The unprecedented shift to remote learning during the Covid-19 pandemic offered a chance to learn about student experiences and needs and possible future trends in unit design. An educator set out to understand the impact of remote learning and assumed that 46% of students would report their studies in the new situation (online) is the same as in the face-to-face context.

In a random sample of 40 university students, 20 rated their overall learning in the virtual format as on par with the face-to-face learning.

Research Question: Has the proportion of students reporting an equal preference for online and face-to-face learning changed due to the Covid-19 pandemic?

Instead of focussing on the proportion of university students reporting the same learning experience in online and face-to-face contexts, we shift our attention to the variable X: the number of university students who reported the same learning experience in online and face-to-face contexts.

1A. Assuming the hypothesised value holds, what are the expected numbers of university students who reported the same learning experience in online and face-to-face contexts?

1B. What are the degrees of freedom associated with this hypothesis test?

1C. What is the value of the test statistic associated with this hypothesis test?

The solution to the system -8x + 5y = -33 and 8x - 4y = 28 is (x, y) = (7, -1).

To solve the given system of equations using the addition method, let's eliminate one variable by adding the two equations together. The system of equations is:

-8x + 5y = -33 (Equation 1)

8x - 4y = 28 (Equation 2)

When we add Equation 1 and Equation 2, the x terms cancel out:

(-8x + 5y) + (8x - 4y) = -33 + 28

y = -5

Now that we have the value of y, we can substitute it back into either Equation 1 or Equation 2 to solve for x. Let's use Equation 1:

-8x + 5(-5) = -33

-8x - 25 = -33

-8x = -33 + 25

-8x = -8

x = 1

Therefore, the solution to the system is (x, y) = (1, -5).

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Answer:

27

Step-by-step explanation:

You do 3159 ÷ 27

Comes out to 27

I found 27 by just plugging in numbers.

Hope this helps

Answer:

There are 27 students in the class.

Step-by-step explanation:

Since the total weight is 3,159 and the average weight is 117lb, you can just divide 3,159 by 117, which will give you 27.

The solution to the initial value problem using the method of separation of variables is y = (x³/3) - (1/2)x + 4/3.

To solve the initial value problem y' = x² - 1/2 with the initial condition y(2) = 3, we can use the method of separation of variables. Here are the steps:

Step 1: Separate the variables

Write the given differential equation in the form:

dy/dx = x² - 1/2

Step 2: Integrate both sides

Integrate both sides of the equation with respect to x:

∫dy = ∫(x² - 1/2) dx

Integration yields:

y = (x³/3) - (1/2)x + C

Step 3: Apply the initial condition

To find the constant C, substitute the initial condition y(2) = 3 into the equation obtained in Step 2:

3 = (2³/3) - (1/2)(2) + C

Simplifying the equation:

3 = 8/3 - 1 + C

3 = 8/3 - 3/3 + C

3 = 5/3 + C

Therefore, C = 3 - 5/3 = 9/3 - 5/3 = 4/3.

Step 4: Write the final solution

Substitute the value of C back into the equation obtained in Step 2:

y = (x³/3) - (1/2)x + 4/3

So, the solution to the initial value problem y' = x² - 1/2, y(2) = 3 is y = (x³/3) - (1/2)x + 4/3.

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Answer:

A) A function is a rule that assigns one input into one output.

The general function is f(x) = y

Where we have one input, x, and one output, y.

But this is a really simple type of function, for example, you could define a function that calculates the volume of a box of length L, width W, and height H as:

V = f(L, W, H) = L*W*H

Then we have "3 inputs" and one output, right?

Well, not exactly, here the set (L, W, H) is called the input, so here we have a single input consisting of 3 variables.

Also we can have functions with a single input into vector-like outputs

For example:

(y, z) = f(x)

So for the input x, we got two values in the output y and z, but this is a single output defined as (y, z), then we always have a single output.

B) The graph of a function is a set of points consisting of one input and the corresponding output.

C) You can determine if a graph represents a function by using the vertical line proof.

A rule that assigns inputs into outputs is only a function if each input is assigned into only one output.

