If this container of gas is heated,
then the pressure inside the container will
increase because pressure increases as
temperature increases.
Hypothesis
Theory
Law

Answer:

Compound A:    1-bromo-1-methylcyclohexane

Compound B:     1-methylcyclohex-1-ene

Explanation:

In this question, we can start with the I.D.H (hydrogen deficiency index):

[tex]I.D.H~=~\frac{(2C)+2+(N)-(H)-(X)}{2}[/tex]

In the formula we have 7 carbons, 13 hydrogens, and 1 Br, so:

[tex]I.D.H~=~\frac{(2*7)+2+(0)-(13)-(1)}{2}=1[/tex]

We have an I.D.H value of one. This indicates that we can have a cyclic structure or a double bond.

We have to keep in mind that the Br atom must be bonded to a tertiary carbon. We can not have a double bond because in the ozonolysis reaction we have only 1 product, therefore, we can not have a double bond in the initial molecule (if we have a double bond in the initial molecule we will have more than 1 product in the ozonolysis reaction).

With this in mind, we will have a cyclic structure. If we have 7 carbons and we need a tertiary alkyl halide. We can have a cyclic structure of 6 members and a methyl group bonded to a carbon that also is bonded to a Br atom (1-bromo-1-methylcyclohexane).

In the reaction with [tex]CH_3CH_2ONa[/tex] we will have an elimination reaction. In other words, we have the production of a double bond inside of the cyclic structure (1-methylcyclohex-1-ene).

See figure 1 for further explanations.

I hope it helps!

Answer:

C) 6.95 M.

Explanation:

Hello,

In this case, considering that the molarity is computed via the ratio of the moles of solute to the volume of the solution in liters:

[tex]M=\frac{n_{solute}}{V_{solution}}[/tex]

Since the volume here is 95.0 mL or also 0.0950 L, the molarity turns out:

[tex]M=\frac{0.660mol}{0.0950L} \\\\M=6.95 M[/tex]

Therefore, answer is C) 6.95M.

Best regards.

Answer:

See explanation

Explanation:

Homemade pH test strips make it a bit difficult to identity the colours that indicate various values of pH on a pH colour scale. These homemade pH strips make the results of the experiment more prone to human error. Also the creator of the test strip is also prone to human error during the creation of the strip.

The commercial pH test strips are more accurate when used.

Answer: A: the components have different properties

Explanation:

The guy above is wrong I’m right got it correct on my unit review on edge

Answer:

A.

Explanation:

The correct answer is B. All liquids are denser than the ball, and honey is denser than corn syrup and maple syrup.

Explanation:

Differences in density cause substances such as solids or liquids to float or sink. In general, the substance sinks if it is denser, or floats if it is less dense. In this context, honey is the substance with the most density because it is at the bottom of the container. Also, honey is followed in density by maple syrup, and then by corn syrup. Moreover, if the ping pong ball floats in the most superficial layer, it is because this is less dense than any of the liquids. According to this, it can be concluded honey is denser than the other liquids, and the liquids are denser than the ball (option B.)

Answer:

b is right  ( all liquids are denser than the ball and honey is denser than corn syrup.)

Explanation:

Answer:

Fluere

i hope this helps!

Answer:

ll represents the shape of an orbital

Explanation:

There are four quantum numbers which give information about various orbitals in an atom. They describe the probability of finding the electron in an atom.

The orbital or azimuthal quantum number is represented as l. This quantum number gives information about the shape of an orbital.

Answer:

positive--real negative--not real

Answer:n a  red blood cell, the control center is the nucleus. A mitochondria is not a nucleus. It is another organelle that produces energy for the cell.

Explanation:

Answer:

the answer would be, 355000 mm/s.

Answer:

A base pair is a pair of bases that form hydrogen bonds in the double stranded DNA molecule.

- Adenine-thymine: A-T

- Guanine-cytosine: G-C

Replication Process:

- Double strand unwinds.

- New nucleorides line up via base pairing.

- Colvalent bonds link nucleotides together in the new strands.

