Answer: 16° F
Step-by-step explanation:
30-15=16
44/15 converted into a mixed number (convert a fraction into a decimal before converting it into a mixed number)
Answer:
cgal to the store with me for the wounds on the number and the kids to today because I'm so 4
Guided Practice
Fill in the blank.
(z−4)(2z+1)=[tex]2z^{2}[/tex]− ___ z−4
A.
7z
B.
9
C.
7
Answer: Gradpoint answer
C.
7
Step-by-step explanation: Math.way answer
Move all terms to the left side and set equal to zero. Then set each factor equal to zero.
Exact Form:
z = 0 , 7/ 4
Decimal Form:
z = 0 , 1.75
Mixed Number Form:
z = 0 , 1 3/ 4
Answer:
7
Step-by-step explanation:
(z – 4)(2z + 1) = z(2z + 1) – 4(2z + 1) = 2z2 + z – 8z – 4 = 2z2 – 7z – 4
The second term is –7z, so 7 fills in the blank.
Given the arithmetic sequence of -21,-6,9,24,... , find an explicit rule for the nth term
Answer:
n = -21 + 15(n-1)
The scale on a drawing is 1 cm = 4.5 meters. If the length of the drawing is 6.2 cm, what is the actual length in meters?
Answer:
I think the awnser is 27.9
Step-by-step explanation:
4.5*6.2=27.9
Help me please! I will give 20 points and Brainliest!
The probability of having a pet is 40%, if you knew that anyone
who has a pet visits a vet (vet means animals' doctor)
with probability =90%. Then the probability of having a pet and
visiting a vet is
The probability of both having a pet and visiting a vet is 0.36 or 36%.
To find the probability of both having a pet and visiting a vet, we multiply the probability of having a pet by the probability of visiting a vet given that the person has a pet.
Let:
P(pet) = probability of having a pet = 40% = 0.40
P(vet | pet) = probability of visiting a vet given that the person has a pet = 90% = 0.90
The probability of having a pet and visiting a vet is given by:
P(pet and vet) = P(pet) * P(vet | pet)
P(pet and vet) = 0.40 * 0.90
P(pet and vet) = 0.36
Therefore, the probability of both having a pet and visiting a vet is 0.36 or 36%.
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A 13 meter ladder is leaning against a wall. It reaches 12 meters up the wall How far is the base of the ladder from the base of the wal
Answer:
5
Step-by-step explanation:
Pythagorean Theorem. The 13-meter ladder is leaning against a wall, so it's the hypotenuse.
It reaches 12 meters up, so 12 is one leg.
[tex]a^{2} +b^{2}=c^{2}[/tex]
[tex]a^{2}+12^{2}=13^{2}[/tex]
[tex]a^{2}+144=169[/tex]
[tex]a^{2}=25[/tex]
a = 5
Can someone pleaseeee help and if you’re correct i’ll give brainliest
Answer C
Step-by-step explanation:
(1 point) how many different ways can a race with 8 runners be completed? (assume there is no tie.)
There are 40,320 different ways the race with 8 runners can be completed.
To determine the number of different ways a race with 8 runners can be completed, we can use the concept of permutations.
In a race with no tie, the order in which the runners finish matters. We want to find the number of permutations of 8 runners.
The formula to calculate permutations is given by n!, where n represents the number of items being permuted.
In this case, there are 8 runners, so the number of different ways the race can be completed is:
8! = 8 x 7 x 6 x 5 x 4 x 3 x 2 x 1 = 40,320.
Each permutation represents a unique arrangement of the runners crossing the finish line. By considering the order of finish for each runner, we account for all possible outcomes in the race.
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" Let set A be the set of all real numbers. For all x and y in A, xRy | xl sy. Determine if the relation is each of these and explain why or why not. (a) Reflexive YES NO (b) Symmetric YES NO
"
Relation of each of these are:
(a) Reflexive: NO
(b) Symmetric: YES
(a) Reflexive: No.
