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Equivalent weight of the compound
caco3​

Answer:

steel because water gold and honey is not a mixture of something

Answer:

Steel

Explanation:

Answer:

the scientific study of matter i believe

Explanation:

because the definition says the branch of science that deals with the identification of the substances of which matter is composed

Answer:

hydrogen dioxide

Explanation:

Hydrogen dioxide  is the name of the binary molecule H2O2 ,therefore option (b) is correct from the image below.

A thick, colorless liquid, H2O2, resembling water, but having a bitter, sour taste, produced by the action of acids on barium peroxide.

It decomposes into water and oxygen, and is manufactured in large quantities for an oxidizing and bleaching agent. Called also oxygenated water.

A colorless, unstable compound of hydrogen and oxygen (H 2 O 2). It is used as an antiseptic and bleaching agent.

Hydrogen dioxide  is the name of the binary molecule H2O2 ,hence option (b) is correct from the image below.

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Answer:

Malleability

Explanation:

Answer:

Malleability is not chemical property

Answer:

When you heat an atom, some of its electrons are "excited* to higher energy levels. When an electron drops from one level to a lower energy level, it emits a quantum of energy. ... The different mix of energy differences for each atom produces different colours. Each metal gives a characteristic flame emission spectrum.

Explanation:

Answer:

a) ²²⁴Ra₈₈ ---> α + ²²⁰Rn₈₆ + Q

b) the Q-value of this reaction is 5.789 MeV

c) the energies (in MeV) of the two associated alpha particles are; 5.69 MeV and 5.449 Mev

Explanation:

a)

The decay equation for the alpha decay is expressed as;

²²⁴Ra₈₈ ---> α + ²²⁰Rn₈₆ + Q

b)

Calculate the Q-value (in MeV) of this reaction.

Q = Mparent - Mdaughter -Mg

Q = MRa - MRn -Mg

= 224.020202 - 220.011384 - 4.00260305

= 0.00621495 amu

= 5.789 MeV

therefore the Q-value of this reaction is 5.789 MeV

c)

Energy of alpha particle is expressed as;

E∝ = MQ / ( m + M)

now this is the maximum energy available for the daughter, ²²⁰Rn going to the ground state;

The energy of the alpha particle gives;

E∝  = 220(5.789) / ( 4 + 220) = 5.69 MeV

as given in the question,The other less frequent alpha occurring 5.5% of the time leaves the daughter nucleus in an excited state of 0.241 MeV above the ground state.

Therefore the energy of this alpha is

E∝ = 5.69 - 0.241 = 5.449 Mev

Therefore the energies (in MeV) of the two associated alpha particles are; 5.69 MeV and 5.449 Mev

d)

Sketch of the nuclear decay scheme have been uploaded along side this answer.

(a)[tex]^{224}Ra_{_{88}}=^4\alpha_{_2}+^{220}Rn_{_{86}}+Q[/tex]

(b) the Q-value of the reaction is 5.789 MeV

(c) The alpha particles have energies of 5.69 MeV and 5.449 MeV

(a) The alpha decay of the radioisotope 224Ra is given by:

         [tex]^{224}Ra_{_{88}}=^4\alpha_{_2}+^{220}Rn_{_{86}}+Q[/tex]

(b) The Q-value  of a reaction is given by:

Q = {mas of reactants - mass of products}c²

[tex]Q = [M_{224Ra} - M_{\alpha} - M_{220Rn}]c^2[/tex]

Q = (224.020202 - 220.011384 - 4.00260305) amu.c²

Q = 0.00621495 × 931.5 MeV   ( since 1 amu.c² = 931.5 MeV)

Q = 5.789 MeV

(c) The energy of the alpha particle is expressed as;

E(α) = MQ / ( m + M)

it is the maximum energy available for the daughter nucleus, ²²⁰Rn going to the ground state.

If the daughter nucleus is at rest then all the energy is carried by the alpha particle.

The energy of the alpha particle is:

E(α)  = 220(5.789) / ( 4 + 220) = 5.69 MeV

Now, for the alpha particle occurring 5.5% of the time and leaving the daughter nucleus in an excited state of 0.241 MeV :

The energy of this alpha particle is

E(α) = 5.69 - 0.241 = 5.449 Mev

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Answer:

You may assume that the same metal is used in each situation. Light is emitted by electrons when they drop from one energy level to a lower level.

Answer:

Hydronium ion

The conjugate acid of water is the hydronium ion ; [tex]H_3O^+,[/tex]

Explanation:

It is an ion formed by the association of a hydrogen ion with a water molecule.

Answer:

b

Explanation:

Answer:

When the cube was placed in the water, the volume of the water changed. When the liquid was poured from the bowl, the shape changed.

Explanation:

When a cube is placed inside water, the volume of the water will change due to the introduction of the cube as the cube will displace some water. Remember that the shape of a liquid is the shape of its container so the shape of the water remains the same.

When the water is poured into a glass, its shape changes as it now assumes the shape of the glass as explained above.

