What is the value of the expression when y = 2? StartFraction 2 minus y Over 4 plus y EndFraction plus StartFraction 3 (y plus 2) Over y EndFraction

Answer: B.  |x-100| = 25

Explanation:

Draw out a number line. Mark 75, 100 and 125 on the number line as points A, B, and C in that order. Don't worry about the spacing.

The value of x represents where the train is. So if we had say x = 85, then it would be at location 85 on the number line. Writing |x-100| is the distance from x to 100. The absolute value ensures the distance is never negative. We want this distance to be 25 because after traveling 25 cm, the switch is turned, and the train goes the other way.

The equation which models the movement of the train is represented by |x − 100| = 25. The correct option is B.

One-variable linear equation The equation for a linear equation in one variable is written as ax+b = 0, where a and b are two integers, and x is a variable. This equation has only one solution. For instance, the linear equation 2x+3=8 only has one variable.

The train's location is indicated by the value of x. Therefore, if x were to equal, let's say, 85, it would be at position 85 on the number line.

The distance between x and 100 is expressed as |x-100|. The distance will never be negative thanks to the absolute value. Because the switch is switched after the train has traveled 25 cm in one direction, we need this distance to be 25 cm.

Therefore, the equation which models the movement of the train is represented by |x − 100| = 25. The correct option is B.

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Answer:

y - x = 69

Step-by-step explanation:

From the figure attached,

Number in each block is the sum of the numbers in the block beneath it.

Therefore, A + 21 = 32 ⇒ A = 11

A + 5 = B ⇒ B = 16

C = 5 + x

D = 32 + B ⇒ D = 32 + 16 = 48

E = B + C ⇒ E = 16 + (5 + x)

               ⇒ E = 21 + x

y = D + E ⇒ y = 48 + (21 + x)

                   y = 48 + 21 + x

                   y = 69 + x

              y - x = 69

Therefore, y - x = 69 will be the answer.

If 2x+7>=0, x>=-3.5 then |2x+7|=2x+7.

Then the inequality becomes:

2x+7>23, 2x>16, x>8.(which is an acceptable result since we already assumed x>=-3.5)

If 2x+7<0, x<-3.5 then |2x+7|= -(2x+7).

Then the inequality becomes:

-(2x+7)>23, 2x+7<-23, 2x <-30, x<-15.

(which is an acceptable result since we already assumed x<-3.5)

Thus the answer is x<-15 or x>8.

The graph is simple. You draw the line of real numbers and "shadow" all numbers above 8 and all numbers bellow - 15.

Answer:

- Decreasing  

Step-by-step explanation:

im not sure of the last two but the others are for sure a no

Answer:

Personal finance

Step-by-step explanation:

Personal finance is a technical term in which a person or group of persons pool resources together for the purpose of budgeting, saving, or spending as they deem fit.

Money in Mark's saving account that he used as a down payment for his car is an example of personal finance.

Step-by-step explanation:

Identify the method that will be used to solve for x for each equation.

4x=20 division property  fo equality

x-11=9 addition property of eqaulity

5x+6x=22 Combining Like terms

5(x-2)=30 distibute property

Answer:

ello

Step-by-step explanation:

Identify the method that will be used to solve for x for each equation.

4x=20 division property  fo equality

x-11=9 addition property of eqaulity

5x+6x=22 Combining Like terms

5(x-2)=30 distibute property

Answer:

Height = 1 inch

Step-by-step explanation:

area of triangle = 1/2 x base x height

       11.5 =1/2 x 23 x height

       23/23 = height

       height = 1

h = 1 inches

The area of a triangle = formula

A = b×h/2

2A = b×h

h = 2A/b

h = 2×11.5in²/23in

= 23in²/23in

= 1 in

Answer:

r = 1.4 %

Step-by-step explanation:

given p(principle) is 1,375$, r(interest rate) is unknown, t(time in years) is 2, and I(Interest / final balance) is 37.10$. The simple interest formula: I = prt can be rewritten as: r = I/pt to solve for r. 37.1 / ( 1325 × 2 ) = 37.1 / 2650 = 0.014 = ( 0.014 * 100 ) % = 1.4 %

Step-by-step explanation:

The outlier is excluded, so the minimum is 59.

