Pretty sure the answer is D.
Someone plz help me
Answer:
maybe falling
Explanation:
Air is a force so its probably pushing down the object then making it fall
I think all objects? Not entirely sure.
true/false. "introduction to general, organic, and biochemistry" by sally solomon
The statement: The claim that "Introduction to General, Organic, and Biochemistry" by Sally Solomon is a real book is: false.
How can we determine the falseness of the claim that "Introduction to General, Organic, and Biochemistry" by Sally Solomon is a real book?The statement that "Introduction to General, Organic, and Biochemistry" by Sally Solomon is a genuine book is not true. It is important to be cautious of false information and ensure the reliability of sources when seeking knowledge. In this case, the book mentioned does not exist in reality and should not be considered a valid reference. It is crucial to critically evaluate the authenticity of sources and verify the credibility of information presented.
Relying on reputable academic textbooks, peer-reviewed journals, and trustworthy educational websites is essential to ensure accurate understanding of subjects like chemistry. By doing so, we can maintain the integrity and credibility of our research and avoid spreading misinformation.
Therefore, the correct answer is: False.
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A 1.00 L volume of gas at 35.0 °C exerts a pressure of 85.5 kPa. What will the pressure
be at 127 °C? Assume constant volume.
Answer:
111.03kPa = P₂
Explanation:
Gay Lussac's Law states that the pressure of a gas is directly proportional to the absolute temperature when volume remains constant.
The equation is:
P₁T₂ = P₂T₁
Where P is pressure and T absolute temperature of 1, initial state and 2, final state of the gas.
P₁ = 85.5kPa
T₂ = 127°C + 273.15 = 400.15K
P₂ = ?
T₁ = 35°C + 273.15 = 308.15K
P₁T₂ = P₂T₁
85.5kPa*400.15K = P₂*308.15K
111.03kPa = P₂Collision theory states that when two molecules collide with each other with sufficient energy and hit in the proper orientation, a
bond is formed. Which action will increase the rate of reaction in a closed container?
A)
adding an inert gas
B)
expand the volume
C)
increase the temperature
D
decrease the concentration
Answer:
c increase the temperature
Explanation:
Can anyone tell me what the answer is?
Answer: c) A. 5.606x10²³atoms is the correct answer.
Explanation:
2LiBr Pb(NO3)
2 → PbBr2 2LiNO3
IBNEED HELP ASAP
NO BULL I NEED ACTUAL HELP
Answer:
god says dont use any assault language okay?
Explanation:
What is the potential energy of a rollercoaster if it weighs 1565 kg and sits on a 115 m tall ride?
Answer:
Explanation:
Potential energy builds as the coaster is going up the loop-the-loop and converts to kinetic energy on the way down and out of the loop-the-loop. The potential energy of the coaster is at its lowest and the kinetic energy is at its highest as the coaster moves in the lowest point of the loop-the- loop.
Calculate the molar mass of a solute in a 1.30 L solution with of 0.50 M
containing 10.5 g of the solute.
Answer: 16 g/mol
Explanation: Molarity is Moles/Liters or Mol/L
(0.50 mol/L)(1.30L) = 0.65mol
(cancels out L)
Molar mass is g/mol so...
10.5g/0.65mol = 16.1 g/mol
Rounded to 2 sig figs is 16 g/mol
For which of the following equations would the value of Kp = Kc(RT)? Note Kc is sometimes called K.
A. A (g) + 2B (s) = C(s) + 2 D (g)
B. 2 NO₂ (g) = N₂O. (g)
C. 2 NBr. (g) = N₂ (g) + 3 Br₂ (g)
D. 2 HI (g) H₂(g) + 12 (g)
The equation for which the value of
Kp = Kc(RT) is valid is B.
2 NO₂(g) ⇌ N₂O₄(g).
The equilibrium constant (Kc) for the forward reaction is the ratio of the product of the concentration of the products to the product of the concentrations of the reactants, with each concentration raised to the power corresponding to the number of moles of that substance in the balanced chemical equation.
The expression for Kc is as follows:
Kc = [C]c [D]d/[A]a [B]b
Where [ ] represents the concentration of each substance in moles per liter and a, b, c, and d are the coefficients in the balanced chemical equation, as shown above.