Answer: When the cube was placed in the water, the shape of the cube stays the same. When the liquid was poured from the bowl into the glass, the shape changed

Explanation:

Answer:

319.8 m/min

Explanation:

533 cm/s

We can convert 533 cm/s to m/min by doing the following:

First, we shall convert 533 cm/s to m/s. This can be obtained as illustrated below:

Recall:

100 cm/s = 1 m/s

Therefore,

533 cm/s = 533 cm/s /100 cm/s × 1 m/s

533 cm/s = 5.33 m/s

Finally, we shall convert 5.33 m/s to m/min. This can be obtained as follow:

1 m/s = 60 m/min

Therefore,

5.33 m/s = 5.33 m/s / 1 m/s × 60 m/min

5.33 m/s = 319.8 m/min

Therefore, 533 cm/s is equivalent to 319.8 m/min

Answer:

D

Explanation:

science shows patterns and anomalies in how the world works

Answer:

- Take 3.3 mL of 3.0-M hydrochloric acid and subsequently add 76.7 mL of water to complete the 100.00 mL.

- Take 11.7mL of 6.0-M hydrochloric acid and subsequently add 88.3 mL of water to complete the 100.00 mL

Explanation:

Hello,

In this case, given that the dilutions are preparedfrom 3.0-M and 6.0-M hydrochloric acid, we must proceed as follows:

- 3.0-M stock: when using this stock, the aliquot you must take is computed as shown below:

[tex]V_1=\frac{M_2V_2}{M_1}=\frac{100.00mL*0.70M}{3.0M}=23.3mL[/tex]

It means that you must take 23.3 mL of 3.0-M hydrochloric acid and subsequently add 76.7 mL of water to complete the 100.00 mL.

- 6.0-M stock: when using this stock, the aliquot you must take is computed as shown below:

[tex]V_1=\frac{M_2V_2}{M_1}=\frac{100.00mL*0.70M}{6.0M}=11.7mL[/tex]

It means that you must take 11.7mL of 6.0-M hydrochloric acid and subsequently add 88.3 mL of water to complete the 100.00 mL.

Regards.

Answer:

A. 40N

Explanation:

Answer:

The reaction is endothermic.

Yes, absorbed

3.06x10¹kJ are absorbed

Explanation:

In the reaction:

2HgO(s) → 2Hg(l) + O₂(g) ΔH = 182kJ

As ΔH >0,

The reaction is endothermic

As the reaction is endothermic, when the reaction occurs,

the heat is absorbed.

Now, based on the equation, when 2 moles of HgO (Molar mass: 216.59g/mol), 182kJ are absorbed.

72.8g are:

72.8g * (1mol / 216.59g) = 0.3361 moles HgO.

that absorb:

0.3361 moles HgO * (182kJ / 2 moles) =

Answer:

True

Explanation: Imagine the Electrons is by the nucleus which give more energy.

Answer:

[tex]\rho =0.9g/mL[/tex]

Explanation:

Hello,

In this case, due to the volume displacement caused the by the object's submersion, it's volume is:

[tex]V=11.8mL-4.5mL=7.3 mL[/tex]

In such a way, considering the mathematical definition of density, it turns out:

[tex]\rho =\frac{m}{V}=\frac{6.5g}{7.3mL}\\ \\\rho =0.89g/mL[/tex]

Rounding to the nearest tenth we finally obtain:

[tex]\rho =0.9g/mL[/tex]

Regards.

Answer:

There can be error in millimetres.

Explanation:

The rounding off can create errors in exact measurement. There can be errors in the measured value and actual measurement of the object. Alexander has rounded his calculation to nearest centimetre then it is possible he can make errors in millimetre calculations. The measured width of the object will not be the actual measurement and it might differ slightly.

Given :

Three block of same mass name A , B and C .

Sides of block A , B and C is 3.0 cm , 5.0 cm and 10.0 cm .

To Find :

Which block has the higher  density .

Solution :

We know , density [tex]\rho[/tex] is given by :

[tex]\rho=\dfrac{M}{V}[/tex]   ......1 )

Here , V is volume .

Now , volume V for cube is given :

[tex]V=a^3[/tex]    .......2 )

(  Here , a is the side of cube )

Now ,form equation 1 we can see if mass remains constant then density decrease with increase in volume.

Therefore , cube with minimum side will have higher density , in this case it is 3 cm block .

Hence , this is the required solution .

Answer:

1. electrons and neutrons protons

2. true

3. electrons are negative and neutrons are neutral

4. true

5. the total number of neutrons and protons

Explanation:

Answer:

a) But-1-ene

b) E-But-2-ene

c) Z-But-2-ene

d) 2-Methylpropene

Explanation:

In this case, if we want to draw the isomers, we have to check the formula [tex]C_4_H8[/tex] in this formula we can start with a linear structure with 4 carbons. We also know that we have a double bond, so we can put this double bond between carbons 1 and 2 and we will obtain But-1-ene.