5. Tania earns $13.50 per hour at the Glendale Florist. She regularly works 40 hours per week. She is paid time-and-a-half for each hour of overtime work. Last week she worked. 43 hours. What was her gross pay for the ...

Missing: michael ‎| Must include: michael

Answer:

31.8

Step-by-step explanation:

24.67x129

=>31.82

=>31.8

Answer:

x = 17

Step-by-step explanation:

4x +22 = 90

4x = 68

x = 68/4

x = 17

Answer:

16.6666666667

Step-by-step explanation:

Answer:

16 2/3

Step-by-step explanation:

Step 1:

5/1 ÷ 3/10

Step 2:

5/1 × 10/3

Step 3:

50/3

Answer:

16 2/3

Hope This Helps :)

Answer:0

Step-by-step explanation: took the quiz

Answer:

515.25 is what she got left

Step-by-step explanation:

Answer: Divide Kayak budget by rental rate

Step-by-step Explanation:

As Joshua is renting for himself alone, the two available options would be the Single Kayak and the Single Sea Kayak.

He can determine the number of hours to rent a Kayak for by dividing his Kayak Budget by the rental rate per hour of the 2 options available to him.

Budget available = $50

Rental rate = $15 per hour

Hours he can rent = 50/15

= 3.33 hours

Budget available = $50

Rental rate = $18 per hour

Hours he can rent = 50/18

= 2.78 hours

Answer:

No

Step-by-step explanation:

t the two equations for the lines into slope-intercept form. ...

Set the two equations for y equal to each other.

Solve for x. ...

Use this x-coordinate and plug it into either of the original equations for the lines and solve for y.

Answer:

m=4

best of luck!

Step-by-step explanation:

Answer:

m=4

Step-by-step explanation:

6+4m-1=21

(6-1=) 5+4m=21

21-5=16

16÷4m = 4

Answer:

no

Step-by-step explanation:

hope this helps

Answer:

Following are the solution:

Step-by-step explanation:

Given equation:

[tex]\frac{dx}{dy}= \frac{y(y-2)}{2}........(a)[/tex]

[tex]\Phi (x) = \frac{2}{1-ce^x}[/tex]

In the question [tex]\Phi (x)[/tex], is a solution of the equation (a) only if when [tex]\Phi (x)[/tex]satisfies equation (a):

let us find [tex]\Phi' (x)[/tex]:-

[tex]\Phi(x) =\frac{d}{dx} \Phi (x)=\frac{d}{dx}(\frac{2}{1-ce^x})[/tex]

                        [tex]= 2 \frac{d}{dx}({1-ce^x}^-1)\\\\= 2 (-1) ({1-ce^x})^{-2} \frac{d}{dx}({1-ce^x})\\\\= -2 ({1-ce^x})^{-2} (-ce^x})\\\\= 2(-ce^x) ({1-ce^x})^{-2} \\\\[/tex]

Now:

[tex]\frac{dy}{dx}=\frac{y(y-2)}{2}\\\\\frac{d}{dx}\Phi (x) =\frac{\Phi (x) (\Phi (x)-2)}{2}\\[/tex]

by subtracting the value of [tex]\Phi (x)[/tex]and [tex]\frac{d}{dx}[/tex][tex]\Phi (x)[/tex],we get:

[tex]\to[/tex][tex]2ce^x(1-ce^x)^-2= \frac{(\frac{2}{1-ce^x})(\frac{2}{1-ce^x})^{-2}}{2}[/tex]

[tex]=2ce^x (1-ce^x)^{-2}=\frac{1}{2}[\frac{2}{1-ce^x}(\frac{2-2(1-ce^x)}{1-ce^x)}]\\\\= \frac{1}{1-ce^x} \times \frac{2ce^x}{1-ce^x}\\\\=\frac{2ce^x}{(1-ce^x)^2}\\\\=2ce^x (1-ce^x)^-2[/tex]