Explanation:

Answer:

The mass of NH₄OH  present in the solution is 8.085 g

Explanation:

Given;

molarity of NH₄OH = 6 M

density of NH₄OH = 0.960 g/mL

mass of NH₄OH  = 37.0 grams

volume of  NH₄OH = mass /density

                                = 37/0.96

                                = 38.54 mL

molarity = moles of solute / Liters of solution

moles of solute  = molarity  x Liters of solution

moles of solute  = 6 x  38.54 x 10⁻³

moles of solute  = 0.231 moles

Reacting mass = number of moles x molecular mass

Molecular mass of NH₄OH = 35 g/mol

Reacting mass = 0.231 mol x 35 g/mol

Reacting mass = 8.085 g

Therefore, the mass of NH₄OH  present in the solution is 8.085 g

Explanation:

for respiration(exchange of gases)

Actually, all leaves have the same structure. The main purpose is to carry the photosynthesis out, that provides food that needs to survive. :)

Answer:

a) 2KOH + NiSO₄ → K₂SO₄ + Ni(OH)₂

b) Ni(OH)₂

c) KOH

d) 0.927 g

e) K⁺=0.067 M, SO₄²⁻=0.1 M, Ni²⁺=0.067 M

Explanation:

a) The equation is:

2KOH + NiSO₄ → K₂SO₄ + Ni(OH)₂   (1)        

b) The precipitate formed is Ni(OH)₂  

c) The limiting reactant is:

[tex] n_{KOH} = V*M = 100.0 \cdot 10^{-3} L*0.200 mol/L = 0.020 moles [/tex]

[tex] n_{NiSO_{4}} = V*M = 200.0 \cdot 10^{-3} L*0.150 mol/L = 0.030 moles [/tex]

From equation (1) we have that 2 moles of KOH react with 1 mol of NiSO₄, so the number of moles of KOH is:

[tex] n = \frac{2}{1}*0.030 moles = 0.060 moles [/tex]                  

Hence, the limiting reactant is KOH.  

d) The mass of the precipitate formed is:

[tex] n_{Ni(OH)_{2}} = \frac{1}{2}*n_{KOH} = \frac{1}{2}*0.020 moles = 0.010 moles [/tex]

[tex] m = n*M = 0.010 moles*92.72 g/mol = 0.927 g [/tex]  

e) The concentration of the SO₄²⁻, K⁺, and Ni²⁺ ions are:

[tex]C_{K^{+}} = \frac{2*\frac{1}{2}*n_{KOH}}{V} = \frac{0.020 moles}{0.300 L} = 0.067 M[/tex]  

[tex]C_{SO_{4}^{2-}} = \frac{\frac{1}{2}*n_{KOH + (0.03 - 0.01)}}{V} = \frac{0.030 moles}{0.300 L} = 0.1 M[/tex]

[tex]C_{Ni^{2+}} = \frac{0.020 moles}{0.300 L} = 0.067 M[/tex]

I hope it helps you!                                                                        

The mass of precipitate formed is 0.93 g .

The equation of the reaction is;

NiSO4(aq) + 2KOH(aq) ---->K2SO4(aq) + Ni(OH)2(s)

The precipitate that forms is Ni(OH)2(s).

To obtain the limiting reactant;

Number of moles of NiSO4 = 200/1000 × 0.150 M = 0.03 moles

Number of moles of KOH = 100/1000 × 0.200 M = 0.02 moles

Since 1 mole of NiSO4 reacts with 2 moles of KOH

x moles of NiSO4 reacts with 0.02 moles of KOH

x =  1 mole  ×  0.02 moles/2 moles  = 0.01 moles of NiSO4

Hence, KOH is the limiting reactant.

Now;

Since 2 mole of KOH yields 1 mole of Ni(OH)2

0.02 moles of KOH yields 0.02 moles ×  1 mole/ 2 mole  = 0.01 moles of  Ni(OH)2

Mass of  Ni(OH)2 produced =  0.01 moles of  Ni(OH)2 × 93 g/mol = 0.93 g

Learn more: https://brainly.com/question/9743981

Answer:

b) low temperature and high pressure

Explanation:

Deviation of gases from their ideal behavior could be as a result of two things which include a very small volume for the gases and the collisions not being elastic enough.

Small volume will decrease the frequency of elastic collisions a gas will experience as a result of the tiny space.

Low temperature will decrease the amount of elastic collisions and energy of the gas and high pressure will decrease the volume which is why there will be a deviation in the ideal behavior of Hcl(g)

Answer:

18.75 g of NH3.

