINLYEST!
Answer:
(a + 4)(b + 1)
Step-by-step explanation:
ab + 4 + a + 4b
Rearrange the expression to find the GCF.
ab + a + 4b + 4
Now find the GCF.
a (b + 1) + 4 (b + 1)
Divide the whole thing by b+1
(a + 4)(b + 1)
WHAT WOULD THiS BE! ♀️
no scammers pleaseee!
Answer:
First find the unit rate for julie
3 hours/45 dollars
0.066 hours/1 dollar
Now based off table, find Jacksons
y = 25x
if x = 1, y would be 25
25 - .066 = 24.934 dollars
Step-by-step explanation:
Dean wants to buy a scooter. He has a coupon for 20% off his purchase, and has already saved $50. If the scooter is $79, how much more money does Dean need to be able to purchase it?
8. find h[n], the unit impulse response of the system described by the following equation y[ n+2] +2y[ n+1] + y[n] = 2x[n+ 2] − x[n+ 1]
The unit impulse response of the system described by the equation y[n+2] + 2y[n+1] + y[n] = 2x[n+2] − x[n+1] is h[n] = 2δ[n+2] − δ[n+1] + δ[n], where δ[n] represents the unit impulse function.
To find the unit impulse response, we need to determine the output of the system when an impulse is applied at the input, i.e., x[n] = δ[n].
Substituting x[n] = δ[n] into the given equation, we have:
y[n+2] + 2y[n+1] + y[n] = 2δ[n+2] − δ[n+1].
Since δ[n] = 0 for n ≠ 0 and δ[0] = 1, we can simplify the equation:
y[n+2] + 2y[n+1] + y[n] = 2δ[n+2] − δ[n+1] + δ[n] = 2δ[n+2] − δ[n+1] + δ[n]δ[n].
Now, comparing the equation with the standard form of the unit impulse response:
h[n] = 2δ[n+2] − δ[n+1] + δ[n],
we can conclude that h[n] is the unit impulse response of the given system.
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a spinner has three same-sized sectors numbered 1, 3, and 5. the spinner is spun once and a coin is tossed. h represents heads, and t represents tails. what is the sample space of outcomes?
A spinner has three same-sized sectors numbered 1, 3, and 5. The spinner is spun once and a coin is tossed. H represents heads, and T represents tails.
The sample space of outcomes is given below: Sample Space of Outcomes: {1H, 1T, 3H, 3T, 5H, 5T}Explanation: In this given problem, the spinner has three same-sized sectors numbered 1, 3, and 5. It indicates that the probability of each sector is equal. The spinner is spun once and a coin is tossed, where H represents heads, and T represents tails. It means that the spinner will land on one of three sectors, and the coin will land on either heads or tails.Therefore, the sample space of outcomes is {1H, 1T, 3H, 3T, 5H, 5T}.
To determine the sample space of outcomes for this situation, we need to consider the possible combinations of the spinner's numbers (1, 3, 5) and the outcomes of the coin toss (H for heads, T for tails).
The spinner has three sectors numbered 1, 3, and 5. Therefore, there are three possible outcomes for the spinner.
The coin toss can result in two outcomes: heads (H) or tails (T).
To find the sample space, we need to consider all possible combinations of the spinner outcomes and the coin toss outcomes.
The sample space of outcomes can be listed as follows:
{1H, 1T, 3H, 3T, 5H, 5T}
Therefore, the sample space of outcomes for this situation consists of the six possible combinations: 1H, 1T, 3H, 3T, 5H, and 5T.
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Given information is that, a spinner has three same-sized sectors numbered 1, 3, and 5. The spinner is spun once and a coin is tossed. h represents heads, and t represents tails. We need to find the sample space of outcomes.
The required sample space of outcomes is {1H, 1T, 3H, 3T, 5H, 5T}.
We can use the formula for the sample space,
Sample space = Set of all possible outcomes.
The possible outcomes of the spinner are 1, 3, and 5. The possible outcomes of the coin are H and T. Therefore,
Sample space of outcomes = {1H, 1T, 3H, 3T, 5H, 5T}.
Hence, the required sample space of outcomes is {1H, 1T, 3H, 3T, 5H, 5T}.
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I need help plzzz
-6p + 19 > 7
Answer:
p < 2
Step-by-step explanation:
hope this is right and have a good day
Find the volume of each figure. Round the answer
5 min
4 mm
18 nm
8 mm