The relation R is not reflexive because there exist elements x in set A for which x is not related to itself. For example, if we take x = 0, then 0 is not less than or equal to 0, so xRx does not hold.
(b) Symmetric: Yes.
The relation R is symmetric because for any x and y in set A, if xRy holds, then yRx also holds. This is because if x is less than or equal to y, then y is greater than or equal to x, satisfying the symmetry property of the relation.
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Provide an appropriate response, Compute the standardized test statistic x 2 to test the claim o 2.38.7 it n - 12. 52-32.4, and a -0.05. O 0.492 12.961 18.490 9.209
The standardized test statistic is 12.961
To test the claim that σ = 2.38.7 with n - 12, a = -0.05 and 52-32.4,
we need to calculate the standardized test statistic.
The appropriate response is 12.961.
So, the standardized test statistic is calculated as follows:
`x = (n - 1)s² / σ²`
Where `n` is the sample size, `s` is the sample standard deviation, and `σ` is the population standard deviation.
`n = 12, s = 52 - 32.4 = 19.6, and σ = 2.38.7`
Then, `x² = (12 - 1)(19.6)² / (2.38.7)² = 12.961`
Therefore, the appropriate response is 12.961`.
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If $120.99 is charged for 654 units of electricity used,find the cost of one unit of electricity
Answer: 0.185
Step-by-step explanation:
Divide 120.99 and 654:
120.99÷654=0.185
So the final answer is 0.185 units.
Hi, can someone please help, and possibly explain the answer please.
Answer:
[tex]x=\frac{-(-2)\±\sqrt{(-2)^2-4(3)(0)} }{2(3)}[/tex]
Step-by-step explanation:
Quadratic formula: [tex]x=\frac{-b\±\sqrt{b^2-4ac} }{2a}[/tex] when the equation is [tex]0=ax^2+bx+c[/tex]
The given equation is [tex]1=-2x+3x^2+1[/tex]. Let's first arrange this so its format looks like [tex]y=ax^2+bx+c[/tex]:
[tex]1=-2x+3x^2+1[/tex]
[tex]1=3x^2-2x+1[/tex]
Subtract 1 from both sides of the equation
[tex]1-1=3x^2-2x+1-1\\0=3x^2-2x+0[/tex]
Now, we can easily identify 3 as a, -2 as b and 0 as c. Plug these into the quadratic formula:
[tex]x=\frac{-b\±\sqrt{b^2-4ac} }{2a}\\x=\frac{-(-2)\±\sqrt{(-2)^2-4(3)(0)} }{2(3)}[/tex]
I hope this helps!
- Andrew plays on a basketball team. In his final game, he scored of
2/5
the total number of points his team scored. If his team scored a total
of 35 total points, how many points did Andrew score?
h
A:35
B:14
C:21
D:25
Answer: 14
Step-by-step explanation:
to find the answer we must figure out what half of 35 points is because Andrew scored 2/5 of 35.
we can write the equation like this:
2/5 of 35 = Andrew's points
2/5 of 35 = 14
therefore 2/5 of 35 is 14
therefore Andrew scored 14 points.
Can you construct a triangle that has side lengths 4 m, 5 m, and 9 m? yes no
Answer:
Yes
Step-by-step explanation:
A triangle can have any side lengths as long as they all touch to make a triangle
Answer:
yes
Step-by-step explanation:
you just had to divide then subtract
A formula of order for approximating the first derivative of a function f gives FO) - 4.50557 for h=1 f(0) - 2.09702 for h=0.5 By using Richardson's extrapolation on the above values, a better approximation of '(0) is: 0.97318 1.00177
A better approximation of f'(0) using Richardson's extrapolation is -6.91412.
To find a better approximation of f'(0) using Richardson's extrapolation, we can apply the formula:
[tex]R(1,1) = f'(h) + (f'(h) - f'(2h))/((1/2)^1 - 1)[/tex], where h is the step size.