Then if we draw a vertical line that intersects our graph, it should intersect it only one time for functions.

If the line intersects the line two times this means that a single input has more than one output, then this is not a function.

Answer:

A: exactly one, each

B: ordered pairs

C: vertical line test

Step-by-step explanation:

The function f(x) = e⁻ˣ² has critical points at x = 0 and inflection points at x = √(1/2) and x = -√(1/2). function does not have any local maximum or minimum points

The given function is f(x) = e⁻ˣ².

a) The derivative of the function f(x) can be found using the chain rule. Let's calculate it:

f'(x) = d/dx(e⁻ˣ²)

f'(x) = -2x × e⁻ˣ²)

b) The second derivative of the function f(x) can be found by differentiating f'(x) with respect to x:

f''(x) = d/dx(-2x × e⁻ˣ²)

= -2 × e⁻ˣ² + (-2x) × (-2x) × e⁻ˣ²)

= -2 × e⁻ˣ² + 4x² × e⁻ˣ²)

= e⁻ˣ²(-2 + 4x²)

c) To find the critical points of the function f(x), we need to solve the equation f'(x) = 0

-2x × e⁻ˣ² = 0

Setting -2x = 0, we get x = 0.

d) To determine the intervals where the function is increasing or decreasing, we can analyze the sign of the first derivative. Recall that

f'(x) = -2x × e⁻ˣ².

When x < 0, e⁻ˣ² is positive, and -2x is negative. Therefore, f'(x) < 0 for x < 0, indicating that the function is decreasing in this interval.

When x > 0, e⁻ˣ² is positive, and -2x is positive. Therefore, f'(x) > 0 for x > 0, indicating that the function is increasing in this interval.

e) To find the inflection points of the function, we need to solve the equation f''(x) = 0

e⁻ˣ²(-2 + 4x²) = 0

Setting -2 + 4x² = 0, we get x² = 1/2, which leads to

x = ±√(1/2)

x = ±(1/√2)

x = ±(√2/2).

Therefore, the function f(x) = e⁻ˣ² has critical points at x = 0 and inflection points at x = √(1/2) and x = -√(1/2). function does not have any local maximum or minimum points

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Answer:

11 maybe???

Step-by-step explanation:

Answer:

2/3πx³

Step-by-step explanation:

Volume of a cone is expressed as;

V = 1/3πx²h ... 1

x is the radius

h is the height of the cone

If the height of a cone is twice the radius of its base, then;

h = 2x ... 2

Substitute equation 2 into 1

Recall that V =  1/3πx²h

V = 1/3πx²(2x)

V = 2/3πx³

Hence the expression that represents the volume of the cone is 2/3πx³ cubic units

Answer:

402 in^3

Step-by-step explanation:

We know that the volume of a sphere = 4 /3 πr^3

Variables:

r = 2in

Solve for 1 toy:

4 /3 πr^3

4/3 π (2in)^3

= 33.51 cubic inches for 1 toy

For 12 toys:

33.51 in^3 * 12 toys = 402.12 in^3 of water for all the toys

Round:

402.12 in^3 ≈ 402 in^3 of water

Please mark brainliest if this helped!

Please mark brainliest if this helped!

The indicated IQ score, corresponding to the shaded area under the curve of 0.5675 in a normal distribution with a mean of 100 and a standard deviation of 15, is approximately 102.55.

To find the indicated IQ score, we need to determine the corresponding z-score using the given information about the normal distribution. Here's how we can calculate it step by step:

Step 1: Identify the shaded area under the curve.

The shaded area under the curve represents the cumulative probability of the IQ scores. In this case, the shaded area is 0.5675 or 56.75%.

Step 2: Convert the cumulative probability to a z-score.

To find the z-score corresponding to the shaded area, we need to find the z-score that gives us a cumulative probability of 56.75%. We can use a standard normal distribution table or a statistical calculator to find the z-score.

Step 3: Find the z-score.

Using a standard normal distribution table, we can search for the closest cumulative probability to 0.5675. The closest cumulative probability we can find in the table is 0.5681, which corresponds to a z-score of approximately 0.17.