[tex]\bold{2ce^x(1-ce^x)^-2=2ce^x(1-ce^x)^-2}[/tex]

[tex]\Phi (x)[/tex] the solution of the given equation. [tex]\Phi (x)[/tex] has one Parameter Family of

[tex]\frac{dy}{dx}=\frac{y(y-2)}{2}[/tex]

[tex]\Phi (x) =\frac{2}{1-ce^x}\\\\_{when} \ \ \ c= 0 \to \Phi (x) =\frac{2}{1-0\times e^x}=2\\\\_{when} \ \ \ c= 1 \to \Phi (x) =\frac{2}{1-1\times e^x}=\frac{2}{1-e^x}\\\\_{when} \ \ \ c= -1 \to \Phi (x) =\frac{2}{1-(-1)\times e^x}=\frac{2}{1+e^x}\\\\_{when} \ \ \ c= 2 \to \Phi (x) =\frac{2}{1-(-2)\times e^x}=\frac{2}{1-2e^x}\\\\_{when} \ \ \ c= -2 \to \Phi (x) =\frac{2}{1-(-2)\times e^x}=\frac{2}{1+2e^x}\\\\[/tex]

Answer:

x = 2/5

Step-by-step explanation:

Solve for x:

x/3 + 2/3 = 2 x

Hint: | Combine x/3 + 2/3 into a single fraction.

x/3 + 2/3 = (x + 2)/3:

(x + 2)/3 = 2 x

Hint: | Make (x + 2)/3 = 2 x simpler by multiplying both sides by a constant.

Multiply both sides by 3:

(3 (x + 2))/3 = 3×2 x

Hint: | Cancel common terms in the numerator and denominator of (3 (x + 2))/3.

(3 (x + 2))/3 = 3/3×(x + 2) = x + 2:

x + 2 = 3×2 x

Hint: | Multiply 3 and 2 together.

3×2 = 6:

x + 2 = 6 x

Hint: | Move terms with x to the left hand side.

Subtract 6 x from both sides:

(x - 6 x) + 2 = 6 x - 6 x

Hint: | Combine like terms in x - 6 x.

x - 6 x = -5 x:

-5 x + 2 = 6 x - 6 x

Hint: | Look for the difference of two identical terms.

6 x - 6 x = 0:

2 - 5 x = 0

Hint: | Isolate terms with x to the left hand side.

Subtract 2 from both sides:

(2 - 2) - 5 x = -2

Hint: | Look for the difference of two identical terms.

2 - 2 = 0:

-5 x = -2

Hint: | Divide both sides by a constant to simplify the equation.

Divide both sides of -5 x = -2 by -5:

(-5 x)/(-5) = (-2)/(-5)

Hint: | Any nonzero number divided by itself is one.

(-5)/(-5) = 1:

x = (-2)/(-5)

Hint: | Simplify the sign of (-2)/(-5).

Multiply numerator and denominator of (-2)/(-5) by -1:

Answer: x = 2/5

Answer: [tex]x=2/5[/tex]

Simplify both sides of the equation

[tex]1/3x+2/3=2x[/tex]

Subtract 2x from both sides

[tex]1/3x+2/3-2x=2x-2x\\-5/3x+2/3=0[/tex]

Subtract 2/3 from both sides

[tex]-5/3x=2/3-2/3=0-2/3\\-5/3x=-2/3[/tex]

Multiply both sides by 3/-5

[tex](3/-5)*(-5/3x)=(3/-5)*(-2/3)\\x=2/5[/tex]

Answer:

19 or 21.

Step-by-step explanation:

I swear.

5 + 5 = 10

10 + 5 = 15

15 + 4 = 19

________________

9 + 9 = 18

18 + 10 = 28

28 - 5 = 23

There are two nines so

23 - 2 = 21

Answer:

200,000+10,000+700+4

Step-by-step explanation:

Answer:

Step-by-step explanation:

2+3+4+5+6=20

20/20=4,000,000

2/20=?