Given the values:
f'(1) = -4.50557 (for h = 1)
f'(0.5) = -2.09702 (for h = 0.5)
Let's calculate R(1,1):
[tex]R(1,1) = f'(1) + (f'(1) - f'(0.5))/((1/2)^1 - 1)\\ = -4.50557 + (-4.50557 - (-2.09702))/(2 - 1)\\ = -4.50557 + (-2.40855)/1\\ = -4.50557 - 2.40855\\ = -6.91412.[/tex]
Therefore, a better approximation of f'(0) using Richardson's extrapolation is -6.91412.
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Someone plz help me giving brainliest
Answer
Use the fact that 45 times 1/9 = 5. Them multiply by 8 to get the answer, 40.
Step-by-step explanation:
5⁄8 ÷ 3⁄8 =________ pls help me
Answer:
1 [tex]\frac{2}{3}[/tex]
Step-by-step explanation:
Answer:
1 2/3
Step-by-step explanation:
First, you rewrite 5/8÷3/8 as a multiplication problem: 5/8*8/3. Now you simply multiply both numerators and denominators: 5x8/8x3 which equals 40/24. So your final answer will be 40/24 or 1 16/24 which equals 1 2/3.
Using the Bisection Method on the interval [-1, 7], how many iterations are required to guarantee a maximum error, e = 0.01?
To guarantee a maximum error of e = 0.01 using the Bisection Method on the interval [-1, 7], approximately 8 iterations are required.
The Bisection Method is an iterative numerical method used to find the root of a continuous function within a given interval. It repeatedly bisects the interval and determines in which subinterval the root lies, based on the sign change of the function. The process continues until the desired accuracy is achieved.
In this case, the interval is [-1, 7] and the maximum error allowed is e = 0.01. The number of iterations required can be determined by finding the number of times the interval can be halved until its length becomes less than or equal to the maximum error.
Initially, the length of the interval is 7 - (-1) = 8. To achieve an error of 0.01, the interval needs to be halved 3 times. After each halving, the length of the interval is reduced by a factor of 1/2. Thus, after 3 iterations, the length becomes 8 * (1/2)^3 = 1.
Since the length of the interval is now less than the maximum error, we can conclude that approximately 8 iterations are required to guarantee a maximum error of 0.01 using the Bisection Method on the interval [-1, 7].
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Let T be a linear transformation given by (v) = Av . A = [2 1 3, 1 1 0,0 1 -3] a) Basis for the kernel of T b) Basis for the range of T. c) The rank of T. d) The nullity of T.
(a) The basis for the kernel of T is {(-1, 1, 1)}. (b) The basis for the range of T is {(2, 1, 0), (1, 1, 1)}. (c) The rank of T is 2. (d) The nullity of T is 1.
(a) To find the basis for the kernel of T, we need to solve the equation T(v) = 0. This is equivalent to finding the null space of the matrix A. By performing row reduction on A, we find that the basis for the kernel is {(-1, 1, 1)}.
(b) The range of T is the set of all possible outputs of T. To find the basis for the range, we can consider the columns of A that correspond to the pivot positions after row reduction. In this case, the columns {2, 1} and {1, 1} correspond to the pivot positions, so the basis for the range is {(2, 1, 0), (1, 1, 1)}.
(c) The rank of T is the dimension of the range, which is the number of linearly independent vectors in the basis for the range. In this case, the rank of T is 2.
(d) The nullity of T is the dimension of the kernel, which is the number of linearly independent vectors in the basis for the kernel. In this case, the nullity of T is 1.
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PLS HELP! I'M SO STUCK!!
Answer:
E
Step-by-step explanation:
i just kinda figured it out
В обращении находится 250 карандашей по 8 д. ед. за единицу, 500 ручек по 12 д. ед. за единицу, 2000 тетрадей по 10 д. ед. за единицу и 412 дневников по 14 д. ед. за единицу. Найти количество денег необходимых для обращения.