Step 4: Convert the z-score to an IQ score.

Now that we have the z-score of 0.17, we can use the formula for transforming z-scores to raw scores:

IQ score = (z-score × standard deviation) + mean

Given that the mean is 100 and the standard deviation is 15, we can calculate the IQ score:

IQ score = (0.17 × 15) + 100

IQ score = 2.55 + 100

IQ score ≈ 102.55

Therefore, the indicated IQ score is approximately 102.55.

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Answer:

3(k*k)-3(3k)-5(2k)+2(5+5)

Step-by-step explanation:

3k²-19k+20

Just find some number that equal the terms when multiplied. ¯\_(ツ)_/¯

DOUBLE CHECK!

3(k*k)-3(3k)-5(2k)+2(5+5)

Multiply what you need to.

3k²-9k-10k+20

Combine like terms.

3k²-19k+20

---

hope it helps

Answer:

i just did this one it is YES

Step-by-step explanation:

The evaluation of ∫30(4f(t) - 6g(t)) dt given that ∫150f(t) dt = -7, ∫30f(t) dt = -8, ∫150g(t) dt = 4, and ∫30g(t) dt = 8 is -80.

Given that ∫150f(t) dt = -7, ∫30f(t) dt = -8, ∫150g(t) dt = 4, and ∫30g(t) dt = 8.

Let us evaluate ∫30(4f(t) - 6g(t)) dt.

Therefore,∫30(4f(t) - 6g(t)) dt = ∫30(4f(t) dt - 6g(t) dt) = 4 ∫30f(t) dt - 6 ∫30g(t) dt

Now, using the given values in the question we can say that,∫30(4f(t) - 6g(t)) dt = 4 ∫30f(t) dt - 6 ∫30g(t) dt = 4 (-8) - 6(8) = -32 - 48 = -80

Therefore, the evaluation of ∫30(4f(t) - 6g(t)) dt given that ∫150f(t) dt = -7, ∫30f(t) dt = -8, ∫150g(t) dt = 4, and ∫30g(t) dt = 8 is -80.

Note: The given integrals ∫150f(t) dt, ∫30f(t) dt, ∫150g(t) dt, and ∫30g(t) dt are only intermediate steps in order to evaluate the final integral.

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Answer:

f

f

v

Step-by-step explanation:

Answer:

so one the MAD is wrong its actually 1 for both and

The multiple would be 4 and 10.

Step-by-step explanation:

4x1=4

10x1=10

The given equation, 9x² + 36y² - 36x + 72y + 36 = 0, represents an ellipse. In standard form, the equation can be written as (x-1)²/4 + (y+1)²/1 = 1. The center of the ellipse is at (1, -1), the vertices are located at (3, -1) and (-1, -1), and the foci are at (2, -1) and (0, -1).

To write the equation 9x² + 36y² - 36x + 72y + 36 = 0 in standard form, we need to complete the square for both the x and y terms. By rearranging the equation, we have 9x² - 36x + 36 + 36y² + 72y + 36 = 0.

Next, we can factor out a 9 from the x terms and a 36 from the y terms: 9(x² - 4x + 4) + 36(y² + 2y + 1) = 0.

Simplifying further, we have 9(x - 2)² + 36(y + 1)² = 36.

Dividing both sides by 36, we get (x - 2)²/4 + (y + 1)²/1 = 1, which is the standard form of an ellipse.

From the standard form, we can determine that the center of the ellipse is located at (1, -1), the vertices are at (3, -1) and (-1, -1), and the foci are at (2, -1) and (0, -1).

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Answer:17

Step-by-step explanation:

0.35•40=14 to find how many they’ve won

14+9=23 is how many they have won or drawn

40-23=17 is how many they’ve lost

The code could be the number "181*2" since the sum of the digits in even positions (8+2) is equal to the sum of the digits in odd positions (1+1).(option A)

To determine if a number could be the code, we need to check if the sum of the digits in even positions is equal to the sum of the digits in odd positions.

Let's analyze the options:

A) 12*9*8: The sum of the digits in even positions is 1+9 = 10, while the sum of the digits in odd positions is 2+8 = 10. Therefore, this number could be the code.