Explanation:

The balanced equation for the reaction is given below:

4NH3 + 5O2 → 4NO + 6H2O

Next, we shall determine the masses of NH3 and O2 that reacted from the balanced equation.

This can be obtained as follow:

Molar mass of NH3 = 14 + (3x1) = 17 g/mol

Mass of NH3 from the balanced equation = 4 x 17 = 68 g

Molar mass of O2 = 16x2 = 32 g/mol

Mass of O2 from the balanced equation = 5 x 32 = 160 g

From the balanced equation above,

68 g if NH3 reacted with 160 g of O2.

Next, we shall determine the excess reactant. This can be obtained as follow:

From the balanced equation above,

68 g if NH3 reacted with 160 g of O2.

Therefore, 40 g of NH3 will react with = (40 × 160)/68 = 94.12 g of O2.

From the calculations made above, we can see that it will take a higher amount of O2 i.e 94.12g than what was given i.e 50g to react completely with 40 g of NH3.

Therefore, O2 is the limiting reactant and NH3 is the excess reactant.

Next we shall determine the mass of excess reactant that reacted. This can be obtained as follow:

From the balanced equation above,

68 g if NH3 reacted with 160 g of O2.

Therefore, Xg of NH3 will react with 50 g of O2 i.e

Xg of NH3 = (68 × 50)/160

Xg of NH3 = 21.25 g

Therefore, 21.25 g of NH3 (excess reactant) were consumed in the reaction.

Finally, we shall determine mass of the remaining excess reactant as follow:

Mass of excess reactant = 40 g

Mass of excess reactant that reacted = 21.25 g

Mass of excess reactant remainig =?

Mass of excess reactant remainig = (Mass of excess reactant) – (Mass of excess reactant that reacted)

Mass of excess reactant remainig

= 40 – 21.25

= 18.75 g

Therefore, the mass of excess reactant remaining is 18.75 g of NH3.

Answer:

250000 J.

Explanation:

From the question given above, the following data were obtained:

Mass (m) = 1250 kg

Velocity (v) = 20.0 m/s.

Kinetic energy (K.E) =?

Kinetic energy is simply defined as energy possed by a body in motion. Mathematically, it is expressed as:

K.E = ½mv²

Where:

K.E is the kinetic energy

m is the mass of the object

v is the velocity of the object.

Thus, we can obtain the kinetic energy of the automobile by using the above formula as illustrated below:

Mass (m) = 1250 kg

Velocity (v) = 20.0 m/s.

Kinetic energy (K.E) =?

K.E = ½mv²

K.E = ½ × 1250 × 20²

K.E = 625 × 400

K.E = 250000 J

Therefore, the kinetic energy of the automobile is 250000 J

Answer:

Transcription

Explanation:

Transcription is when you make a copy of the RNA from DNA. This is how the mRNA can leave the nucleus which exists to the cytoplasm and into ribosomes where protein synthesis occurs.

Answer:

Why does matter exist?

Explanation:

1) You can tell the temperature by counting a cricket's chirps! 2) Sandstorms can swallow up entire cities. 3) Dirt mixed with wind can make dust storms called black blizzards. ... 5) The coldest temperature ever officially recorded was -89.2°C.

Answer:

Explanation:

In 150 ml of .06 g / ml solution , gram of iodine = 150 x .06 g = 9 g

Let volume of given concentration of .12 g / ml required be V

In volume V , gram of iodine = V x .12 g

According to question

V x .12 = 9 g

V = 9 / .12 = 75 ml

So, 75 ml of .12 g/ml will be taken and it is diluted to the volume of 150 ml to get the solution of required concentration .

Answer:

d. There are two moles of hydroxide for each mole of these compounds.

Explanation:

calcium hydroxide, strontium hydroxide, and barium hydroxide all have two hydroxide compunds. the difference between each of these compounds is they all contain a different element along with hydroxide.

Answer:

c. CH3CH2CH2CH3 > d. CH3CH(CH3)2 > b. CH3CH2CH3 > a. CH3CH3

Explanation:

Hello,

In this case, considering the physical properties of hydrocarbons we find that the longer the carbon chain, the higher the boiling point as more energy is required for the phase transition from liquid to gas, thus, we see that c. CH3CH2CH2CH3 and d. CH3CH(CH3)2 have the highest boiling points since they have four carbons both. Then, we have b. CH3CH2CH3 which has three carbon atoms and the lowest boiling point is had by a. CH3CH3.