Answer:
Ты русский? на этом сайте только американцы они тебе не помогут ни чем
Step-by-step explanation:
7) Determine if the polynomials below are in the point polynomial time Justynach an! (points ==-+ 2022 in Riel (b) 3 points / 20021011.101 +2022 in C[x]. (c) 3 points] /= x+ 2022 in F7649[*] (Note that 7649 is prime. (d) pon-2 +3 in (e) [4 points] / -6° - 21x + 700 in Q[*]. (f) 14 points) f = 625x3 - 6633r2 + 86- 8855 in Qlur).
Let us check the given polynomials for point polynomial time as follows:
(a) Justynach an! (points ==-+ 2022 in Riel) This polynomial is not in point polynomial time because there is no condition on the polynomial and points.
(b) 3 points / 20021011.101 +2022 in C[x] This polynomial is not in point polynomial time because the given points are not on the polynomial.
(c) /= x+ 2022 in F7649[*] This polynomial is in point polynomial time because it is a monic polynomial and the given point is on the polynomial.
(d) pon-2 +3 This polynomial is not in point polynomial time because it is a constant polynomial and there are no points to verify.
(e) [4 points] / -6° - 21x + 700 in Q[*] This polynomial is in point polynomial time because all the points are on the polynomial.
(f) f = 625x3 - 6633r2 + 86- 8855 in Qlur. This polynomial is in point polynomial time because all the points are on the polynomial.
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Please help me with this test I’m so bad at math
Answer:
4 is 13.75 and 5 is 14.704
Step-by-step explanation:
the Question is on the image
99 times the sum of v and 9
Answer:
Step-by-step explanation:
99(v + 9) is all you need here.
9. Find x. Round answer to nearest whole number.
A) 58
B) 59
C) 60
D) 61
Answer:
the answer. is 60 because you round of 64
A Ferris wheel car moves from point C to point D on the circle shown below:
Circle A is shown with points C and D on the circle and the central angle C A D marked 42 degrees. The diameter is 30 feet.
HELP NOW!! 100 POINTS!!! What is the arc length the car traveled, to the nearest hundredth?
7.91 feet
8.32 feet
10.99 feet
11.89 feet
Answer:
10.99
Step-by-step explanation:
Took the test and it said it was this one :)
The arc length of the car traveled, to the nearest hundredth is 10.99feet
The formula for calculating the length of an arc is expressed as:
L = theta/360 × 2pi r
Given that
Radius r = d/2 = 30/2 =15ft
theta = 42 degrees
pi = 3.14
Substitute the given values into the formula as shown
L = 42/360×2(3.14)(15)
L = 42/360×94.2
L = 3956.4/360
L = 10.99feet
This shows that the arc length of the car traveled, to the nearest hundredth is 10.99feet
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Solve the following quadratic equation for all values of xx in simplest form. 16+2x²=30
fill in the blank.one dimension, ________blank, is used to classify social media and is shown in figure 20-1 on the x-axis, ranging from "words" to "animation."
One dimension, called "media richness," is used to classify social media and is shown on the x-axis of Figure 20-1. It ranges from "words" to "animation" and represents the level of interactivity and information.
In the context of social media, the concept of media richness refers to the degree of richness or complexity in the communication channel. It is a measure of the ability of a medium to convey information effectively, facilitate understanding, and support interaction between users.
Media richness is influenced by factors such as the presence of nonverbal cues, immediate feedback, personalization, and the capacity for multiple communication channels. Figure 20-1 likely represents a graphical representation or classification of social media based on their media richness.
The x-axis of the figure represents the continuum of media richness, ranging from "words" to "animation." At one end of the spectrum, "words" represent text-based communication platforms that primarily rely on written content. As we move towards the other end, "animation" represents media that incorporate rich visual and interactive elements such as videos, graphics, and multimedia features.
By placing different social media platforms along this dimension, Figure 20-1 provides a visual representation of their relative media richness levels. It helps in understanding the varying capabilities and characteristics of different social media platforms and their potential for communication, engagement, and information sharing.
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