B) 181*2: The sum of the digits in even positions is 8+2 = 10, and the sum of the digits in odd positions is 1+1 = 2. These sums are not equal, so this number cannot be the code.

Based on the given information, only option A (1298) satisfies the condition where the sums of the digits in even and odd positions are equal.

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The probability of a Type I error in rejection region a is 0.01.

We must  find  the area under the t-distribution curve outside the rejection region, assuming a two-tailed test in order to to determine the probability of making a Type I error in each rejection region.

for a. t > 2.718, and df = 11:

Using a t-distribution table,  the probability is 0.01.

b. t < -1.476, df = 5:

Using a t-distribution table the probability is 0.05.

c. t < -2.060 or t > 2.060, df = 25:

Using a t-distribution table, the area in each tail is  0.025.

The combined probability of a Type I error in rejection region c is

0.025 + 0.025 = 0.05.

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The 95% confidence interval estimate of the overall difference in the percentages of Democrats and Republicans that prioritize protecting the environment is approximately 37.0% ± 5.0%.

Calculate the proportions for Democrats and Republicans:

Proportion of Democrats prioritizing environment = 731/850 ≈ 0.860

Proportion of Republicans prioritizing environment = 466/950 ≈ 0.490

Next, calculate the standard error (SE) of the difference between the proportions:

SE = √[(p1(1 - p1))/n1 + (p2(1 - p2))/n2]

= √[(0.860(1 - 0.860))/850 + (0.490(1 - 0.490))/950]

≈ √(0.000407 + 0.000245)

≈ √0.000652

≈ 0.0255

Now, calculate the margin of error (ME) using the critical value for a 95% confidence level (z-value):

ME = z × SE

≈ 1.96 × 0.0255

≈ 0.04998

Finally, construct the confidence interval:

Difference in proportions ± Margin of error

(0.860 - 0.490) ± 0.04998

0.370 ± 0.04998

The 95% confidence interval is approximately 37.0% ± 5.0%.

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Answer:

The probability of getting a white or green gumball is 35.64%.

Step-by-step explanation:

1. calculate the total number of gumballs in the gumball machine

35 + 22 + 30 + 14 = 101 gumballs

2. calculate the number of white and green gumballs combined

22 + 14 = 36 w/g gumballs

3. divide the number of white and green gumballs combined by the total number of gumballs in the gumball machine

36 / 101 = 0.3564

Answer: the probability of getting a white or green gumball is 35.64% (0.3564).

Probability is the chance of occurring an event from the total possible outcomes.

The probability of getting a white or a green gumball is 57/101.

It is the chance of occurring an event from the total possible outcomes.

We have,

Green gumballs = 35

White gumballs = 22

Purple gumballs = 30

Blue gumballs = 14

Total gumballs = 35 + 22 + 30 + 14 = 101

The combination is given by:

= [tex]^nC_{r}[/tex]

= n! / r! (n-r)!

The probability of choosing a white gumball:

= [tex]\frac{^{22}C_{1}}{^{101}C_{1} }[/tex]

= 22 / 101

The probability of choosing a green gumball:

= [tex]\frac{^{35}C_{1}}{^{101}C_{1} }[/tex]

= 35 / 101

The probability of getting a white or a green gumball:

= 22/101 + 35 / 101

= (22 +35) / 101

= 57 / 101

Thus the probability of getting a white or a green gumball is 57/101.

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After considering the given data we conclude that it is proven that [tex]limnan = a (and) a + 0[/tex], and there exists a positive number k and a positive integer m such that Jan> k, whenever n > m.