Nevertheless for both c. and d. we can see that c. has a straight chain whereas d. a branched chain, it means that c, has the highest boiling point due to the higher surface area for energy transfer.

Therefore, the order from highest to lowest is:

c. CH3CH2CH2CH3 > d. CH3CH(CH3)2 > b. CH3CH2CH3 > a. CH3CH3

Regards.

Answer:

False

False

they both will stay on the water

Hope this helped

Answer:

21 cm 3 that is the answer

Answer:

[tex]CrO_3[/tex]

Explanation:

Hello,

In this case, considering that the compound is 48% oxygen, we infer it is 52% chromium, therefore, by using their atomic masses we compute the moles by assuming those percentages as masses:

[tex]n_{Cr}=52g*\frac{1mol}{52g}=1mol\\ \\n_O=48g*\frac{1mol}{16g}=3mol[/tex]

Next, by dividing by the smallest moles, we find the subscripts in the empirical formula:

[tex]Cr=\frac{1}{1} =1\\\\O=\frac{3}{1} =3[/tex]

Which are also expressed in the smallest whole numbers, therefore the empirical formula is:

[tex]CrO_3[/tex]

Which corresponds to the chromic oxide or chromium (IV) oxide.

Regards.

Answer:

3

Explanation:

For decimals, you always start at the first non-zero number and count all the way to the end of the number. To count the number of significant figures this number has, you start at 6 and count every number after that for a total of 3.

Answer:

Final temperature is 32.56 °C

Explanation:

The specific heat of a substance is the amount of heat required to raise the temperature of 1g of the substance by 1°C.

The following equation/formula is used;

Q = m × c × ΔT

Where; Q= amount of heat supplied

(cal)

M= mass of ethanol (g)

C= specific heat of ethanol

(cal/g °C)

ΔT= change in temperature (°C)

i.e. (final temperature - initial

temperature)

According to the question, Q= 100 calories (cal), M= 18g, C= 0.581 cal/g °C, initial temperature = 23°C, final temperature = ?

Hence, we insert our values into the equation;

Q = m × c × ΔT

ΔT = Q/mc

(Final T - Initial T) = Q/mc

(Final T - 23) = 100/ 18 × 0.581

(Final T - 23) = 100/10.458

Final T - 23 = 9.562

Final T = 23 + 9.562

Final T = 32.562

Hence, the final temperature of ethanol is 32.56°C

Explanation:

Cobalt extraction refers to the techniques used to extract cobalt from its ores and other compound ores. Several methods exist for the separation of cobalt from copper and nickel. They depend on the concentration of cobalt and the exact composition of the used ore.

Cobalt ore

Contents:

The ores are treated by a sulfatizing roast in a fluidized bed furnace to convert copper and cobalt sulfides into soluble sulfates and iron into insoluble hematite. The calcine is subsequently leached with sulfuric acid from the spent copper recovery electrolyte. Oxide concentrates are introduced at this leaching step to maintain the acid balance in the circuit. Iron and aluminum are removed from the leach solution by the addition of lime, and copper is electrowon on copper cathodes. A part of the spent electrolyte enters the cobalt recovery circuit and is purified by the removal of iron, copper, nickel, and zinc prior to the precipitation of cobalt as its hydroxide. This is accomplished by the addition of more lime to raise the pH until the remaining copper precipitates. This copper is sent back to the copper circuit. As more lime is then added, a copper-cobaltite precipitates and is fed back to the leaching process. Sodium hydrosulfide (NaHS) is added (along with some metallic cobalt as a catalyst) to precipitate nickel sulfide (NiS). Hydrogen sulfide (H2S) and sodium carbonate (Na2CO3) are then added to precipitate zinc sulfide (ZnS). Lime is then added to saturation to precipitate cobalt(II) hydroxide (Ca(OH)2). In the final stages, this cobalt hydroxide is redissolved and the metal is refined by electrolysis. The resulting cobalt cathodes are crushed and vacuum degassed to obtain a pure cobalt metal.