Thermodynamic equilibrium constant is denoted by Kp. If we use the ideal gas law, we can link Kp and Kc as follows:
Kp = Kc(RT)ⁿ
where R is the ideal gas constant, T is the temperature in Kelvin, and n is the number of moles of gaseous product minus the number of moles of gaseous reactant.
For the equation,
2 NO₂(g) ⇌ N₂O₄(g)
we can see that the products and reactants are in gas phase.
Hence, the value of
Kp = Kc(RT)
is valid for this equation.
Answer: B. 2 NO₂(g) ⇌ N₂O₄(g)
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Sam is about to drop a golf ball from his hand.
Get ready, you should catch it.
Answer:
As an object falls, its gravitational potential energy decreases as its speed—and therefore its kinetic energy—increases.
Explanation:
Study Island
What conditions apply to masses mA and ms for the acceleration to be in one direction (nay, ma down the plane), or in the opposite direction? Check all that apply 0 mA > m sin (mA up the plane) Determine a formula for the acceleration of the system in terms of mA, mp. 0, and 9. Ignore the mass of the cord and pulley, Express your answer in terms of the variables mA, mp.0, and g. mB9-mAgsine mBmA Previous Answers ✓ Correct Constants / Periodic Ta What conditions apply to masses mA and mB for the acceleration to be in one direction (say, mA down the plane), or in the opposite direction? Check all that apply. O mA > mosin 0 (mA up the plane) masinº < mb (mA up the plane) MA> msin 0 (ma up the plane) mA< MB (mA down the plane) MA > MB (mA down the plane) mA> mB sine (mA down the plane) Ain 0 > MB (mA up the plane) m > mB (mA up the plane) MA< MB (mA up the plane) masin > mA down the plante) OMA > msin ma down the plane) Asin mar de te plane) Submit
The conditions that apply to masses mA and mB for the acceleration to be in one direction (say, mA down the plane), or in the opposite direction are as follows:
1. mA > mB sine (mA down the plane)
2. mB9-mAg sine mBnA
The conditions that apply to masses mA and mB for the acceleration to be in one direction (say, mA down the plane), or in the opposite direction are as follows:
1. mA > mB sine (mA down the plane)
2. mB9-mA gsine mBnA
When the value of mass mA is greater than mB sine (mA down the plane), the acceleration is in one direction.
When mB9-mAgsine mBmA is greater, the acceleration is in the opposite direction.
Determine a formula for the acceleration of the system in terms of mA, mp.0, and 9.
Ignore the mass of the cord and pulley, Express your answer in terms of the variables mA, mp.0, and g.
The formula for acceleration of the system in terms of mA, mp, 0 and 9 is given below;
a = (mB-mAsinθ)/(mA + mB + m0) * g
Where,
θ = angle of inclination of the plane.
g = acceleration due to gravity.
mA = mass of object A.
mB = mass of object B.
m0 = mass of the pulley and cord.
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Balance the following equation
_MgF2 + _Li2CO3 -> _MgCO3 + _LiF
Answer:
1 MgF2 + 1 Li2CO3 --> 1 MgCO3 + 2 LiF
Explanation:
Drag and drop each trait to the name it describes.
Kim
Understands gardening
Wendell
Gonzalo
Learn English quickly
Is determined and strong
Can be impatient
Tries new things easily
Helps his family survive
Answer:
Kim:
Is determined and strong Tries new things easilyWendell:
Can be impatient Understands gardeningGonzalo:
Learns English quickly Helps his family surviveExplanation:
did it on Edge.
a 20.00 ml sample of 0.150 m hf solution is titrated with 0.250 m naoh. (ka hf = 7.2 x 10-4)
At 25% and 50% neutralization, the pH remains the same, approximately 3.14. At 100% neutralization, the pH increases significantly to approximately 12.70 due to the hydrolysis of the resulting salt NaF.
To solve this problem, we'll consider the reaction between HF and NaOH. HF is a weak acid and NaOH is a strong base. The reaction can be written as follows:
HF + NaOH → NaF + H₂O
Given that the initial concentration of HF is 0.150 M and the concentration of NaOH is 0.250 M, we'll use the stoichiometry of the reaction to determine the concentrations of HF and NaOH at different stages of neutralization.
A. When neutralization is 25% complete:
25% of the HF will react with NaOH, which means 75% of the HF remains. Since the reaction between HF and NaOH is 1:1, the concentration of HF remaining will be 0.150 M * 0.75 = 0.1125 M. The concentration of NaOH consumed will be 0.250 M * 0.25 = 0.0625 M.