To prove that if [tex]limnan = a (and) a + 0[/tex], then there exists a positive number k and a positive integer m such that Jan> k, whenever n > m, we can apply the definition of a limit.
Definition of a limit: Let assume (an) be a sequence of real numbers. We interpret that the limit of (an) as n approaches infinity is a,
denoted limnan = a, if for every ε > 0, there exists a positive integer N such that [tex]\{|an - a| < \epsilon\} whenever}\{ n > N\}[/tex].
Then lets proceed with the proof
Consider that [tex]limnan = a (and) a + 0.[/tex]
Let [tex]\epsilon = a/2[/tex]. Since a + 0, we know that a > 0, so [tex]\epsilon[/tex] > 0.
Applying the definition of a limit, there exists a positive integer [tex]N_1[/tex] such that [tex]|an - a| < \epsilon (whenever) n > N_1.[/tex]
Then [tex]k = a/\epsilon = 2[/tex]. Since [tex]\epsilon = a/2, (we have) k = 2.[/tex]
Then  [tex]m = max\{N1, k\}[/tex] Hence, for n > m, we have:
[tex]n > N_1, (since) m \geq N_1[/tex].
[tex]n > k,( since) m \geq k.[/tex]
Therefore, we have:
[tex]|an - a| < \epsilon , (by the description) of N_1[/tex].
[tex]\epsilon = a/2 < a/k, (since) k = 2.[/tex]
[tex]|an - a| < a/k,[/tex] by applying substitution.
[tex]an - a < a/k[/tex], since |an - a| is positive.
[tex]an < a(1 + 1/k)[/tex], by adding a to both sides.
[tex]an < a(1 + 1/2) = 3a/2.[/tex]
Hence , we have shown that there exists a positive number k = 2 and a positive integer [tex]m = max\{N1, k\}[/tex] such that Jan> k, whenever n > m.
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The evidence and data support Evan's argument that plants predominantly acquire the materials they need to grow from air and water .

Evan's statement is supported by evidence and data that demonstrate how plants obtain the majority of the materials they need to grow from air and water. Here are some key points to support his argument:

Carbon Dioxide (CO2) from the air: Through the process of photosynthesis, plants take in carbon dioxide from the air. They use the carbon dioxide along with water and sunlight to produce glucose and oxygen. This glucose serves as an essential energy source for plant growth and development.

Water: Plants absorb water from the soil through their root systems. Water plays a critical role in various plant processes, including nutrient uptake, transportation, and the maintenance of cell turgidity. It is a primary component of plant cells and is necessary for photosynthesis to occur.

Essential nutrients from the soil: While air and water provide the primary materials for plant growth, plants also require certain nutrients to thrive. These essential nutrients, such as nitrogen, phosphorus, and potassium, are typically obtained from the soil. However, it's important to note that these nutrients are often dissolved in water and taken up by plant roots.

Experimentation and research: Numerous scientific experiments and studies have been conducted to investigate plant nutrient uptake. These experiments have confirmed that plants can grow and develop using only air, water, and the necessary nutrients found in these sources.

The evidence and data support Evan's argument that plants predominantly acquire the materials they need to grow from air and water. While nutrients from the soil are essential, the primary sources of plant growth materials are carbon dioxide from the air and water, which are crucial for photosynthesis and various physiological processes in plants.

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Answer:

x+y=5

×-y=1

2x/2=6/2

x=3

while x+y=5

3+y=5

y=5-3

y=2

Answer:

C

Step-by-step explanation:

(3, 2)

The solution to the differential equation y'' + y = csc(x) using the variation of parameters method is y(x) = cos(x)ln|sin(x)| + Csin(x), where C is a constant.

To solve the differential equation by variation of parameters, we first find the complementary solution (the solution to the homogeneous equation). The homogeneous equation is y'' + y = 0, which has the solution y_c(x) = Acos(x) + Bsin(x), where A and B are constants.

Next, we find the particular solution using the variation of parameters method. We assume the particular solution is of the form y_p(x) = u(x)cos(x) + v(x)sin(x), where u(x) and v(x) are unknown functions.

We differentiate y_p(x) to find y_p' and y_p'' and substitute them into the original differential equation. After simplification, we obtain u'(x)sin(x) - v'(x)cos(x) = csc(x).

To solve this system of equations, we find the derivatives u'(x) and v'(x) and integrate them to obtain u(x) and v(x). Finally, we substitute u(x) and v(x) into the particular solution form y_p(x) = u(x)cos(x) + v(x)sin(x).