2/20×4,000,000÷20/20=400,000

20/20=4,000,00

3/20

3/20×4000000÷20/20=600,000

20/20=4,000,000

4/20

4/20×4,000,000÷20/20=800,000

20/20=4,000,000

5/20

5/20×4,000,000÷20/20=1,000,000

20/20=4,000,000

6/20

6/20×4,000,000÷20/20= 1,200,000

2:3:4:5:6=400,000 :600,000: 800,000 : 1,000,000: 1,200,000

Answer:

ffdfssss

Step-by-step explanation:

fdfdfdfd

Answer:

x is invalid.

Step-by-step explanation:

Note the equal sign, what you do to one side, you do to the other. Remember to follow PEMDAS.

PEMDAS is the order of operation, and =

Parenthesis

Exponents (& Roots)

Multiplication

Division

Addition

Subtraction

First, distribute -4 to all terms within the parenthesis:

-4(1 - 6x) = (-4 * 1) + (-4 * -6x) = -4 + 24x

24x - 22 = -4 + 24x

Isolate the variable, x. Subtract 24x from both sides:

24x (-24x) - 22 = -4 + 24x (-24x)

0 - 22 = -4 + 0

-22 ≠ -4, therefore, this question is invalid.

~

Answer:

The between the given vector and the positive direction of the x-axis is approximately 41.186º.

Step-by-step explanation:

Let be [tex]\vec u = 8\,i + 7\,j[/tex] and [tex]\vec v = i[/tex] (Positive direction of the x-axis), the angle between both vectors can be determined from definition of dot product:

[tex]\vec u \bullet \vec v = \|\vec u\|\cdot \|\vec v\| \cdot \cos \theta[/tex]

Angle is cleared:

[tex]\cos \theta = \frac{\vec u\bullet \vec v}{\|\vec u\|\cdot \|\vec v\|}[/tex]

[tex]\theta = \cos^{-1}\left(\frac{\vec u \bullet \vec v}{\|\vec u\|\cdot \|\vec v\|} \right)[/tex]

The norms of [tex]\vec u[/tex] and [tex]\vec v[/tex] are found by Pythagorean Theorem:

[tex]\|\vec u\| = \sqrt{8^{2}+7^{2}}[/tex]

[tex]\|\vec u\| \approx \sqrt{113}[/tex]

[tex]\|\vec v\| = 1[/tex]

The dot product between both vectors is:

[tex]\vec u \bullet \vec v = (8)\cdot (1) + (6)\cdot (0)[/tex]

[tex]\vec u \bullet \vec v = 8[/tex]

The angle is now calculated:

[tex]\theta = \cos^{-1}\left(\frac{8}{\sqrt{113}} \right)[/tex]

[tex]\theta \approx 41.186^{\circ}[/tex]

The between the given vector and the positive direction of the x-axis is approximately 41.186º.

Steps to solve:

2g - 13 = 3

~Add 13 to both sides

2g = 16

~Divide 2 to both sides

g = 8

Best of Luck!

The solution to the equation 2g - 13 = 3 is g = 8.

To solve the equation 2g - 13 = 3 for g, we'll perform the necessary steps to isolate the variable g on one side of the equation.

Starting with the given equation:

2g - 13 = 3

First, we'll add 13 to both sides to eliminate the -13 term on the left side:

2g - 13 + 13 = 3 + 13

2g = 16

Next, to isolate the variable g, we divide both sides by 2:

(2g)/2 = 16/2

g = 8

Therefore, the solution to the equation 2g - 13 = 3 is g = 8.

In this equation, we initially have a linear expression involving the variable g and a constant term. By performing algebraic operations, we rearrange the equation to have g on one side and the constant value on the other side. This isolates the variable and provides us with a specific value for g that satisfies the equation. In this case, the value of g is determined to be 8, which can be verified by substituting it back into the original equation to see if it holds true.

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