To calculate the pH at this stage, we need to consider the dissociation of HF. HF dissociates as follows:
HF ⇌ H⁺ + F⁻
The Ka of HF is given as 7.2 x 10⁻⁴. We'll assume that the concentration of F⁻ is negligible compared to the concentration of HF.
Using the Ka expression, we can calculate the concentration of H⁺:
Ka = [H⁺][F⁻] / [HF]
7.2 x 10⁻⁴ = [H⁺][0.1125 M] / [0.1125 M]
[H⁺] = 7.2 x 10⁻⁴ M
Therefore, the pH at 25% neutralization is approximately -log(7.2 x 10⁻⁴) = 3.14.
B. When neutralization is 50% complete:
50% of the HF will react with NaOH, which means 50% of the HF remains.
The concentration of HF remaining will be 0.150 M (0.50) = 0.075 M.
The concentration of NaOH consumed will be 0.250 M (0.50) = 0.125 M.
Using the same Ka expression as before, we can calculate the concentration of H⁺:
Ka = [H⁺][F⁻] / [HF]
7.2 x 10⁻⁴ = [H⁺][0.075 M] / [0.075 M]
[H⁺] = 7.2 x 10⁻⁴ M
Therefore, the pH at 50% neutralization is approximately -log(7.2 x 10⁻⁴) = 3.14.
C. When neutralization is 100% complete:
At this point, all of the HF has reacted with NaOH, resulting in the formation of NaF and water. The concentration of HF is zero, and the concentration of NaF is equal to the concentration of NaOH consumed, which is 0.250 M (0.2000 L) = 0.050 M.
Since NaF is a salt of a strong base and a weak acid, it will hydrolyze to produce F⁻ ions and a small number of OH⁻ ions. The concentration of F⁻ will be 0.050 M, and the concentration of OH⁻ will be negligible compared to F⁻.
The solution will be basic due to the presence of F⁻ ions. The pH can be calculated from the pOH:
pOH = -log[OH⁻]
pOH = -log(0.050) ≈ 1.30
pH = 14 - pOH = 14 - 1.30 ≈ 12.70
Therefore, when neutralization is 100% complete, the pH is approximately 12.70.
At 25% and 50% neutralization, the pH remains the same, approximately 3.14. This indicates that the solution is buffered due to the presence of the weak acid HF and its conjugate base F⁻. However, at 100% neutralization, the pH increases significantly to approximately 12.70 due to the hydrolysis of the resulting salt NaF. The solution becomes basic at this point.
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Burning a candle melts the wax, but also burns the wick. Explain how burning a candle involves both physical and chemical changes.
Answer:
Burning of the candle is both physical and chemical change. Burning of the candle melts the wax and hence physical state of wax has changed from solid to liquid.
Again the wax combines with the atmospheric oxygen and changes to carbon dioxide, heat and light.
Thus both the changes are accompanied by the burning of the candle.
Explanation:
hope this helps!
~mina
Weight is the measure of gravity on an object measured by a weight in Newtons. Weight changes if gravitational force changes.
Mass is the amount of kilogram in an object measured by a __________ in grams and does not change…it stays the _________.
Mass is an intrinsic property of matter and is measured in kilograms. The mass of a bird is a constant. A 15-gram bird is 15 grams, whether measured on the Earth, the Moon, or Mars. Weight is a measure ofthe force of gravity on a physical object and is measured in newtons.
What do all electrolytes have in common?
They have low melting points.
They are polar molecules.
They have mobile ions in solution.
They are compounds of carbon.
Which element is in the lanthanide family?
Answer:
The 15 elements, together with their chemical symbols, are lanthanum (La)
Answer:
PM Promethium
Explanation:
9 moles of Ammonia (NH3) are added to 50 L of H2O at a temperature of 29°C. The vapor pressure of water alone is 29.96 mmHg at 29°C. What is the vapor pressure of the Ammonia solution?
Answer: The vapor pressure of the solution at [tex]29^0C[/tex] is 29.86 mm Hg
Explanation:
As the relative lowering of vapor pressure is directly proportional to the amount of dissolved solute.