The final solution is y(x) = y_c(x) + y_p(x), which simplifies to y(x) = cos(x)ln|sin(x)| + Csin(x), where C is the constant of integration.

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The exact value of A in the general solution is 13

Also, the DEQ is separable

From the question, we have the following parameters that can be used in our computation:

y = Ax² + C/x

The differential equation is given as

y' + y/x = 39x

When y = Ax² + C/x is differentiated, we have

y' = 2Ax - Cx⁻²

So, we have

2Ax - Cx⁻² + y/x = 39x

Recall that

y = Ax² + C/x

So, we have

2Ax - Cx⁻² + (Ax² + C/x)/x = 39x

Evaluate

2Ax - Cx⁻² + Ax + Cx⁻² = 39x

This gives

2Ax +  Ax  = 39x

So, we have

3Ax = 39x

By comparing both sides of the equation, we have

3A = 39

Divide both sides by 3

A = 13

Hence, the value of A in the general solution is 13

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Answer: 5.4

Step-by-step explanation:

Pretty Simple 5 squared plus 2 squared is 29.Just find the square root of that and it is the third side.:)

Answer:

5^2 + 2^2 = 29

sqr root of 29 is 5.385

Step-by-step explanation:

Answer:

8/3 gram

Step-by-step explanation:

Since the hanger is said to be in balance, then the weight on the right balances the weight on the left ;

Right hand side = Left hand side

12 = 4 + x + x + x

12 = 4 + 3x

12 - 4 = 3x

8 = 3x

8/3 = 3x / 3

x = 8/3 gram

The lesser of the two eigenvalues is λ = -1. Its corresponding eigenvector is [-42 29].

The greater of the two eigenvalues is λ = 1. Its corresponding eigenvector is [42 29].

To solve the system of differential equations:

x' = -29x + 42y

y' = -20x + 29y

We can rewrite it in matrix form as follows:

X' = AX

where X = [x y] is a vector, X' represents the derivative of X with respect to time, and A is the coefficient matrix. In this case, A is given by:

A = [ -29 42 ]

[ -20 29 ]

To find the eigenvalues and eigenvectors, we need to solve the characteristic equation:

det(A - λI) = 0

where λ is the eigenvalue and I is the identity matrix. Solving this equation will give us the eigenvalues, and by substituting these eigenvalues back into the equation (A - λI)V = 0, where V is the corresponding eigenvector, we can find the eigenvectors.

Let's calculate the eigenvalues first. We have:

A - λI = [ -29 42 ]

[ -20 29 ] - λ [ 1 0 ]

[ 0 1 ]

Expanding the determinant, we get:

(-29 - λ)(29 - λ) - (42)(-20) = 0

(λ + 29)(λ - 29) + 840 = 0

λ² - 29² + 840 = 0

λ² - 841 + 840 = 0

λ² = 1

λ = ±1

So the eigenvalues are λ = 1 and λ = -1.

To find the corresponding eigenvectors, we substitute each eigenvalue back into the equation (A - λI)V = 0.

For λ = 1, we have:

[ -29 42 ] [ v₁ ] [ 0 ]

[ -20 29 ] [ v₂ ] = [ 0 ]

This gives us the following system of equations:

-29v₁ + 42v₂ = 0

-20v₁ + 29v₂ = 0

Solving this system, we find that v₁ = 42 and v₂ = 29.

Therefore, the eigenvector corresponding to the eigenvalue λ = 1 is [42 29].

For λ = -1, we have:

[ -29 42 ] [ v₁ ] [ 0 ]

[ -20 29 ] [ v₂ ] = [ 0 ]

This gives us the following system of equations:

-29v₁ + 42v₂ = 0

-20v₁ + 29v₂ = 0

Solving this system, we find that v₁ = -42 and v₂ = 29.

Therefore, the eigenvector corresponding to the eigenvalue λ = -1 is [-42 29].

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Complete Question:

Solve the system of differential equations

x' = -29x + 42y

y' = -20x + 29y

x(0) = -15, y(0) = -11

The lesser of the two eigenvalues is Its corresponding eigenvector is

The greater of the two eigenvalues is Its corresponding eigenvector is