For the next isomer, we can move the double bond to carbons 2 and 3. When we do this can have two structures. When the methyl groups are placed on the same side we will obtain Z-But-2-ene. When the methyls groups are placed on opposite sides we will obtain E-But-2-ene.

Finally, we can use a linear structure of three carbons with a methyl group in the middle with a double bond, and we will obtain 2-Methylpropene.

See figure 1 to further explanations.

I hope it helps!

Answer:

the average atomic mass in amu of X is 25.39 amu

Explanation:

The computation of the average atomic mass in the amu of X is shown below:

Average mass is

= Product sum + atomic mass of each and every isotope

Now the average mass

= (80.5 ÷ 100 × 25 amu) + (19.5 ÷ 100 × 27 amu)

= 20.125 + 5.265

= 25.39 amu

Hence, the average atomic mass in amu of X is 25.39 amu

The average atomic mass of X is 25.39 amu.

It is the quantity of matter present within an atom of an element.

Based on the given information,

• The unknown element X has the isotopes, 25X (80.5% abundant) and 27X (19.5% abundant).

Now the atomic mass of X can be calculated by using the formula,

[tex]=\frac{(M1*A1)+(M2*A2)}{A1+A2}[/tex]

Here, M1 and M2 are the atomic masses, and A1 and A2 are their  abundances.

Now putting the values we get,

[tex]= \frac{(25*80.5)+(27*19.5)}{80.5+19.5} \\\\= \frac{2012.5+526.5}{100} \\= \frac{2539}{100} \\= 25.39 amu[/tex]

Thus, the average atomic mass of X is 25.39 amu.

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Answer:

Title: Effect of soda color on the choice of Allison's friends.

Independent variable: Color of Soda

Dependent variable: Friends' choice/Number of friends that chose a particular soda

Please find the data table attached as an image.

Explanation:

A data table is used to organize the data recorded after an experiment. The data table shows the title of the experiment, which is written directly above the table. It also shows the independent variable (on the first column) and the dependent variable (on other columns to the right).

- In this experiment, the title of the data table can be written as EFFECT OF COLOR OF SODA ON THE CHOICE OF ALLISON'S FRIENDS.

- The independent variable is the manipulated or changed variable, which is the COLOR OF SODA in this case.

- The dependent variable is the variable that is measured in an experiment, which is the NUMBER OF FRIENDS THAT CHOSE EACH SODA in this case.

Answer:

The figure is a molecule and a compound

Explanation:

Because it have 2 cluster molecules

Answer:

An energy transformation is the change of energy from one form to another. Energy transformations occur everywhere every second of the day. There are many different forms of energy such as electrical, thermal, nuclear, mechanical, electromagnetic, sound, and chemical.

Explanation:

Answer:

1) 1/√K

2) 1/K

3) √K

Explanation:

As general rules of operation of equilibrium constants:

For the reaction:

A + B ⇄ C + D; Equilibrium constant = K

C + D ⇄ A + B; K' = 1/K

2A + 2B ⇄ 2C + 2D; K'' = K²

Thus, as equilibrium constant of:

2CO2 + 4H2O ⇄ 2CH3OH + 3O2

Is K:

1) CH3OH + 3/2 O2 ⇄ CO2 + 2H2O

K' = 1 / K^(1/2) = 1/√K

2) 2CH3OH + 3O2 ⇄ 2CO2 + 4H2O

K' = 1/K

3) CO2 + 2H2O ⇄ CH3OH + 3/2 O2

K' = K^(1/2) = √K

Answer:

See explanation

Explanation:

a) A large value of K shows that the reaction is product favoured. It implies that more reactants are converted to products and the equilibrium concentration of products in the system is far higher than that of the reactants. The reaction will proceed towards the right hand side.

b)A small value of K implies that the reaction is reactant favoured. There are more reactants than products present at equilibrium and the reaction will proceed towards the lefthand side.

c) K=1 implies the presence of a significant concentration of reactants and products in the system at equilibrium.

Answer:

N,N-dimethylacetamide < Methyl acetate < Acetaldehyde

Acetaldehyde - least acidic

Methyl acetate -  acidic

N,N-dimethylacetamide - most acidic

Explanation:

The order of acidity of the organic compound under study is primarily influenced by their resonance effect. The resonance effect explains how polar a particular molecule is from the interaction between pi -bonds or a lone electron pair and a pi-bond in a molecule.

In acetaldehyde popularly known as ethanal, the CH₃CHO functional group -CHO is attached to an adjacent end of the compound, which has a lesser resonance effect than methyl acetate.

Methyl acetate, also known as methyl ethanoate, is an ester family with the formula CH₃COOCH₃ is also lesser in its acidity compared to N,N-dimethylacetamide.

Therefore, the order of acidity from the least acidic to the most is:

N,N-dimethylacetamide < Methyl acetate < Acetaldehyde

Acetaldehyde - least acidic

Methyl acetate - acidic

N,N-dimethylacetamide - most acidic