The formula for relative lowering of vapor pressure will be,
[tex]\frac{p^o-p_s}{p^o}=i\times x_2[/tex]
where,
[tex]\frac{p^o-p_s}{p^o}[/tex]= relative lowering in vapor pressure
i = Van'T Hoff factor = 1 (for non electrolytes)
[tex]x_2[/tex] = mole fraction of solute
=[tex]\frac{\text {moles of solute}}{\text {total moles}}[/tex]
Given : 9 moles of [tex]NH_3[/tex] are dissolved in 50 L or 50000 ml of water
mass of water = [tex]density\times volume = 1g/ml\times 50000ml=50000g[/tex]
moles of solvent (water) = [tex]\frac{\text{Given mass}}{\text {Molar mass}}=\frac{50000g}{18g/mol}=2778moles[/tex]
Total moles = moles of solute + moles of solvent = 9 mol + 2778 mol = 2787
[tex]x_2[/tex] = mole fraction of solute
=[tex]\frac{9}{2787}=3.2\times 10^{-3}[/tex]
[tex]\frac{29.96-p_s}{29.96}=1\times 3.2\times 10^{-3}[/tex]
[tex]p_s=29.86mmHg[/tex]
Thus the vapor pressure of the solution at [tex]29^0C[/tex] is 29.86 mm Hg
some solution splashes on the lab bench when pouring the solution into the buchner funnel during vacuum filtration. the mass of precipitate data value will be __ the actual value.
If some solution splashes on the lab bench when pouring the solution into the buchner funnel during vacuum filtration, the mass of precipitate data value will be less than the actual value
How to determine the massWhen solution splashes onto the lab bench, some of the precipitate may be lost, resulting in a lower amount of collected precipitate in the Buchner funnel than expected.
This loss leads to a lower mass measurement when compared to the actual value if no solution had splashed. Therefore, the mass of precipitate data value will be less than the actual value.
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Hey Friends Can Yall Help Me Show Ya Work And Don’t Comment No B.S Cause Yu Will Get Cursed Out
What would cause entropy to increase in a reaction?
A. The products becoming more spread out
B. The products forming an ordered pattern
C. The products forming fewer molecules
D. The products forming a more rigid structure
i think A but if I'm wrong sorry
then if increasing then becoming spread out so letter A
ClO3−
Draw the molecule by placing atoms on the grid and connecting them with bonds. Include all lone pairs of electrons. Show the formal charges of all atoms in the correct structure.
The molecule ClO₃⁻ consists of one chlorine atom (Cl) and three oxygen atoms (O), with a negative charge (⁻) on the molecule.
The molecule ClO₃⁻ consists of one chlorine atom (Cl) and three oxygen atoms (O), with a negative charge (⁻) on the molecule.
The chlorine atom (Cl) is in the center, bonded to one oxygen atom (O) through a single bond and to the other two oxygen atoms (O) through double bonds. Each oxygen atom (O) has two lone pairs of electrons around it.
When all the electrons of an atom are shared equally, the charge attained by the atom is known as a formal charge.
The formal charge can be calculated as:
Formal charge =
valence electron - non-bonding electron - bonding electron/2
In the molecule, the formal charge of Oxygen = -1.
In the molecule, the formal charge of Chlorine = +2
The oxygen atom has 8 electrons, in which 2 are shared in the bond formation, and 6 electrons are valence electrons.
The chlorine atom has 7 valence electrons in which 6 electron pairs are shared with the oxygen atom, and 1 lone pair has been available with Cl.
The structure of molecule ClO₃⁻ has been given in the image attached. The image shows the available lone pairs and the bonding in the structure.
Thus, the molecule has a formal charge of -1 on all oxygen atoms, and +2 on the Cl atom.
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Question 3 (1 point)
Which option correctly ranks the states of matter from slowest to fastest particle
speed.
1. gas, liquid, solid
2. solid, liquid, gas
3. solid, gas, liquid
4. gas, solid, liquid
.Which statement is not true or the dissolution of ZNCO3 (s) in acid:
1. The dissolution of ZnCO3 is facilitated by the formation of a weak acid
2. The dissolution of ZNCO3 is facilitated by the formation of a complex ion
3. The dissolution of ZNCO3 is facilitated by the evolution of a gas
4. The dissolution of ZNCO3 is facilitated by the decomposition of carbonic acid to CO2 and H20
The statement that is not true for the dissolution of ZnCO₃ (s) in acid is option 3: "The dissolution of ZnCO₃ is facilitated by the evolution of a gas."
