Which is an example of heat transfer by convection?

Answer:

Tension in the chains - In a chain drive, technically, you have a closed-chain (which has no end) going around 2 pulley or gears; looking closely you have 2 parallel chains going in opposite direction. If kept in horizontal direction, the one below the other is the slack side and the other the tight side. The tension on the upper or tight side is more than the slack side. So you need to keep in mind to keep your chain drive tight so that there is no loss or rotation or lags.

Sizes of the pulley/gear - The chain will be warped around a pair of pulley or gear. The sizes of these pulley/gear will also determine the efficiency of the chain drive (consider one big and one small)

Number of pulley/gear - If the number of pulley/gear is more and chain wrapped on it with little complexity will result in decrease in efficiency because of extra tension.

Length of the chain drive - You cannot have much too long chain drive. It will make your slack side more heavy because the end are further away. You have to apply more power and possibilities of lag increases decreasing efficiency. In an ideal situation, this won't happen, but this world isn't ideal.

Friction between chains & pulley/gear - If you have studied gears (involving its teeth), you will come to know that there is friction offered on the two meeting surfaces.

Angle of contact - This would have been explained better with a diagram. Although, if you are familiar with the terms you won't have difficulty understanding. Angle of contact is the angle the chain forms with the pulley/gear at the point of contact with the center of the pulley. The angle of contact should not be too small, or else the things will be slippery.

Explanation:

Complete Question

A student bikes to school by traveling first dN = 0.900 miles north, then dW = 0.300 miles west, and finally dS = 0.100 miles south.

Similarly, let d⃗ W be the displacement vector corresponding to the second leg of the student's trip. Express d⃗ W in component form.

Express your answer as two numbers separated by a comma. Be careful with your signs.

Answer:

The value is  [tex]dT  =  ( -0.3,  0.8)[/tex]

Explanation:

From the question we are told that

   The first displacement is  [tex]dN  =  0.900 \  due  \  North[/tex] i.e positive  y-axis

   The  second displacement is  [tex]dW =  0.300 \  miles  \  due \  west[/tex] i.e negative  x-axis

   The final displacement is  [tex]dS =  0.100 \  miles \ due \ south[/tex] i.e  negative  y-axis

Generally dW in component for is  

      [tex]dW =  (-0.3 ,  0)[/tex]  

Generally the  total displacement of the student is mathematically represented as

     [tex]dT  =  ( -0.3,  (0.90 - 0.10))[/tex]

      [tex]dT  =  ( -0.3,  0.8)[/tex]

Answer:

In MeV: 10.674 × 10^(34) MeV

In TeV: 10.674 × 10^(28) TeV

Explanation:

We are given that;

1.78 × 10^(-36) kg = 1 eV

We are now told that the blue whale has an average mass of 1.90 × 10^(5) kg

Thus, converting this mass of the blue whale to eV, we have;

(1.90 × 10^(5) × 1)/(1.78 × 10^(-36)) = 10.674 × 10^(40) eV

Now, converting to mega electron volts;

From conversions;

1 eV = 10^(-6) MeV

Thus,

10.674 × 10^(40) eV will be;

(10.674 × 10^(40) × 10^(-6))/1 = 10.674 × 10^(34) MeV

Also, converting to Tera electron Volts;

From conversion, we know that;

1 eV = 10^(-12) TeV

Thus;

10.674 × 10^(40) eV will give;

(10.674 × 10^(40) × 10^(-12))/1 = 10.674 × 10^(28) TeV

Answer:

180

Explanation:

4m/s x 45s=180m

Answer:

I'm in college and i'm a senior so i will graduate this year.

Explanation:

Answer:

f block on edge 2020

Explanation:

hope this helps:)

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Answer:

2m 4m2Explanation:rteji3ujnrej

1. .134

2. 22.34

3. 330

4. 4350

Answer:

E = 27 J

Explanation:

It is given that,

Mass of a kitten is 1.5 kg

Initially, it was at a height of 1.8 m refrigerator and finally jumps to a 0.9 m height counter.

We need to find the kitten's gravitational  potential energy on top of the counter. Potential energy is possessed due to the position of an object. It can be given by :

[tex]E=mgh[/tex]

g is acceleration due to gravity

[tex]E=1.5\ kg\times 10\ m/s^2\times 1.8\ m\\E=27\ J[/tex]

So, the kitten's gravitational  potential energy on top of the counter is 27 J.

copper wire is the example of superconductor

Answer:

Take the numbers and fill them in graph.

Plot time as X and speed as Y and afterward join then like a line graph.

Answer:

Explanation:

If I drop a paper clip from rest and it falls freely until it hits the ground with a speed of 30 m/s,we ae to find the time taken for the ball to drop. To do that we will use the equation of motion v = u + gt

v is the final velocity = 30m/s

u is the initial velocity = 0m/s (the object drops from rest)

g is the acceleration due to gravity = 9.81m/s²

time is the time taken

Substituting the given parameters into the formula;

30 = 0 + (9.81)t

30 = 9.81t

t = 30/9.81

t = 3.06secs

Hence it will take the object 3.06secs in free fall