The ______ of a function is the complete set of inputs, whereas the _______ is the set of all outputs​

Step-by-step explanation:

then put x valule into KL equation

Answer:

when x goes opposite side of equals to sign of x changes and same goes with 4 then x=5+4 then the answer will be 9

Answer:

$220 is the amount of simple interest you will earn

Step-by-step explanation:

I = p * r * t

Principle = $2000

Rate = 5.5% (you need to change this to a decimal by dividing by 100) or

         0.055

Time = 2 years

I = 2000 * 0.055 * 2

I = $220

Answer: 6/11

Work Shown:

22 people total, 10 men, so 22-10 = 12 women are in the class.

12/22 = (2*6)/(2*11) = 6/11 is the fraction of women in the class

Answer:

I'm pretty sure the answer they want is 12/22 or 6/11 students are women although some people are not men or women which technically makes the question impossible to solve.

Answer:

There are 35 adult dogs and 20 puppies

Step-by-step explanation:

Represent the puppies with P and the Adult dogs with A

Given

[tex]A : P = 7 : 4[/tex]

Dogs = 55

Required

Determine A and P

First, we need to sum the ratios;

[tex]Total = A + P[/tex]

[tex]Total = 7 + 4[/tex]

[tex]Total = 11[/tex]

Adult Dogs is then calculated as follows;

[tex]A = \frac{A\ Ratio}{Total} * Dogs[/tex]

[tex]A = \frac{7}{11} * 55[/tex]

[tex]A = \frac{385}{11}[/tex]

[tex]A = 35[/tex]

Puppies is calculated by subtracting the number of adult dogs from the total

[tex]P = Dogs - Adult\ Dogs[/tex]

[tex]P = 55 - 35[/tex]

[tex]P = 20[/tex]

Hence;

There are 35 adult dogs and 20 puppies

Answer:

x=(-9)

PQ=2

PR=3

Step-by-step explanation:

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Answer:

x=1

Step-by-step explanation:

Anytime there is a vertical line, the y value becomes infinite as the line goes on forever. The only restriction on the line is on the x value of your coordinate. The same goes for a horizontal line, only the x value would become infinite and the y value would be constant.

Vertical Line: (x,∞)

Horizontal Line: (∞,y)

Answer:

The displacement of the object on this intervals is 1.33 m.

Step-by-step explanation:

Given that,

The function of velocity is

[tex]v=\dfrac{1}{2t+4}\ m/s[/tex]

For 0 ≤ t ≤8 , n = 2

We need to calculate the intervals

Using formula for intervals

For, n = 1

[tex]\Delta x=\dfrac{t_{f}-t_{i}}{n}[/tex]

[tex]\Delta x=\dfrac{8-0}{2}[/tex]

[tex]\Delta x=4[/tex]

So, The intervals are (0,4), (4,8)

We need to calculate the velocity

Using given function

[tex]v=\dfrac{1}{2t+4}[/tex]

For first interval (0,4),

Put the value into the formula

[tex]v_{0}=\dfrac{1}{2\times0+4}[/tex]

[tex]v_{0}=\dfrac{1}{4}[/tex]

For first interval (4,8),

Put the value into the formula

[tex]v_{4}=\dfrac{1}{2\times4+4}[/tex]

[tex]v_{4}=\dfrac{1}{12}[/tex]

We need to calculate the total displacement

Using formula of displacement

[tex]D=(v_{0}+v_{4})\times(\Delta x)[/tex]

Put the value into the formula

[tex]D=(\dfrac{1}{4}+\dfrac{1}{12})\times4[/tex]

[tex]D=1.33\ m[/tex]

Hence, The displacement of the object on this intervals is 1.33 m.

The displacement of the object whose velocity function is given is 1.33 m

The given parameters are:

[tex]\mathbf{v = \frac{1}{2t + 4},\ 0 \le t \le 8; n =2}[/tex]

The end point of intervals is calculated as:

[tex]\mathbf{\triangle t = \frac{b - a}{n}}[/tex]

So, we have:

[tex]\mathbf{\triangle t= \frac{8 - 0}{2}}[/tex]

[tex]\mathbf{\triangle t = \frac{8}{2}}[/tex]

[tex]\mathbf{\triangle t= 4}[/tex]

So, the intervals are (0,4) and (4,8)

Calculate the velocity at the beginning of each interval

[tex]\mathbf{v_0 = \frac{1}{2(0) + 4} = \frac 14}[/tex]

[tex]\mathbf{v_4 = \frac{1}{2(4) + 4} = \frac 1{12}}[/tex]

Calculate the displacement (S) using:

[tex]\mathbf{S = (v_0 + v_4) \times \triangle t}[/tex]

So, we have:

[tex]\mathbf{S = (1/4 + 1/12) \times 4}[/tex]

Expand

[tex]\mathbf{S = 1 + 1/3}[/tex]

Add

[tex]\mathbf{S = 1 \frac 13}[/tex]

Express as decimals to 2 decimal places

[tex]\mathbf{S = 1.33}[/tex]

Hence, the displacement is 1.33 m

Read more about displacement at:

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Answer:

A

Step-by-step explanation:

Answer:

1/5

Step-by-step explanation:

I put it in a graphing calculator and converted it into a fraction

Answer:

Difference between upper and lower limits is : 1,816

Step-by-step explanation:

A CI (confidence interval ) for  t student distribution is:

( μ₀  - t(α/2)* s/√n  ;    μ₀  + t(α/2)* s/√n )

Where:

μ₀  is the mean and s the standard deviation of the dstribution

n size of the sample

CI = 90 %     means   α = 10 %    α = 0,1      α/2  = 0,05

and degree of freedom   df = n - 1   df = 40

From t student table we get:

tα/2  =  1,6839

Then:

t(α/2)* s/√n  =  1,6839* 3,41/√40

t(α/2)* s/√n  =  0,908

8,73 - 0,908   =  7,822

8,73 + 0,908  = 9,638

CI (90%)  =  ( 7,822  ;  9,638 )

Difference between upper and lower cut-offs points is:

Δ = 1,816

Answer:

x=3/8

Step-by-step explanation:

Steps to solve:

x^2 + 2x + 3 when x = 4

~Substitute

4^2 + 2(4) + 3

~Simplify

16 + 8 + 3

~Add

24 + 3

~Add

27

Best of Luck!

Answer:

3.5

Step-by-step explanation:

total pretzel=10 1/2 or10.5

no. of brother = 3

now,

10.5 pretzel for each borther= 10.5/3

=3.5 ans

Answer:

- 5

Step-by-step explanation:

Step 1:

4 ( 2y + 1 ) = 2 ( y - 13 )

Step 2:

8y + 4 = 2y - 26

Step 3:

6y + 4 = - 26

Step 4:

6y = - 30

Answer:

y = - 5

Hope This Helps :)

Answer:

Rs.15

Step-by-step explanation:

3% = 3/100 × 500 = 15

Answer:45

Step-by-step explanation:

[9(7-3)+13]-[11-(6+9)]

[9(4)+13]-[11-(15)]

[36+13]-[4]

49-4

45

Answer: The answer is 53

Answer:

11

Step-by-step explanation:

Answer:

5

Step-by-step explanation:

Since, A, B, C, D are collinear.

[tex] \implies A - B - C - D \\

\therefore \: AD = (AB + BC) + CD \\ \therefore \: 18 = AC + CD.. (\because AB + BC =AC) \\ \therefore \: 18 = 8 + CD \\ \therefore \: 18 - 8 = CD \\ \therefore \: 10 = CD \\ \\ \because \: BC + CD = BD \\ BC = BD - CD \\ BC = 15 - 10 \\ BC = 5 \\ [/tex]

Answer:

y=400h

Where y is distance and h is time.

Answer:

complementary

Step-by-step explanation:

yes

The word that describes their measures of ∠1 and ∠2 is: complementary.

Recall:

From the information given, we know that:

m∠1 and m∠2 forms a right angle.

Since a right angle = 90 degrees, therefore:

m∠1 + m∠2 = 90° (complementary)

Therefore, the word that describes their measures of ∠1 and ∠2 is: complementary.

Learn more about complementary angles on:

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Answer:

Step-by-step explanation:

Answer:

Step-by-step explanation:

Hello,

[tex](goh)(x)=g(h(x))=2\left( \sqrt{x^2+1}\right)^2=2(x^2+1)\\\\x=(goh)((goh)^{-1}(x))=2((goh)^{-1}(x)^2+1)\\ \\\left((goh)^{-1}(x)\right)^2=\dfrac{x}{2}-1=\dfrac{x-2}{2}\\ \\(goh)^{-1}(x)=\sqrt{\dfrac{x-2}{2}}[/tex]

And this is a function defined for x-2 [tex]\geq[/tex] 0, meaning x [tex]\geq[/tex] 2

Thanks

Answer:

c

Step-by-step explanation:

They are not commutative because the domains of f(x) and g(x) are different.

The functions  [tex]f(x) = x^{3}[/tex] and [tex]g(x) = \frac{1}{x^{3} }[/tex] are not commutative because domains of f(x) and g (x) are different.

Here,

The functions are [tex]f(x) = x^{3}[/tex] and [tex]g(x) = \frac{1}{x^{3} }[/tex] and graph of the function are shown in figure.

We have to check the function are composite or not.

What is Domain of function?

The domain of a function is the set of all possible inputs for the function.

Now,

Domain of function  [tex]f(x) = x^{3}[/tex] is ( -∞, ∞).

And, Domain of function [tex]g(x) = \frac{1}{x^{3} }[/tex] is ( -∞,0 ) U ( 0, ∞).

Hence, the domain of the functions are different so they are not commutative.

So, The functions  [tex]f(x) = x^{3}[/tex] and [tex]g(x) = \frac{1}{x^{3} }[/tex] are not commutative because domains of f(x) and g (x) are different.

Learn more about the Domain of function visit:

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Answer:

D:{x∈R}

R:{y∈R}

Step-by-step explanation:

This is just a linear function. I know this because the degree of the x-variable is 1.

Domain and range are sets of possible values the function can have - though not necessarily at the same time.

Thus, there are no restrictions to the domain and range unless context is given.

Therefore, the domain and range is:

D:{x∈R}

R:{y∈R}