When ZnCO₃ dissolves in acid, such as hydrochloric acid (HCl), several reactions occur. The true statements are:
1. The dissolution of ZnCO₃ is facilitated by the formation of a weak acid: In the presence of an acid, the carbonate ion (CO₃²⁻) reacts with H⁺ ions from the acid to form carbonic acid (H₂CO₃), which is a weak acid.
2. The dissolution of ZnCO₃ is facilitated by the formation of a complex ion: The Zn²⁺ ion from ZnCO₃ can form a complex with H₂O molecules or other ligands present in the solution.
4. The dissolution of ZnCO₃ is facilitated by the decomposition of carbonic acid to CO₂ and H₂O: Carbonic acid (H₂CO₃) decomposes into carbon dioxide (CO₂) and water (H₂O), releasing CO₂ gas.
Therefore, option 3 is not true because the dissolution of ZnCO₃ is not directly facilitated by the evolution of a gas, but rather by the formation of a weak acid, complex ion formation, and decomposition of carbonic acid.
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How would you prepare a 35 ml solution of 95% (volume/volume solution of ethanol?
Explanation:
Solutions. 1. If 47 g of KCl dissolved in enough water to give 375 mL of soloution, what is the molarity ... vo volume of solute . ... v/v ethanol, how much 95% v/v ethanol ... prepare 200. mL ...
Mesitylene is a liquid hydrocarbon. Burning 0.115 g of the compound produces 0.379 g of CO2 and 0.1035 g of water. Find the empirical formula of mesitylene. This is a combustion reaction. All the carbon in the CO2 produced comes from the sample. All the hydrogen in the water produced comes from the sample. Hydrocarbons are binary compounds, made only of carbon and hydrogen.
The empirical formula is C3H4.
The empirical formula of mesitylene can be found using the data provided in the problem statement.Let's write the balanced combustion reaction for mesitylene first:2 C9H12 + 25 O2 → 18 CO2 + 12 H2OThe molar mass of the compound (C9H12) can be calculated as follows:9 moles of carbon × 12 g/mol = 108 g/mol12 moles of hydrogen × 1 g/mol = 12 g/molMolar mass of the compound = 108 + 12 = 120 g/molThe amount of CO2 produced is 0.379 g and the amount of H2O produced is 0.1035 g.Moles of CO2 produced = 0.379 g / 44 g/mol = 0.0086 molesMoles of H2O produced = 0.1035 g / 18 g/mol = 0.00575 molesUsing the balanced chemical equation, we can calculate the moles of C9H12 required to produce these amounts of CO2 and H2O. Since we know that the ratio of carbon to water in the compound is 9:12, we can determine the number of moles of each element present in the compound.Moles of C9H12 required = (0.0086 mol CO2 × 2 mol C9H12) / 18 mol CO2 = 0.00096 mol C9H12Moles of carbon = 0.00096 mol C9H12 × 9 mol C / mol C9H12 = 0.00864 mol C9H12Moles of hydrogen = 0.00575 mol H2O × 2 mol H / mol H2O = 0.0115 mol HUsing the mole ratios, we can find the empirical formula:Moles of carbon = 0.00864 mol C9H12 × (1 mol / 0.00864 mol) = 1 mol C9H12Moles of hydrogen = 0.0115 mol H / 0.00864 mol = 1.33 mol H9 carbon atoms and 12 hydrogen atoms are present in one molecule of C9H12. To convert this to an empirical formula, we need to divide by the greatest common factor (GCF), which is 3. Therefore, the empirical formula is C3H4.
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What number and types of atoms occur in a formula unit of
Ca(NO3),?
Answer:
help with mine ill help with yours
Answer:
1 calcium atom, 2 nitrogen atoms, and there are 6 oxygen atoms
Explanation:
Express your answer in complete form in the order of orbital filling as a string without blank space between orbitals. For example, 1s 22s 2 should be entered as 1s 228 2.
To answer the question, it is important to have an understanding of the order of orbital filling.
The order of orbital filling describes the order in which electrons occupy orbitals.
This order can be determined using the aufbau principle, which states that electrons will occupy the lowest-energy orbital available.
The order of orbital filling is as follows: 1s 2s 2p 3s 3p 4s 3d 4p 5s 4d 5p 6s 4f 5d 6p 7s 5f 6d 7p
Therefore, the complete form of the order of orbital filling, without blank spaces between orbitals, is:1s2s2p3s3p4s3d4p5s4d5p6s4f5d6p7s5f6d7p
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