What is 3^2/3 equal to

Answer:

g

Step-by-step explanation:

the point at the intersection of the parabola and its line of symmetry

Answer:

A

Step-by-step explanation:

Step-by-step explanation:

The given equation is :

2x = 10

We need to find the value of x.

This equation has one solution as it is a linear equation having one variable i.e. x.

Dividing both sides by 2,

x = 5

So, the value of x is equal to 5.

Put x = 5. So,

2(5) = 10

10 = 10

Hence, this is the required solution.

Answer:f

Step-by-step explanation:d

Answer:

Step-by-step explanation:

Answer:

24 is awnser

Step-by-step explanation:

Pls mark me as brainliest

Answer:

10 h 55 min

Step-by-step explanation:

13 h 10 - 2h = 11 h 10

11 h 10 - 15 min = 10 h 55 min

Answer:

3/10

Step-by-step explanation:

Answer:

ill be figuring this out rn, (theres a caculator thingy online if nobody helps u)

Step-by-step explanation:

44.4 is the Percent and as a fraction its

111/250 (thats what i got)

6.66 as a dec. and as a fraction its 333/50

sorry if these are wrong bur its what i got.

Answer:

25

Step-by-step explanation:

Find the prime factors of each term in order to find the greatest common factor (GCF),

25

Answer:

.12

Step-by-step explanation:

First set up your proportion.

[tex] \frac{3}{25} = \frac{12}{100} [/tex]Multiply 3 and 25 by 4 to get 12 and 100.

the answer would be 12 hundredths or .12

[tex]\huge\text{Hey there!}[/tex]

[tex]\mathsf{-12=6\sqrt{x+4}}[/tex]

[tex]\mathsf{6 \sqrt{x + 4}=-12}[/tex]

[tex]\textsf{DIVIDE your BOTH SIDES by 6}[/tex]

[tex]\mathsf{\dfrac{6\sqrt{x + 4}}{6}= \dfrac{-12}{6}}[/tex]

[tex]\textsf{Introduce the new temporary equation}[/tex]

[tex]\mathsf{\sqrt{x + 4}=-2}[/tex]

[tex]\textsf{SOLVE for your SQUARE ROOT }[/tex]

[tex]\mathsf{\sqrt{{x + 4}}=-2}[/tex]

[tex]\mathsf{Like: x + 4 = (-2)^2}[/tex]

[tex]\textsf{SQUARE EACH of your SIDES}[/tex]

[tex]\mathsf{x + 4 = 4}[/tex]

[tex]\textsf{SUBTRACT your BOTH SIDES by 4 }[/tex]

[tex]\mathsf{x + 4 -4= 4-4}[/tex]

[tex]\mathsf{Cancel\ out\ 7-7 \ because\ it\ gives\ you\ 0}[/tex]

[tex]\textsf{Solving for your last temporary question}[/tex]

[tex]\mathsf{x = 4-4}[/tex]

[tex]\mathsf{4-4 = \bf 0}[/tex]

[tex]\mathsf{\bf x = 0}[/tex]

[tex]\textsf{Plug your x-value (x = 0) to make sure it works for your original equation}[/tex]

[tex]\textsf{You will see that it doesn’t work for the original problem so this means that the}\\\textsf{original equation \bf does NOT have any solutions.}[/tex]

[tex]\boxed{\boxed{\large\text{Answer: \huge\bf No solutions}}}\huge\checkmark[/tex]

[tex]\text{Good luck on your assignment and enjoy your day!}[/tex]

~[tex]\frak{Amphitrite1040:)}[/tex]

Answer:

k = 4/25 or 0.16

Step-by-step explanation:

Given the following data;

y = 4/5

x = 5

To find the variation constant, k;

y is directly proportional to x

Mathematically, y = kx

Substituting into the formula, we have;

4/5 = k5

Cross-multiplying, we have;

4 = 25k

k = 4/25

Answer:

angle 3x = 78°

angle opposite (4x + 30) = 226°

Step-by-step explanation:

It has 6 sides, so:

total interior angles sum = (180° x 6) - 360° = 720°

720° = 90° + 3x + 90° + 118° + (360° - (4x + 30°)) + 118°

combine like terms:

720° = 3x + 416° + (360° - 4x - 30°)

720° = -x + 746°

x = 26°

Answer:

The answer to the question provided is 60.

Answer:

The Pythagorean theorem states that a2 + b2 = c2 in a right triangle where c is the longest side. You can use this equation to figure out the length of one side if you have the lengths of the other two.

Answer:

B. 6.2

Step-by-step explanation:

The calculation is done by hand and verified by a TI-84 calculator.

Brooke earned $9.00 in interest over one year on her account with $90 at a 10% annual interest rate, compounded annually.

To solve this problem, we can use the formula for compound interest:

A =[tex]P(1 + r/n)^(^n^t^)[/tex]

where A is the amount of money in the account after t years, P is the principal (the initial amount of money), r is the annual interest rate as a decimal, n is the number of times the interest is compounded per year, and t is the time period in years.

In this case, we want to find the interest earned in one year, so we can set t = 1. We know that Brooke has $90 in her account, so P = 90. The annual interest rate is 10%, or 0.1 as a decimal. The interest is compounded annually, so n = 1.

We can plug these values into the formula and solve for the amount of money in the account after one year:

A = [tex]90(1 + 0.1/1)^(^1^*^1^)[/tex]

A = 90(1.1)

A ≈ 99

The amount of money in the account after one year is approximately $99. So, Brooke earned $99 - $90 = $9 in interest. To the nearest cent, this is $9.00.

In conclusion, using the formula for compound interest, we can calculate the interest earned on an account given the initial balance, annual interest rate, number of compounding periods per year, and time period.

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Answer:0.66666666666667

Step-by-step explanation:

Answer:

180

Step-by-step explanation:

Answer:

Step-by-step explanation:

Greatest common factor of 6x and 9y is 3.

6x + 9y = 3(2x + 3y)

:::::

Greatest common factor of 3c and 11c is c.

3c + 11c = (3+11)c

Answer:

nsdjdhbdeihddjjdoeuriehdisueueeuhd

Answer:

the 3rd one

Step-by-step explanation:

Answer:

24 units

Step-by-step explanation:

Original perimeter:

5+4+3=12

When each side length is doubled, the original perimeter is doubled.

12*2=24

Answer:

if the length of each side is is doubled then

5×2 = 10

4×2 = 8

3×2 = 6

perimeter of new figure = 10 + 8 + 6

= 24 units

hope this helps good day mate

Answer:

5

Step-by-step explanation:

That whole circle equals 180, so just add 99 plus 76 and subtract it from 180.

Answer:

C. =

Step-by-step explanation:

whenever you have |  | It will always be positive so -6 turns to 6 and that makes it equal.

Answer:

the blue block 'side' is 10

the pink block ' bottom' is 9

the cream 'side' block is 13 (length)

the green back triangle next to the blue side is also 10

and the other side of the green back triangle is 8

Answer:

V(x) = 4(1.35)x, and it grows.

Step-by-step explanation:

The statement that illustrates the approximate value of the bond in hundreds of dollars over time in years is:

"The value of the bond can be approximated by the quadratic equation V(x) = 0.725x² + 0.675x + 4.

An equation contains one or more terms with variables connected by an equal sign.

Example:

2x + 4y = 9 is an equation.

2x = 8 is an equation.

We have,

We can use the given data points to approximate the relationship between the value of the bond and time by fitting a curve that best fits the points.

Based on the given data,

It seems that the value of the bond is increasing at an accelerating rate over time.

We can try to approximate this relationship by fitting a quadratic equation to the data.

Let's assume that the relationship between the value of the bond and time can be approximated by the quadratic equation:

V(x) = ax² + bx + c

where V(x) is the value of the bond in hundreds of dollars after x years, and a, b, and c are constants to be determined.

To solve for a, b, and c, we can use the three data points for which we have values of V(x):

V(0) = 4, V(1) = 5.4, V(2) = 7.29

Substituting these values into the equation.

a(0)² + b(0) + c = 4

a(1)² + b(1) + c = 5.4

a(2)² + b(2) + c = 7.29

Simplifying.

c = 4

a + b + c = 5.4

4a + 2b + c = 7.29

Substituting c = 4.

a + b = 1.4

4a + 2b = 3.29

Solving for a and b.

a = 0.725

b = 0.675

Now,

The equation that approximates the relationship between the value of the bond and time is:

V(x) = 0.725x² + 0.675x + 4

This equation tells us that the value of the bond is increasing at an accelerating rate over time, starting at $400 (or 4 hundred dollars) and increasing by approximately 0.725 hundred dollars for each year squared, plus 0.675 hundred dollars for each year, plus a constant 4 hundred dollars. For example, after 5 years, the value of the bond would be approximately:

V(5) = 0.725(5)² + 0.675(5) + 4 = 23.75

Therefore,

The statement that illustrates the approximate value of the bond in hundreds of dollars over time in years is:

"The value of the bond can be approximated by the quadratic equation V(x) = 0.725x² + 0.675x + 4.

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